Resistors. Consider a uniform cylinder of material with mediocre to poor to pathetic conductivity ( )

Similar documents
10/25/2005 Section 5_2 Conductors empty.doc 1/ Conductors. We have been studying the electrostatics of freespace (i.e., a vacuum).

Version 001 HW#6 - Electromagnetism arts (00224) 1

Physics 1402: Lecture 7 Today s Agenda

Section 4.8. D v(t j 1 ) t. (4.8.1) j=1

Math 8 Winter 2015 Applications of Integration

Designing Information Devices and Systems I Discussion 8B

Designing Information Devices and Systems I Spring 2018 Homework 7

Designing Information Devices and Systems I Fall 2016 Babak Ayazifar, Vladimir Stojanovic Homework 6. This homework is due October 11, 2016, at Noon.

I1 = I2 I1 = I2 + I3 I1 + I2 = I3 + I4 I 3

Chapter E - Problems


Signal Flow Graphs. Consider a complex 3-port microwave network, constructed of 5 simpler microwave devices:

Homework Assignment 6 Solution Set

14.4. Lengths of curves and surfaces of revolution. Introduction. Prerequisites. Learning Outcomes

University of Alabama Department of Physics and Astronomy. PH126: Exam 1

Definite Integrals. The area under a curve can be approximated by adding up the areas of rectangles = 1 1 +

5.4 The Quarter-Wave Transformer

Physics 2135 Exam 1 February 14, 2017

Summary of equations chapters 7. To make current flow you have to push on the charges. For most materials:

Designing Information Devices and Systems I Spring 2018 Homework 8

Improper Integrals. Type I Improper Integrals How do we evaluate an integral such as

Sample Exam 5 - Skip Problems 1-3

Space Curves. Recall the parametric equations of a curve in xy-plane and compare them with parametric equations of a curve in space.

A REVIEW OF CALCULUS CONCEPTS FOR JDEP 384H. Thomas Shores Department of Mathematics University of Nebraska Spring 2007

PROPERTIES OF AREAS In general, and for an irregular shape, the definition of the centroid at position ( x, y) is given by

200 points 5 Problems on 4 Pages and 20 Multiple Choice/Short Answer Questions on 5 pages 1 hour, 48 minutes

Chapter 4 Homework solution: P4.2-2, 7 P4.3-2, 3, 6, 9 P4.4-2, 5, 8, 18 P4.5-2, 4, 5 P4.6-2, 4, 8 P4.7-2, 4, 9, 15 P4.8-2

#6A&B Magnetic Field Mapping

Electromagnetism Answers to Problem Set 10 Spring 2006

Introduction to Electronic Circuits. DC Circuit Analysis: Transient Response of RC Circuits

Homework Assignment 9 Solution Set

DIRECT CURRENT CIRCUITS

APPLICATIONS OF THE DEFINITE INTEGRAL

Lecture 1: Electrostatic Fields

Section 6.1 Definite Integral

Suppose we want to find the area under the parabola and above the x axis, between the lines x = 2 and x = -2.

Homework Assignment 3 Solution Set

Polynomial Approximations for the Natural Logarithm and Arctangent Functions. Math 230

Hints for Exercise 1 on: Current and Resistance

1B40 Practical Skills

Section 6: Area, Volume, and Average Value

On the diagram below the displacement is represented by the directed line segment OA.

Improper Integrals, and Differential Equations

Physics 2135 Exam 3 April 21, 2015

Math 113 Exam 2 Practice

The Regulated and Riemann Integrals

f(x) dx, If one of these two conditions is not met, we call the integral improper. Our usual definition for the value for the definite integral

7.1 Integral as Net Change and 7.2 Areas in the Plane Calculus

2A1A Vector Algebra and Calculus I

The area under the graph of f and above the x-axis between a and b is denoted by. f(x) dx. π O

63. Representation of functions as power series Consider a power series. ( 1) n x 2n for all 1 < x < 1

Problem 1. Solution: a) The coordinate of a point on the disc is given by r r cos,sin,0. The potential at P is then given by. r z 2 rcos 2 rsin 2

Candidates must show on each answer book the type of calculator used.

Fundamental Theorem of Calculus

Exam 1 Solutions (1) C, D, A, B (2) C, A, D, B (3) C, B, D, A (4) A, C, D, B (5) D, C, A, B

Phys102 General Physics II

R(3, 8) P( 3, 0) Q( 2, 2) S(5, 3) Q(2, 32) P(0, 8) Higher Mathematics Objective Test Practice Book. 1 The diagram shows a sketch of part of

7.6 The Use of Definite Integrals in Physics and Engineering

CAPACITORS AND DIELECTRICS

Polynomials and Division Theory

Riemann is the Mann! (But Lebesgue may besgue to differ.)

5.1 How do we Measure Distance Traveled given Velocity? Student Notes

Overview. Before beginning this module, you should be able to: After completing this module, you should be able to:

Unit #10 De+inite Integration & The Fundamental Theorem Of Calculus

Physics 202, Lecture 10. Basic Circuit Components

Problem Solving 7: Faraday s Law Solution

MTH 122 Fall 2008 Essex County College Division of Mathematics Handout Version 10 1 October 14, 2008

Reading from Young & Freedman: For this topic, read the introduction to chapter 24 and sections 24.1 to 24.5.

Physics 3323, Fall 2016 Problem Set 7 due Oct 14, 2016

Math 554 Integration

Math 113 Exam 1-Review

In Mathematics for Construction, we learnt that

7.1 Integral as Net Change Calculus. What is the total distance traveled? What is the total displacement?

Lecture 7 notes Nodal Analysis

Review of Gaussian Quadrature method

2. THE HEAT EQUATION (Joseph FOURIER ( ) in 1807; Théorie analytique de la chaleur, 1822).

potentials A z, F z TE z Modes We use the e j z z =0 we can simply say that the x dependence of E y (1)

Best Approximation. Chapter The General Case

Lecture 5 Capacitance Ch. 25

5.7 Improper Integrals

MAT187H1F Lec0101 Burbulla

Math 1B, lecture 4: Error bounds for numerical methods

Problems for HW X. C. Gwinn. November 30, 2009

Problem Set 3 Solutions

Potential Formulation Lunch with UCR Engr 12:20 1:00

An Overview of Integration

1.2. Linear Variable Coefficient Equations. y + b "! = a y + b " Remark: The case b = 0 and a non-constant can be solved with the same idea as above.

4.4 Areas, Integrals and Antiderivatives

Calculus 2: Integration. Differentiation. Integration


Math 116 Calculus II

x = b a n x 2 e x dx. cdx = c(b a), where c is any constant. a b

Linear Inequalities. Work Sheet 1

Mathematics. Area under Curve.

Special Relativity solved examples using an Electrical Analog Circuit

Section 4: Integration ECO4112F 2011

Chapter 4: Techniques of Circuit Analysis. Chapter 4: Techniques of Circuit Analysis

CHAPTER : INTEGRATION Content pge Concept Mp 4. Integrtion of Algeric Functions 4 Eercise A 5 4. The Eqution of Curve from Functions of Grdients. 6 Ee

This final is a three hour open book, open notes exam. Do all four problems.

Definite integral. Mathematics FRDIS MENDELU

Transcription:

10/25/2005 Resistors.doc 1/7 Resistors Consider uniform cylinder of mteril with mediocre to poor to r. pthetic conductivity ( ) ˆ This cylinder is centered on the -xis, nd hs length. The surfce re of the ends of the cylinder is. y the cylinder hs current flowing into it (nd thus out of r. it), producing current density ( ) By the wy, this cylinder is commonly referred to s resistor! Q: Wht is its resistnce R of this resistor, given length, cross-section re, nd conductivity? A: Let s first egin with the circuit form of Ohm s Lw: R im tiles The Univ. of Knss Dept. of EEC

10/25/2005 Resistors.doc 2/7 where is the potentil difference etween the two ends of the resistor (i.e., the voltge cross the resistor), nd is the current through the resistor. From electromgnetics, we know tht the potentil difference is: nd the current is: ( r E ) d ds Thus, we cn comine these expressions nd find resistnce R, E r within the resistor, expressed in terms of electric field ( ) nd the current density within the resistor: R E d ds Lets evlute ech integrl in this expression to determine the resistnce R of the device descried erlier! im tiles The Univ. of Knss Dept. of EEC

10/25/2005 Resistors.doc 3/7 1) The voltge is the potentil difference etween point nd point : ( r E ) d Q: But, wht is the electric field E? A: The electric field within the resistor cn e determined from Ohm s Lw: E We cn ssume tht the current density is pproximtely constnt cross the cross section of the cylinder: ˆ Likewise, we know tht the conductivity of the resistor mteril is constnt: As result, the electric field within the resistor is: E ˆ im tiles The Univ. of Knss Dept. of EEC

10/25/2005 Resistors.doc 4/7 Therefore, integrting in stright line long the -xis from point to point, we find the potentil difference to e: 1 E d ˆ ˆ d d 2) We likewise know tht the current through the resistor is found y evluting the surfce integrl: ds ˆ ˆ ds ds Therefore, the resistnce R of this prticulr resistor is: im tiles The Univ. of Knss Dept. of EEC

10/25/2005 Resistors.doc 5/7 R 1 An interesting result! Consider resistor s sort of clogged pipe. ncresing the cross-sectionl re mkes the pipe igger, llowing for more current flow. n other words, the resistnce of the pipe decreses, s predicted y the ove eqution. Likewise, incresing the length simply increses the length of the clog. The current encounters resistnce for longer distnce, thus the vlue of R increses with incresing length. Agin, this ehvior is predicted y the eqution shown ove. For exmple, consider the cse where we dd two resistors together: R 1 1 R 2 2 1 2 im tiles The Univ. of Knss Dept. of EEC

10/25/2005 Resistors.doc 6/7 We cn view this cse s single resistor with length 1 + 2, resulting in totl resistnce of: R totl 1 + 2 1 2 + R + R 1 2 But, this result is not the lest it surprising, s the two resistors re connected in series! Now let s consider the cse where two resistors re connected in different mnner: 1 R1 1 2 R2 2 im tiles The Univ. of Knss Dept. of EEC

10/25/2005 Resistors.doc 7/7 We cn view this s single resistor with totl cross sectionl re of 1 + 2. Thus, its totl resistnce is: R totl ( 1 + 2) ( + ) 1 1 2 1 2 + 1 1 + R1 R2 Agin, this should e no surprise, s these two resistors re connected in prllel. MPORTANT NOTE: The result R is vlid only for the resistor descried in this hndout. Most importntly, it is vlid r ). only for resistor whose conductivity is constnt ( ( ) 1 1 f the conductivity is not constnt, then we must evlute the potentil difference cross the resistor with the more generl expression: E d d im tiles The Univ. of Knss Dept. of EEC