Basic Trigonometry. Trigonometry deals with the relations between the sides and angles of triangles.

Similar documents
Examples: Identify three pairs of parallel segments in the diagram. 1. AB 2. BC 3. AC. Write an equation to model this theorem based on the figure.

The Pythagorean Theorem & Special Right Triangles

Chapter 6 Summary 6.1. Using the Hypotenuse-Leg (HL) Congruence Theorem. Example

LT 2.1 Study Guide and Intervention Classifying Triangles

Name Date Period Notes Formal Geometry Chapter 8 Right Triangles and Trigonometry 8.1 Geometric Mean. A. Definitions: 1.

Statistics. To find the increasing cumulative frequency, we start with the first

5-1 Practice Form K. Midsegments of Triangles. Identify three pairs of parallel segments in the diagram.

Los Angeles Unified School District Periodic Assessments. Geometry. Assessment 2 ASSESSMENT CODE LA08_G_T2_TST_31241

Class : IX(CBSE) Worksheet - 1 Sub : Mathematics Topic : Number system

Algebra 1B. Unit 9. Algebraic Roots and Radicals. Student Reading Guide. and. Practice Problems

Unit 4-Review. Part 1- Triangle Theorems and Rules

The Theorem of Pythagoras

1/19 Warm Up Fast answers!

Individual Round Arithmetic

Downloaded from

Geometry Note Cards EXAMPLE:

Integrated Math II. IM2.1.2 Interpret given situations as functions in graphs, formulas, and words.

Pre-Algebra (7) B Mathematics

8-2 The Pythagorean Theorem and Its Converse. Find x. 27. SOLUTION: The triangle with the side lengths 9, 12, and x form a right triangle.

Answers. Investigation 4. ACE Assignment Choices. Applications. The number under the square root sign increases by 1 for every new triangle.

Part (1) Second : Trigonometry. Tan

chapter 1 vector geometry solutions V Consider the parallelogram shown alongside. Which of the following statements are true?

Geometry Warm Up Right Triangles Day 8 Date

Find the geometric mean between 9 and 13. Find the geometric mean between

( ) ( ) Geometry Team Solutions FAMAT Regional February = 5. = 24p.

Vocabulary. Term Page Definition Clarifying Example altitude of a triangle. centroid of a triangle. circumcenter of a triangle. circumscribed circle

Nozha Directorate of Education Form : 2 nd Prep. Nozha Language Schools Ismailia Road Branch

UNIT 1 SIMILARITY, CONGRUENCE, AND PROOFS Lesson 9: Proving Theorems About Triangles Instruction

Histogram, cumulative frequency, frequency, 676 Horizontal number line, 6 Hypotenuse, 263, 301, 307

Question 1 (3 points) Find the midpoint of the line segment connecting the pair of points (3, -10) and (3, 6).

Name: Period: Date: Given: is the bisector of Draw JD and DL such that it makes triangle DJL. Then answer the question. a. 17 b. 73 c. 118 d.

Nozha Directorate of Education Form : 2 nd Prep

Brunswick School Department Honors Geometry Unit 6: Right Triangles and Trigonometry

Pythagoras Theorem and Its Applications

Similarity of Triangle

7.5 Proportionality Relationships

Incoming Magnet Precalculus / Functions Summer Review Assignment

Geometry Final Review. Chapter 1. Name: Per: Vocab. Example Problems

Section 5.1. Perimeter and Area

Name: Class: Date: 5. If the diagonals of a rhombus have lengths 6 and 8, then the perimeter of the rhombus is 28. a. True b.

SMT 2018 Geometry Test Solutions February 17, 2018

Proofs. by Bill Hanlon

Properties of Isosceles and Equilateral Triangles

Midpoint M of points (x1, y1) and (x2, y2) = 1 2

Common Core Edition Table of Contents

1 st Preparatory. Part (1)

Correlation of 2012 Texas Essential Knowledge and Skills (TEKS) for Algebra I and Geometry to Moving with Math SUMS Moving with Math SUMS Algebra 1

For math conventions used on the GRE, refer to this link:

Test Corrections for Unit 1 Test

Pythagoras theorem (8 9)

Introduction to Vectors

Algebra and Trig. I. P=(x,y) 1 1. x x

0609ge. Geometry Regents Exam AB DE, A D, and B E.

Precalculus Summer Assignment 2015

Unit 5, Lesson 4.3 Proving the Pythagorean Theorem using Similarity

Indicate the answer choice that best completes the statement or answers the question.

MATH 109 TOPIC 3 RIGHT TRIANGLE TRIGONOMETRY. 3a. Right Triangle Definitions of the Trigonometric Functions

0113ge. Geometry Regents Exam In the diagram below, under which transformation is A B C the image of ABC?

Answer Explanations for: ACT June 2012, Form 70C

2. In ABC, the measure of angle B is twice the measure of angle A. Angle C measures three times the measure of angle A. If AC = 26, find AB.

Algebra II/Geometry Curriculum Guide Dunmore School District Dunmore, PA

Integer (positive or negative whole numbers or zero) arithmetic

9.7 Extension: Writing and Graphing the Equations

Kansas City Area Teachers of Mathematics 2018 KCATM Math Competition. GEOMETRY and MEASUREMENT GRADE 7-8

Unit 1 Review. To prove if a transformation preserves rigid motion, you can use the distance formula: Rules for transformations:

8 Right Triangle Trigonometry

SOLUTIONS SECTION A SECTION B

GEOMETRY. Similar Triangles

Answers. Chapter 9 A92. Angles Theorem (Thm. 5.6) then XZY. Base Angles Theorem (Thm. 5.6) 5, 2. then WV WZ;

Inequalities for Triangles and Pointwise Characterizations

Alg. (( Sheet 1 )) [1] Complete : 1) =.. 3) =. 4) 3 a 3 =.. 5) X 3 = 64 then X =. 6) 3 X 6 =... 7) 3

Study Guide for Benchmark #1 Window of Opportunity: March 4-11

Subject: General Mathematics

Indicate the answer choice that best completes the statement or answers the question. Find the volume of the solid.

3, 5, Inequalities in One Triangle. Use the Exterior Angle Inequality Theorem to list all of the angles that satisfy the stated condition.

Midterm Review Packet. Geometry: Midterm Multiple Choice Practice

Q1. The sum of the lengths of any two sides of a triangle is always (greater/lesser) than the length of the third side. askiitians

1. If two angles of a triangle measure 40 and 80, what is the measure of the other angle of the triangle?

Lyman Memorial High School. CP Pre-Calculus Prerequisite Packet. Name:

Directions: Examine the Unit Circle on the Cartesian Plane (Unit Circle: Circle centered at the origin whose radius is of length 1)

Math Contest, Fall 2017 BC EXAM , z =

Content Guidelines Overview


During: The Pythagorean Theorem and Its converse

Higher Geometry Problems

triangles in neutral geometry three theorems of measurement

Level 1: Simplifying (Reducing) Radicals: 1 1 = 1 = 2 2 = 4 = 3 3 = 9 = 4 4 = 16 = 5 5 = 25 = 6 6 = 36 = 7 7 = 49 =

Distance. Warm Ups. Learning Objectives I can find the distance between two points. Football Problem: Bailey. Watson

Geometry Problem Solving Drill 07: Properties of Triangles

Shape Perimeter Area. + s 3. + s 2. side 3 (s 3 ) base (b) and side 1 (s 1

Glossary. Glossary Hawkes Learning Systems. All rights reserved.

CHAPTER 12 HERON S FORMULA Introduction

Unit 8. ANALYTIC GEOMETRY.

Pre RMO Exam Paper Solution:

RMT 2014 Geometry Test Solutions February 15, 2014

Geometry. A. Right Triangle. Legs of a right triangle : a, b. Hypotenuse : c. Altitude : h. Medians : m a, m b, m c. Angles :,

Not all triangles are drawn to scale. 3. Find the missing angles. Then, classify each triangle by it s angles.

ANALYTICAL GEOMETRY Revision of Grade 10 Analytical Geometry

Right Triangles And Trigonometery

2014 Summer Review for Students Entering Algebra 2. TI-84 Plus Graphing Calculator is required for this course.

Transcription:

Basic Trigonometry Trigonometry deals with the relations between the sides and angles of triangles. A triangle has three sides and three angles. Depending on the size of the angles, triangles can be: - right-angled: one of the angles is 90 o. - acute: all angles are less than 90 o. -obtuse: one of the angles is more than 90 o. Depending on the relations between the sides, triangles can be classified as: - equilateral: all sides are equal; - isosceles: two of the three sides are equal; - scalene: the sides have different, random lengths.

Any triangle has a series of properties: - the sum of the three angles is always 180 o. (A + B + C = 180 o ) - the perimeter (P) of a triangle is the sum of the three sides. (P = a + b + c) - the area (A) is half the product of a side (s) and its respective altitude (h). A = s * h / 2 - if we know the sides but cannot determine any altitude, we can use Heron's formula to calculate the area. This formula makes use of the sides lengths and the semi-perimeter (S) of the triangle. Heron's formula: A = S S a S b (S c) S = P / 2 The sides of a triangle measure 5, 29 and 30 meters respectively. Calculate its area. First, we calculate the semiperimeter: S = (5 + 29 + 30) / 2 S = 64 / 2 S = 32 Then, we put the numbers into Heron s formula: A = 32 32 5 32 29 (32 30) A = 32 27 3 2 A = 5184 A = 72 m

Special triangles have special properties that can help us calculate more easily: The isosceles triangle: The angles opposite the equal sides are, in turn, equal. Any altitude is also a median, an angle bisector and a perpendicular bisector. The equilateral triangle: All sides are equal, all angles are 60 o. The area of an equilateral triangle can be determined without calculating any altitude first. The formula we need only uses the length of the side (s): A = s 2 * 3 / 4 Calculate the area of an equilateral triangle, knowing that its side is 6 cm. We simply need to put the length of the side in the equation: A = 6 2 * 3 / 4 A = 36 3 / 4 A = 9 3 cm 2 (See the algebra lesson on reducing this equation if you re not sure how that worked)

The right-angled triangle: In a right-angled triangle, the sides which form the 90 degrees angle are called legs or catheti ( sg: cathetus). The side opposite the right angle is called the hypotenuse. The most famous calculation generally done in a right-angled triangle involves the determination of a side using Pythagoras s theorem. This states that the square hypotenuse equals the sum of the squared catheti: a! + b! = c! In a right-angled triangle, the legs are 5, respectively 12 cm long. Calculate the hypotenuse. Let x be the hypotenuse. Using Pythagoras s theorem, we know that x 2 = 5 2 + 12 2 x 2 = 25 + 144 x 2 = 169 x = 169 x = +/- 13 Because x represents length, it cannot be a negative number, so we always choose the positive one. Therefore, the hypotenuse is 13 cm. The lengths of the sides are always positive numbers, but they are not always natural. The numbers can also be fractional or even irrational. There are, however, several sets of natural numbers that fit into Pythagoras s theorem. These are called Pythagorean Triples. Some examples are: (3, 4, 5), (5, 12, 13), (8, 15, 17), (7, 24, 25) etc., and their multiples. For example, since (3, 4, 5) is a Pythagorean triple, then (6, 8, 10) or (9, 12, 15) will also fit into the Pythagoras s formula. Because a leg in a right-angled triangle is the altitude corresponding to the other leg, the formula for calculating the area can be translated as half the product of the two catheti. A = a * b / 2

In a right-angled triangle, the catheti are 6, respectively 8 cm. Calculate the area of the triangle. One way to go would be to calculate the hypotenuse (which would be 10, since (6, 8, 10) form a Pythagorean triple, as discussed above), then try to determine the altitude corresponding to the hypotenuse. This would be quite complicated. A simple way would be to take one cathetus as a base, and the other cathetus as the corresponding altitude. Therefore, the area will be A = 6 * 8 / 2 A = 48 / 2 A = 24 cm 2 There are two special types of right-angled triangles: - the isosceles right triangle, in which the legs are equal. In this type of triangles, the ratio of the three sides is 1:1: 2. - the 30 o -60 o -90 o triangle. The three numbers represent the angles. In such triangles, the ratio of the sides is 1:2: 3. Another way to determine the ratio is to remember that the leg opposite the 30 o angle is half the hypotenuse. Using Pythagoras's theorem, one can easily calculate the remaining side.

Advanced Trigonometry The following two sections are unlikely to be required in your testing, however, if you want to take your skills to a higher level, continue reading! Midsegments Any triangle has three midsegments i.e., three segments that unite the middle points of each pair of sides of the triangle. In the triangle on the right, the midsegments are segments XY, YZ and XZ, because X is the middle of AB (AX = XB), Y is the middle of BC (BY = YC) and Z is the middle of AC (AZ = ZC). Each midsegment is parallel to the side it does not intersect, and is also half of that side. So, XY / AC = XZ / BC = YZ / AB = 1/2 All the triangles that the midsegments form inside the original triangle are identical (the sides have the same sizes, the angles have the same measures). Trapeziums also have midsegments. In the trapezium on the right, the midsegment is MN. M is the middle of AD (AM = MD), while N is the middle of BC (BN = NC). In trapeziums, the midsegment is the arithmetic mean of the two parallel sides. Therefore, MN = (AB + CD) / 2 The Intercept Theorem As we have seen, the midsegment divides the sides in segments with ratios of 1/2. If we draw another parallel, that intersects the sides at other points than the middle, then the ratios will change, but the segments will still be directly proportional. In the triangle on the right, XY is parallel to BC, but XY is not a midsegment. Therefore, according to the Intercept Theorem, AX / AB = AY / AC = XY / BC

Also, the segments are directly proportional between themselves. AX / XB = AY / YC We can use this theorem when we have a parallel line inside a triangle, in order to determine the length of the sides or the segments. Let us consider that AY / AC is 5/8 and AX is 10. Calculate AB. According to the Intercept theorem, AX / AB = AY / AC. If the ratio is 5/8, then AX / AB = 5/8 AX = 10, so 10 / AB = 5/8 AB = 10 * 8 / 5 AB = 16