VOLUME OF A TETRAHEDRON IN THE TAXICAB SPACE

Similar documents
Chinese Checker Versions of the Pythagorean Theorem

A TAXICAB VERSION OF A TRIANGLE S APOLLONIUS CIRCLE

International Journal of Pure and Applied Mathematics Volume 30 No ,

The tangents and the chords of the Poincaré circle

THE TAXICAB HELIX ON TAXICAB CYLINDER

ZEYNEP CAN. 1 Introduction. KoG Z. Can, Ö. Gelişgen, R. Kaya: On the Metrics Induced by Icosidodecahedron...

Research Article On the Plane Geometry with Generalized Absolute Value Metric

On the Iso-Taxicab Trigonometry

On Conics in Minkowski Planes

10. Show that the conclusion of the. 11. Prove the above Theorem. [Th 6.4.7, p 148] 4. Prove the above Theorem. [Th 6.5.3, p152]

Vectors - Applications to Problem Solving

The Brahmahupta s theorem after Coxeter

Mathematics. Single Correct Questions

1. The positive zero of y = x 2 + 2x 3/5 is, to the nearest tenth, equal to

Mathematics 2260H Geometry I: Euclidean geometry Trent University, Fall 2016 Solutions to the Quizzes

Course 212: Academic Year Section 1: Metric Spaces

Geometry. A. Right Triangle. Legs of a right triangle : a, b. Hypotenuse : c. Altitude : h. Medians : m a, m b, m c. Angles :,

b = 2, c = 3, we get x = 0.3 for the positive root. Ans. (D) x 2-2x - 8 < 0, or (x - 4)(x + 2) < 0, Therefore -2 < x < 4 Ans. (C)

Time : 3 hours 02 - Mathematics - July 2006 Marks : 100 Pg - 1 Instructions : S E CT I O N - A

UNCC 2001 Comprehensive, Solutions

H2 MATHS SET D PAPER 1

MATH 241 FALL 2009 HOMEWORK 3 SOLUTIONS

CENTROIDS AND SOME CHARACTERIZATIONS OF PARALLELOGRAMS

y mx 25m 25 4 circle. Then the perpendicular distance of tangent from the centre (0, 0) is the radius. Since tangent

The Distance Formula. The Midpoint Formula

Ion Patrascu, Florentin Smarandache A Sufficient Condition for the Circle of the 6 Points to Become Euler s Circle

Objectives. Cabri Jr. Tools

1966 IMO Shortlist. IMO Shortlist 1966

Created by T. Madas VECTOR PRACTICE Part B Created by T. Madas

VARIOUS CENTROIDS OF POLYGONS AND SOME CHARACTERIZATIONS OF RHOMBI

Homework Assignments Math /02 Fall 2017

chapter 1 vector geometry solutions V Consider the parallelogram shown alongside. Which of the following statements are true?

Math 9 Chapter 8 Practice Test

12-neighbour packings of unit balls in E 3

The group of isometries of the French rail ways metric

Department of Systems Innovation, School of Engineering, The University of Tokyo 2011 Entrance Examination and Answer Sheets.

Chapter (Circle) * Circle - circle is locus of such points which are at equidistant from a fixed point in

Written test, 25 problems / 90 minutes

Seul Lee, Dong-Soo Kim and Hyeon Park

Give a geometric description of the set of points in space whose coordinates satisfy the given pair of equations.

PREPARED BY: ER. VINEET LOOMBA (B.TECH. IIT ROORKEE) 60 Best JEE Main and Advanced Level Problems (IIT-JEE). Prepared by IITians.

Year 12 into 13 Maths Bridging Tasks

Module 2: Reflecting on One s Problems

SOLVED PROBLEMS. 1. The angle between two lines whose direction cosines are given by the equation l + m + n = 0, l 2 + m 2 + n 2 = 0 is

Arkansas Tech University MATH 2914: Calculus I Dr. Marcel B. Finan. Solution to Section 4.5

2 Review: Modeling Molecules with Spherical Balls

SOME SPECIAL KLEINIAN GROUPS AND THEIR ORBIFOLDS

11 th Annual Harvard-MIT Mathematics Tournament

0112ge. Geometry Regents Exam Line n intersects lines l and m, forming the angles shown in the diagram below.

ON THE RELATIVE LENGTHS OF SIDES OF CONVEX POLYGONS. Zsolt Lángi

Practice Assessment Task SET 3

Forum Geometricorum Volume 13 (2013) 1 6. FORUM GEOM ISSN Soddyian Triangles. Frank M. Jackson

HIGH SCHOOL - PROBLEMS

UNIT 3 CIRCLES AND VOLUME Lesson 1: Introducing Circles Instruction

Y. D. Chai and Young Soo Lee

ALGEBRA 2 X. Final Exam. Review Packet

Projects in Geometry for High School Students

Extra FP3 past paper - A

Isogonal Conjugates in a Tetrahedron

Definitions, Axioms, Postulates, Propositions, and Theorems from Euclidean and Non-Euclidean Geometries by Marvin Jay Greenberg ( )

= 10 such triples. If it is 5, there is = 1 such triple. Therefore, there are a total of = 46 such triples.

Index. Excerpt from "Art of Problem Solving Volume 1: the Basics" 2014 AoPS Inc. / 267. Copyrighted Material

PREPRINT 2005:51. The Maximum Polygon Area and its Relation to the Isoperimetric Inequality MAGNUS KARLSSON BO BERNDTSSON

Q.2 A, B and C are points in the xy plane such that A(1, 2) ; B (5, 6) and AC = 3BC. Then. (C) 1 1 or

Existence Postulate: The collection of all points forms a nonempty set. There is more than one point in that set.

The Radii of Hyper Circumsphere and Insphere through Equidistant Points

1 Line n intersects lines l and m, forming the angles shown in the diagram below. 4 In the diagram below, MATH is a rhombus with diagonals AH and MT.

Test Corrections for Unit 1 Test

4.Let A be a matrix such that A. is a scalar matrix and Then equals :

Homework Assignments Math /02 Fall 2014

RMT 2013 Geometry Test Solutions February 2, = 51.

TETRAHEDRA SHARING VOLUME, FACE AREAS, AND CIRCUMRADIUS: A HEDRONOMETRIC APPROACH

Functional Analysis MATH and MATH M6202

Trigonometry: Applications of Trig Functions (2D & 3D), Other Geometries (Grade 12) *

1 What is the solution of the system of equations graphed below? y = 2x + 1

High School HS Geometry 1819 GSE Geometry Unit 5 Full Touchstone

nx + 1 = (n + 1)x 13(n + 1) and nx = (n + 1)x + 27(n + 1).

( 1 ) Show that P ( a, b + c ), Q ( b, c + a ) and R ( c, a + b ) are collinear.

b) Write the contrapositive of this given statement: If I finish ALEKS, then I get points.

NATIONAL BOARD FOR HIGHER MATHEMATICS. M. A. and M.Sc. Scholarship Test. September 24, Time Allowed: 150 Minutes Maximum Marks: 30

MAT100 OVERVIEW OF CONTENTS AND SAMPLE PROBLEMS

Math Requirements for applicants by Innopolis University

On the Distortion of Embedding Perfect Binary Trees into Low-dimensional Euclidean Spaces

THE CYCLIC QUADRANGLE IN THE ISOTROPIC PLANE

Sponsored by: UGA Math Department and UGA Math Club. Team Round / 1 hour / 210 points November 16, 2013 WITH SOLUTIONS

ADDITIONAL MATHEMATICS

Practice Test Geometry 1. Which of the following points is the greatest distance from the y-axis? A. (1,10) B. (2,7) C. (3,5) D. (4,3) E.

A Class of Möbius Iterated Function Systems

Math Wrangle Practice Problems

Convergence of a Generalized Midpoint Iteration

some characterizations of parabolas.

Classical Theorems in Plane Geometry 1

Exercises for Unit I I I (Basic Euclidean concepts and theorems)

UNC Charlotte Super Competition - Comprehensive test March 2, 2015

Area Formulas. Linear

SOME EQUIVALENT CONDITIONS FOR CONIC SECTIONS

Heronian tetrahedra are lattice tetrahedra

SAT SHEET (calculators allowed)

Complex Descartes Circle Theorem

0609ge. Geometry Regents Exam AB DE, A D, and B E.

Transcription:

VOLUME 21, NUMBER 1, 2009 21 VOLUME OF A TETRAHEDRON IN THE TAXICAB SPACE H. Barış Çolakoğlu and Rüstem Kaya Abstract. In this paper, we give the taxicab version of the Heron- Tartaglia formula to calculate the volume of a tetrahedron using the taxicab distance. 1. Introduction. The three dimensional taxicab space is constructed by using the taxicab metric d T (P, Q) = x 1 x 2 + y 1 y 2 + z 1 z 2 in three dimensional Cartesian space instead of the well-known Euclidean metric d E (P, Q) = [ (x 1 x 2 ) 2 + (y 1 y 2 ) 2 + (z 1 z 2 ) 2], where P = (x 1, y 1, z 1 ) and Q = (x 2, y 2, z 2 ). In the taxicab space, the taxicab distance d T between points P and Q is the length of one of the shortest paths from P to Q composed of line segments, each parallel to a coordinate axis. Since taxicab geometry has a distance function different from that in Euclidean geometry, it is interesting to study the taxicab analogues of topics that include the distance concept in Euclidean geometry [1, 2, 3, 4, 5, 7]. Here, we study the following problem: How can one compute the volume of a tetrahedron using the taxicab distance? 2. Preliminaries. In Euclidean geometry the well-known Heron s Formula, which expresses the area A of a triangle in terms of the lengths of its edges a, b, c, can be given by or A 2 = 1 ( 2a 2 b 2 + 2a 2 c 2 + 2b 2 c 2 a 4 b 4 c 4) 16 A 2 = p(p a)(p b)(p c), where p = (a + b + c)2 which is the semiperimeter of the triangle. The taxicab version of Heron s Formula was given in [4] by Ozcan and Kaya. The generalization of Heron s Formula to the volume of a tetrahedron is also well-known in Euclidean geometry: Let l i, 1 i 6, denote the the Euclidean lengths of the edges of tetrahedron ABCD such that l 1 = d E (B, C), l 2 = d E (A, C), l 3 = d E (A, B), l 4 = d E (D, C), l 5 = d E (D, A),

22 MISSOURI JOURNAL OF MATHEMATICAL SCIENCES and l 6 = d E (D, B) (see Figure 1). Then the volume V of tetrahedron ABCD can be calculated by the formula V 2 = 1 144 (l 2 1 l2 5 (l2 2 + l2 3 + l2 4 + l2 6 l2 1 l2 5 ) + l2 2 l2 6 (l2 1 + l2 3 + l2 4 + l2 5 l2 2 l2 6 ) + l 2 3 l2 4 (l2 1 + l2 2 + l2 5 + l2 6 l2 3 l2 4 ) l2 1 l2 2 l2 3 l2 1 l2 4 l2 6 l2 2 l2 4 l2 5 l2 3 l2 5 l2 6 ) which is known as Heron-Tartaglia Formula [6]. The aim of this work is to give a taxicab version of this formula. Figure 1 3. Taxicab Version of Heron-Tartaglia Formula. In the taxicab space, there are cases in which it is possible to construct infinitely many tetrahedra having given taxicab lengths of its edges t i, 1 i 6, such that no two have the same volume (see Example). Therefore, knowing only the taxicab lengths of edges of a tetrahedron is not sufficient to calculate its volume generally. Moreover, taxicab lengths of these edges are not invariant, in general, under rotations and reflections. Thus, we use the coordinates of vertices of the tetrahedron additionally to give a general volume formula for the tetrahedron in taxicab geometry. The following example refers to Figure 2, in which two different taxicab circles are shown. Recall that a taxicab circle with center C and radius r is the set of all points whose taxicab distance to C is r. This locus of points is a square with center C, each side having slope ±1, and each diagonal having length 2r. Just as for a Euclidean circle, the center C and one point at a taxicab distance r from C completely determine the taxicab circle. Example. Let a, b, and c be positive real numbers, and let B = (0, a, 0), C = (0, 0, 0), D = (0, 0, c), P = (0, b, 0) and P = ( b, 0, 0) be points in the taxicab space. Choose a point A in the line segment P P, such that ABCD is a tetrahedron. Let C 1 and C 2 be taxicab circles in the plane z = 0, with centers C and B, and with radius b and (a + b), respectively (see Figure 2). Since A is on both C 1 and C 2, it is obvious that d T (C, A) = b and d T (B, A) = a + b. Now, it is easy to see that if the

VOLUME 21, NUMBER 1, 2009 23 point A moves on the line segment P P, the taxicab lengths of edges of tetrahedron ABCD do not change, but the volume of tetrahedron ABCD changes since the area of triangle ABC changes. Thus, there are infinitely many tetrahedra ABCD having taxicab lengths of its edges d T (B, C) = a, d T (A, C) = b, d T (A, B) = a + b, d T (D, C) = c, d T (D, A) = c + b, and d T (D, B) = c + a, such that no two have the same volume. Figure 2 The following theorem gives a general volume formula for the tetrahedron in the taxicab space. Theorem. The volume V of tetrahedron ABCD with the vertices A = (a 1, a 2, a 3 ), B = (b 1, b 2, b 3 ), C = (c 1, c 2, c 3 ), and D = (d 1, d 2, d 3 ) in the taxicab space, can be calculated by the formula V 2 = 1 144 ((α 1 t 1 ) 2 (α 5 t 5 ) 2 ((α 2 t 2 ) 2 + (α 3 t 3 ) 2 + (α 4 t 4 ) 2 + (α 6 t 6 ) 2 (α 1 t 1 ) 2 (α 5 t 5 ) 2 ) + (α 2 t 2 ) 2 (α 6 t 6 ) 2 ((α 1 t 1 ) 2 + (α 3 t 3 ) 2 + (α 4 t 4 ) 2 + (α 5 t 5 ) 2 (α 2 t 2 ) 2 (α 6 t 6 ) 2 ) + (α 3 t 3 ) 2 (α 4 t 4 ) 2 ((α 1 t 1 ) 2 + (α 2 t 2 ) 2 + (α 5 t 5 ) 2 + (α 6 t 6 ) 2 (α 3 t 3 ) 2 (α 4 t 4 ) 2 ) (α 1 t 1 ) 2 (α 2 t 2 ) 2 (α 3 t 3 ) 2 (α 1 t 1 ) 2 (α 4 t 4 ) 2 (α 6 t 6 ) 2 (α 2 t 2 ) 2 (α 4 t 4 ) 2 (α 6 t 6 ) 2 (α 3 t 3 ) 2 (α 5 t 5 ) 2 (α 6 t 6 ) 2 ),

24 MISSOURI JOURNAL OF MATHEMATICAL SCIENCES where α 1 = (b j c j ) 2 α 2 = (a j c j ) 2 α 3 = (a j b j ) 2 α 4 = (c j d j ) 2 α 5 = (a j d j ) 2 α 6 = (b j d j ) 2 b j c j, a j c j, a j b j, c j d j, a j d j, b j d j, and t 1 = d T (B, C), t 2 = d T (A, C), t 3 = d T (A, B), t 4 = d T (D, C), t 5 = d T (D, A), t 6 = d T (D, B). Proof. Let ABCD be a tetrahedron in the taxicab space with vertices A = (a 1, a 2, a 3 ), B = (b 1, b 2, b 3 ), C = (c 1, c 2, c 3 ), D = (d 1, d 2, d 3 ) such that the taxicab lengths of its edges t 1 = d T (B, C), t 2 = d T (A, C), t 3 = d T (A, B), t 4 = d T (D, C), t 5 = d T (D, A), t 6 = d T (D, B) (see Figure 3). Let l i be Euclidean lengths of the edges with taxicab lengths t i, 1 i 6, respectively. Figure 3 The following equation, which relates the Euclidean distance to the taxicab distance between two points in the Cartesian space, can be easily

VOLUME 21, NUMBER 1, 2009 25 derived by a straightforward calculation with the coordinate definitions of d E (P, Q) and d T (P, Q) given in Section 1. If the line through P and Q has direction vector p, q, r, then d E (P, Q) = [ (p 2 + q 2 + r 2) ( p + q + r ) ] d T (P, Q). Since b 1 c 1, b 2 c 2, b 3 c 3 is a direction vector of the line through B = (b 1, b 2, b 3 ) and C = (c 1, c 2, c 3 ), one can obtain using the last equation that d E (B, C) = (b j c j ) 2 b j c j d T (B, C). Thus, l 1 = α 1 t 1, where α 1 = (b j c j ) 2 Similarly, one obtains that b j c j. l i = α i t i, 1 i 6, where each α i is as in the statement of the theorem. Replacing l i with α i t i, 1 i 6, in the Heron-Tartaglia Formula, one gets the equation in the statement of the theorem, which is the taxicab version of the Heron- Tartaglia Formula. Remark. Every convex polyhedron can be thought of as the union of a finite number of tetrahedra with a common vertex and with bases in the faces of the polyhedron. Therefore, the volume of any convex polyhedron given by its vertices in the taxicab space can be calculated using the taxicab version of the Heron-Tartaglia Formula. Considering the Remark, one can easily obtain the volume formula for the taxicab sphere in terms of the length of its edge or its radius, using the taxicab version of the Heron-Tartaglia Formula, as follows. The volume V of the taxicab sphere with radius r (see Figure 4) can be calculated by the formula V = 4 3 r3 or V = 1 6 l3, where l is the taxicab length of an edge of the taxicab sphere.

26 MISSOURI JOURNAL OF MATHEMATICAL SCIENCES Figure 4 Ref erences 1. Z. Akca, R. Kaya, On the Distance Formulae in Three Dimensional Taxicab Space, Hadronic Journal, 27 (2004), 521 532. 2. Y. P. Ho and Y. Liu, Parabolas in Taxicab Geometry, Missouri Journal of Mathematical Sciences, 10 (1997), 151 159. 3. E. F. Krause, Taxicab Geometry, Addision-Wesley, Menlo Park, California, 1975. 4. M. Özcan, R. Kaya, Area of a Triangle in Terms of the Taxicab Distance, Missouri Journal of Mathematical Sciences, 15 (2003), 178 185. 5. M. Özcan, R. Kaya, On the Ratio of Directed Lengths in the Taxicab Plane and Related Properties, Missouri Journal of Mathematical Sciences, 14 (2002), 107 117. 6. I. K. Sabitov, The Generalized Heron-Tartaglia Formula and Some of its Consequences, Sb. Math., 189 (1998), 1533 1561. 7. D. J. Schattschneider, The Taxicab Group, American Mathematical Monthly, 91 (1984), 423 428.

VOLUME 21, NUMBER 1, 2009 27 Mathematics Subject Classification (2000): 51F99, 51K05, 51K99 H. Barış Çolakoğlu Department of Mathematics Faculty of Arts and Sciences Eskişehir Osmangazi University 26480, Eskişehir, Turkey email: bariscolakoglu@hotmail.com Rüstem Kaya Department of Mathematics Faculty of Arts and Sciences Eskişehir Osmangazi University 26480, Eskişehir, Turkey email: rkaya@ogu.edu.tr