Jacobian for n-dimensional Spherical Coordinates

Similar documents
Notes on Special Functions

Integration is the reverse of the process of differentiation. In the usual notation. k dx = kx + c. kx dx = 1 2 kx2 + c.

1 Schroenger s Equation for the Hydrogen Atom

+ dxk. dt 2. dt Γi km dxm. . Its equations of motion are second order differential equations. with intitial conditions

CBE 6333, R. Levicky 1. Orthogonal Curvilinear Coordinates

7 Curvilinear coordinates

MATH 280 Multivariate Calculus Fall Integration over a curve

Problem Solving 1: Line Integrals and Surface Integrals

Expansion of 1/r potential in Legendre polynomials

Figure 21:The polar and Cartesian coordinate systems.

4.4 Change of Variable in Integrals: The Jacobian

Figure 25:Differentials of surface.

Chapter 4. The First Fundamental Form (Induced Metric)

MATH 280 Multivariate Calculus Fall Integration over a surface. da. A =

MULTIVARIABLE INTEGRATION

Practice Final Solutions

Appendix A Vector Analysis

Math Vector Calculus II

Contents. MATH 32B-2 (18W) (L) G. Liu / (TA) A. Zhou Calculus of Several Variables. 1 Multiple Integrals 3. 2 Vector Fields 9

Connection to Laplacian in spherical coordinates (Chapter 13)

Integrals in cylindrical, spherical coordinates (Sect. 15.7)

Substitutions in Multiple Integrals

INTEGRATION WORKSHOP 2003 COMPLEX ANALYSIS EXERCISES

1 Differential Operators in Curvilinear Coordinates

Fundamentals of Mathematics (MATH 1510)

10.1 Curves Defined by Parametric Equation

Candidates are expected to have available a calculator. Only division by (x + a) or (x a) will be required.

Multiple Integrals and Vector Calculus (Oxford Physics) Synopsis and Problem Sets; Hilary 2015

Summary for Vector Calculus and Complex Calculus (Math 321) By Lei Li

MULTIVARIABLE INTEGRATION

the Cartesian coordinate system (which we normally use), in which we characterize points by two coordinates (x, y) and

Inverse Problem Theory. Complements to the Jan. 7, 2004 course. Albert Tarantola

Appendix: Orthogonal Curvilinear Coordinates. We define the infinitesimal spatial displacement vector dx in a given orthogonal coordinate system with

4 The Trigonometric Functions

Math 221 Examination 2 Several Variable Calculus

Probability Density versus Volumetric Probability. Albert Tarantola. September 20, Probability Density (the Standard Definition)

AN INTRODUCTION TO CURVILINEAR ORTHOGONAL COORDINATES

Student name: Student ID: Math 265 (Butler) Midterm III, 10 November 2011

APPENDIX 2.1 LINE AND SURFACE INTEGRALS

JUST THE MATHS SLIDES NUMBER 3.1. TRIGONOMETRY 1 (Angles & trigonometric functions) A.J.Hobson

Trigonometric Functions. Section 1.6

Geometry and Motion Selected answers to Sections A and C Dwight Barkley 2016

DO NOT BEGIN THIS TEST UNTIL INSTRUCTED TO START

Multiple Integrals and Vector Calculus: Synopsis

Instructions: No books. No notes. Non-graphing calculators only. You are encouraged, although not required, to show your work.

Double Integrals. Advanced Calculus. Lecture 2 Dr. Lahcen Laayouni. Department of Mathematics and Statistics McGill University.

Integral Theorems. September 14, We begin by recalling the Fundamental Theorem of Calculus, that the integral is the inverse of the derivative,

Unit Circle: The unit circle has radius 1 unit and is centred at the origin on the Cartesian plane. POA

MATH2000 Flux integrals and Gauss divergence theorem (solutions)

MATH H53 : Final exam

Coordinates 2D and 3D Gauss & Stokes Theorems

xy 2 e 2z dx dy dz = 8 3 (1 e 4 ) = 2.62 mc. 12 x2 y 3 e 2z 2 m 2 m 2 m Figure P4.1: Cube of Problem 4.1.

MAT137 Calculus! Lecture 6

Laplace equation in polar coordinates

In this chapter we study several functions that are useful in calculus and other areas of mathematics.

Orthogonal Curvilinear Coordinates

1. (a) (5 points) Find the unit tangent and unit normal vectors T and N to the curve. r (t) = 3 cos t, 0, 3 sin t, r ( 3π

Tangent Planes, Linear Approximations and Differentiability

Summary: Curvilinear Coordinates

MATH 228: Calculus III (FALL 2016) Sample Problems for FINAL EXAM SOLUTIONS

14. Rotational Kinematics and Moment of Inertia

S12.1 SOLUTIONS TO PROBLEMS 12 (ODD NUMBERS)

which has a check digit of 9. This is consistent with the first nine digits of the ISBN, since

Gradient, Divergence and Curl in Curvilinear Coordinates

Chapter 1. Vector Analysis

Introduction and Vectors Lecture 1

ENGINEERINGMATHEMATICS-I. Hrs/Week:04 Exam Hrs: 03 Total Hrs:50 Exam Marks :100

Gauss s Law & Potential

Chapter 2. Coordinate Systems and Transformations

Rule ST1 (Symmetry). α β = β α for 1-forms α and β. Like the exterior product, the symmetric tensor product is also linear in each slot :

1 Potential due to a charged wire/sheet

Chapter 6. Quantum Theory of the Hydrogen Atom

Topic 7. Electric flux Gauss s Law Divergence of E Application of Gauss Law Curl of E

Ma 1c Practical - Solutions to Homework Set 7

Review problems for the final exam Calculus III Fall 2003

Mathematics 205 Solutions for HWK 23. e x2 +y 2 dxdy

Chapter 2 Acoustical Background

Math 3435 Homework Set 11 Solutions 10 Points. x= 1,, is in the disk of radius 1 centered at origin

Curvilinear coordinates

SOLUTIONS TO THE FINAL EXAM. December 14, 2010, 9:00am-12:00 (3 hours)

PARAMETRIC EQUATIONS AND POLAR COORDINATES

Solutions to Sample Questions for Final Exam

Maths for Map Makers

QMUL, School of Physics and Astronomy Date: 18/01/2019

arxiv:math.ca/ v2 17 Jul 2000

Final exam (practice 1) UCLA: Math 32B, Spring 2018

MATH20411 PDEs and Vector Calculus B

Chapter Given three points, A(4, 3, 2), B( 2, 0, 5), and C(7, 2, 1): a) Specify the vector A extending from the origin to the point A.

(1) Recap of Differential Calculus and Integral Calculus (2) Preview of Calculus in three dimensional space (3) Tools for Calculus 3

Title Intuition Formalities Examples 3-D. Curvature. Nicholas Dibble-Kahn. University of California, Santa Barbara. May 19, 2014

Things You Should Know Coming Into Calc I

ENGI Gradient, Divergence, Curl Page 5.01

y=1/4 x x=4y y=x 3 x=y 1/3 Example: 3.1 (1/2, 1/8) (1/2, 1/8) Find the area in the positive quadrant bounded by y = 1 x and y = x3

ANTENNAS. Vector and Scalar Potentials. Maxwell's Equations. E = jωb. H = J + jωd. D = ρ (M3) B = 0 (M4) D = εe

A PROOF OF THE GAUSS-BONNET THEOREM. Contents. 1. Introduction. 2. Regular Surfaces

1 Isotropic Covariance Functions

Appendix to Lecture 2

x n cos 2x dx. dx = nx n 1 and v = 1 2 sin(2x). Andreas Fring (City University London) AS1051 Lecture Autumn / 36

Solutions: Homework 5

Sheet 06.6: Curvilinear Integration, Matrices I

Transcription:

Jacobian for n-dimensional Spherical Coordinates In this article we will derive the general formula for the Jacobian of the transformation from the Cartesian coordinates to the spherical coordinates in n dimensions without the use of determinants. In general, the equation for the sphere of radius R in integer n dimensions is x 1 + x +... + x n = R (1) where x 1, x,..., x n are Cartesian coordinates. The n-dimesnsional sphere is often called n-hypersphere. For n = we have just the equation of a circle, and for n = 3 the equation of a three-dimensional sphere. To compute the area of a circle or the volume of a three-dimensional sphere it is convenient to carry out the appropriate integrations in azimuthal and spherical coordinates, respectively. The computation of the volume of the n-dimensional sphere would require integration in n-dimensional spherical coordinates. The derivation of the transformation from the Cartesian coordinates x 1, x,..., x n to the n-dimensional spherical coordinates r, θ, φ 1,... φ n has been presented in [1]. For example the transformation for five dimensions is given by equations (19) and for n dimensions is 1 : x 1 = r cos φ 1 : x = r sin φ 1 cos φ 3 : x 3 = r sin φ 1 sin φ cos φ 3... i :... n : n 1 : n : x i = r sin φ 1 sin φ... sin φ i 1 cos φ i x n = r sin φ 1 sin φ... sin φ n 3 cos φ n x n 1 = r sin φ 1 sin φ... sin φ n cos θ x n = r sin φ 1 sin φ... sin φ n sin θ () where 0 φ i π, i = 1,..., n and 0 θ π. The n-dimensional spherical coordinates are created in such way that they are orthogonal what means that the scalar product of their any two basis vectors, which are sometimes called versors, î r, î θ, î φi for i = 1,,..., n is equal zero. The n-dimensional Cartesian coordinates are also orthogonal. 1

The transformation from one set of coordinates to another one involves the change of the infinitesimally small volume element. In Cartesian coordinates the volume element is simply dv (x 1,x,...,x n) = dx 1 dx 1... dx n (3) and the change from the Cartesian to the spherical coordinates involves the Jacobian J(r, θ, φ 1, φ,..., φ n ) of the transformation, so we must write the formula for the volume element in the n-dimensional spherical coordinates as dv (r,θ,φ 1,φ,...,φ n ) = J(r, θ, φ 1, φ,..., φ n )drdθdφ 1 dφ... dφ n (4) The Jacobian is a determinant of the n by n matrix of partial derivatives x 1 x 1 x 1 x r θ φ 1 1 φ n x x x x r θ φ 1 φ n...... (5). x n x n x n x r θ φ 1 n φ n For how Jacobian determinant emerges in the transformation of variables we will point the reader to []. We will analyze the Jacobians of transformations from the Cartesian to the spherical coordinates for dimensions n = 1,, 3, 4, 5 without actually computing any determinants, and we will develop the general formula for the Jacobian of the transformation of coordinates for any dimension n >. Computing the Jacobian determinants even for a three-dimensional spherical coordinates transformation is cumbersome. We will employ another method which is based on the definition of the angle measure in radians and on the orthogonality of the spherical coordinates. The radian measure dα of a central angle of a circle is defined as the ratio of the length dl α of the arc the angle subtends divided by the radius r of the circle dα = dl α r We may express the value of the volume element dv (r,θ,φ 1,φ,...,φ n ) as dv (r,θ,φ 1,φ,...,φ n ) = drdl θ dl φ1 dl φ... dl φn (7) (6)

by virtue of orthogonality of the versors î r, î θ, î φi for i = 1,,..., n along the radius r and tangent to the coordinate lines θ, φ i for i = 1,,..., n, respectively at the point (r, θ, φ 1,..., φ n ). The versors for threedimesional spherical coordinates which are denoted in this article by î r, î θ, î φ1 are illustrated in [3]. θ is azimuthal angle coordinate, and φ i is called i-th polar angle coordinate. For n = 1 1 : x 1 = r (8) we just make a variable substitution and dv (r) = J(r)dr = dr (9) what gives J 1 = J(r) = 1. For n = we add azimuthal angle θ as the second coordinate 1 : x 1 = r cos θ : x = r sin θ (10) and we have for θ : dθ = dl θ /r (11) The volume element for n = is dv (r,θ) = J(r, θ)drdθ = drdl θ = rdrdθ (1) and J = J(r, θ) = r. For n = 3 we need to add to the coordinates the polar angle φ 1 1 : x 1 = r cos φ 1 : x = r sin φ 1 cos θ 3 : x 3 = r sin φ 1 sin θ (13) and we have for φ 1 : dφ 1 = dl φ1 /r θ : dθ = dl θ /(r sin φ 1 ) (14) 3

We come to the above formulas just by taking into account that the angle dφ 1 subtends the arc of length dl φ1 of the radius r, and that the angle dθ subtends the arc of length dl θ of the radius r sin φ 1. The volume element in 3 dimensions is dv (r,θ,φ 1) = J(r, θ, φ 1 )drdθdφ 1 = drdl θ dl φ1 = r sin φ 1 drdθdφ 1 (15) and the Jacobian J 3 = J(r, θ, φ 1 ) = r sin φ 1. For n = 4 we add to the coordinates the polar angle φ and it gives for 1 : x 1 = r cos φ 1 : x = r sin φ 1 cos φ 3 : x 3 = r sin φ 1 sin φ cos θ 4 : x 4 = r sin φ 1 sin φ sin θ φ 1 : dφ 1 = dl φ1 /r φ : dφ = dl φ /(r sin φ 1 ) θ : dθ = dl θ /(r sin φ 1 sin φ ) (16) (17) Now the situation is that the angle dφ 1 subtends the arc of length dl φ1 of the radius r as before, the angle dφ subtends the arc of length dl φ of the radius r sin φ 1, which is the new radius as given in (16) in the formula for x, and that the angle dθ subtends the arc of length dl θ of the radius r sin φ 1 sin φ also by analogy to the situation for 3 dimensions. In other words we develop the above relations as a consequence of the definition of the spherical coordinates in 3 dimensions in equations (13) and by following the relations in (14). The volume element in 4 dimensions is dv (r,θ,φ 1,φ ) = J(r, θ, φ 1, φ )drdθdφ 1 dφ = drdl θ dl φ1 dl φ (18) = r 3 sin φ 1 sin φ drdθdφ 1 dφ and the Jacobian J 4 = J(r, θ, φ 1, φ ) = r 3 sin φ 1 sin φ. For n = 5 we have 1 : x 1 = r cos φ 1 : x = r sin φ 1 cos φ 3 : x 3 = r sin φ 1 sin φ cos φ 3 4 : x 4 = r sin φ 1 sin φ sin φ 3 cos θ 5 : x 5 = r sin φ 1 sin φ sin φ 3 sin θ (19) 4

and for φ 1 : dφ 1 = dl φ1 /r φ : dφ = dl φ /(r sin φ 1 ) φ 3 : dφ 3 = dl φ3 /(r sin φ 1 sin φ ) θ : dθ = dl θ /(r sin φ 1 sin φ sin φ 3 ) This gives the volume element for 5 dimensions (0) dv (r,θ,φ 1,φ,φ 3 ) = J(r, θ, φ 1, φ, φ 3 )drdθdφ 1 dφ dφ 3 = drdl θ dl φ1 dl φ dl φ3 (1) = r 4 sin 3 φ 1 sin φ sin φ 3 drdθdφ 1 dφ dφ 3 and the Jacobian J 5 = J(r, θ, φ 1, φ, φ 3 ) = r 4 sin 3 φ 1 sin φ sin φ 3. We notice that our Jacobian for 5 dimensions is just the product of the denominators from the equations (0). The pattern for the Jacobian of the transformation from n Cartesian coordinate system to the system of n-dimensional spherical coordinates clearly reveals itself. For n > n J n = J(r, θ, φ 1, φ,..., φ n ) = r n 1 sin n 1 k φ k () The Jacobian we derived may be used in computing the volume V n (c) or the surface S n (r) of a n-dimensional sphere of radius c or r, respectively. V n (c) = c r=0 S n (r) = π π θ=0 = π π θ=0 φ 1 =0 c φ 1 =0 r=0 π φ =0 r n 1 dr π k=1 φ n =0 π n π θ=0 dθ J n drdθdφ 1 dφ... dφ n (3) k=1 φ k =0 sin n 1 k φ k dφ k π π J n dθdφ 1 dφ... dφ n (4) φ =0 φ n =0 π n π = r n 1 dθ sin n 1 k φ k dφ k θ=0 k=1 φ k =0 The further computation is an exercise in applying the formula for the integral of the type π/ 0 ( ) sin n x cos m dx = 1 B 1 (n + 1), 1 (m + 1) 5 (5)

where B is the Beta function, which is defined in [4] and [5] to compute the integral of powers of sine, and then the application of the Euler gamma function Γ which is described in [4], [6] and [7] and which is related to the function Beta B(x, y) = Γ(x)Γ(y) Γ(x + y) (6) Properties of Euler Gamma function used in this article are presented also in [8]. For natural values of x the Euler Gamma function has the property Γ(x) = (x 1)! (7) If we substitute x + 1 for x in the above equation, then we obtain Γ(x + 1) = x! = x(x 1)! = xγ(x) (8) The relation Γ(x + 1) = xγ(x) (9) is valid also for real values of x. Also ( 1 Γ = ) π (30) Then we have S n (r) = r n 1 π Γn ( 1) Γ( 1n) = π 1 n r n 1 Γ( 1n) (31) V n (R) = R r=0 S n (r) dr = π 1 n R n nγ( 1 n) (3) In particular for n = 3, i.e. for three dimensions we can obtain the formulas for the surface area and for the volume of a sphere. For the sphere surface area from equation (31) we have S 3 (r) = π 3 r Γ( 3) = ( π) 3 r Γ( 3) (33) From equations (9) and (30) we can compute the value of Γ ( ) 3 ( 3 ( 1 ) Γ = Γ ) + 1 = 1 ( 1 ) Γ = 1 π (34) 6

and substitute it into equation (33) S 3 (r) = ( π) 3 r (35) π obtaining the well known formula for the surface area S 3 (r) of a threedimensional sphere of radius r 1 S 3 (r) = 4πr (36) For the sphere volume V 3 (R) of a three-dimensional sphere from equation (3) we obtain and we receive V 3 (R) = ( π) 3 R 3 3Γ( 3 ) = ( π) 3 R 3 (37) π 3 V 3 (R) = 4 3 πr3 (38) what is also a familiar formula for the volume of a sphere of radius R. References [1] K.S. Miller, Multidimensional Gaussian Distributions, John Wiley & Sons, Inc., New York, London, Sydney, 1964. [] R.A. Hunt, Calculus, nd ed., HarperCollins College Publishers, 1994. [3] http://mathworld.wolfram.com/sphericalcoordinates.html [4] N.N. Lebedev, Special Functions and Their Applications, Translation by R.A. Silverman, Dover Publications, Inc., New York, 197. [5] http://mathworld.wolfram.com/betafunction.html [6] Emil Artin, The Gamma Function, Translation by Michael Butler, Dover Publications, Inc., Mineola, New York, 015. [7] http://mathworld.wolfram.com/gammafunction.html [8] Donald A. McQuarrie, Mathematical Methods for Scientists and Engineers, University Science Books, Sausalito, California 003. 7

Pawel Jan Piskorz (paweljs@gmail.com) 46 Tynan Ct Erie, CO 80516-708 USA 8