Oxidation-Reduction (Redox) Reactions (4.4) 2) The ox. state of an element in a simple ion is the charge of the ion. Ex:

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Redox reactions: Oxidation-Reduction (Redox) Reactions (4.4) Oxidation & reduction always occur simultaneously We use OXIDATION NUMBERS to keep track of electron transfers Rules for Assigning Oxidation Numbers: 1) the ox. state of any free (uncombined) element is zero. Ex: 2) The ox. state of an element in a simple ion is the charge of the ion. Ex: 3) the ox. # for hydrogen is +1 (unless combined with a metal, then it has an ox. # of 1) 4) the ox. # of fluorine is always 1. 5) the ox. # of oxygen is usually 2. 6) in any neutral compound, the sum of the oxidation # s = zero. 7) in a polyatomic ion, the sum of the oxidation # s = the overall charge of the ion. **use these rules to assign oxidation # s; assign known # s first, then fill in the # s for the remaining elements: Examples: Assign oxidation # s to each element: a) NaNO3 d) H3PO4 b) SO3 2- e) Cr2O7 2- c) HCO3 - f) K2Sn(OH) 6 Oxidation-Reduction Reactions: oxidation & reduction always occur together (as one loses electrons, the other gains them) oxidation: reduction: oxidizing agents: reducing agents: 76

A reaction is redox if a change in oxidation # happens; if no change in oxidation # occurs, the reaction is nonredox. Examples: MgCO3 MgO + CO2 Zn + CuSO4 ZnSO4 + Cu NaCl + AgNO3 AgCl + NaNO3 CO2 + H2O C6H12O6 + O2 Balancing Redox Equations In balancing redox equations, the # of electrons lost in oxidation (the increase in ox. #) must equal the # of electrons gained in reduction (the decrease in ox. #) There are 2 methods for balancing redox equations: 1. Change in Oxidation-Number Method: based on equal total increases and decreases in oxidation # s Steps: 1) Write equation and assign oxidation # s. 2) Determine which element is oxidized and which is reduced, and determine the change in oxidation # for each. 3) Connect the atoms that change ox. # s using a bracket; write the change in ox. # at the midpoint of each bracket. 4) Choose coefficients that make the total increase in ox. # = the total decrease in ox. #. 5) Balance the remaining elements by inspection. Example: S + HNO3 SO2 + NO + H2O If needed, reactions that take place in acidic or basic solutions can be balanced as follows: Acidic: Basic: 1. add H2O to the side needing 1. balance as if in acidic solution oxygen 2. then add H + to balance the 2. then, add enough OH - to both hydrogen sides to cancel out each H + (making H20) & then cancel out water as appropriate 77

Example: Balance the following equation, assuming it takes place in acidic solution. ClO4 - + I - Cl - + I2 2. The Half-Reaction Method: separate and balance the oxidation and reduction half-reactions. Steps: 1) write equation and assign oxidation # s. 2) Determine which element is oxidized and which is reduced, and determine the change in oxidation # for each. 3) Construct unbalanced oxidation and reduction half reactions. 4) Balance the elements and the charges (by adding electrons as reactants or products) in each halfreaction. If occurring in acidic or basic solutions, you might need to balance H & O on their own. a) Balance all the elements except H and O b) Balance O using H2O c) Balance H using H + d) Balance charge using electrons 5) Balance the electron transfer by multiplying the balanced half-reaction by appropriate integers. 6) Add the resulting half-reaction and eliminate any common terms to obtain the balanced equation. Example: Balance the following using the half-reaction method: HNO3 + H2S NO + S + H2O 78

Consider the reaction: Zn(s) + CuSO4(aq) Cu(s) + ZnSO4(aq) Electrochemical Cells (18.1-18.6) If the 2 solutions are physically connected, but are connected by an external wire, electrons can still be transferred through the wire. Electrons flowing through a wire generate energy in the form of electricity. An electrochemical cell is a container in which chemical reactions produce electricity or an electric current produces chemical change. When an electrochemical cell produces electricity, it is also known as a voltaic cell. In the copper-zinc cell, the Cu and Zn electrodes (strips of each metal) are immersed in sulfate solutions of their respective ions (CuSO4 and ZnSO4) The solutions are separated by a porous barrier (prevents solutions from mixing, but allows ions to pass through), or a salt bridge (any medium through which ions can pass slowly). Cu 2+ ions gain 2 electrons at the surface of the Cu strip, where they are deposited as Cu atoms: Zn atoms in the Zn strip are losing electrons to become Zn 2+ ions in solution: Voltaic cells are divided into 2 components called HALF CELLS: consist of a metal electrode in contact with a solution of its own ions. The ANODE is the half cell at which oxidation occurs; (a source of electrons) The CATHODE is the half cell at which reduction occurs (use up electrons) o electrons flow from left to right (anode to cathode) o we can predict the direction of the electron flow in any given cell using the activity series and reduction potentials for metals (see Table 18.1, p. 520) o The more negative the Standard Reduction Potential value, the more likely a metal is to give up its electrons (become oxidized) and serve as the anode. 79

The reaction in the cell will be spontaneous if the E for the cell is positive; it is calculated as follows: E cell = E cathode E anode consider the zinc-copper cell: Zn 2+ + 2e - Zn E = Cu 2+ + 2e - Cu E = -reduction of zinc has the lower value, so Zn is the anode -what is the E for the cell? consider a cell made from Al and Zn: Zn 2+ + 2e - Zn E = -what is the anode? Al 3+ + 3e - Al E = -what is the E for the cell? Batteries are voltaic cells: a voltage is generated by a battery only if electrons continue to be removed from 1 substance and transferred to another; when equilibrium is reached between the 2 half cells, the battery is dead. Rechargeable batteries: an external voltage source is applied to the battery s electrodes and reverses the half-reactions; this restores the electrodes to their original state. while the battery is being used, it operates as a voltaic cell (converts chemical energy into electric energy) while the battery is being charged, it operates as an electrolytic cell (converts electric energy into chemical energy) 80