Isothermal vs. adiabatic compression

Similar documents
Physics 4C. Chapter 19: Conceptual Questions: 6, 8, 10 Problems: 3, 13, 24, 31, 35, 48, 53, 63, 65, 78, 87

Lecture 3 Examples and Problems

Thermodynamics Second Law Entropy

First Law of Thermodynamics

Homework Chapter 21 Solutions!!

Physics 207 Lecture 27

ESCI 341 Atmospheric Thermodynamics Lesson 6 Thermodynamic Processes

TEST 5 (phy 240) 2. Show that the volume coefficient of thermal expansion for an ideal gas at constant pressure is temperature dependent and given by

#64. ΔS for Isothermal Mixing of Ideal Gases

δq T = nr ln(v B/V A )

Physics 240: Worksheet 30 Name:

Physics 3 (PHYF144) Chap 2: Heat and the First Law of Thermodynamics System. Quantity Positive Negative

Chapter 20: Exercises: 3, 7, 11, 22, 28, 34 EOC: 40, 43, 46, 58

Chapter 3 The Kinetic Theory of Gases 3.1. Ideal Gases Experimental Laws and the Equation of State

Thermodynamics and Gases

G4023 Mid-Term Exam #1 Solutions

Chapter 5 rd Law of Thermodynamics

Problem Set #6 solution, Chem 340, Fall 2013 Due Friday, Oct 11, 2013 Please show all work for credit

Chemical Engineering Department University of Washington

A quote of the week (or camel of the week): There is no expedience to which a man will not go to avoid the labor of thinking. Thomas A.

Non-Ideality Through Fugacity and Activity

Chapter 21 - The Kinetic Theory of Gases

NAME and Section No.

NAME and Section No. it is found that 0.6 mol of O

Adsorption: A gas or gases from a mixture of gases or a liquid (or liquids) from a mixture of liquids is bound physically to the surface of a solid.

STATISTICAL MECHANICS

HEAT, WORK, AND THE FIRST LAW OF THERMODYNAMICS

Grain elevator. You need to convince your boss that this is a very inefficient system.

Force = F Piston area = A

Problem: Calculate the entropy change that results from mixing 54.0 g of water at 280 K with 27.0 g of water at 360 K in a vessel whose walls are

MAE140 - Linear Circuits - Fall 13 Midterm, October 31

General Formulas applicable to ALL processes in an Ideal Gas:

Chapter 8 Balances on Nonreactive Processes 8.1 Elements of Energy Balances Calculations 8.1a Reference States A Review

Chapter 19 The First Law of Thermodynamics

Chapters 18 & 19: Themodynamics review. All macroscopic (i.e., human scale) quantities must ultimately be explained on the microscopic scale.

University Physics AI No. 10 The First Law of Thermodynamics

5.62 Physical Chemistry II Spring 2008

Name: SID: Discussion Session:

CHAPTER 7 ENERGY BALANCES SYSTEM SYSTEM. * What is energy? * Forms of Energy. - Kinetic energy (KE) - Potential energy (PE) PE = mgz

between standard Gibbs free energies of formation for products and reactants, ΔG! R = ν i ΔG f,i, we

Example problems. Chapter 3: The Kinetic Theory of Gases. Homework: 13, 18, 20, 23, 25, 27 (p )

= r. / cisely It was not isothermal, nor exactly adia- ! If / l/l /! i i \ i LjSj?

PHYS1001 PHYSICS 1 REGULAR Module 2 Thermal Physics Chapter 17 First Law of Thermodynamics

THE FIRST LAW OF THERMODYNAMICS

PHYSICS 212 MIDTERM II 19 February 2003

Adiabatic Sorption of Ammonia-Water System and Depicting in p-t-x Diagram

Physical Chemistry I for Biochemists. Chem340. Lecture 16 (2/18/11)

Managing Capacity Through Reward Programs. on-line companion page. Byung-Do Kim Seoul National University College of Business Administration

Chemistry 163B Free Energy and Equilibrium E&R ( ch 6)

Physics 141. Lecture 14. Frank L. H. Wolfs Department of Physics and Astronomy, University of Rochester, Lecture 14, Page 1

THE ARIMOTO-BLAHUT ALGORITHM FOR COMPUTATION OF CHANNEL CAPACITY. William A. Pearlman. References: S. Arimoto - IEEE Trans. Inform. Thy., Jan.

Introduction to Vapor/Liquid Equilibrium, part 2. Raoult s Law:

find (x): given element x, return the canonical element of the set containing x;

PART I: MULTIPLE CHOICE (32 questions, each multiple choice question has a 2-point value, 64 points total).

6. Hamilton s Equations

The first law of thermodynamics continued

MAE140 - Linear Circuits - Winter 16 Midterm, February 5

% & 5.3 PRACTICAL APPLICATIONS. Given system, (49) , determine the Boolean Function, , in such a way that we always have expression: " Y1 = Y2

Chemistry 420/523 Chemical Thermodynamics (Spring ) Examination 1

ME 440 Aerospace Engineering Fundamentals

Assignment 4. Adsorption Isotherms

Problem Points Score Total 100

CinChE Problem-Solving Strategy Chapter 4 Development of a Mathematical Model. formulation. procedure

One Dimensional Axial Deformations

Solution Thermodynamics

Molecular structure: Diatomic molecules in the rigid rotor and harmonic oscillator approximations Notes on Quantum Mechanics

Lecture Note 3. Eshelby s Inclusion II

y i x P vap 10 A T SOLUTION TO HOMEWORK #7 #Problem

TP A SOLUTION. For an ideal monatomic gas U=3/2nRT, Since the process is at constant pressure Q = C. giving ) =1000/(5/2*8.31*10)

FE REVIEW OPERATIONAL AMPLIFIERS (OP-AMPS)( ) 8/25/2010

ME 300 Exam 2 November 18, :30 p.m. to 7:30 p.m.

ANSWERS. Problem 1. and the moment generating function (mgf) by. defined for any real t. Use this to show that E( U) var( U)

( ) 1/ 2. ( P SO2 )( P O2 ) 1/ 2.

Chemistry 531 Spring 2009 Problem Set 6 Solutions

Chapter 12. Ordinary Differential Equation Boundary Value (BV) Problems

I affirm that I have never given nor received aid on this examination. I understand that cheating in the exam will result in a grade F for the class.

4.2 Chemical Driving Force

THE VIBRATIONS OF MOLECULES II THE CARBON DIOXIDE MOLECULE Student Instructions

6.3.7 Example with Runga Kutta 4 th order method

One-sided finite-difference approximations suitable for use with Richardson extrapolation

Textbook Problem 4.2: The theory in question has two scalar fields Φ(x) and φ(x) and the Lagrangian. 2 Φ ( µφ) 2 m2

Outline. Unit Eight Calculations with Entropy. The Second Law. Second Law Notes. Uses of Entropy. Entropy is a Property.

KIRCHHOFF CURRENT LAW

Physics 4B. Question and 3 tie (clockwise), then 2 and 5 tie (zero), then 4 and 6 tie (counterclockwise) B i. ( T / s) = 1.74 V.

PETE 310 Lectures # 24 & 25 Chapter 12 Gas Liquid Equilibrium

Phase transition. Asaf Pe er Background

Hidden Markov Model Cheat Sheet

5.04, Principles of Inorganic Chemistry II MIT Department of Chemistry Lecture 32: Vibrational Spectroscopy and the IR

Chapter Newton s Method

Power-sum problem, Bernoulli Numbers and Bernoulli Polynomials.

Week 11: Chapter 11. The Vector Product. The Vector Product Defined. The Vector Product and Torque. More About the Vector Product

Modelli Clamfim Equazioni differenziali 7 ottobre 2013

CHEMISTRY Midterm #2 answer key October 25, 2005

MAE140 - Linear Circuits - Fall 10 Midterm, October 28

PHYS 1443 Section 004 Lecture #12 Thursday, Oct. 2, 2014

The Kinetic Theory of Gases

Calculating the Quasi-static Pressures of Confined Explosions Considering Chemical Reactions under the Constant Entropy Assumption

Lecture 12: Discrete Laplacian

Lecture 2 Grand Canonical Ensemble GCE

MASS HAUL DIAGRAM. Determination of eartworks volumes From all cross-sections (including the typical crosssection)

Transcription:

Isothermal vs. adabatc comresson 1. One and a half moles of a datomc gas at temerature 5 C are comressed sothermally from a volume of 0.015 m to a volume of 0.0015 m. a. Sketch the rocess on a dagram and show what corresonds to the work done on the gas. b. Calculate the work done on the gas. (Ignore vbratonal energy of the molecules) c. How much heat flowed nto the gas? d. What s the fnal ressure of the gas?

(Isothermal vs. adabatc comresson) 2. The same system undergoes an adabatc comresson wth the same ntal and fnal volumes. a. Sketch the rocess on the same dagram you used for the sothermal rocess. b. Is the fnal temerature hgher, lower or the same as n the sothermal comresson? Exlan. c. Fnd the fnal temerature of the gas. d. Accordng to your dagram, s the fnal ressure greater, lesser or the same as n the sothermal case? Exlan why (.e., what s the energy flow n each case?). Calculate the fnal ressure. e. Based on your dagram, would the amount of work done on the gas be larger, smaller, or the same as n the sothermal case? What about the heat flow? Exlan your answers brefly. f. Comute the work done on the gas for ths rocess. [Hnt: There s a long way to do ths, the ntegral of d, and a short way, usng the frst law of thermodynamcs.]

Isothermal vs. adabatc comresson 1. One and a half moles of a datomc gas at temerature 5 C are comressed sothermally from a volume of 0.015 m to a volume of 0.0015 m. a. Sketch the rocess on a dagram and show what corresonds to the work done on the gas. W fnal b. Calculate the work done on the gas. ntal f f d f W d nrt ln nrt J 0.0015 m W 1.5 moles8.1 27 K 5 Kln 88 J mol K 0.015 m Snce W>0 when work s done by the gas, then the work done on the gas s Won = +88 J. c. How much heat flowed nto the gas? Frst law of thermodynamcs: U Q W Snce T s constant, U 0, thus QW 88 J. (Q < 0, thus ths s absorbed heat) d. What are the ntal and fnal ressure of the gas? J 1.5 moles 8.1 08 K nrt mol K 0.015 m f 5 2.56 10 Pa J 1.5 moles 8.1 08 K nrt mol K 0.0015 m f 2.56 10 Pa

(Isothermal vs. adabatc comresson) 2. The same system undergoes an adabatc comresson wth the same ntal and fnal volumes as n art 1. a. Sketch the rocess on the same dagram you used for the sothermal rocess. adabatc fnal sothermal ntal b. Is the fnal temerature hgher, lower or the same as n the sothermal comresson? Exlan. Snce Q = 0, W = ΔU. W < 0 (volume decrease), so nternal energy ncreases, and that, for an deal gas, means a temerature ncrease. c. Fnd the fnal temerature of the gas. 1 For an adabatc rocess, T constant, wth Therefore, T T 1 1 f f 1 1.1 0.015 m Tf T 08 K 77 K f 0.0015 m 7 1. for a datomc deal gas. 5 d. Accordng to your dagram, s the fnal ressure greater, lesser or the same as n the sothermal case? Exlan why (.e., what s the energy flow n each case?). Calculate the fnal ressure. For an adabatc rocess, constant. Therefore,

(Isothermal vs. adabatc comresson) f f 1. 5 0.015 m 6 f 2.5610 Pa 6.10 Pa f 0.0015 m Ths fnal ressure after the adabatc rocess s greater than the fnal ressure after the sothermal rocess obtaned n art d of secton 1. e. Based on your dagram, would the amount of work done on the gas be larger, smaller, or the same as n the sothermal case? What about the heat flow? Exlan your answers brefly. Work s the area under the curve. The work s thus larger for the adabatc rocess. The heat flow s zero for the adabatc case, so the heat flow s larger for the sothermal case. f. Comute the work done on the gas for ths rocess. The short way: We can answer the queston usng the frst law, U Q W. For an adabatc rocess, Q = 0. 5 For a datomc deal gas, U nrt. 2 Therefore, 5 5 J W U nrt 1.5 moles8.1 77 K 08 K 1.510 J 2 2 mol K Agan, we need to be careful wth the sgn: the work n the exresson above s done by the gas, so the work done on the gas s W W 1.5 10 J on The long way: f We can also do the ntegral W d. For any ont along the adabatc rocess, constant at the fnal value, for nstance. Then, constant. We can evaluate the f f.

(Isothermal vs. adabatc comresson) Usng ths exresson for ressure n the ntegral for work, we obtan: f f d 1 1 f f W d ff 1 1 1 f 6 1. 6. 10 Pa 0.0015 m 1 1 W 0. 0. 0. 0.0015 m 0.015 m Agan, Won W 1.5 10 J 1.5 10 J Recall that for the sothermal rocess, the work done on the gas was 88 J. The work done on the gas s greater n the adabatc rocess.