Bent linear trigonal planar trigonal pyramidal Polar nonpolar nonpolar polar Sp 3 sp sp 2 sp 3

Similar documents
Chapter 9 practice questions

MOLECULAR ORBITAL DIAGRAM KEY

CHM 151 Practice Final Exam

Subtopic 4.2 MOLECULAR SHAPE AND POLARITY

Chem 1210 Final Spring points Dr. Luther Giddings

Review for Chapter 4: Structures and Properties of Substances

Bonding/Lewis Dots Lecture Page 1 of 12 Date. Bonding. What is Coulomb's Law? Energy Profile: Covalent Bonds. Electronegativity and Linus Pauling

Molecular shape is determined by the number of bonds that form around individual atoms.

2. Write the electron configuration notation and the electron dot notation for each: (a) Ni atom (b) Ni 2+ ion (c) Ni 3+ ion

Bonding. Honors Chemistry 412 Chapter 6

51. Pi bonding occurs in each of the following species EXCEPT (A) CO 2 (B) C 2 H 4 (C) CN (D) C 6 H 6 (E) CH 4

SL Score. HL Score ! /30 ! /48. Practice Exam: Paper 1 Topic 4: Bonding. Name

Molecular Geometry and intermolecular forces. Unit 4 Chapter 9 and 11.2

Ch 10 Chemical Bonding, Lewis Structures for Ionic & Covalent Compounds, and Predicting Shapes of Molecules

Chemistry 121: Topic 4 - Chemical Bonding Topic 4: Chemical Bonding

General Chemistry Multiple Choice Questions Chapter 5

IB Chemistry 11 Kahoot! Review Q s Bonding

2011, Robert Ayton. All rights reserved.

Chemical Bonding II: Molecular Geometry and Hybridization of Atomic Orbitals Chapter 10

Downloaded from

MC Molecular Structures, Dipole Moments, Geometry, IMF Name: Date:

Valence Bond Theory - Description

Unit Six --- Ionic and Covalent Bonds

Multiple Choice. Multiple Choice

Chemical bonding is the combining of elements to form new substances.

1. Choose the CORRECT abbreviated electron configuration for copper. a. [Ar] 4s 1 3d 10 b. [Ar] 4s 1 3d 8 c. [Ar] 4s 2 3d 9 d.

Test Bank for Introductory Chemistry Essentials 5th Edition by Tro

Name Unit Three MC Practice March 15, 2017

Ex. 1) F F bond in F = 0 < % covalent, no transfer of electrons

Name Date Class MOLECULAR COMPOUNDS. Distinguish molecular compounds from ionic compounds Identify the information a molecular formula provides

CHEM 110 Exam 2 - Practice Test 1 - Solutions

Chapter 9. Chemical Bonding II: Molecular Geometry and Bonding Theories

16. NO 3, 5 + 3(6) + 1 = 24 e. 22. HCN, = 10 valence electrons

Bonding. Polar Vs. Nonpolar Covalent Bonds. Ionic or Covalent? Identifying Bond Types. Solutions + -

Chemical Bonds. Chapter 6

CHEMISTRY 102 Spring 2013 Hour Exam I Page 1. Which molecule(s) has/have tetrahedral shape and which molecule(s) is/are polar?

Chapter 9. Lewis Theory-VSEPR Valence Bond Theory Molecular Orbital Theory

Chapter 6 Chemistry Review

AP Chemistry- Practice Bonding Questions for Exam

Memorize: Understand: Know how to:

m measured m if 100%ionic

IB Topics 4 & 14 Multiple Choice Practice

Bonding and IMF practice test MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

Chapter 16 Covalent Bonding

CHEMISTRY HONORS LEOCE Study Guide

CHAPTER 5: Bonding Theories - Explaining Molecular Geometry. Chapter Outline

Molecular Geometries. Molecular Geometries. Remember that covalent bonds are formed when electrons in atomic orbitals are shared between two nuclei.

Chemical Bonding AP Chemistry Ms. Grobsky

Atoms have the ability to do two things in order to become isoelectronic with a Noble Gas.

Unit 9: CHEMICAL BONDING

Chapter 7 Chemical Bonding and Molecular Structure

Q. No. 2 Bond formation is. Neither exothermic nor endothermic

Adapted from CHM 130 Maricopa County, AZ Molecular Geometry and Lewis Dot Formulas Introduction

Covalent Bonding and Molecular Structures

CHEMISTRY. Chapter 10 Theories of Bonding and Structure. The Molecular Nature of Matter. Jespersen Brady Hyslop SIXTH EDITION

CHEMISTRY 110 EXAM 2 Feb 25, 2013 FORM A

Molecular Geometry. Dr. Williamson s Molecular Geometry Notes. VSEPR: Definition of Terms. Dr. V.M. Williamson Texas A & M University Student Version

Molecular Geometry. Dr. Williamson s Molecular Geometry Notes. VSEPR: Definition of Terms. VSEPR: Electronic Geometries VSEPR

Covalent bonding does not involve electrostatic attraction between oppositely charged particles.

Essential Organic Chemistry. Chapter 1

Helpful Hints Lewis Structures Octet Rule For Lewis structures of covalent compounds least electronegative

10-1. The Shapes of Molecules, chapter 10

1) Based on the octet rule, magnesium most likely forms a ion. A) Mg- B) Mg6+ C) Mg2+ D) Mg6- E) Mg2-

Chapter 7. Chemical Bonding I: Basic Concepts

Chapter 10: Chemical Bonding II: Molecular Shapes; VSEPR, Valence Bond and Molecular Orbital Theories

General and Inorganic Chemistry I.

AP Chemistry. Unit #7. Chemical Bonding & Molecular Shape. Zumdahl Chapters 8 & 9 TYPES OF BONDING BONDING. Discrete molecules formed

Unit 9: CHEMICAL BONDING

PART 3 Chemical Bonds, Valence Bond Method, and Molecular Shapes. Reference: Chapter 9 10 in textbook

Chapter 9 Molecular Geometry and Bonding Theories

You might find the following useful. CHEMISTRY 1A Fall 2008 EXAM 3 Key CHAPTERS 7, 8, 9 & part 10

Form J. Test #4 Last Name First Name Zumdahl, Chapters 8 and 9 November 23, 2004

Valence Shell Electron Pair repulsion

Chemical Bonding II. Molecular Geometry Valence Bond Theory Phys./Chem. Properties Quantum Mechanics Sigma & Pi bonds Hybridization MO theory

Test bank for Chemistry The Central Science 10th Edition by Brown, LeMay, Bursten

STD-XI-Science-Chemistry Chemical Bonding & Molecular structure

CHM1045 Exam 3 Chapters 5, 8, & 9

Chem 121 Final Exam. (2) 1) A cube measures 3.21 cm on one side. Calculate its volume in liters (cm 3 = ml) and put the answer in the box.

Chapter 4. Molecular Structure and Orbitals

You May Remove this page from the front of the exam. Avogadro s number: NA = 6.022x 1023 mol-1

What Do Molecules Look Like?

CHAPTER 3 CHEMICAL BONDING NUR FATHIN SUHANA BT AYOB SMK SULTAN ISMAIL, JB

Chem 102 Exam #1--Winter, 2006

Multiple Choice Identify the letter of the choice that best completes the statement or answers the question.

Chapter 8 Covalent Boding

CHEMICAL BONDING. Chemical Bonds. Ionic Bonding. Lewis Symbols

Chapter 9. Molecular Geometry and Bonding Theories

Chemistry 104 Final Exam Content Evaluation and Preparation for General Chemistry I Material

Chemistry Chapter 6 Test Review

I. Multiple Choice Questions (Type-I)

Ionic and Molecular Compounds

Ionic and Molecular Compounds

Instant download Test bank for Chemistry The Central Science 10th Edition by Brown, LeMay, Bursten CLICK HERE

SMK SULTAN ISMAIL JB, NUR FATHIN SUHANA BT AYOB

Chemical Bonding Chapter 8

Form Code X. (1) 2.56 x photons (2) 5.18 x photons (3) 9.51 x photons (4) 5.15 x photons (5) 6.

Chapter 8 Test Study Guide AP Chemistry 6 points DUE AT TEST (Wed., 12/13/17) Date:

Chapter 7. Ionic & Covalent Bonds

Exam Review Questions - Multiple Choice

PROPERTIES OF SOLIDS SCH4U1

Transcription:

Name period ap chemistry unit 3 worksheet 1. What are structural isomers? Draw two isomers of pentane. Compounds with the same formula but different structures. See in class 2. give the formula for each of the following a. pentane C 5H 12 c. 2Hexene C 6H 12 e. 1butyne C 4H 6 g. benzene C 6H 6 b. heptane C 7H 16 d. proponol C 3H 7OH f. ethane C 2H 6 h. methane CH 4 3. The molecules BF 3 and SO 3 are both trigonal planar. Does this information completely define the bond angles of these molecules? No, double bonds take up more space so the bond angle will be slightly less than 120 4. List the molecular shapes which are always polar. Bent, trigonal pyramidal, see saw, tshaped, square pyramidal 5. Give the molecular geometry, bond angles, and polarity for each of the following molecules a. Cl 2O b. N 2O c. SO 3 d. SO 3 2 Bent linear trigonal planar trigonal pyramidal 109.5 180 120 109.5 Polar nonpolar nonpolar polar Sp 3 sp sp 2 sp 3 e. ICl 2 f. PF 5 g. ICl 3 h. CO 3 2 linear trigonal bipyramidal Tshaped trigonal planar 180 120, 90 90 120 Nonpolar nonpolar polar nonpolar sp 2 i.sf 6 j. TeF 4 k. ClO 3 l. PBr 3 octahedral seesaw trigonal pyramidal trigonal pyramidal 90 90, 120 109.5 109.5 Nonpolar polar polar polar sp 3 sp 3 6. The molecules NF 3, BF 3, and ClF 3 all have the same molecular formulas of the type XF 3, but the molecules have different geometries. Predict the shape of each and explain the origin of the differing shapes. NF 3: trigonal pyramidal : one lone pair BF 3: trigonal planar: no lone pairs ClF 3: Tshaped: 2 lone pairs 7. The three species NH 2, NH 3, and NH 4 + have HNH bond angles of 105, 107, and 109 respectively. Explain the variation in bond angles. 105 has two lone pairs on the central atom 107 has one lone pair on the central atom 109 has no lone pairs on the central atom 8. Tell the hybrid orbitals used in each molecule in question 3 (you do not need to do expanded octets) See above

9. Give the approximate value for the indicated bond angles and tell the hybrid orbitals used in the following molecules a. c. HOClO HCOH <109.5 <<109.5 b. d. HC=CH HCOCH 180 120 10. Predict whether the following molecules possess dipole moments a. HCN b. BF 3 c. XeF 4 d. CCl 4 11. What is the difference between a sigma and pi bond? Which is generally stronger? Sigma: overlap is between nuclei Pi: overlap is above and below nuclei Sigma are generally stronger 12. If an atom uses an sp 2 hybrid orbital, how many unhybridized p orbitals in the same valence shell remain on the atom? How many pi bonds can the atom form? 1 1 13. a. Draw the Lewis structure for methane and formaldehyde, H 2CO. see in class b. What is the hybridization at the carbon atoms for each? Sp 3 and sp 2 c. The carbon atom in methane cannot participate in multiple bonding, whereas that in formaldehyde can. Explain this observation. All of the p orbitals have been hybridized in methane, but in formaldehyde, there is a left over p orbital that can create a pi bond 14. Acetone has the following Lewis structure: a. What is the total number of valence electrons in the molecule? 24 b. How many valence electrons are used for sigma bonds? 18 c. How many valence electrons are used for pi bonds? 2 d. How many valence electrons remain in nonbonding pairs in the molecule? 4 e. What is the hybridization at the central carbon atom of the molecule? Sp 2 15. a.draw the structure for acetic acid: see in class b. What is the molecular geometry around each carbon atom? Tetrahedral, trigonal planar

c. What type of hybrid orbitals does each carbon have? sp 3, sp 2 16. Name three elements which... a) cannot have expanded octets when it is the central atom in a molecule. C, N, O b) do not need an octet to form stable compounds. H, Be, B 17. Is the pi bond in NO 2 localized or delocalized? How do you know? Delocalized. There is resonance 18. How many sigma bonds and pi bonds does each of the following molecules have? a. b. 10 sigma and 3 pi 9 sigma and 9 pi 19. What type of intermolecular forces operates between a. All molecules London dispersion b. Polar molecules dipoledipole c. The hydrogen of a polar bond and a nearby small, very electronegative atom? Hydrogen bonding 20. Put the following in order of increasing polarizability : GeCl 4, CH 4, SiCl 4, SiH 4, GeBr 4 CH 4, SiH 4, SiCl 4, GeCl 4, GeBr 4 21. What kind of attractive forces must be overcome to a. Boil water hydrogen bonding and London dispersion b. Melt KCl ionic bonds c. Sublime I 2 london dispersion d. Boil H 2S dipole dipole and London dispersion 22. The dipole moments of HCl and HI are 1.08 D and 0.44 D respectively a. Which of these substances will have the greater dipoledipole interaction? HCl b. Which of these substances will have the greater London dispersion forces? HI 23. Boiling point Substance Suggest a reason why CH 3CN has a higher 231 K C 3H 8 boiling point than C 3H 8. 355 K CH 3CN It is polar and the C 3H 8 is nonpolar 24. Nitrogen and carbon monoxide have almost equal masses. Explain why the boiling point of carbon monoxide is slightly higher than that of nitrogen Carbon monoxide is more polarizable and so the London dispersion forces are stronger

25. Which member of the following pairs of substances would you expect to have a higher boiling point? a. N 2 or O 2 b. CH 4 or SiH 4 c. NaCl or CH 3Cl d. CH 3Cl or CH 4 26. Put the following in order of increasing boiling points: CO 2, O 2, BaCl 2, H 2O, H 2S O 2, CO 2, H 2S, H 2O, BaCl 2 27. Which of the following has the fewest pi bonds and is nonpolar? a.hcch b.co 2 c.co 3 2 d.n 2 e.so 2 28. A student places a mixture of plastic beads consisting of polypropylene (PP) and polyvinyl chloride (PVC) in a 1.0 L beaker containing distilled water. After stirring the contents of the beaker vigorously, the student observes that the beads of one type of plastic sink to the bottom of the beaker and the beads of the other type of plastic float on the water. The chemical structures of PP and PVC are represented by the diagrams below, which show segments of each polymer. a. Given that the spacing between polymer chains in PP and PVC is similar, the beads that sink are made of which polymer? Explain. The PVC beads sink. The spacing between chains is similar, but a Cl atom has a greater mass than CH 3 (b) The boiling point of liquid propene (226 K) is lower than the boiling point of liquid vinyl chloride (260 K). Account for this difference in terms of the types and strengths of intermolecular forces present in each liquid. Both substances have dipoledipole interactions and London dispersion forces (or propene is essentially nonpolar with only LDFs while vinyl chloride has both LDFs and dipoledipole forces). Propene contains a CH 3 group, but vinyl chloride contains a Cl atom. Vinyl chloride thus has a larger electron cloud, is more polarizable, and has a larger dipole moment. Thus intermolecular attractions are stronger in vinyl chloride, which results in it having the higher boiling point. Review 29. Write the noble gas configuration for the following a. Sn b. Cr c. Fe 2+ d. Ag [Kr]5s 2 4d 10 5p 2 [Ar]4s 1 3d 5 [Ar]3d 6 [Kr]5s 2 4d 9 30. a. How many molecules are in 5.63 g of methane? 2.11 x 10 23 molecules b. How many hydrogen atoms are in 5.63 g of methane? 8.47 x 10 23 hydrogen atoms c. How many moles are in 14.5 g of aluminum sulfate? 0.0424 mol d. What is the molar mass of iron(iii) hydroxide? 106.8 g/mol e. How many grams are in 3.20 moles of potassium sulfide? 353 g

31. Complete the following table Symbol # of neutrons # of protons # of electrons Atomic # Mass # 136 2 56 Ba 80 56 54 56 136 56 Mn 31 25 25 25 56 199 Au 120 79 79 79 199 41 Ca 2+ 21 20 18 20 41 19. Substance E has 29 protons, 28 electrons, and 34 neutrons. Substance F has 29 protons, 27 electrons, and 34 neutrons. Substances E and F can be categorized as A) different elements B) ions C) isotopes D) nuclides E) nucleons 20. A 0.144g sample of a hydrocarbon is analyzed by combustion analysis, 0.352 g of carbon dioxide and 0.0480 g of water is produced. Find the empirical formula of the hydrocarbon. C 2H 3 21. Which is a list of elements listed in order of increasing ionization energy? A) Na, K, Rb B) Ne, Ar, Kr C) Al, Mg, Na D) Br, Cl, F E) O, S, Se 22. Which property generally increases down a group but decreases from left to right a. Melting point b. electronegativity c. ionization energy d. atomic radius 23. What is the nuclear charge for the following atoms a. Na b. F c. Sn d. P e. Ar 11 9 50 15 18 24. Which of the following explains why oxygen atoms, in their ground state, are paramagnetic? a. Pauli exclusion principle b. electron shielding c. Hund s rule d. aufbau principle 25. How many valence electrons does nitrogen have? 5 26. An atom has the electron configuration 1s 2 2s 2 2p 6 3s 2 3p 2. How many valence electrons does this atom have? 4 27. Which atom will have the largest radius in each pair. a. K, Na b. Na, Na + c. Br, Br d. K, B