aloalkanes AS3 1 ALOALKANES Structure ontain the functional group X where X is a halogen (F,l, or I) Types aloalkanes halogen is attached to an aliphatic skeleton alkyl group aloarenes halogen is attached directly to a benzene (aromatic) ring aryl group lassification aloalkanes are classified according to what is attached to the X functional group. X X X methyl primary secondary tertiary 1 2 3 X Names Based on the original alkane skeleton with a prefix indicating halogens and their position. 3 2 2 l 1chloropropane 3 l 3 2chloropropane 2 ll 3 1,2dichloropropane 3 ( 3 ) 3 2bromo2methylpropane Q.1 Draw and name all the structural isomers of 3 6 2, 4 9 l and 5 11. Q.2 lassify the structural isomers of 4 9 l and 5 11 as 1, 2 or 3. Physical properties Boiling pts boiling point increases with mass for isomeric compounds the greater the degree of branching, the lower the boiling point Solubility haloalkanes are soluble in organic solvents but insoluble in water
2 AS3 aloalkanes NULEOPILI SUBSTITUTION REATIONS Theory halogens have a greater electronegativity than carbon a dipole is induced in the X bond and it becomes polar the carbon is thus open to attack by nucleophiles δ δ polarity in a bond Nucleophiles examples are O, N, N 3 and 2 O possess at least one LONE PAIR of electrons are attracted to the slightly positive (electron deficient) carbon Basic mechanism the nucleophile uses its lone pair to provide the electrons for a new bond the halogen is displaced as an ion as carbon can only have 8 electrons in its outer shell the result is substitution following attack by a nucleophile the mechanism is therefore known as NULEOPILI SUBSTITUTION Nu Nu Rate of reaction the rate of reaction depends on the strength of the X bond I... 238 kjmol 1... 276 kjmol 1 l... 338 kjmol 1 F... 484 kjmol 1 WEAKEST BOND EASIEST TO BREAK FASTEST REATION Advanced work This form of nucleophilic substitution is known as S N 2; it is a bimolecular process. An alternative method involves the initial breaking of the X bond to form a carbocation, or carbonium ion, (a unimolecular process S N 1 mechanism), which is then attacked by the nucleophile. S N 1 is favoured for tertiary haloalkanes where there is steric hindrance to the attack and a more stable tertiary, 3, carbocation intermediate is formed.
aloalkanes AS3 3 1. NaO Reagent Aqueous sodium (or potassium) hydroxide onditions Reflux in aqueous solution (SOLVENT IS IMPORTANT) Product Nucleophile Alcohol hydroxide ion (O ) Equation e.g. 2 5 (l) NaO (aq) > 2 5 O (l) Na (aq) O O WARNING It is important to quote the solvent when answering questions. Elimination takes place when ethanol is the solvent SEE LATER The reaction (and the one with water) is sometimes known as YDROLYSIS 2. KN Reagent Aqueous, alcoholic potassium (or sodium) cyanide onditions Reflux in aqueous, alcoholic solution Product Nitrile (cyanide) Nucleophile cyanide ion (N ) Equation 2 5 KN (aq/alc) > 2 5 N K N N Importance reaction is that it extends the carbon chain by one carbon atom The N group can then be converted to carboxylic acids or amines. ydrolysis 2 5 N 2 2 O > 2 5 OO N 3 Reduction 2 5 N 4[] > 2 5 2 N 2
4 AS3 aloalkanes 3. N 3 Reagent Aqueous, alcoholic ammonia onditions Product Reflux in aqueous, alcoholic solution under pressure Amine (or its salt due to a reaction with the acid produced) Nucleophile Ammonia (N 3 ) Equation 2 5 N 3 (aq / alc) > 2 5 N 2 N 3 (aq / alc) > N 4 2 5 2N 3 (aq / alc) > 2 5 N 2 N 4 N N N 2 Problem The amine produced is also a nucleophile (lone pair on the N) and can attack another molecule of haloalkane to produce a 2 amine. This in turn is a nucleophile and can react further producing a 3 amine and, eventually an ionic quarternary ammonium salt. 2 5 N 2 2 5 > ( 2 5 ) 2 N diethylamine, a 2 amine ( 2 5 ) 2 N 2 5 > ( 2 5 ) 3 N triethylamine, a 3 amine ( 2 5 ) 3 N 2 5 > ( 2 5 ) 4 N tetraethylammonium bromide, a 4 salt 4. 2 O A similar reaction to that with O takes place with water. It is slower as water is a poor nucleophile. Equation e.g. 2 5 (l) 2 O (l) > 2 5 O (l) (aq)
aloalkanes AS3 5 ELIMINATION REATIONS OF ALOALKANES Problem The products of reactions between haloalkanes and O are influenced by the solvent. Both mechanisms take place simultaneously but the choice of solvent favours one route. Solvent Product Action of O WATER ALOOL NULEOPILE SUBSTITUTION ALOOL ALKENE BASE ELIMINATION Reaction Reagent Alcoholic sodium (or potassium) hydroxide onditions Reflux in alcoholic solution Product Alkene Elimination Equation 3 7 NaO (alc) > 3 6 2 O Na O δ δ 3 O 3 2 the O ion acts as a base and picks up a proton the proton comes from a carbon atom next to the one bonded to the halogen the electron pair left moves to form a second bond between the carbon atoms the halogen is displaced overall there is ELIMINATION of. Q.5 What organic products are formed when concurrent substitution and elimantion takes place with 3 3? omplication The O removes a proton from a carbon atom adjacent the bearing the halogen. If there had been another carbon atom on the other side of the alogen bond, its hydrogen(s) would also be open to attack. If the haloalkane is unsymmetrical (e.g. 2bromobutane) a mixture of isomeric alkene products is obtained. Q.6 What organic products do you get with alcoholic NaO and 3 2 3? Explain your answers with a mechanism.