High energy neutrinos from curvature pions in magnetars

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High energy neutrinos from curvature pions in magnetars Tamás Herpay MTA ELTE, Statistical and Biological Physics Research Group Collaborators: Péter Mészáros, András Patkós, Soeb Razzaque

Motivation Neutrino physics plays an important role in astrophysics At very high energy, only the neutrinos reach the earth in their original form = Only neutrinos can provide us information about very high energy astrophysical processes Detecting these high energy neutrinos can give us a chance to test the different models for dark matter, supernovas, gamma ray burst, neutron stars, magnetars... We investigated the pion (subsequent neutrino) radiation by protons accelerated in very strong electromagnetic field of magnetars. 1

Overview The possible sources of neutrino flux detected on earth Curvature and synchrotron pion radiation in electromagnetic field by protons Different models for the electromagnetic field of magnatars Consideration of the back reaction force by pion and photon radiation in the equation of motion of protons The solution of the equation of motion and the intensity of the corresponding pion(neutrino) radiation Conclusion 2

Neutrinos sources and energy scales At low energy: Big bang Radioactive decays Reactors, fusion (Sun) 10 3 ev 10 3 ev 10 6 ev At high energy: Cosmic rays in the atmosphere 10 9 ev?? WIMP annihilation???? Active Galactic Nuclei (AGN) 10 12 ev Magnetars 10 12 ev Gamma Ray Burst (GRB) 10 15 ev KM3NET ICECUBE ICECUBE detector can detect neutrinos up to 10 17 ev 3

Processes of neutrino emission Charged pion decays: π ± µ ± + ν µ ( ν µ ), µ ± e ± + ν e ( ν e ) + ν µ (ν µ ) Inverse β decay in magnetic field (B): p + B n + e + + ν e Proton pion processes: photomeson interaction: proton neutron collision: in magnetic field synchrotron type radiation: p + γ + n + π + p + n n + n + π + p + B p + π 0 + B n + π + + B (p + γ + B) 4

Pion emission in magnetic field p + B { p + π 0 + B [1] n + π + + B [2] Photon radiation: p + B p + γ + B Pion nucleon interaction: =g ρ 5N π, source: ρ 5N = N τγ 5 N H Nπ I proton photon interaction: H pγ I =ej µa µ, source:j µ = pγ µ p Semiclassical treatment of the synchrotron radiation in homogenous magnetic field: The constant source of photon radiation is the j µ current of protons = analogous description can be used for the pion radiation. The photon radiation is dominant in week magnetic field, however at very high B the pions dominates the radiation. Especially, B can reach 10 15 Gauss on the surface of magnetars. [1] V. L. Ginzburg and G. F. Zharkov (1964); A. Tokuhisa and T. Kajino (1999) [2] G. F. Zharkov (1965); T. Herpay and A. Patkós (2007) 5

Synchrotron type pion/photon radiation 1e+25 1e+20 1e+15 P [MeV/s] 1e+10 100000 π + π 0 γ 1 1e-05 1e-05 0.0001 0.001 0.01 0.1 1 10 100 1000 xi=b/b 0 γ χ = B B 0 γ, γ = E p m p, B 0 = 1.5 10 20 G = π + radiation dominates if Bγ 10 18 G = Large magnetic and accelerating field is neccessary 6

Magnetars Nuetron stars with strong magnetic field magnetars Very compact objects: mass: M 1.4 solar mass radius: R 10 km strong magnetic field: B 10 12 15 G fast rotation: P = 2π/Ω 1 100 ms Casey Reed, Pennstate University Strong gamma and X-ray emission = magnetars are loosing their rotation energy very quickly (about 10000 years). Fast rotation and strong magnetic field = strong electric field = protons/ions can reach very high energy in the magnetosphere 7

The standard model of the magnetosphere Assumptions: ÓÔ Ò Ð Ð Ò Magnetic dipole field Ω In our case the rotation axis and dipol vector are anti parelell µ Ö Ø Ð Ð Ò J + The surface is perfect conductor Consequences: The Lorentz force acts on the free surface charges: F v/c B θ p B r = 0 ÐÓ Ð Ð Ò ρ < 0 J In the corotating reference frame, E θ = E θ + v φ B r /c = 0 R P. Goldrich, W. H. Julian (1969) R L = Ω/c Laplace eq. plus boundary conditions = electric quadrupole field The corotating reference frame is limited by the speed of light (c), at the so called light cylinder R L =Ω/c = closed field region 8

Models of the magnetosphere Space charge evolves in the closed field lines region, which corotating with the magnetar and screens the electric field In the open field region the quadrupole electric field almost paralallel with the magnetic field lines E R = RΩ c B 0 (at the surface) and so the protons/ions are accelerated from the surface This simple model doesn t take into account the back reaction of current and the interactions of the accelerated charged particles. Modern models make attempt to the selfconsistent description: (1) vacuum gap model = acceleration near the light cylinder (2) space charge gap model = acceleration near the surface Ω µ θ p R ÓÔ Ò Ð Ð Ò J + Ö Ø Ð Ð Ò B r = 0 ÐÓ Ð Ð Ò J ρ < 0 R L = Ω/c [1] Medin, Lai 2008; [2] Harding, Muslimov 2002; 9

Curvature radiation The common properties of magnetar models: B E The magnitude of the electric field: = RΩ c B The parallel component of the electric field to the magnetic field is much larger than the perpendicular component, γ γ E B 0 and E E Simple physical picture: p decreasing quickly due to synchrtotron radiation = acceleration along the B lines = the main part of the high enegry radiation corresponds to the curvature of the B field. γ = p mc, γ = p mc 10

Synchrotron vs. curvature radiation Synchrotron radiation ( v B): Curvature radiation: P γ = 2 3 e2 m 2 ( ebγ m 2 ) 2 2 3 e2 m 2 χ 2 P cγ = 2 3 e2 m 2 ( γ 2 mr c ) 2, Rc : curv.radius In both cases the radiation arises from the curvature of trajajectory. The effect of the magnetic field is only the determination of the curvature radius, R = mγ eb One can define the curvature χ parameter: χ = ebγ m 2 χ c = γ2 mr c The above explanation remains true for the π 0 and π + radiation by protons (V. Berezinsky, 1987) 11

Curvature radiation as a back reaction force Lorentz force = trajectory of protons without radiation photon, π 0 and π + rdiadiation = decreasing the energy of protons: P = P i = de i dt = de p dt, i = photon, π0, π + i i = assuming that the radiation is a dissipative force in the e.o.m., γ = e mc ( E + ) 1 γ B 1 + γ 2 P γ2 + 1 γ mc 2 γ γ, γ = p mc, B( r): dipole field; E( r): SCLF electric field (Harding, 2002) E( r) has both parallel and perpendicular component to the magnetic field, and P depends on the curvature radius R c and γ. 12

Equation of motion χ = γ2 mr c P depends on χ and it depends on the curvature radius which can be written as 1 R c = 1 + γ 2 γ 3 γ γ = 1 + γ 2 γ 3 γ 2 γ 2 ( γ γ) 2 and so P P[ γ, χ( γ, γ)] = both side of the e.o.m. depend on γ Fortunately γ appears only in the γ γ combination, ( which can ) be calculated directly from the e.o.m.: γ γ E + 1+ γ 1 2 γ B γ χ = e m 3 1 γ γ ( 1 + γ 2 E( r) + γ B( r) ) and finally P depends on only γ: P =P ph +P π 0+P π + P[ γ, χ( γ)] 13

The equations r = The six coupled differential equations: γ 1 + γ 2, γ = e m ( E( r) + ) 1 γ B( r) 1 + γ 2 P ( γ, χ( γ, r)) γ2 + 1 γ m γ γ The expressions of the radiation intensity for χ < 1: [ P photon = 2 ] 3 3 em2 χ 2, P π 0 = g 2 m π mm π χ exp χ m P π + = g 2 m 2(m/m π) 2 (2 [ 2 m π /m) 3 [ ] 4 χ exp 24 1 + 2m/mπ χ m ( mπ ) 2 ] 14

The path of the protons The electric field depends on R 0, M, B 0, P 2π/Ω. 5 R 0 =10 km 4.5 4 M =1.4 M 3.5 B 0 [G] P [ms] 10 15 1 10 15 10 10 14 1 z/r 0 3 2.5 2 1.5 1 0.5 magnetic field lines particle paths y/r 0 0 1 2 3 4 5 ρ/r 0 The path of the proton for different initial angle (10 15 G, 1ms) x/r 0 15

The solution 1e+10 1e+10 1e+08 10 15 G, 1ms 10 15 G,10ms 10 14 G, 1ms 1e+08 1e+06 1e+06 E p /m p 1e+04 1e+04 E p /m p 1e+02 1e+00 (a) (b) 1e+02 1e-00 1e-02 1e+20 1e-02 1e+20 de/dt [Mev/s] 1e+10 1e+00 1e-10 1e-20 10 15 G, 1ms:photon π+ π 0 (c) 10 15 G,10ms: photon π+ 10 14 G, 1ms: photon π+ (d) 1e+10 1e+00 1e-10 1e-20 de/dt [Mev/s] 1e-14 1e-12 1e-10 1e-08 1e-06 1e-04 1e-14 1e-12 1e-10 1e-08 1e-06 1e-04 t[s] t[s] The energy of the protons (a,b); The intensity of different radiations (c,d) 16

Ions mass: Am p ; charge: Ze. Ion acceleration m ma and e Ze replacement in the Lorentz force Assuming that the radiation intensity for the ions is the incoherent sums of individual nucleonic contribution: P π 0 AP π 0 because both protons and neutrons can emit π 0 with the same probaility P π + AP π + because the radiation of π + by protons and radiation of π by neutorns having the same probability P ph ZP ph The solution provide that ions can reach the same order of energy as the protons. However, the transverse momentum transfer from individual nucleons to photons and pions (k 100 MeV) larger than the average maximum energy of the nucleons 10 MeV 17

Detected neutrino flux From magnetar models the outflow rate of protons: Ṅ B 0Ω 2 R 3 0 ec = 1.4 10 33B 15R 3 6 P 2 1 s, where B 15 = B 0 /(10 15 G) and R 6 = R 0 /(10 km) In case of B = 10 15 G and P = 1 ms each proton decays into π +, and each pions produce π + µ + + ν µ, µ + e + + ν e + ν µ two neutrino ν µ, ν e and one anti neutrino ν µ. And on the earth, the corresponding neutrino number is Ṅ ν = 7.3 10 5B 15R6 3 1 P 2 D10 2 year in a 1 km 2 detector, where D 10 = D/(10kpc) is the distance of the magnetar. 18

Detected neutrino energy Typical pion energy radiated by protons E π E p /4 0.25 10 9 GeV Taking into account the energy loss of pions and muons in the magnetosphere, the energy of the produced neutrinos E νµ 33 TeV and E νµ,ν e 3.3 TeV and using the effectivity of the ICECUBE detector P ν µ 1.3 10 6 E ν /TeV one can obtain the detected neutrino flux on earth: Ṅ ν { 6.3 10 5 1 year for ν µ 9.5 10 4 1 year for ν e, ν µ from a magnetar (B = 10 15 G; P = 1 ms) at 10 kparsec distance. These values are too large comparing the experiments. 19

Conclusion The charged pion (and subsequent neutrino) radiation comparable with photon radiation only in magnetars which have B 10 15 G and P 1 ms But in this case the corresponding neutrino flux on the earth is too large comparing to the experiments. These magnetars don t exist in our galaxy or their rotation axis doesn t point to the earth. Publications: T. Herpay, A. Patkós, Jphys. G (2007) T. Herpay, S. Razzaque, A. Patkós, P. Mészáros, JCAP (2008) 20