Assume the bending moment acting on DE is twice that acting on AB, i.e Nmm, and is of opposite sign.

Similar documents
* 7 *? f 7 T e & d. ** r : V ; - r.. ' V * - *. V. 1. fb & K try *n 0AC/A+J-* ' r * f o m e F o ^ T *?, * / / L * o : ± r ' *

SCATTER DIAGRAM ESTIMATED VS OBSERVED RUN OFF AT STATION A37 LUPANE RAINFALL STATION

ft *6h^{tu>4^' u &ny ^ 'tujj Uyiy/Le^( ju~ to^a)~^/hh-tjsou/l- U r* Y o ^ s t^ ' / { L d (X / f\ J -Z L A ^ C (U 'o # j& tr & [)aj< l# 6 j< ^

4 W. Girl W a y f a r e r s A s s o c i a t i o n, P. 0. B o x 97, D e a r Madam, R E : U S S OF L E A K S H A L L :

PURE BENDING. If a simply supported beam carries two point loads of 10 kn as shown in the following figure, pure bending occurs at segment BC.

Abode. When buried, lly wlmm the Ceremony was performed.

p r * < & *'& ' 6 y S & S f \ ) <» d «~ * c t U * p c ^ 6 *

Oil'll. 't Or) [xdl^i^, CtJiMr^ ~t x. tbu to#*a) rf. 3*^^1IlSr>' r e u <i^-^j O. , y r v u \ r t o < x * ^ v t a ^ c? ] % & y^lcji-*'**'* (» &>~r~

CHAPTER 4. Stresses in Beams

in tlio Year Ono thousand Qtgbtb hundred tns&

! J*UC4j u<s.< U l*4 3) U /r b A a ti ex Ou rta + s U fa* V. H lu< Y ^i«iy /( c * i U O rti^ ^ fx /i«w

Volledige beskrywinj; van bcwysstukkc/ciendom Detailed description of exhibits/property [S.O. 328 (7) (b) en/and S.O.

PINE STREET. DURBAN. Issued by It Action Committe of African National Congress & Nattl Indian Congress

OUTCOME 1 - TUTORIAL 3 BENDING MOMENTS. You should judge your progress by completing the self assessment exercises. CONTENTS

ENGINEERING COUNCIL DIPLOMA LEVEL MECHANICS OF SOLIDS D209 TUTORIAL 3 - SHEAR FORCE AND BENDING MOMENTS IN BEAMS

Sample Question Paper

Page 19. Abode. f a t ce ^i/c ^ rt l u. h c t. lia /tt*. fi.fccufftu. ct^ f f te m itu. / t /c a n t «//, StJ A :/. 7^ f t v f * r * r/m rr//,,

Name :. Roll No. :... Invigilator s Signature :.. CS/B.TECH (CE-NEW)/SEM-3/CE-301/ SOLID MECHANICS

&GGL S. Vol.» I>l OCESE: S t. H e l e n a PARISH: St. Paul REGI STER : feorla L. D A T E D :

Chapter Objectives. Copyright 2011 Pearson Education South Asia Pte Ltd

2012 MECHANICS OF SOLIDS

Entrance exam Master Course

UNIVERSITY OF SASKATCHEWAN ME MECHANICS OF MATERIALS I FINAL EXAM DECEMBER 13, 2008 Professor A. Dolovich

Structural Steel Design Project

3IZL15E OF LEBANESE LIGTIT'T'fij.

ThP Small of Appl.es. and Miafling PSEaona could be seen to. constitute the spectrum of white male identity in South Africa-

WALL D*TA PRINT-OUT. 3 nmth ZONE

Unit Workbook 1 Level 4 ENG U8 Mechanical Principles 2018 UniCourse Ltd. All Rights Reserved. Sample

PDDC 1 st Semester Civil Engineering Department Assignments of Mechanics of Solids [ ] Introduction, Fundamentals of Statics

Sabah Shawkat Cabinet of Structural Engineering Walls carrying vertical loads should be designed as columns. Basically walls are designed in

twenty one concrete construction: shear & deflection ARCHITECTURAL STRUCTURES: FORM, BEHAVIOR, AND DESIGN DR. ANNE NICHOLS SUMMER 2014 lecture


CHAPTER 4: BENDING OF BEAMS

Figure 2.9 Positioning of compliance gauges used for closure measurements.

REVOLVED CIRCLE SECTIONS. Triangle revolved about its Centroid

ENT345 Mechanical Components Design

By Dr. Mohammed Ramidh

Sub. Code:

and F NAME: ME rd Sample Final Exam PROBLEM 1 (25 points) Prob. 1 questions are all or nothing. PROBLEM 1A. (5 points)

Part 1 is to be completed without notes, beam tables or a calculator. DO NOT turn Part 2 over until you have completed and turned in Part 1.

QUESTION BANK SEMESTER: III SUBJECT NAME: MECHANICS OF SOLIDS

QUESTION BANK DEPARTMENT: CIVIL SEMESTER: III SUBJECT CODE: CE2201 SUBJECT NAME: MECHANICS OF SOLIDS UNIT 1- STRESS AND STRAIN PART A

IDE 110 Mechanics of Materials Spring 2006 Final Examination FOR GRADING ONLY

B A P T IS M S solemnized. Hn the County of

SPMT Loadout Ramp Design Spreadsheet (

Engineering Science OUTCOME 1 - TUTORIAL 4 COLUMNS

CH. 4 BEAMS & COLUMNS

CIV100 Mechanics. Module 5: Internal Forces and Design. by: Jinyue Zhang. By the end of this Module you should be able to:

Deflections and Strains in Cracked Shafts due to Rotating Loads: A Numerical and Experimental Analysis

DESIGN FOR FATIGUE STRENGTH

Determine the resultant internal loadings acting on the cross section at C of the beam shown in Fig. 1 4a.

BE Semester- I ( ) Question Bank (MECHANICS OF SOLIDS)

f r '/>/// >. / IS LA X O ^t. ll II<G!V.i, I&neiAiiS in the S a k is ii Ciiu h c h Y a iu», in the Year yr/r/r.. efe y ; 4 /ryes / 1

A CONNECTION ELEMENT FOR MODELLING END-PLATE CONNECTIONS IN FIRE

Moments of inertia of a cross section

MARKS DISTRIBUTION AS PER CHAPTER (QUESTION ASKED IN GTU EXAM) Name Of Chapter. Applications of. Friction. Centroid & Moment.

CIVIL DEPARTMENT MECHANICS OF STRUCTURES- ASSIGNMENT NO 1. Brach: CE YEAR:

SN QUESTION YEAR MARK 1. State and prove the relationship between shearing stress and rate of change of bending moment at a section in a loaded beam.

Stress Analysis Lecture 4 ME 276 Spring Dr./ Ahmed Mohamed Nagib Elmekawy

SAULT COLLEGE OF APPLIED ARTS & TECHNOLOGY SAULT STE. MARIE, ONTARIO COURSE OUTLINE STRENGTH OF MATERIALS MECHANICAL TECHNOLOGY

COURSE TITLE : APPLIED MECHANICS & STRENGTH OF MATERIALS COURSE CODE : 4017 COURSE CATEGORY : A PERIODS/WEEK : 6 PERIODS/ SEMESTER : 108 CREDITS : 5

Chapter 3. Load and Stress Analysis. Lecture Slides

Samantha Ramirez, MSE

9.5 Compression Members

Properties of Sections

DETERMINING THE STRESS PATTERN IN THE HH RAILROAD TIES DUE TO DYNAMIC LOADS 1

5. What is the moment of inertia about the x - x axis of the rectangular beam shown?

SPECIFIC VERIFICATION Chapter 5

Beam Design - FLOOR JOIST

UNIT 1 STRESS STRAIN AND DEFORMATION OF SOLIDS, STATES OF STRESS 1. Define stress. When an external force acts on a body, it undergoes deformation.

Mechanics of Materials CIVL 3322 / MECH 3322

SIGN CONVENTION OF STRESS RESULTANTS

2014 MECHANICS OF MATERIALS

2. Determine the deflection at C of the beam given in fig below. Use principal of virtual work. W L/2 B A L C

CIVIL ENGINEERING

v f e - w e ^ C c ^ ^ o e s r v i c e ^ ^.

UNSYMMETRICAL BENDING

Chapter 7 FORCES IN BEAMS AND CABLES

SECOND ENGINEER REG. III/2 APPLIED MECHANICS

Design issues of thermal induced effects and temperature dependent material properties in Abaqus

7 TRANSVERSE SHEAR transverse shear stress longitudinal shear stresses

Advanced Structural Analysis EGF Section Properties and Bending

DESIGN AND DETAILING OF COUNTERFORT RETAINING WALL

Name (Print) ME Mechanics of Materials Exam # 2 Date: March 29, 2017 Time: 8:00 10:00 PM - Location: WTHR 200

Level 7 Postgraduate Diploma in Engineering Computational mechanics using finite element method

Appendix A: Details of Deformation Analyses

Flexure: Behavior and Nominal Strength of Beam Sections

UNIVERSITY OF BOLTON SCHOOL OF ENGINEERING. BEng (HONS) CIVIL ENGINEERING SEMESTER 1 EXAMINATION 2016/2017 MATHEMATICS & STRUCTURAL ANALYSIS

Civil Engineering Design (1) Design of Reinforced Concrete Columns 2006/7

Chapter 3. Load and Stress Analysis

Supplement: Statically Indeterminate Frames

UNIT- I Thin plate theory, Structural Instability:

Level 3 Cambridge Technical in Engineering

Bending Stress p375. Bending-Stress Page 1

Due Tuesday, September 21 st, 12:00 midnight

Structural design of helicopter landing platform for super-yacht

ENGINEERING SCIENCE H1 OUTCOME 1 - TUTORIAL 4 COLUMNS EDEXCEL HNC/D ENGINEERING SCIENCE LEVEL 4 H1 FORMERLY UNIT 21718P

BOLLARD STRENGTH CHECK

PERIYAR CENTENARY POLYTECHNIC COLLEGE PERIYAR NAGAR - VALLAM THANJAVUR. DEPARTMENT OF MECHANICAL ENGINEERING QUESTION BANK

Lecture 15 Strain and stress in beams

Transcription:

232 End cf Do run Assume the bending moment acting on DE is twice that acting on AB, i.e. 138 240 Nmm, and is of opposite sign. n n Distance between BM couple = ^ x 432 = 288 mm o Magnitude of forces of couple = =. 480 N Extreme fibre stress = ^ = ~ A,44 MPc. Stress at node h Stress at node i Consider ndhp: r! J x 4,44 = +2,96 MPa x 4,44 = +1,48 MPa Total force on surface between D and h - x 72 - +266 N Position /

Position of centroid : 2,96 x 72 x ^ = 7 680 Nmm 1.48 x = i 280 = 33,6 mm from D., 8 960 Force on node D - +266 x Force on node h - +266 x - +142 N = +124 N +266 N Consider phiq: Total force on hi ' -r-'-." x 72 = +160 N Position of centroid : 1,48 x 72 x ^ = 3 839 Nmm 1.48 x = 1 280 5 119 5 119 32 mm from h. Force on h = x (72-32) +88,9 N Force of i = Uftp- x 32 * +71.1 N +160,0 N Consider ql.j: Total force on ij «+1,48 x = +53>3 N Force on i = +53,3 x * +35,5 N Force on j = + 53,3 x i = +1?.8 N +53,3 N Forces on nodes Node D (204) : +142 N Node h (178) : +124 +89 = +213 N Node i /...

234 Node i (152) +71,1 +35,5 - +107 Ncde 3 (126) +17,8-17,8 = 0 Node k (100) Node 1 (74) Node E (48) -107 N -213 N -142 N CA.1.Ll). Possible loads on a small two-storey building with a 126 mm thick concrcte slab were assumed and are shown on Figure 58. n Top of column Bending moment = 18 000 N mm/n.m width Bending moment couple = P = -!".- 94 M/inm width End fibre stress Stress at node b = -0,655 MPa 2 = ± 1,31 MPa Consider /

Consider Abed: Total force on surface Ab = ^ x 72 = -70,74 N Position of centroid (from Case (a)) is 32 mm from A Force on node A = -70,74 x 40-7? Force on node h U -70,74 x 12 Consider bee: Total force ort be -0,655-4-Z2. _ 23,58 N 9 - C. -39,30 N = -31,44 N -70,74 N Force on node b = -<-3,58 x 0,667 = -15,73 N Force of node c = -23,58 x 0,333 = -7,85 N,! N Uniformly distributed load on column Force on nodes 233 and 237 : -2,33 x 36 = -83,9 N Force on nodes 234, 235 and 236 : - -167,8 N Forccg on nodes on top of column Node A (233) -39,3-83,9 = -123,2 N Node b (234) -31,4-15,7-167,8 = -214,? N Node c (235) -7,8 + 7,8-167,8 = -167,8 N Mode f (236) +31,4 + 15,7-167,8 = -120,7 N Node B (237) + 39,3-83,9 = -44,6 N End of Beam Bending moment = 36 000 Nmm Distance between bending moment couple Magnitude of forces of couple = = 2 = 288 mm = 125 N Extreme /

Extreme fibre stress = * 1>16 MPa Stress on node h = : 7 = +0,773 Mia Stress on node i = Consider ndhp: J - +0,337 MPa Total force on surface Dh C. x 72 = +69,6 N Position of centroid (from Case (a)) is 33,6 in from D. Force on node D +69,6 x = +37,12 N Force on node h = +69,6 x +32,48 N +69,60 N Consider phi.fi: Total force on hi - ^ x 72 = +41,76 N c FJ<^ition of centroid is 32 mm from h. Force on h /...

Force on h x (72-32) Force on i - x 32 Iu 237 = +23,20 N +18,56 N +41,76 N Consider (il.j: Total force on ij = +0,387 x +13,93 N Force on i = +13,93 x *7 Force on j = +13,93 x 4 +9,29 N +4,64 N +13,93 N Forces on nodes it) horizontal direction Node D (204) Node h (178) Node i (152) Node i (126) Node k (100) Node 1 (74) Node E (48) Shear stress on DE +37,1 N +32,5 + 23,2» +55,7 N +18,6 + 9,3 = +27,9 N + <1,6-4,6 =0-27,9 N -55,7 N -37,1 N Assuming load on end DE of beam from floor, \all and beam = 208 N Shear stress = 1-- o > = 0,48 MPa I?. Vertical force on nodes 204 and 48 ~ 0,48 x 36 = 17,3 N Vertical force on nodes 178, 152, 126, 100 ond 7': = 34,6 N Vertical Loads on Nodal Points on Top of Beam Distributed load -0,0323 N/mm ' Node 190 Node 199 Node POO -0,032 x 18-0,032 x 36-0,032 x (18 + 36) -0,58 N -1,16 N -1,75 N Node 201 : /

238 Node 201 : -0,032 x 72 Node 202 : -0,032 x (?6 + 72) Node 203 : -0,032 x 144 Node 204 : -0,032 x 72 = -2,33 N = -3,49 N = -4,66 N = -2,33 N Total force on Node 204 : -2,33-17,3 = -19,6 N CASE (c) In addition ^o the Loads of Case (b), horizontal loads were applied a3 shown on Figure 59. These loads were arbitrarily selected. The total load on the column from the brickwork was 252 N and this caused a tension of 252 N applied on the end of the beam. B 0,5 MPa 0,778 MPa n O r t U c i ;o t it

239 Area on sketch Total load on surface Moments about node Rec tangle Triangle Position of centroid (mm) Bvwr 81,6 5 184 460 69,2 from r rwxs 48,0 1 641 58 35,4 from 3 sxyt 55,8 1 814 129 34,8 from t tyzu 32,0 551 16 17,7 from u uzcm 34,6 599 16 17,8 from c Horizontal forces on nodes Node D (237) Node r (232) Node s (227) Node t (222) Node v (213) Node C (198) -39,2-42,4-23,6-24,4-27,0-28,8-15,7-16,3-17,1-17,5-39,2 N = -66,0 N = -51,4 N = -44,5 N = -33,4 N = -17,5 N -252,0 N End of Beam It was arbitrarily decided to distribute the tension on the end of the beam so that the stress at D was twice the stress at E i.e. 0,778 and 0.389 MPa respectively. Check : x ^32 = 252 N Nodal Point Stress on Node Nodal Point Stress on Node D 0,778 k 0,519 h 0,713 1 0,454 i 0,648 E 0,389 J 0,583

240 Area on sketca Total load on surface Moments about node Rectangle Triangle Position of centroid (mm) ndhp 53,7 1 848 'G 35,5 from h phiq 49,0 1 680 56 35,4 from i qi,1 44,3 1 512 56 35,4 from j,jkk 39,7 1 344 55 35,3 from k kkll 35,0 1 176 56 35,2 from 1 11EE 30,3 1 008 35,1 from E 252,0 H ori zontnl forcer. on end o f benni nodr':; Node D (204) +26,5 = +26,5 N + 37,1 = +63,6 N Node h (178) + 27,2 +24,1 = +51,3 N +55,7 = +107,0 N Node i (152) + 24,9 f 21,8 = + (';6,7 N +27,9 = +74,6 N Node j (126) +22,5 + 19,5 - +42,0 N 0 = +42,0 N Node k (100) + 20,2 + 17,1 = +37,3 N -27,9 3 +9,4 N Node 1 (74) +17,9 + 14,8 = +32,7 N -55,7 r -23,0 N Node E (48) + 15,5 = +15,5 N -37,1 = -21,6 N O CASE (c) The loading was the same as in Case (c) except that the horizontal stresses on the stub column and the horizontal stresses on the end of the beai.i were 10 times higher. ilor i zont.-i ] f'orr.r ", on column edge nodes Node B (237) : -392 Node r (232) : -424 Node s (227) : -244 Node t. (222) : -288 = -392 N 236 = -660 N 270 = -514 N 157 = -445 K

241 Node v (213) Nodo C (198) -163-171 -175-334 n -175 N -2 520 N Horizontal forces on end of beam nodes Node D (204) +265 - +265 N +37 = +302 N Node h (178) + 272 + 241 = +513 N +56 = +569 N Node i (152) + 249 +218 a +467 N +28 = +495 N Node j (126) + 225 + 195 = +420 N 0 = +420 N Node k (100) + 202 + 171 = + 373 N -28 +345 N Node 1 (74) + 179 +148 = -*-327 N -56 = +271 N Node E (48) +155 = + 155 N -37 = +118 N +2 520 N NOTE: The element numbers higher than 173 and the nodal point numbers higher than 185 change in the case of the cracked junctions, i.e. Uncracked Cracked Node B 237 239 Node r 232 234 Node s 227 229 Node t 2?2 224 Node v 211 215 Node C 198 199 Mode A 233 235 Node b 234 236 Node c 235 237 Node f 236 238 ctr*.

Author Boardman Vivian Reginald Name of thesis The Effect Of Compressive Stress On The Expansion Of Brickwork And Its Implication In Buildings. 1977 PUBLISHER: University of the Witwatersrand, Johannesburg 2013 LEGAL NOTICES: Copyright Notice: All materials on the University of the Witwatersrand, Johannesburg Library website are protected by South African copyright law and may not be distributed, transmitted, displayed, or otherwise published in any format, without the prior written permission of the copyright owner. Disclaimer and Terms of Use: Provided that you maintain all copyright and other notices contained therein, you may download material (one machine readable copy and one print copy per page) for your personal and/or educational non-commercial use only. The University of the Witwatersrand, Johannesburg, is not responsible for any errors or omissions and excludes any and all liability for any errors in or omissions from the information on the Library website.