SSC MAINS (MATHS) MOCK TEST-10 (SOLUTION)

Similar documents
SSC (Tier-II) (Mock Test Paper - 2) [SOLUTION]

SSC MAINS MATHS 68 (SOLUTION)

SSC (PRE + MAINS) MATHS M O C K TEST PAPER HANSRAJ MATHS ACADEMY

SSC MAINS (MATHS) MOCK TEST-14 (SOLUTION)

[Class-X] MATHEMATICS SESSION:

Solutions. S1. Ans.(c) Sol. Try Using option and divide With given option

SSC (PRE + MAINS) MATHS M O C K TEST PAPER HANSRAJ MATHS ACADEMY

C.B.S.E Class X

Solutions to RSPL/1. Mathematics 10

MATHEMATICS ( CANDIDATES WITH PRACTICALS/INTERNAL ASSESSMENT ) ( CANDIDATES WITHOUT PRACTICALS/INTERNAL ASSESSMENT )

( Bifurcated Syllabus ) ( According to Syllabus of Class X only) PART - I

2. In an AP. if the common difference (d) = -4, and the seventh term (a7) is 4, then find the first term.

SSC [PRE+MAINS] Mock Test 230 [Answer with Solution]

114 Handy Formulae for Quantitative Aptitude Problems Author: Sagar Sonker Table of Contents

Guess Paper 2013 Class IX Subject Mathematics

CDS-I 2019 Elementary Mathematics (Set-C)

HKCEE 1993 Mathematics II

then the value of a b b c c a a b b c c a a b b c c a a b b c c a

Quantitative Aptitude Formulae

SEAT NO. QUESTION PAPER CODE NO. FEBRUARY MATHEMATICS (English) (Total Marks - 100)

KENDRIYA VIDYALAYA GACHIBOWLI, GPRA CAMPUS, HYD 32

Number system. 1. When sum and difference of two numbers (X and Y) are given, then X = (sum + difference)/2 Y = (sum + difference)/2

MockTime.com. Subject Questions Marks Time -Ve Maths hrs 1/3 CDS MATHEMATICS PRACTICE SET

2 nd Term Test Maris Stella College- Negombo. Mathematics

Grade 8(Mathematics) EV 4( )

CBSE CLASS-10 MARCH 2018

Model Answer Paper 24(24 1) 2 12

4016/01 October/November 2009

MT EDUCARE LTD. SUMMATIVE ASSESSMENT Roll No. Code No. 31/1

MASTERS TUITION CENTER DEEPAK SIR QUADRATIC EQUATIONS

CAREER POINT PRE FOUNDATION DIVISON CLASS-9. IMO Stage-II Exam MATHEMATICS Date :

Geometry. A. Right Triangle. Legs of a right triangle : a, b. Hypotenuse : c. Altitude : h. Medians : m a, m b, m c. Angles :,

Range: The difference between largest and smallest value of the. observation is called The Range and is denoted by R ie

S MATHEMATICS (E) Subject Code VI Seat No. : Time : 2½ Hours

MATHS QUESTION PAPER CLASS-X (MARCH, 2011) PART-A

CBSE QUESTION PAPER CLASS-X MATHS

CBSE CLASS-10 MARCH 2018

10 th CBSE (SESSION : ) SUBJECT : MATHS SUMMATIVE ASSESSMENT-II SOLUTION _SET-1_CODE NO. 30/1

Regd. Office : Aakash Tower, Plot No.-4, Sec-11, MLU, Dwarka, New Delhi Ph.: Fax :

ICSE Solved Paper, 2018

MT - MATHEMATICS (71) GEOMETRY - PRELIM II - PAPER - 6 (E)

Preliminary chapter: Review of previous coursework. Objectives

AREAS RELATED TO CIRCLES

1 Tons of Free Study Materials & E books by Call , SSC CHSL 2016 MATHS SOLVED PAPER

COMMON UNITS OF PERIMITER ARE METRE

OBJECTIVE TEST. Answer all questions C. N3, D. N3, Simplify Express the square root of in 4

Mathematics Class X Board Paper 2011

MATHEMATICS. (Two hours and a half) Answers to this Paper must be written on the paper provided separately.

SAMPLE TEST MATHEMATICS ExPLANATIONS OF CORRECT ANSWERS

Number System. Properties of Centers of Triangle Centroid : MATHEMATICS FOR RRB ALP STAGE-II EXAM

SSC CGL PAPER 16 th August 2015 Morning Shift Part C Quantitative Aptitude

a b b a 182. Possible values of (a, b, c) Permutation 3 2 = = = 6 = 3 = = 6 = 1

G.C.E.(O.L.) Support Seminar

Sixth Form Entrance Mathematics

CBSE Class X Mathematics Sample Paper 03

8 th grade practice test. Objective 1.1a

No. Items Working Column Mark

27 th ARYABHATTA INTER-SCHOOL MATHEMATICS COMPETITION 2010 CLASS = VIII

Paper: 02 Class-X-Math: Summative Assessment - I

MATHCOUNTS State Competition Countdown Round Problems This section contains problems to be used in the Countdown Round.

GATE Formulas & Shortcuts for Numerical Computation

GATUNDU FORM 4 EVALUATION EXAM 121/1 MATHEMATICS PAPER I JULY/AUGUST 2015 TIME: 2 ½ HOURS

KENDRIYA VIDYALAYA SANGATHAN, HYDERABAD REGION

Class 9 th Everyday Mathematics

KENDRIYA VIDYALAYA SANGATHAN, HYDERABAD REGION

In examples 1 to 3, write the correct answer from the given four options:

Answer-key & Solution

PGT Mathematics. 1. The domain of f(x) = is:-

81-E If set A = { 2, 3, 4, 5 } and set B = { 4, 5 }, then which of the following is a null set? (A) A B (B) B A (C) A U B (D) A I B.

CBSE CLASS X MATH -SOLUTION Therefore, 0.6, 0.25 and 0.3 are greater than or equal to 0 and less than or equal to 1.

RAO IIT ACADEMY / GANIT PRABHUTWA EXAMINATION / STD - VIII / QP + SOLUTIONS JEE MEDICAL-UG BOARDS KVPY NTSE OLYMPIADS GANIT PRABHUTWA EXAMINATION

Given that m A = 50 and m B = 100, what is m Z? A. 15 B. 25 C. 30 D. 50

Rao IIT Academy/ ICSE - Board 2018_Std X_Maths_QP + Solutions JEE MEDICAL-UG BOARDS KVPY NTSE OLYMPIADS. X - ICSE Board MATHS - QP + SOLUTIONS

London Examinations IGCSE

General Mathematics Paper 2, May/June 2009

1 BANK EXAM TODAY CAREER TODAY

PRACTICE TEST 1 Math Level IC

( 3x 2 y) 6 (6x 3 y 2 ) x 4 y 4 b.

Name: GEOMETRY: EXAM (A) A B C D E F G H D E. 1. How many non collinear points determine a plane?

Assignment Mathematics Class-VII

VISHAL BHARTI PUBLIC SCHOOL SUBJECT-MATHEMATICS CLASS-VI ASSIGNMENT-4 REVISION (SEPTEMBER)

ICSE QUESTION PAPER Class X Maths (2016) Solution

Math 5SN. Answer Key. Part A. Part B. The ordered pairs are (1, 10), (5, 8) as well as the ordered pair whose coordinates are (3, 9).

S4 National 5 Write-On Homework Sheets

B A. S. Thomas College Mount Lavinia Term II Examination 2015 Mathematics I. 1. Find the cost of 10 pens if the cost of one pen is Rs.8.

A. 180 B. 108 C. 360 D. 540

KENDRIYA VIDYALAYA SANGATHAN, HYDERABAD REGION

You must have: Ruler graduated in centimetres and millimetres, protractor, compasses, pen, HB pencil, eraser, calculator. Tracing paper may be used.

ACT Test Prep. Name: Class: Date: Multiple Choice Identify the choice that best completes the statement or answers the question.

CBSE MATHEMATICS (SET-2)_2019

1 / 23

Mathematics. Sample Question Paper. Class 9th. (Detailed Solutions) 2. From the figure, ADB ACB We have [( 16) ] [( 2 ) ] 3.

Mu Alpha Theta State 2007 Euclidean Circles

Elizabeth City State University Elizabeth City, North Carolina STATE REGIONAL MATHEMATICS CONTEST COMPREHENSIVE TEST BOOKLET

SAMPLE QUESTION PAPER Class-X ( ) Mathematics. Time allowed: 3 Hours Max. Marks: 80

Evaluation of Trigonometric Functions and Their Inverses Kenneth Williams

Jexpo Solved paper 2014 Mathematics

Solutions Math is Cool HS Championships Mental Math

SSC (GD)MOCK TEST 12 (SOLUTION)

The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION GEOMETRY

Transcription:

SS MINS (MTHS) MOK TEST-0 (SOLUTION). () x 8 y 8 Sum x and y together can finish the job. () 8 M 60 60 minutes M W W 00 50 (00 x) (50 50) 00 50 (00 x) 00 00 x 00 x 00 Extra workers needed 00. () x can copy 80 pages in 0 hrs x can copy 0 pages in 0 0 5 hrs 80 x and y can copy 5 pages in 7 hrs x and y can copy 0 pages in 7 5 0 hrs x y 0 5 x 5 sum y can copy 0 pages in 0 0 hrs.. () TQ, x can complete the job 6 days y can complete the job 6 days x 8 y 6 sum 5 time taken by x and y to complete the job 8 5 9 5 days 5. () TQ, mount paid by Mr. x 0 8.5 0 8.5 00 0.65% mount paid by Mr. y 8.5 0 0 8.5 00 0.65% 6. () Percentage profit 5 0 5 0 00 7. () Total reduction.5% 0 0 0 0 8% 00 8. () Total marked price ` 0000 TQ, Total cost price 0000 7500 ` 8500 cost of each window ` 8500 5 ` 00 9. () : : : : 5 : : 5 : : 9 : 6 : 0 ( ) : ( ) (9 6) : (6 0) 5 : 6 0. () For first 8 months 00 8 : 00 8 For next months 00 : 50 For last months 50 : 50 00 : 000 Ratio of profit of and : 0. () Let each bus has 00 seats fter leaving, seats needed to be occupied 00 5 80 80 Required fraction 00 9 0. () : : For first 6 months 00 6 : 500 6 : 0 6 For last 6 months 00 6 : 500 6 : 500 6 600 : 6000 : 000 Ratio of profit of, and 600 : 6000 : 000 6 : 0 : 5. () Initially, ratio of story books and other books 7 : Story books 5 other books 5 7 Finally, ratio of story books and other books 5 : 8

Other books total story books 5 60 The number of story books collected 60 5 08. () Ratio of numbers 7 : 9 Product of numbers 575 greater number 9 5 5. () TQ, The weight of th person 575 7 9 9 5 95 kg 6. () Largest -digit number formed by 0, and 0 Smallest -digit number form by 0, and 0 0 0 verage of numbers 7. () verage of six numbers.95 verage of first two numbers. verage of next two numbers.85 The average of remaining numbers.95 6..85.6 8. () Let eight even numbers are a, a, a, a 6, a 8, a 0, a and a a ( a ) ( a ) ( a 6) ( a 8) ( a 0) ( a ) ( a ) 9 8 a 7 9 a 86 the largest number 86 00 9. () a b > 50 a b > 00 (b) b > 00 0b > 00 b > 0 a b > 0 least value of a is 0. () Required average 9 59 89. () Let. P. of watch ` 00.P. S.P 00 0% profit 0 0% less ` 0% profit 90 08 0 60 90 actual cost price 00 0 ` 50 9. () Let cost price `00 Loss 0% 50% of selling price ` 80 actual selling price ` (80 ) ` 60 60 00 Percentage gain 00 00 60%. () Selling price of mixed tea ` 0/ kg ost price of mixed tea 0 5 6 ` 800 Tea Tea 80 80 0 800 60 Required ratio 0 : 60 :. () Selling price ` P Profit % ost price ` 00 P Selling price ` Q Loss % ost price ` 00 Q 96 TQ, ost price ost price 00 96 Q 00 P Q : P 96 : 6 : 7 5. () Selling price of ost price of ` P Loss of 5% Selling price of ost price of 00 ` P 75 Profit of 0% ost price of 00 00 ` P 75 0 ` 0 9 P 6. () ost price ` 5 Selling price ` 0 0 5 Profit percent 00 0% 5 7. () Let population of country x Population of country after increase in population x 0 00 0 00 0 00.78x Percentage increase.78x x x 00 7.8%

8. () The number of days the same amount of juice would last is 5 00 5 days 0 9. () Price of book after discount ` 70 If discount is between 0% and 5% then maximum possible original price 70 00 75 ` 60 0. () Ratio of cost price and selling price 0 : 0 Profit percent 00 0% 0. () Let time taken upstream x Then time taken downstream x Ratio of speed of downstream and upstream : ratio of speed of boat in still water and of current is : :. () P ( ) 6 P ( ) 6 Sum Time taken by both pipes to fill the tank 6 5 hours. () verage speed of farmer 6 9 S S 9 0 9 6 9 5 9 km /hr Ratio of time with speed of km/hr and 9 km/hr 0 9 : 5 9 : 5 distance travelled on foot 6 kms. () TQ, Upstream speed 6 6 6 kms/hr ownstream speed 8 6 8 kms/hr The speed of current 8 6 km/hr 5. () Let principal P TQ, 0 P 00 P 00 0 P 00 0 P 00 ` 00 6. () TQ, P 5 65 00 P ` 700 principal ` 700 r 7. () mount S 00 S r 50 8. () TQ, 9. () 0. () 0 P 00 0 P ` 000 6 cm cm The whole surface area rea of base curved surface area of cylinder curved surface of cone r rh rl () () 9 5 8 F E G 6 6 In and E E E E 6 F F FG Required volume () 9 5 0

. () rea of triangle inradius sum of length of sides External diameter internal diameter. () 6 50 50 sq. cm m 5 sin 5 rea of 00 00 cm 8. () Height of glass h 0000 50 sq. cm. 000 0 h Number of drops volume of drops ase area h 6 h cm. () TQ, Height circumference h c Volume of cylinder r h ( r ) h c c c 5. () 6. () TQ, rea of isosceles triangle b a b sq. units 7. () External diameter 78 m Internal diameter 700 m breadth of road 78 700 m 8. () Radius of circle 8 cm Perimeter of square ircumference of circle r 7 8 58 cms Length of the side of square 58 cm 9. () Increase in area 5 5 5 5 00 50. () 0 cm 0 cm 0 cm 0 0 0 S 5 cm rea of 5(5 0)(5 0)(5 0) 5 5 5 5 75 5 cm rea of 75 5 rea of 50 5 cm 5. () Let side of square a cm rea of square a cm rea of new square 50 a 00 9 a Required ratio 9 a : a 9 : 5. () rea of circle sq cm Length of longest chord iameter 6 cm 5. () Let length of longer diagonal x TQ, x x 56 x 56 cm Length of larger diagonal cm 5. () m 5 5 5... m 5 5 5 5... 0.5%

55. () m 5 m m m 5...(i) n 5 5 5... n 5 5 5 5... n 5 n n n 5...(ii) m m n n m n m n 0 (m n)(m n) (m n) 0 (m n)(m n ) 0 m n 0 5x 5 y x y 5 z 0 z 5x 5 x 5 y y 5 5 z z 5 59. () TQ, p m pm(p m) (p m) 7 pm(6) (6) 6 8 pm pm 8 60. () TQ, x m m n x m n x 0 m n 0 m n 6. () (0, ) (, 0) rea of rea of O 5 5 5 5x 5x 5 y 5 y x y 5 z 5 z 5 z x y z 5 x y z 5 0 56. () TQ, Related speed of nita and Romita 6 7 km/hr Speed of nita km/hr Speed of Romita (7 ) km/hr 57. () Side of square (x ) iagonal of square x x ( ) x x x x unit Side of square unit 58. () S a b c Let a, b and c s s(s c)(s a)(s b) ( ) ( )( ) () ab () ()abc 6 ( ) ()0 ( ) a b c () ( ) 6 sq. units p 6. () p p p p p p p 8 p p 0 6. () TQ, K K (K ) 0 K 6. () 5 E In E and E E E E E 5 5 5 9 5 : 9

65. () P Q T 8 R S 7 O 5 70. () 5 0 0 rea of ab sin In TRO RT 6 8 cm 7. () 0 0 sin 5 5 sq. cm P 66. () OR 7 cm OT 7 8 5 cm In TSO OT 5 cm OS 5 cm TS 5 5 0 cm length of PS 0 0 cm 80 80 90 56 67. () In equilateral triangle Inradius : outer radius : 68. () a O Q 8 In PQO O PO OQ 60 O 60 90 90 8 80 OPQ PQ 90 66 7. () In rectangle, m m length of diagonal 5 m TQ, a b b 0 ab 0 ab 0 (a b) a b ab (0) (0) 80 69. () Perimeter of triangle cms ircumference of in-circle cms Inradius 7 7 cms rea of triangle radius perimeter of triangle 7. () Side of triangle : : : 5 : : 5 : () (5) 5 69 () So triangle is a right-angled triangle. 7. () sin cos ( cos ) cos cos cos cos cos 0 cos cos cos 0 cos(cos ) (cos ) 0 ( cos )(cos ) 0 Either cos 0 or cos 0 cos never be zero. So cos 0 7 8 cm cos cos 60 60

75. () a, b and c are the sides of the triangle a b c ab bc ca (given) a b c ab bc ca a b ab b c bc c a ca 0 (a b) (b c) (c a) 0 a b c ll angles of the triangle are equal i.e. 80 60 sin sin sin sin 60 9 76. () a sin b cos c squaring both sides, a sin b cos ab sin cos c...(i) a b a b...(ii) Subtracting equation (ii) from (i) a a sin b b cos ab sincos a b c a ( sin ) b ( cos ) ab sin cos a b c a cos b sin ab sincos a b c (a cos b sin) a b c a cos b sin ± a b c 77. () sin cos sin(90 ) sin cos cos sin cos cos cos sin cos sin cot cot cot 78. () (sec tan ) 5 (tan tan ) 5 6 tan 5 6 tan 5 tan 6 tan cos tan 79. () x cos 0 sin 60 x x 8 tan 5.sec 60 cosec 60 () () x 8 80. () tan (given) cosec cosec sec sec sin cos sin cos sin sin cos sin sin cos tan tan 5 8. () sin( 0 ) 8. () sin( 0 ) 0 60 0 cos cos 0 P Q QR PR QR 0 cm 0 cos 0 0 cm and PQ PR R 0 sin 0 sin 60

PQ 0 0 cm rea of PQR PQ QR 0 0 50 cm 8. () cos cos 0 8. () ( cos) cos 0 cos 0 cos 0 cos cos cos cos 0 0 x y x y x y y x y y 5 85. () 50% of x 0% of y 86. () 50 00 x 0 00 y x y 0 00 00 50 x y 5 x : y : 5 x y x y x y 5 5 5 :......... 9 8... 8 9 9 8 9 8 9 8... 9 8 9 9 8 9 8 87. () Let number x TQ, (x 5) x 5 x 50x 65 x 5 50x 65 5 50x 650 x 88. () Total armies 656 TQ, 656 (9) 8 remaining armies 8 89. () 90. () 7 7 7... x x 7 7 7... x 7 x x x 7 0 x 9x 8x 7 0 x(x 9) 8(x 9) 0 (x 8)(x 9) 0 x 8 or 9 7 7 7... 9 9. () Total heads 80 Total legs 0 If all heads are of cows, then legs should be 80 70 If all heads are of hens, then legs should be 80 60 Hens ows 60 70 0 00 60 5 : number of cows 80 0 5 9. () n(n )(n ) is always divisible by 6. 9. () () 5 9. () Time exceed by only 8 hours Time exceed by only hours time required to finish the work together by and 6 hrs 6 hrs 8 hrs 5

95. () Person earns ` 000 for 50 hours Regular wages per hour ` 000 50 ` 0 dditional wages per hour ` 0 ` 60 Total earning ` 00 dditional earning ` (00 000) ` 00 Extra hours worked 00 60 5 hours 96. () Required ratio 00 : 70 0 : 7 97. () verage mark in the second term 80 80 75 65 60 5 7 98. () Number of students travelling by public bus 5 800 0 60 99. () Students who use institute s bus 6 800 80 60 Students do not use institute bus (800 80) 0 00.() Number of students who go to institute on foot (60 6 8 5 ) 60 7 800 60 60 SS MINS (MTHS) MOK TEST- 0 (NSWER KEY). (). (). (). () 5. () 6. () 7. () 8. () 9. () 0. (). (). (). (). () 5. () 6. () 7. () 8. () 9. () 0. (). (). (). (). () 5. () 6. () 7. () 8. () 9. () 0. (). (). (). (). () 5. () 6. () 7. () 8. () 9. () 0. (). (). (). (). () 5. () 6. () 7. () 8. () 9. () 50. () 5. () 5. () 5. () 5. () 55. () 56. () 57. () 58. () 59. () 60. () 6. () 6. () 6. () 6. () 65. () 66. () 67. () 68. () 69. () 70. () 7. () 7. () 7. () 7. () 75. () 76. () 77. () 78. () 79. () 80. () 8. () 8. () 8. () 8. () 85. () 86. () 87. () 88. () 89. () 90. () 9. () 9. () 9. () 9. () 95. () 96. () 97. () 98. () 99. () 00. () 6