SKEMA JAWAPAN KERTAS 1 JUJ KIMIA SET D 11 C 21 A 31 D 41 C 2 C 12 B 22 D 32 C 42 A 3 C 13 B 23 C 33 A 43 B 4 C 14 B 24 D 34 A 44 B

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SKEMA JAWAPAN KERTAS JUJ KIMIA SET - 07 SKEMA PRAKTIS BESTARI JUJ KIMIA SET KERTAS, & D C A D 4 C C B D C 4 A C B C A 4 B 4 C 4 B 4 D 4 A 44 B 5 A 5 C 5 A 5 A 45 A 6 B 6 C 6 C 6 B 46 D 7 B 7 C 7 C 7 A 47 A 8 C 8 A 8 B 8 D 48 B 9 C 9 D 9 D 9 B 49 B 0 B 0 B 0 B 40 C 50 C 454 Set Hak Cipta JUJ Pahang 07

KIMIA SET KERTAS, & MARKING SCHEME PAPER SET JUJ CHEMISTRY 07 Question No Scheme Sub (a) (i) smallest neutral particles (ii) (iii) electron (iv). One similarity. one different Sample answer :. Same number of proton /proton number // same number of electron. Different number of neutron / nucleon number (b) (i) 70 / 70 o C (ii) (iii). Heat energy absorbed. is used to overcome the forces of attraction between particles Correct arrangement (at least x with same size & do not overlapping each other) Total s 9 Question No Scheme Sub (a) (i) The chemical formula that shows the simplest ratio of atoms of each element in the compound (ii) C H 4 O (b). value of n. Molecular formula Sample answer : (CH ) n = 4 // (+ ())n = 4 // 4n = 4 // n = Molecular formula = C H 6 (c) (i) Mass (ii) 64 + (4)+ 6(6) // 88 (iii) Correct value with unit Answer :. X 88 g // 5.6 g (iv). Correct formula of reactants and product. balanced Answer : Cu(NO ) CuO + 4NO + O 454 Set Hak Cipta JUJ Pahang 07 Total s 9

KIMIA SET KERTAS, & Question No scheme Sub (a) (i) Chlorine/Cl (ii) Aluminium (iii) Argon atom has achieved stable octet electron arrangement (b) (i) Cl (ii) The forces of attraction between nucleus and electron in Cl atoms is stronger than Na atom. (c) (i) Ionic bond (ii) + - Na Cl (iii).correct number of ion and nucleus is labelled.correct electron arrangement and charged. Soluble in water//. High melting and boiling point//. Conduct electricity in aqueous and molten state + Any two Total s 0 Question No scheme Sub 4 (a) (i) Silicon dioxide / silica (ii) stabiliser /emulsifier (iii) Flavouring agent//thickening agent//colouring agent (iv) Analgesic // paracetamol (b) (i) N +H NH. Correct formula of reactants and products. Balanced equation (ii). Type of fertilizer. % of N in urea. % of N in ammonium sulphate 4. Conclusion Answer: Urea. % of N in urea %of N in ammonium sulphate =(8/60) x00% =(8/) x 00% =46.67% =.% + 4 % of nitrogen atom by mass for urea is higher than ammonium sulphate Total s 0 454 Set Hak Cipta JUJ Pahang 07

KIMIA SET KERTAS, & Question No Scheme 5 (a) (i) Increase of hydrogen gas per unit time // decrease of mass of zinc per unit time (b) (i). draw the triangle. calculation Sub 4.5-9 cm // 4.5 cm // 0.4 cm s - 0-60 s 60 s (ii) 4-6 cm s - // 5 cm s - // 0.5 cm s - 0-60 60 (iii) Because the concentration of acid decrease with time (c) (i) Volume of gas / cm Set II Set I Time / s (ii). size of zinc is smaller. remain the volume and concentration of hydrochloric acid. (d) (i) Put 5 g/a packet of fine sugar in hot water and cold water in two cups. Sugar in hot water dissolve faster. (ii). temperature higher in hot water. water particles has higher kinetic energy Total s Question No Scheme Sub 6(a) (i) Na + -, NO, H +, OH - (accept name of ions) (ii). hydrogen ions (iii). put glowing wooden splinter into a test tube. The wooden splinter lights up (iv). Suggest the suitable electrode (can infer from diagram). functional diagram. correct label : Anode : silver electrode ; Cathode : iron spoon Electrolyte : silver nitrate solution Iron spoon silver Silver nitrate solution 454 Set Hak Cipta JUJ Pahang 07 4

KIMIA SET KERTAS, & Question No (b) (i). Anode : Zn Zn + + e. Cathode : Cu + + e Cu Scheme Sub (iii). Change copper electrode to silver electrode // change zinc electrode to magnesium electrode// any suitaible pair of electrodes. Reason : Distance between Ag and Zinc / Mg and Cu in electrochemical series is further Total s Question No 7 (a) (i). structural formula. name Scheme Sub + Butan --ol -methylpropan--ol + * *Any two isomer (ii). Reaction I = esterification X Y z Functional group // Carbon-carbon double bond // Carboxyl group // carboxylate group 454 Set Hak Cipta JUJ Pahang 07 5 Homologous series Alkene Carboxylic acid ester -methylpropan--ol name But--ene Butanoic acid Butyl etanoate ++ ++ ++ 4 0

KIMIA SET KERTAS, & Question No (b) Scheme. Correct formula of reactants and product. balanced Sub C H 8 + 5O CO + 4H O & 4. Calculation Propene % of carbon () x 00 4 = 85.7% Propane () x 00 44 = 8.8% + 5. % of carbon atom by mass in propene is higher than propane. 6. Propene produces more soot than propane 6 Total s 0 Question No scheme Sub 8 (a). V = sodium carbonate. W= copper(ii) sulphate. X = nitric acid 4. Y = copper(ii) oxide 5. Z= Carbon dioxide 6. Double decomposition reaction // precipitation reaction Correct formula of reactants + 7 & 8. Reaction I : Na CO + CuSO 4 CuCO + Na SO 4 9& 0. Reaction II : CuCO + HNO Cu(NO ) + CO +H O (b) Compare and contrast : Similarities :. Both experiment produce black residue ++. Both experiment released gas when heated Differences:. Exp I produced colourless gas and Exp II produced brown gas 4. Exp turns the limewater chalky and Exp II turns moist blue litmus paper to red * Choose any 4. mole 5. ratio mole 6. correct answer with unit Answer : Mol = 6./4 // 0.05 Ratio : mol CuCO : mol CO 0.05 mol CuCO : 0.05 mol CO Answer : 0.05 x 4 dm //. dm 0 6 454 Set Hak Cipta JUJ Pahang 07 6

KIMIA SET KERTAS, & Question No scheme Sub (c).egg shells contain calcium carbonate. Calcium carbonate can react with acid. Calcium carbonate can dissolved in acid 4. Egg shell becomes soft//easier to insert in the bottle 4 Total s 0 Question scheme No 9 (a) Elephant Toothpaste Cold Pack Types Exothermic Endothermic of reaction Energy profile diagram Sub + Total energy content -Correct level and label energy -correct equation & H Total energy content of the reactants is higher than products (b) (i). State solution A,. solution B. precipitate D (can infer from procedure) 4-9. procedure 0. data -. calculation Sample answer :. Solution A = sodium chloride solution. solution B silver nitrate solution,. Precipitate D = silver chloride -Correct level and label energy -correct equation & H Total energy content of the products is higher than reactants Procedure : 4. Measure [0 00 cm ] of sodium chloride [any suitable solution] [0.5.0 moldm - ] solution and pour the solution into a plastic/polystryrene cup 5.Measure [0 00 cm ] of silver nitrate [any suitable solution] [0.5.0 moldm - ] solution and pour the solution into another plastic/polystryrene cup 6. record initial temperature for both solutions + + + 8 454 Set Hak Cipta JUJ Pahang 07 7

KIMIA SET KERTAS, & Question No scheme 7. pour sodium chloride solution quickly into the silver nitrate solution 8.stir the mixture 9. record the highest temperature reached Sub 0. Initial temperature of sodium chloride solution = T o C Initial temperature of silver nitrate solution = T o C Average Initial temperature = (T+ T)/ = Ta o C Highest temperature = Tb o C. heat given out = mc = 00 x 4. x (Tb Ta) 000 = w kj. number of mol = 50 x /000 = 0.05. Heat of precipitation = - w/0.05 = -X kjmol - max Total s 0 Question Answer Sub 0 (a)(i). suitable metal R : Zn/Mg s Types of reaction Half equation Zn/Mg CuSO 4. oxidation. reduction 4. Zn Zn + + e 5. Cu + + e Cu + + (a)(ii) 6. Name the ion present in the colourless solution = copper(ii) ions Change in oxidation number Zn/Mg CuSO 4. 0 +. + 0 Role. Reducing agent 4. Oxidizing agent (b) Sample answer :. Metal : Zn/Al Procedure :. Clean Zn/Al strip and iron nail with sand paper. Coil Zn/Al strip around the iron nail and put in a test tube 4. Put the iron nail only into another test tube. 5. Pour the hot agar-agar/jelly solution that has been mixed with potassium hexacyanoferrate(iii) and phenolphthalein indicator until the iron nail immersed into both test tube. 6 + + 4 454 Set Hak Cipta JUJ Pahang 07 8

KIMIA SET KERTAS, & Question Answer Sub 6. Leave the test tubes aside for a few days. s 7. Observation Pair of metal Zn/Al and iron nail Iron nail Observation pink spot form Blue spot form Half equation for oxidation of metals 8. Test tube I : Zn Zn + + e 9. Test Tube II : Fe Fe + + e 0. Conclusion When a more electropositive metal is in contact with iron, the metal inhibits rusting // iron does not rust when in contact with a more electropositive metal 0 Total s 0 END OF MARKING SCHEME PAPER 454 Set Hak Cipta JUJ Pahang 07 9

KIMIA SET KERTAS, & PERATURAN PEMARKAHAN KIMIA KERTAS JUJ SET 07 Able to state the colour change correctly (a) Answer: Pink colour change to colourless Able to state the colour change less correctly Purple to colourless Able to state an idea of colour Sample Answer: Pink // Colourless// Purple Able to record all burette readings accurately to decimal places Answer: (b) Titration Initial reading (cm ) Final reading (cm ) I 0.00 6.00 II 0.50 4.50 III 5.50 0.50 Able to record all the burette readings correctly to decimal places or able to record at least 4 reading correctly // uniform decimal places Able to record at least burette reading correctly without decimal places 454 Set Hak Cipta JUJ Pahang 07 0

KIMIA SET KERTAS, & Able to consruct a table that contains the following information.. Hading in the table : Set, Initil reading/cm, Final reading/cm, Volume of acid/cm. Transfer all the burette readings from (b) correctly. With unit at the heading (c) Titration Initil reading/cm Bacaan awal/cm Final reading/cm Bacaan akhir/cm Volume of acid/cm Isipadu asid/cm I 0.00 6.00 6.00 II 0.50 4.50 4.00 III 5.50 0.50 5.00 Able to construct a table less correctly Able to construct a table that contains the following information. Headings in the table : suitable heading. column with heading without data/ column only Initial reading Final reading 454 Set Hak Cipta JUJ Pahang 07

KIMIA SET KERTAS, & Able to calculate the average volume and concentration of hydrochloric acid with unit correctly (d) Answer: Average volume of hydrochloric acid = 6.00 + 4.00 + 5.00 ---------------------------- = 5.00 cm --- p Concentration of hydrochloric acid M HCl V HCl = M NaOH V NaOH M HCl X 5.00 =.0 X 50.00 ---- p // 5.00 M HCl = 50.00 M HCl = 50.00 5.00 =.0 mol dm - ---- p Able to calculate the average volume and concentration of hydrochloric acid correctly without unit Able to calculate volume of acid OR concentration of acid correctly Able to classify all the acids into strong and weak acid correctly Strong acids Asid kuat Weak acids Asid lemah (e) Sulfuric acid Nitric acid Citric acid Ethanoic acid Able to classify at least acids correctly Able to classify at least acids correctly/reverse 454 Set Hak Cipta JUJ Pahang 07

KIMIA SET KERTAS, & Able to state all inferences correctly (a) Test tube A B C D Inference Iron nail does not rust //Fe + does not present Iron nail rust // Fe + Present / formed Iron nail does not rust // Fe + does not present Iron nail rust // Fe + Present / formed Able to state inferences correctly Able to state inferences correctly (b) Able to state the relationship between manipulated varible and responding variable with direction correctly When a more/less electropositive metal / higher/lower than iron in Electrochemical series is in contact with iron, iron (nail) does not rust/rust Able to state the hypothesis less correctly The rusting of iron is faster / slower, if a less / more electropositive metal is in contact with iron/fe Able to give an idea of hypothesis Iron rust when in contact with other metal // other metal affect the rusting of iron. Able to state all the variables correctly (c) Manipulated variable : Type / different electropositive metal Responding variable : Rusting // presence of blue sport Constant variable : Type of iron nail // iron //medium in which the iron are kept Able to state any two of variables in this experiment correctly Able to state any two of variables in this experiment correctly 454 Set Hak Cipta JUJ Pahang 07

KIMIA SET KERTAS, & Able to give one operational definition of the experiment correctly with the following aspects: i) what you do ii) what you observe (d). when iron nail is coiled/in contact with a less electropositive metal (copper)/metal located below iron in electrochemical series. Rusting of iron is the formation of blue spot/colouration Able to state at least two criteria correctly Rusting of iron is the formation of blue spot /colouration or when iron nail is coiled/in contact with a less electropositive metal Able to state an idea of operational definition Blue spot/rusting occur Able to predict the observation correctly (e) Answer: The intensity of blue spot/colouration is very high//higher than test tube B. Able to predict the observation The intensity of blue spot/colouration is high Able to predict the observation Blue spot/colour 454 Set Hak Cipta JUJ Pahang 07 4

KIMIA SET KERTAS, & Able to state the relationship correctly between the time taken and the amount of rust form correctly. Time taken. Formation of rust. Comparison (f) The longer the time taken, the bigger/greater/larger the rust form //the longger the time taken, more rust is form //the rust form is greater/bigger/larger when the time taken is longer //the rust form in one week is more/bigger/greater/larger than one day Able to state the relationship between the time taken and the amount of rust form less correctly. Time taken/formation of rust The rust form is bigger/greater/larger //the form is directly proportional to the time taken Able to state any idea of relationship The rust is form/change//rust is small/less 454 Set Hak Cipta JUJ Pahang 07 5

KIMIA SET KERTAS, & Able to give the problem statement correctly How does the effectiveness of cleansing action of two different types of cleansing agent in hard water? (a) // What is the difference in effectiveness of cleansing action in hard water using soap and detergent? Able to give the problem statement less correctly How does different type of cleansing agent affect the effectiveness of cleansing action in hard water? // To investigate the effectiveness of different type of cleansing agent in hard water. Able to give an idea of statement of the problem To study the effectiveness of cleansing action in hard water Able to state all variables correctly (b) Manipulated variable :Types of cleansing agent//soap and detergent Responding variable : Effectiveness of cleansing agent//ability to remove the oily stains on cloth Constant variable : Hard water//cloth with oily stains//size of cloth Able to state any two variables correctly Able to state any one variable correctly 454 Set Hak Cipta JUJ Pahang 07 6

KIMIA SET KERTAS, & Able to state the relationship between the manipulated variable and the responding variable correctly Detergent is more effective than soap in hard water. // Detergent in hard water can remove the oily stains on cloth while soap cannot. Able to state the relationship between the manipulated variable and the responding variable incorrectly (c) Detergent is more effective // Soap is less effective // Detergent in hard water can remove the oily stains on cloth //soap cannot remove stain on cloth. Able to state an idea of hypothesis Able to give the completely list of the apparatus and materials Answer: Apparatus: Beakers, measuring cylinder, glass rod Material: Soap, detergent, [cleansing agent X dan cleansing agent Y], 0.5 - mol dm- magnesium sulphate solution/[sea water/hard water], pieces of cloth with oily stains. (d) Able to give the list of the apparatus and materials correctly but not completely Answer: Apparatus: Any containers, glass rod Material: Cleansing agent, cloth with oily stains. Able to give two materials and at least one apparatus Answer : Material: Soap solution / detergent, hard water [any container] No response or wrong response 0 454 Set Hak Cipta JUJ Pahang 07 7

KIMIA SET KERTAS, & Able to state all procedures correctly Sample answer : (e). Label beakers as A and B respectively. Fill all the beakers with [50-00 cm ]of hard water / magnesium sulphate solution. Add cleansing agent X/detergent in beaker A and cleansing agent Y/soap in bikar B. 4. Place a piece of cloth with oily stain into each beaker 5. Stir the solution in each beaker using glass rod until no change can be observed 6. Wash the oily stain on each piece of cloth using the solution in each beaker 7. Record the observation. Able to state three steps of procedures correctly Steps,, 5, 6, Able to state two steps of procedures correctly Steps,, 6 Able to exhibit the tabulation of data that includes the following information.. Headings Sample answer : (f) Beaker A B Observation Able to tabulate the data incompletely. Titles without unit Beaker No response given / wrong response 0 PERATURAN PEMARKAHAN TAMAT 454 Set Hak Cipta JUJ Pahang 07 8