Most Continuous Functions are Nowhere Differentiable

Similar documents
Math 328 Course Notes

Continuous functions that are nowhere differentiable

Baire category theorem and nowhere differentiable continuous functions

SOME QUESTIONS FOR MATH 766, SPRING Question 1. Let C([0, 1]) be the set of all continuous functions on [0, 1] endowed with the norm

THEOREMS, ETC., FOR MATH 515

ANALYSIS WORKSHEET II: METRIC SPACES

REAL AND COMPLEX ANALYSIS

g 2 (x) (1/3)M 1 = (1/3)(2/3)M.

From now on, we will represent a metric space with (X, d). Here are some examples: i=1 (x i y i ) p ) 1 p, p 1.

Metric Spaces and Topology

converges as well if x < 1. 1 x n x n 1 1 = 2 a nx n

Spaces of continuous functions

MATH 202B - Problem Set 5

Math 209B Homework 2

Bounded Derivatives Which Are Not Riemann Integrable. Elliot M. Granath. A thesis submitted in partial fulfillment of the requirements

1 Topology Definition of a topology Basis (Base) of a topology The subspace topology & the product topology on X Y 3

Real Analysis Notes. Thomas Goller

Math General Topology Fall 2012 Homework 11 Solutions

THE INVERSE FUNCTION THEOREM

MAA6617 COURSE NOTES SPRING 2014

Summer Jump-Start Program for Analysis, 2012 Song-Ying Li

Analysis Comprehensive Exam Questions Fall F(x) = 1 x. f(t)dt. t 1 2. tf 2 (t)dt. and g(t, x) = 2 t. 2 t

FUNCTIONS WITH MANY LOCAL EXTREMA. 1. introduction

Functional Analysis Exercise Class

Continuous Functions on Metric Spaces

Metric Spaces Math 413 Honors Project

Economics 204 Fall 2011 Problem Set 2 Suggested Solutions

Continuity of convex functions in normed spaces

Solutions Final Exam May. 14, 2014

Math 421, Homework #9 Solutions

Problem set 5, Real Analysis I, Spring, otherwise. (a) Verify that f is integrable. Solution: Compute since f is even, 1 x (log 1/ x ) 2 dx 1

Definition 6.1. A metric space (X, d) is complete if every Cauchy sequence tends to a limit in X.

Problem Set 5. 2 n k. Then a nk (x) = 1+( 1)k

(a) For an accumulation point a of S, the number l is the limit of f(x) as x approaches a, or lim x a f(x) = l, iff

CONTENTS. 4 Hausdorff Measure Introduction The Cantor Set Rectifiable Curves Cantor Set-Like Objects...

Metric Spaces Lecture 17

CHAPTER 9. Embedding theorems

Principles of Real Analysis I Fall VII. Sequences of Functions

2 Sequences, Continuity, and Limits

Nonlinear equations. Norms for R n. Convergence orders for iterative methods

Chapter 1. Introduction

Real Analysis Math 131AH Rudin, Chapter #1. Dominique Abdi

Continuity. Chapter 4

MATH 140B - HW 5 SOLUTIONS

Continuity. Chapter 4

P-adic Functions - Part 1

Bootcamp. Christoph Thiele. Summer As in the case of separability we have the following two observations: Lemma 1 Finite sets are compact.

van Rooij, Schikhof: A Second Course on Real Functions

Chapter 8: Taylor s theorem and L Hospital s rule

Stone-Čech compactification of Tychonoff spaces

Exam 2 extra practice problems

ON SPACE-FILLING CURVES AND THE HAHN-MAZURKIEWICZ THEOREM

MATH 51H Section 4. October 16, Recall what it means for a function between metric spaces to be continuous:

Analysis III. Exam 1

Selçuk Demir WS 2017 Functional Analysis Homework Sheet

MATH 131A: REAL ANALYSIS (BIG IDEAS)

Mathematical Analysis Outline. William G. Faris

Functional Analysis HW #3

d(x n, x) d(x n, x nk ) + d(x nk, x) where we chose any fixed k > N

The Space of Continuous Functions

Thus f is continuous at x 0. Matthew Straughn Math 402 Homework 6

10 Typical compact sets

1 Definition of the Riemann integral

Austin Mohr Math 704 Homework 6

The Arzelà-Ascoli Theorem

Analysis Finite and Infinite Sets The Real Numbers The Cantor Set

1 The Local-to-Global Lemma

APPLICATIONS OF DIFFERENTIABILITY IN R n.

Immerse Metric Space Homework

Quick Tour of the Topology of R. Steven Hurder, Dave Marker, & John Wood 1

Math 341 Summer 2016 Midterm Exam 2 Solutions. 1. Complete the definitions of the following words or phrases:

FUNCTIONAL ANALYSIS LECTURE NOTES: COMPACT SETS AND FINITE-DIMENSIONAL SPACES. 1. Compact Sets

2. Metric Spaces. 2.1 Definitions etc.

Analysis Comprehensive Exam Questions Fall 2008

Assignment-10. (Due 11/21) Solution: Any continuous function on a compact set is uniformly continuous.

MASTERS EXAMINATION IN MATHEMATICS SOLUTIONS

Review of Multi-Calculus (Study Guide for Spivak s CHAPTER ONE TO THREE)

Walker Ray Econ 204 Problem Set 3 Suggested Solutions August 6, 2015

MT804 Analysis Homework II

MAT 570 REAL ANALYSIS LECTURE NOTES. Contents. 1. Sets Functions Countability Axiom of choice Equivalence relations 9

Metric Spaces. DEF. If (X; d) is a metric space and E is a nonempty subset, then (E; d) is also a metric space, called a subspace of X:

Introduction and Preliminaries

Introduction to Topology

Continuity. Matt Rosenzweig

ABSTRACT INTEGRATION CHAPTER ONE

I. The space C(K) Let K be a compact metric space, with metric d K. Let B(K) be the space of real valued bounded functions on K with the sup-norm

MATH 5640: Fourier Series

Chapter 3: Baire category and open mapping theorems

Chapter 1: Banach Spaces

SOLUTIONS TO SOME PROBLEMS

7 About Egorov s and Lusin s theorems

Introduction to Proofs in Analysis. updated December 5, By Edoh Y. Amiran Following the outline of notes by Donald Chalice INTRODUCTION

Analysis Qualifying Exam

2019 Spring MATH2060A Mathematical Analysis II 1

Metric Spaces Math 413 Honors Project

(convex combination!). Use convexity of f and multiply by the common denominator to get. Interchanging the role of x and y, we obtain that f is ( 2M ε

NOTES ON EXISTENCE AND UNIQUENESS THEOREMS FOR ODES

Introductory Analysis I Fall 2014 Homework #9 Due: Wednesday, November 19

Summer Jump-Start Program for Analysis, 2012 Song-Ying Li. 1 Lecture 7: Equicontinuity and Series of functions

Analysis III Theorems, Propositions & Lemmas... Oh My!

Transcription:

Most Continuous Functions are Nowhere Differentiable Spring 2004 The Space of Continuous Functions Let K = [0, 1] and let C(K) be the set of all continuous functions f : K R. Definition 1 For f C(K) we define f, the norm of f, by f = sup{ f(x) : x K}. Since K is compact and f is continuous, f is well-defined. Exercise 2 Prove that f g f h + h g for all f, g, h C(K) Definition 3 We say (f n ) is a Cauchy sequence in C(K) if for all ɛ > 0 there is N N such that f n f m < ɛ for all n, m N. Note that (f n ) converges to g uniformly if and only if for all ɛ > 0 there is N N such that f n g < ɛ for all n N. Moreover, we know that any Cauchy sequence is uniformly convergent. Since the uniform limit of continuous functions is continuous, we have the following proposition. Proposition 4 If (f n ) is a Cauchy sequence in C(K), then there is f C(K) such that f n converges to f. Definition 5 We say that F C(K) is closed if every Cauchy sequence in F converges to an element of F. 1

Definition 6 If f C(K) and ɛ > 0, let B ɛ (f) = {g C(K) : f g < ɛ}. We call B ɛ (f) the open ball of radius ɛ around f. Similarly, we define B ɛ (f) = {g C(K) : f g ɛ}. Lemma 7 Each B ɛ (f) is closed. Proof Suppose (f n ) is a Cauchy sequence in B ɛ (f). Suppose f n g. If x K, then f n (x) f(x) ɛ for all n. Hence g(x) f(x) ɛ for all x and g f ɛ. Note that if g B ɛ (f) and 0 < δ ɛ f g, then B δ (g) B ɛ (f). Definition 8 We say that D C(K) is dense if D B ɛ (f) is nonempty for every open ball. Intuitively, D is dense if every continuous function on K can be wellapproximated by functions in D. Definition 9 We say that p : K R is piecewise-linear if there is a partition 0 = a 0 < a 1 <... < a n = 1 of [0, 1] such that p is linear on the interval [a i, a i+1 ] for i = 0,..., n. Let P L(K) C(K) be the set of piecewise linear continuous functions on K. Theorem 10 P L(K) is dense in C(K). Proof Suppose f C(K) and ɛ > 0. Since K is compact, f is uniformly continuous on K. Thus there is δ > 0 such that f(x) f(y) < ɛ/2 for all x, y K with x y < δ. Let 0 = a 0 < a 1 <... < a n = 1 be a partition of [0, 1] such that a i+1 a i < δ for i = 0, 1,.... Let p : K R be the piecewise linear function such that p(a i ) = f(a i ) and p is linear on each [a i, a i+1 ] for all i. If x K, there is an i such that a i x a i+1. Then p(x) f(a i ) = p(x) p(a i ) p(a i+1 ) p(a i ) < ɛ/2 and f(x) f(a i ) < ɛ/2. Thus p(x) f(x) < ɛ and p B ɛ (f). 2

Baire Category in C(K) We begin by generalizing some concepts from R to C(K). Definition 11 We say that E C(K) is nowhere dense if for all open balls B ɛ (f), there is an open ball B δ (g) B ɛ (f) with D B δ (g) =. We say that E C(K) is meager if E = n=1 where each E n is nowhere dense. Meager sets are sometimes called sets of first-category. Meager sets share some of the properties of measure zero sets. Exercise 12 a) If E is meager and F E, then F is meager. b) If E 1, E 2,... are meager, then E = n=1 E n is meager. We think of meager sets as being small. It is important to show that not every set is meager. Theorem 13 (Baire Category Theorem for C(K)) C(K) is not meager. Proof Suppose E = E n where each E n C(K) is nowhere dense. We will find f C(K) with f E by constructing a sequence (f n ) converging uniformly to f as follows: Let f 0 C(K). Let ɛ 0 = 1. Given f n and ɛ n > 0, since E n is nowhere dense we can find f n+1 B ɛn (f n ) and ɛ n+1 > 0 such that: i) B ɛn+1 (f n+1 ) B ɛn (f n ); ii) B ɛn+1 (f n+1 ) E n =. We claim that the sequence (f n ) is Cauchy. Let ɛ > 0. Choose N such that ɛ N < ɛ. If n > m N, then f n B ɛm (f m ). Hence f n f m ɛ m < ɛ. Thus there is f C(K) such that f n f. Since f n B ɛm (f m ) for all n > m, and, by Lemma 7, B ɛm (f m ) is closed, we know that f B ɛm (f m ) for all m. Since B ɛm (f m ) E m =, f E m for any m. Thus f C(K) \ E. Exercise 14 Prove that every open or closed ball is nonmeager. We give a useful characterization of nowhere dense closed sets. E n 3

Lemma 15 Suppose F C(K) is closed. The following are equivalent: i) F is nowhere dense; ii) there is no open ball B ɛ (f) F. Proof i) ii) Clear. ii) i) Suppose F is not nowhere dense. Then there is an open ball B ɛ (f) such that every open ball F B δ (g) whenever B δ (g) B ɛ (f). We claim that B ɛ (f) F. Let g B ɛ (f). For each n we can find f n B 1/n (g) E. Then f n converges uniformly to g. Hence g E. Thus B ɛ (f) E. Nowhere Differentiable Functions Let D = {f C(K) : f is differentiable at x for some x K}. We will prove that D is meager. By the Baire Category Theorem, this gives another proof that there are nowhere differentiable continuous functions. Indeed, it tells us that most continuous functions on K are nowhere differentiable! Let A n.m = { f C(K) : there is x K such that f(t) f(x) t x Lemma 16 If f D, then f A n,m for some n and m. n if 0 < x t < 1 m Proof Suppose f is differentiable at x. Choose n such that f (x) < n. There is δ > 0 such that f(t) f(x) t x < n if 0 < t x < δ. Choose m such that 1/m < δ. Then f A n,m. Lemma 17 Each A n,m is closed. Proof Suppose (f i ) is a Cauchy sequence in A n,m and f i f. For each i we can find x i K such that f i (t) f i (x i ) t x n for all 0 < x t < 1 m. By the Bolzono Weierstrass Theorem (x i ) has a convergent subsequence. By replacing the sequence f n by a subsequence, we may, without loss of 4 }.

generality, assume that (x i ) converges. Suppose x i converges to x. Suppose 0 < x t < 1. Then m f(t) f(x) t x = lim f i (t) f i (x i ) i t x i n. Hence f A n,m. Lemma 18 Each A n,m is nowhere dense. Proof Since A n,m is closed, if suffices, by Lemma 15, to show that A n,m does not contain an open ball. Consider the open ball B ɛ (f). We must find g B ɛ (f) with g A n,m. By Theorem 10, we can find a piecewise linear p(x) such that f p < ɛ/2. Since the graph of p is a finite union of line segments, p is differentiable at all but finitely many points and we can find M N such that p (x) M for all x where p is differentiable. Choose k > 2(M+n). ɛ There is a continuous piecewise linear function φ(x) where φ(x) 1 for all x K and φ (x) = ±k for all x where k is differentiable. [Consider the partition a i = i/k for i = 0,..., k and let φ(a i ) = 0 if i is even and 1 if i is odd.] Let g(x) = p(x) + ɛ 2 φ(x). Since f p < ɛ/2 and g p < ɛ/2, f g < ɛ. We claim that g A n,m. Let x [0, 1]. If p and φ are differentiable at x, then g (x) = p (x) ± ɛ 2 k Since p (x) M, g (x) > n. In general, we can find l > m such that g [x, x + 1 and g [x 1, x] are linear and the absolute value of the slope is l l greater than n. In particular, if 0 < x t < 1 < 1, then l m g(t) g(x) t x > n and g A n,m. Thus B ɛ (f) A n,m. Theorem 19 D is meager. In particular, there are continuous nowhere differentiable functions. 5

Proof Since each A n,m is nowhere dense, A = n=1 m=1 A n,m is meager. Since D A, D is meager. By the Baire Category Theorem for C(K), we know that C(K) is not meager. Thus there is f C(K) with f D. Indeed, if we think of meager sets as being small, this tells us that most f C(K) are nowhere differentiable. 6