Module 16 : Line Integrals, Conservative fields Green's Theorem and applications. Lecture 48 : Green's Theorem [Section 48.

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Module 16 : Line Integrals, Conservative fields Green's Theorem and applications Lecture 48 : Green's Theorem [Section 48.1] Objectives In this section you will learn the following : Green's theorem which connects the line integral with the double integral. 48.1 Green's Theorem for simple domains : We analyze next the relation between the line integral and the double integral. 48.1.1 Definition: Consider a region in the plane defined by Figure: Caption text. where are continuously differentiable functions. Such a region is called a vertically simple region or a type- I region in Let denote the boundary of this domain, being traversed in the counter-clockwise direction (i.e., as you move along the boundary, the domain lies to the left). Then the boundary can be broken into parts

where and are the vertical line segments, is the graph and is the graph 48.1.2 Theorem (Green's theorem for simple domains): Let be continuously-differentiable scalar fields, where. Let be a vertically simple region in which can be represented as where both the function are continuously differentiable. Further, let be such that and its boundary are inside. Then where is given the counter-clockwise orientation. Let us write where the curves and have, respectively, the following parameterizations Then ----------(47) A similar calculation will give us

----------(48) From and we have 48.1.3 Note : Arguments similar to the above theorem will tell us that conclusion of Green's theorem also holds for regions type : of the where are continuously differentiable. Such regions are called horizontally simple regions or type-ii regions in 48.1.4 Example : Let us verify Green's theorem for scalar field where and the region is given by The boundary of is the unit circle. Figure 196. with boundary circle A parameterization of is Thus,

And Hence 48.1.5 Extending Green's theorem beyond simple regions : In theorem we proved green's theorem for simple domains (horizontally simple or vertically simple). Though a complete and rigorous argument is beyond the scope of these notes, we show how Green's theorem extends to more general regions as follows: 1. Let be the region enclosed by a simple closed curve. Then Figure: Splitting a region into simple regions The region can be subdivided into finite number of simple regions by line segments parallel to the axes. As in

figure above, is divided into three non overlapping regions and. For each region, Green's theorem holds, and we have where is the boundary of the region, traversed counter clockwise direction. Since where and are the line segments joining the first point with the second point. Thus, adding the above equations for, we have This says that Green's theorem holds for the region. 2. As a particular case of (i) we get that Green's theorems holds for regions as shown in the figure below : Figure: Simple region Joining any two or more such regions, we get Green's theorem for regions of the type:

Figure: Joining simple regions For example, for the annular region, the Green's theorem states: Note that is oriented counter-clockwise while is clockwise. Thus, Green's theorem extends to domains with finite number of holes also: Figure: Splitting a region into simple regions 48.1.6 Example: Consider the line integral of the vector field, over any piecewise smoothly closed curve that does not include the origin. Let be oriented counter-clockwise. Figure: Piecewise smooth curve not including origin Then, by Green's theorem, if is the region enclosed,

Let us also compute the line integral of over a piecewise smooth, simple closed curve that includes origin, oriented counter clockwise. Figure: Piecewise closed curve including origin Since does not intersect the origins, we can find some such that the circle lies completely inside. We orient clockwise, and consider the region enclosed by and. Thus, by Green's theorem, we have Hence 48.1.6 Some other forms of Green's Theorem: 1. Flux form of Green's theorem: Consider a simple closed curve oriented counter-clockwise. Let be the region enclosed by it. Let the arc-

length parameterizations for be Then, the unit tangent vector to at a point is given by and the unit-normal, pointing outward to the region, is given by Let be a continuously differentiable vector-field in a domain which includes both and. Then, by Green's theorem ----------(49) If we write then, ----------(50) and From, and, we have ----------(51) Thus, the flux of across a simple closed curve is the double integral of the divergence of over the region enclosed by This is called the flux-form of Green's theorem. 2. Work form of Green's Theorem Consider a force field and representing ----------(52) Also on the other hand

----------(53) Thus, by Green's theorem, using (52), (53) we have The integral on the left represents the work done in moving against a force field along the curve This is called the work from of the Green's theorem. This is also called the Curl form of the Green's theorem Practice Exercises 1. Verify Green's theorem in each of the following cases: 1. 2. where, is the region inside the triangle with vertices 2. Verify Green's theorem for the region that is inside the square with vertices and but is outside the rectangle with vertices and and is the boundary of this region. Answer: Both integral are equal to 3. Show that Green's theorem is applicable for the region, the inside of the ellipse and out side the circle, and hence compute where is the boundary of the region. Answer: 4. Let be differentiable function of a single variable and is a piecewise smooth simple closed path. Show that 5. Verify the flux form and the curl form of the Green's theorem for the following: 1., and is the region bounded by the circle 2., and is the region bounded by the lines Answer: (i) (ii) Recap: In this section you have learnt the following

Green's theorem which connects the line integral with the double integral. [Section 48.2] Objectives In this section you will learn the following : Computations of line integrals and area enclosed by a curve. Sufficient condition for conservativeness of a vector field. Integral formulae for the laplacian. 48.2 Applications of Green's Theorem: 48.2.1 Evaluations of line-integrals : Green's theorems help us to evaluate certain line integrals by evaluating the corresponding double integral. For example, we want to compute the line integral where is the boundary of the square Using Green's theorem, we can convert this to a double integrals. Let, the boundary of the region be given anticlockwise orientation. Figure: Design with oriented boundary Then, by Green's theorem,

. 48.2.2 Area enclosed by a curve : Let be a simple closed curve in enclosing a region. Consider the vector field where in. Then, by Green's theorem, ----------(54) Similarly, if and in, we have by Green's theorem, ----------(55) From and, we have Thus, the area of the region is given by In case have parameterizations: Then, the area enclosed by is given by If has polar representation we get 48.2.3 Sufficient condition for a vector-field to be conservative : Suppose is a simply-connected open set in and is a vector field,

such that ----------(56) In this case, we claim that there exists a function such that In other words, a planer-vector field in a simply connected region is conservative if (56) is satisfied. In view of theorem, it is enough to show that the line integral for every simple closed curve in. This indeed happens:, first given a simle closed curve, as is simply conected, we can find a region such that is the boundary of. Then, by Green's theorem, Hence, is conservative. 48.2.4 Change of Variable formula in : As another application of the Green's theorem we can deduce the change of variables formula, as stated in theorem 42.1.2. Let be a transformation defined on an open simply connected subset of such that if, then have continuous partial derivatives, both are one-one onto and. Let be simply connected, with. Then, we claim that. Let us first prove it in the particular case when Similar arguments can be given for general case. Let be the boundary of and the boundary of. We observe that as if is oriented anticlockwise, then is also anticlockwise. Let

be a parameterizations of in the anticlockwise direction. Then Figure: Transframation T is a parameterizations of in the anticlockwise direction. Now by Green's theorem 48.2.5 Integral formulas for the Laplacian : Recall that the operator called the Laplacian operator, in the plane is defined by where is any scalar field having second order partial derivatives. Let us consider one such function and define the vector field We apply Green's theorem to to get

where is the unit normal to for the given orientation. Recalling that for a differentiable function, derivative of in the direction of, let us write Then, we have In the particular we have the following, ----------(57) ----------(58) Another such formula is obtained by considering a scalar field as above, and observing by Green's theorem we get ----------(59) Equations (57), (58) and (59) are called Green's identities. Scalar fields which satisfy the relation, are called harmonic functions. For a harmonic function, if on, then equation (59) gives

Hence In case is such that any two points can be connected by a path parallel to axes, this implies that is a constant scalar field. Thus, for a harmonic function, if its rate of change along the unit tangent direction to in zero, then is constant in the region enclosed by. Practice Exercises 1. Use Green's theorem to evaluate the integral where is the boundary of the region given by 1. is the square with vertices 2. is the square with vertices 3. is the disc of radius and center Answers: (i), (ii), (iii) 2. Find the area of the following regions using Green's theorem: 1. The area lying in the first quadrant of the cardioid 2. The region under one arch of the cycloid 3. The region bounded by the limaçon and the two axes. Answer: (i) (ii) (iii) 3. Compute the area enclosed by 1. the cardioid: r= a(1-2. the lemniscate: r Answer:

(i) (ii) 4. Let be a simple closed curve in the -plane enclosing a region. The polar moment of inertia of is defined to be Show that 5. Consider having continuous partial derivatives on the unit disc If on circle the boundary of Let. Using Green's theorem show that 6. Let be any closed curve in the plane. Show that 7. Using Green's identities, compute for the following: (ii) 1. 2. and is the triangle with vertices Answer: (i) Recap In this section you have learnt the following Computations of line integrals and area enclosed by a curve. Sufficient condition for conservativeness of a vector field. Integral formulae for the laplacian.