A Note on Conic Sections and Tangent Circles

Similar documents
Farey Fractions. Rickard Fernström. U.U.D.M. Project Report 2017:24. Department of Mathematics Uppsala University

Mathematics. Area under Curve.

Polynomials and Division Theory

, MATHS H.O.D.: SUHAG R.KARIYA, BHOPAL, CONIC SECTION PART 8 OF

Space Curves. Recall the parametric equations of a curve in xy-plane and compare them with parametric equations of a curve in space.

Diophantine Steiner Triples and Pythagorean-Type Triangles

NORMALS. a y a y. Therefore, the slope of the normal is. a y1. b x1. b x. a b. x y a b. x y

k ) and directrix x = h p is A focal chord is a line segment which passes through the focus of a parabola and has endpoints on the parabola.

P 1 (x 1, y 1 ) is given by,.

Thomas Whitham Sixth Form

Two Interesting Integer Parameters of Integer-sided Triangles

CONIC SECTIONS. Chapter 11

/ 3, then (A) 3(a 2 m 2 + b 2 ) = 4c 2 (B) 3(a 2 + b 2 m 2 ) = 4c 2 (C) a 2 m 2 + b 2 = 4c 2 (D) a 2 + b 2 m 2 = 4c 2

Chapter 9 Definite Integrals

Duke Math Meet

set is not closed under matrix [ multiplication, ] and does not form a group.

Sketch graphs of conic sections and write equations related to conic sections

10 Vector Integral Calculus

4 VECTORS. 4.0 Introduction. Objectives. Activity 1

Lecture 2: January 27

AN INEQUALITY OF OSTROWSKI TYPE AND ITS APPLICATIONS FOR SIMPSON S RULE AND SPECIAL MEANS. I. Fedotov and S. S. Dragomir

Exploring parametric representation with the TI-84 Plus CE graphing calculator

8. Complex Numbers. We can combine the real numbers with this new imaginary number to form the complex numbers.

STRAND J: TRANSFORMATIONS, VECTORS and MATRICES

5: The Definite Integral

Edexcel GCE Core Mathematics (C2) Required Knowledge Information Sheet. Daniel Hammocks

The Shortest Confidence Interval for the Mean of a Normal Distribution

Algebra II Notes Unit Ten: Conic Sections

Golden Sections of Triangle Centers in the Golden Triangles

On the diagram below the displacement is represented by the directed line segment OA.

KEY CONCEPTS. satisfies the differential equation da. = 0. Note : If F (x) is any integral of f (x) then, x a

I. Equations of a Circle a. At the origin center= r= b. Standard from: center= r=

Lesson-5 ELLIPSE 2 1 = 0

(e) if x = y + z and a divides any two of the integers x, y, or z, then a divides the remaining integer

Two Triads of Congruent Circles from Reflections

Improper Integrals. The First Fundamental Theorem of Calculus, as we ve discussed in class, goes as follows:

p-adic Egyptian Fractions

Drill Exercise Find the coordinates of the vertices, foci, eccentricity and the equations of the directrix of the hyperbola 4x 2 25y 2 = 100.

Vectors , (0,0). 5. A vector is commonly denoted by putting an arrow above its symbol, as in the picture above. Here are some 3-dimensional vectors:

Lecture 3: Equivalence Relations

An Alternative Approach to Estimating the Bounds of the Denominators of Egyptian Fractions

New Geometric Constructions to Determine the Radius of Curvature of Conics at any Point

S56 (5.3) Vectors.notebook January 29, 2016

The area under the graph of f and above the x-axis between a and b is denoted by. f(x) dx. π O

Calculus Module C21. Areas by Integration. Copyright This publication The Northern Alberta Institute of Technology All Rights Reserved.

Definite Integrals. The area under a curve can be approximated by adding up the areas of rectangles = 1 1 +

The Dirichlet Problem in a Two Dimensional Rectangle. Section 13.5

Math 231E, Lecture 33. Parametric Calculus

R(3, 8) P( 3, 0) Q( 2, 2) S(5, 3) Q(2, 32) P(0, 8) Higher Mathematics Objective Test Practice Book. 1 The diagram shows a sketch of part of

Torsion in Groups of Integral Triangles

Bases for Vector Spaces

DEFINITION The inner product of two functions f 1 and f 2 on an interval [a, b] is the number. ( f 1, f 2 ) b DEFINITION 11.1.

7. Indefinite Integrals

A study of Pythagoras Theorem

US01CMTH02 UNIT Curvature

GEOMETRY OF THE CIRCLE TANGENTS & SECANTS

Geometric Inequalities in Pedal Quadrilaterals

7.1 Integral as Net Change and 7.2 Areas in the Plane Calculus

CIRCULAR COLOURING THE PLANE

Math 1102: Calculus I (Math/Sci majors) MWF 3pm, Fulton Hall 230 Homework 2 solutions

Things to Memorize: A Partial List. January 27, 2017

SOME INTEGRAL INEQUALITIES OF GRÜSS TYPE

Ellipse. 1. Defini t ions. FREE Download Study Package from website: 11 of 91CONIC SECTION

I1 = I2 I1 = I2 + I3 I1 + I2 = I3 + I4 I 3

Section 14.3 Arc Length and Curvature

12 TRANSFORMING BIVARIATE DENSITY FUNCTIONS

CM10196 Topic 4: Functions and Relations

PARABOLA EXERCISE 3(B)

The practical version

Chapter 6 Techniques of Integration

Linear Inequalities. Work Sheet 1

JEE(MAIN) 2015 TEST PAPER WITH SOLUTION (HELD ON SATURDAY 04 th APRIL, 2015) PART B MATHEMATICS

A New Solution to the Intersection Problem of Mendelsohn Triple Systems. Rachel Watson

AQA Further Pure 1. Complex Numbers. Section 1: Introduction to Complex Numbers. The number system

Hamiltonian Cycle in Complete Multipartite Graphs

Conducting Ellipsoid and Circular Disk


Physics 116C Solution of inhomogeneous ordinary differential equations using Green s functions

MTH 505: Number Theory Spring 2017

Analytically, vectors will be represented by lowercase bold-face Latin letters, e.g. a, r, q.

2.4 Linear Inequalities and Interval Notation

Matrix Algebra. Matrix Addition, Scalar Multiplication and Transposition. Linear Algebra I 24

Section 6.1 Definite Integral

dx dt dy = G(t, x, y), dt where the functions are defined on I Ω, and are locally Lipschitz w.r.t. variable (x, y) Ω.

Triangles The following examples explore aspects of triangles:

Suppose we want to find the area under the parabola and above the x axis, between the lines x = 2 and x = -2.

CHAPTER 10 PARAMETRIC, VECTOR, AND POLAR FUNCTIONS. dy dx

Ch AP Problems

Section 7.1 Area of a Region Between Two Curves

Review of Gaussian Quadrature method

APPLICATIONS OF DEFINITE INTEGRALS

dt. However, we might also be curious about dy

Indefinite Integral. Chapter Integration - reverse of differentiation

WENJUN LIU AND QUÔ C ANH NGÔ

13.3 CLASSICAL STRAIGHTEDGE AND COMPASS CONSTRUCTIONS

Quadratic Forms. Quadratic Forms

Minimal DFA. minimal DFA for L starting from any other

Homework Assignment 6 Solution Set

Linear Inequalities: Each of the following carries five marks each: 1. Solve the system of equations graphically.

Congruent Contiguous Excircles

Transcription:

Forum Geometricorum Volume 17 017 1 1. FORUM GEOM ISSN 153-1178 A Note on Conic Sections nd Tngent Circles Jn Kristin Huglnd Astrct. This rticle presents result on circles tngent to given conic section nd to ech other. The result is proved using set of prmeteriztions tht cover ll possile scenrios. 1. Introduction The ojective of this rticle is to estlish the following. Theorem 1. Suppose S is conic section of eccentricity 1 if it is n ellipse There exists set S, which is either conic section or union of two conic sections, with the following property. For two circles P nd Q ech tngent to S t two points, nd to ech other externlly t point not on S if S is hyperol, the centers of the two circles R 1 nd R tht re lso tngent externlly to P nd Q nd tngent to S lie on S. For other prolems involving tngent circles, see [1,, 3, ]. The proof of Theorem 1 is sed on explicit prmeteriztions of P, Q nd R 1, given S. It is not necessry to check R seprtely, ecuse of symmetry. In ech cse, the proposed set S is clerly either conic section or union of two conic sections, s climed, ut the following conditions lso need to e verified: The proposed point of tngency etween ny circle mong P, Q nd R 1 nd S lies on S. The proposed center of R 1 lies on the proposed curve i.e., S, or one of its components. c The distnce etween the proposed center of ny circle nd the corresponding proposed point of tngency with S is equl to the proposed rdius. d The line segment from the proposed center of ny circle to the corresponding proposed point of tngency with S is norml to S. e The distnce etween the proposed centers of two mutully tngent circles is equl to the sum of their proposed rdii. Verifying conditions c nd e is generlly done y setting Δx nd to e the differences etween the proposed x- nd y-coordintes respectively for the points in question, nd Δz to e the proposed distnce i.e., the rdius or the sum of the Puliction Dte: Jnury 5, 017. Communicting Editor: Pul Yiu.

J. K. Huglnd rdii, nd checking tht Δx + Δz 1 is stisfied. The nottion with Δx nd is lso used when verifying condition d.. Ellipse.1. Prmeteriztion. For the ellipse S: x y + 1,, S is the ellipse x y + 1 where 1 + nd With prmeters α nd u stisfying. sin α, 0 <α π, α u π α, we define three circles P, Q, R 1 with centers nd rdii given elow, nd verify tht their points of tngency with S re s in the rightmost column see Figure 1. P Center Rdius Point of tngency with S cos u α, 0 sin u α cosu α 1, ± Q cos u + α, 0 sin u + α R 1 cos u, 1 cos u sinu cosu+α, ± 1 cos u, 1 cos u cosu α cosu+α Figure 1. Exmple of circles tngent to n ellipse

A note on conic sections nd tngent circles 3.. Verifiction. nd re trivil. c For P or Q, wehve Δx + 1 cos u ± α +cos u ± α sin u ± α Δz. For R 1,wehve Δx + cos cos u ± α+ 1 cos u ± α α cos α Δx + 1 cos u cos α + 1 cos u cos α 1 cos u cos α 1 cos u sin u Δz. d The slope of the tngent of S t the point x, y is x, s cn e shown with y sic clculus. For P or Q, tking the point of tngency with positive y-coordinte, we hve 1 cosu±α 1 cosu±α cos u ± α cos u ± α y x. For R 1,wehve Δx cos u 1 cos u 1 cos u cos u y x. e The distnce etween the proposed centers of P nd Q is cos u α cos u + α sin u sin α sin u sin u α+sinu + α, which equls the sum of the proposed rdii.

J. K. Huglnd If we insted consider either P or Q together with R 1, the expressions for Δx, nd Δz re s follows: Δx cos u ± α 1 + cos u cos u sin u sin α 1 + cos u cos u cos α +sin u sin α sinucos u sin α + cos u cos α + 1 + cos u sin u cos u sin α + 1 cos u cos α + + 3 Δz sin u ± α+ sin u sin u ± cos u sin α+ sin u sin u cos α + cos u sin α ± sin u cos u sin α sin u + 3 sin u + sin u ± sin u cos u sin α., 1 cos u cos, α The reder cn verify tht when we insert these expressions into 1 the terms with ± or cncel out, while collecting the remining terms yields Ξsin u +Ξcos u Ξ, where Ξ 5 + + +, which of course lso implies cncelltion. 3. Prol 3.1. Prmeteriztion. For the prol S: y cx, S is the prol x y c + 1 3 8c.

A note on conic sections nd tngent circles 5 With prmeter u 1 c, we define the circles P, Q, R 1 in the tle elow, nd verify tht the points of tngency with S re s given in the rightmost column see Figure. P Q R 1 3 Center Rdius Point of tngency with S 0,cu u + 1 c u 1 c ± u u c,cu u 0,cu + u + 1 c u + 1 c ± u + u c,cu + u u 1,cu 1 u c 8c u 1,cu 1 c c Figure. Exmple of circles tngent to prol 3.. Verifiction. Trivil, since ll proposed points of tngency hve the form ± m, cm. With x 3 u 1,wehve c x y c + 1 3 8c c u 1 c + 1 8c cu 1 8c s required. c For P or Q, wehve For R 1,wehve Δx + Δx + 1 16 u ± u 1 + u ± 1 Δz c c c. u 1 1 u c + Δz. 8c d The slope of the tngent of S t the point m, cm is c m, nd so the slope of the line segment from the center of the corresponding circle to the point

6 J. K. Huglnd of tngency must e 1 c.forp nd Q nd tking the point of tngency with m positive x-coordinte, we hve trivilly Δx 1 c 1 m c m, nd for R 1 we hve lmost eqully trivilly Δx 1 8c 1 1 m c m. e The distnce etween the proposed centers of P nd Q is u, which is equl to the sum of their rdii. If we insted consider P or Q long with R 1,wehve Δx + 9 u 1 16 c + u ± 5 8c. Hyperol 5 16 u ± 5u c + 1 c.1. Prmeteriztion. For the hyperol S: x y 1. 5 u ± 1 Δz. c S is the union of two hyperols S 1 nd S. The first component of S is the hyperol S 1 x y 1, where 1 + +, + +. With prmeter u, we define the circles P, Q, R 1 P Q Center + + R 1 u + + u + u + u + + u +, u +, 0, 0 Rdius + u + u + + u + + u + + + nd verify tht the points of tngency with S re s follows see Figure 3. Point of tngency with S P + u + u, ± + u + u Q + u + + u, ± + u + + u R 1 u +, u + + u

A note on conic sections nd tngent circles 7 Figure 3. Exmple of circles tngent to hyperol with center of R 1 on S 1 The second component of S is the hyperol S x y 1, where P Q + +, 1 + +. With prmeter u Center 0, + 0, + R 1 u + +, we define the circles P, Q, R 1 + u u + u + u +, u + Rdius + u + u + u + + u + + nd verify tht the points of tngency with S re s follows see Figure. Point of tngency with S P ± + u u +, + u u Q ± + u + u +, + u + u R 1 u + u, + + u

8 J. K. Huglnd Figure. Exmple of circles tngent to hyperol with center of R 1 on S.. Verifiction. For the first component of S, oth P nd Q hve proposed points of tngency with S of the form m, ± m. For the second component, they hve proposed points of tngency of the form ± m +,m. In oth cses, it is cler tht x y 1is stisfied. For R1, we get in oth cses x y + + + 1. In similr fshion, we hve x y + + x y + + + 1, + 1. c For P nd Q with the first component S 1, strting with the proposed center nd points of tngency with S for P or Q, wehve

A note on conic sections nd tngent circles 9 Δx + + u + ± u + + u + ± u + + u + + u ± u + u + + u ± + u + Δz. For R 1,wehve Δx + u + + + u + 1 + + u + + + 1 + + u + u 1 u + + Δz. + + u + + u + + For P nd Q with the second component S, we hve similrly Δx + + u ± u + + + u ± u + + u + u ± u + u + + u ± + u Δz, nd for R 1 we hve Δx + u + + + u + + u + + + u + u 1 1 + + u + + u + + Δz. + 1 + + + u +

10 J. K. Huglnd d The slope of the tngent of S t the point x, y is x, nd so the slope of y the line segment from the center of the corresponding circle to its point of tngency x, y with S must e y.forp or Q for the verifiction for the first component x of S, tking the point of tngency with positive y-coordinte, we hve Δx For R 1,wehve Δx u u + + u + ± u y + u + ± u x. + + u u + + + y x. For the verifiction for the second component of S, tking the point of tngency with positive x-coordinte for P or Q, we hve similrly Δx nd for R 1,wehve Δx u u + + u ± u + u ± u + + + u u + + + y x, y x. e Verifying the condition for P nd Q is rther trivil for oth components of S.ForP or Q long with R 1, with the first component, we hve Δx + 3 1 + + u + + ± + u + 3 + + + 3 + + + u + + + u + ± + 3 + + u + u +,

A note on conic sections nd tngent circles 11 Δz + + + u + + + + u + u u + + ± u + + + u + u + + u +, + u ± + u + + + + u + + + + u + + + nd the reder cn verify tht 1 is stisfied. Likewise, for the second component of S,wehve, Δx Δz + + u + + + + + + 3 + u + +, + 3 + u + ± u + + 3 + + + 3 + + + u + ± u + 5 + u + u + u + 3 u u + + u + u + ± + u +, 6 + + u +3 + u + u + + + u + u + + + + u ± u + u 3 + + + +, for which 1 gin is stisfied.

1 J. K. Huglnd 5. Conclusion The prmeteriztions cover ll possile scenrios, nd Theorem 1 is thus proved. Strictly speking, the set of points where R 1 cn hve its center is in generl not the entire conic section, ut suset s implied y the conditions tht we hve included for the prmeters. References [1] H. Fukgw nd D. Pedoe, Jpnese Temple Geometry Prolems, Chrles Bge Reserch Centre, Winnipeg, 1989. [] H. Fukgw nd J. F. Rigy, Trditionl Jpnese Mthemtics Prolems of the 18th nd 19th Centuries, SCT Press, Singpore, 00. [3] H. Fukgw nd T. Rothmn, Scred Mthemtics, Jpnese Temple Geometry, Princeton University Press, 008. [] T. Rothmn, Jpnese Temple Geometry, Scientific Americn, 78, My 1998, 85 91. Jn Kristin Huglnd: Arnstein Arneergs vei 30, Leilighet 308, 1366 Lysker, Norwy E-mil ddress: dmin@neutreeko.net