Topic 9 - Taylor and MacLaurin Series

Similar documents
TAYLOR AND MACLAURIN SERIES

( a) ( ) 1 ( ) 2 ( ) ( ) 3 3 ( ) =!

CS321. Numerical Analysis and Computing

Taylor Polynomials and Approximations - Classwork

CS537. Numerical Analysis and Computing

Power Series: A power series about the center, x = 0, is a function of x of the form

Error for power series (Day 2) YOU MAY USE YOUR CALCULATOR TO COMPUTE FRACTIONS AND OTHER SIMPLE OPERATIONS

Calculus 2 - D. Yuen Final Exam Review (Version 11/22/2017. Please report any possible typos.)

Practice Problems: Taylor and Maclaurin Series

e to approximate (using 4

f t dt. Write the third-degree Taylor polynomial for G

CHAPTER 5: FOURIER SERIES PROPERTIES OF EVEN & ODD FUNCTION PLOT PERIODIC GRAPH

f x x c x c x c... x c...

(Figure 2.9), we observe x. and we write. (b) as x, x 1. and we write. We say that the line y 0 is a horizontal asymptote of the graph of f.

, 4 is the second term U 2

Z ß cos x + si x R du We start with the substitutio u = si(x), so du = cos(x). The itegral becomes but +u we should chage the limits to go with the ew

Chapter 10: Power Series

We are mainly going to be concerned with power series in x, such as. (x)} converges - that is, lims N n

Maclaurin and Taylor series

10.5 Positive Term Series: Comparison Tests Contemporary Calculus 1

( 1) n (4x + 1) n. n=0

It is often useful to approximate complicated functions using simpler ones. We consider the task of approximating a function by a polynomial.

Math 113 Exam 4 Practice

62. Power series Definition 16. (Power series) Given a sequence {c n }, the series. c n x n = c 0 + c 1 x + c 2 x 2 + c 3 x 3 +

(a) (b) All real numbers. (c) All real numbers. (d) None. to show the. (a) 3. (b) [ 7, 1) (c) ( 7, 1) (d) At x = 7. (a) (b)

Math 113 Exam 3 Practice

9.3 Power Series: Taylor & Maclaurin Series

Calculus with Analytic Geometry 2

6.3 Testing Series With Positive Terms

10.6 ALTERNATING SERIES

(A sequence also can be thought of as the list of function values attained for a function f :ℵ X, where f (n) = x n for n 1.) x 1 x N +k x N +4 x 3

Example 2. Find the upper bound for the remainder for the approximation from Example 1.

x x x Using a second Taylor polynomial with remainder, find the best constant C so that for x 0,

1. (25 points) Use the limit definition of the definite integral and the sum formulas 1 to compute

g () n = g () n () f, f n = f () n () x ( n =1,2,3, ) j 1 + j 2 + +nj n = n +2j j n = r & j 1 j 1, j 2, j 3, j 4 = ( 4, 0, 0, 0) f 4 f 3 3!

Taylor Series (BC Only)

MAT1026 Calculus II Basic Convergence Tests for Series

Section 1.4. Power Series

9.3 Taylor s Theorem: Error Analysis for Series. Tacoma Narrows Bridge: November 7, 1940

MAT136H1F - Calculus I (B) Long Quiz 1. T0101 (M3) Time: 20 minutes. The quiz consists of four questions. Each question is worth 2 points. Good Luck!

Representing Functions as Power Series. 3 n ...

Math 113 Exam 3 Practice

4x 2. (n+1) x 3 n+1. = lim. 4x 2 n+1 n3 n. n 4x 2 = lim = 3

CHAPTER 10 INFINITE SEQUENCES AND SERIES

SOLUTIONS TO EXAM 3. Solution: Note that this defines two convergent geometric series with respective radii r 1 = 2/5 < 1 and r 2 = 1/5 < 1.

Carleton College, Winter 2017 Math 121, Practice Final Prof. Jones. Note: the exam will have a section of true-false questions, like the one below.

Infinite Sequences and Series

Math 106 Fall 2014 Exam 3.2 December 10, 2014

Chapter 6 Infinite Series

A sequence of numbers is a function whose domain is the positive integers. We can see that the sequence

Continuous Functions

Math 106 Fall 2014 Exam 3.1 December 10, 2014

Sequences and Series of Functions

Series: Infinite Sums

SUMMARY OF SEQUENCES AND SERIES

1 Generating functions for balls in boxes

Math 128A: Homework 1 Solutions

Solutions to Final Exam Review Problems

MIDTERM 3 CALCULUS 2. Monday, December 3, :15 PM to 6:45 PM. Name PRACTICE EXAM SOLUTIONS

Sequences A sequence of numbers is a function whose domain is the positive integers. We can see that the sequence

Topic 1 2: Sequences and Series. A sequence is an ordered list of numbers, e.g. 1, 2, 4, 8, 16, or

In algebra one spends much time finding common denominators and thus simplifying rational expressions. For example:

Sequences. A Sequence is a list of numbers written in order.

Section 11.8: Power Series

5 Sequences and Series

MA131 - Analysis 1. Workbook 9 Series III

An alternating series is a series where the signs alternate. Generally (but not always) there is a factor of the form ( 1) n + 1

PLEASE MARK YOUR ANSWERS WITH AN X, not a circle! 1. (a) (b) (c) (d) (e) 3. (a) (b) (c) (d) (e) 5. (a) (b) (c) (d) (e) 7. (a) (b) (c) (d) (e)

E. Incorrect! Plug n = 1, 2, 3, & 4 into the general term formula. n =, then the first four terms are found by

AP Calculus Chapter 9: Infinite Series

18.440, March 9, Stirling s formula

Ma 530 Introduction to Power Series

Please do NOT write in this box. Multiple Choice. Total

Calculus BC and BCD Drill on Sequences and Series!!! By Susan E. Cantey Walnut Hills H.S. 2006

Ma 530 Infinite Series I

Solutions to Practice Midterms. Practice Midterm 1

Convergence: nth-term Test, Comparing Non-negative Series, Ratio Test

Comparison Study of Series Approximation. and Convergence between Chebyshev. and Legendre Series

THE INTEGRAL TEST AND ESTIMATES OF SUMS

1.3 Convergence Theorems of Fourier Series. k k k k. N N k 1. With this in mind, we state (without proof) the convergence of Fourier series.

Fall 2013 MTH431/531 Real analysis Section Notes

x c the remainder is Pc ().

ECE Notes 6 Power Series Representations. Fall 2017 David R. Jackson. Notes are from D. R. Wilton, Dept. of ECE

Math 113, Calculus II Winter 2007 Final Exam Solutions

ENGI Series Page 6-01

MATH301 Real Analysis (2008 Fall) Tutorial Note #7. k=1 f k (x) converges pointwise to S(x) on E if and

Ans: a n = 3 + ( 1) n Determine whether the sequence converges or diverges. If it converges, find the limit.

Part I: Covers Sequence through Series Comparison Tests

Phys. 201 Mathematical Physics 1 Dr. Nidal M. Ershaidat Doc. 12

10.1 Sequences. n term. We will deal a. a n or a n n. ( 1) n ( 1) n 1 2 ( 1) a =, 0 0,,,,, ln n. n an 2. n term.

Quiz. Use either the RATIO or ROOT TEST to determine whether the series is convergent or not.

1 Approximating Integrals using Taylor Polynomials

Some Variants of Newton's Method with Fifth-Order and Fourth-Order Convergence for Solving Nonlinear Equations

INFINITE SEQUENCES AND SERIES

Math F15 Rahman

REVIEW 1, MATH n=1 is convergent. (b) Determine whether a n is convergent.

Notes #3 Sequences Limit Theorems Monotone and Subsequences Bolzano-WeierstraßTheorem Limsup & Liminf of Sequences Cauchy Sequences and Completeness

1 Lecture 2: Sequence, Series and power series (8/14/2012)

CHAPTER 6d. NUMERICAL INTERPOLATION

Transcription:

Topic 9 - Taylor ad MacLauri Series A. Taylors Theorem. The use o power series is very commo i uctioal aalysis i act may useul ad commoly used uctios ca be writte as a power series ad this remarkable result has give rise to may importat results i calculus. Taylors Theorem is states that i () is a well behaved uctio the it ca be represeted by the ollowig power series. () = () = c ( a) where c = () (a) c + c( a) + c2( a) 2 + c c2( a) +.. This power series will coverge or all values o with a < R, or some value R. The Taylors power series o a uctio is usually writte i the orm below ad is called the Taylor series o the uctio at a.! () ( ) ( a)! () = (a) + (a) ( a) + (a) ( a) 2 + + (a) ( a) + + v (a) ( a) 4 + Deiitio: The MacLauri s Series is the special case o Taylors Series with a =. () ()! ( ) '' () (4) '() () 2 () () 4 = ()... This power series will coverge or all values o with < R, or some value R. MacLauris series is a commoly used versio or the power series o a uctio as it teds to geerate simpler polyomials. Whe we state that a uctio is well behaved we mea that it is cotiuous ad all its derivatives eist at least at oe poit = a or a Taylors series ad at = or a MacLauris series to eist. Here is a list o the most commo MacLauri series.. 2. e!. si (2 )! 4. cos 2 (2)! 5. ta 2 (2 ) = + + 2 + + 4 + 5 + = + + 2 + + 4 + 2 = + 5 5! 7 7! + = 2 + 4 6 6! + 8 8! + = + 5 5 7 7 + Page

B Fidig MacLauris ad Taylors series. Eample : Fid the MacLauris series (MacLauris Epasio) or the uctio () = e. Solutio: We start by idig a suitable umber o derivatives at a = i order to detect a geeral patter. () = e () = e = () = e () = e = () = e () = e = () = e () = e = v () = e v () = e = MacLauris epasio is () = () + () + () 2 + () + v () 4 + () = + + 2 + + 4 + () = + + 2 + + 4 + So the power series () = e ()! ( )!! Page 2

Eample 2: Fid the Taylors series (Taylors Epasio) or the uctio () =si. at a = π We start by idig a suitable umber o derivatives at = i order to detect a patter. () = si (π) = si π = () = cos (π) = cosπ = () = si (π) = siπ = () = cos (π) = cosπ = v () = si v (π) = si π = v () = cos (π) = cosπ = The geeral patter here is very simple whe it is a odd derivative the umber is or ad whe it is a eve derivative it is zero. So we eed a geeral rule that oly geerates values or the odd derivatives ad igores the eve derivatives. Odd umbers ca be geerated by usig 2 so the odd (2 ) th 2 - derivative will have coeiciet ( ) So (2 ) (π) = ( ) 2 The Taylors epasio or () = si about = π is () = () = () = (π) + (π) ( π) ( π) + (π) + + ( π) ( ) (2 )! 2 ( π) 2 + (π) + ( π)5 5! + ( π) + v (π) ( π) 4 + Page

Eample : Fid the Taylors series (Taylors Epasio) or the uctio () =. at a = We start by idig a suitable umber o derivatives at = i order to detect a geeral patter. () = 2 = () = () 2 = () = 2 2 () = 2 () 2 = 2 () =. 5 2 2 2 () = 2. 2 () 5 2 =. 2 2 () = 2. 2. 5 2 7 2 () = 2. 2. 5 2 () 7 2 =..5 2 v () = 9.. 5. 7 2 2 2 2 2 v () = 2. 2. 5 2. 7 2 () 9 2 =..5.7 2 4 The geeral patter here is quite comple so the best strategy is to look at idividual patters withi the result. The irst patter to otice is that the sequece o values alterates rom positive to egative to positive etc this is geerated by usig ( ) or ( ) + i this particular case we have that ( ) works. The et patter is that the deomiator o the derivatives has powers o 2, so that the th derivative uses.. The last patter is the umerators which cosist o the product o odd umbers, so or 2 eample the 4 th derivative uses the product o the irst 4 odd umbers..5.7 so the th derivative will use the product o the irst odd umbers =..5.7.9.(2 ) What we do ow is to try ad get a geeral ormula or this product...5.7.9.(2 ) =.2..4..2 =.2..4..2 2.4.6.8. 2 2 (.2..4.5..) = (2)! 2! Puttig this all together we get () () = ( ) (2)! 2 2! epasio about =. () = () + () ( ) + () = ( ) (2)! 2 2! ( a) 2 + () so we have the ollowig Taylors ( ) + v () ( ) 4 + () =. ( ) + ( 2 2 2.() 2 2 () )2 +..5 ( 2 () ) +..5.7 ( 2 4 () )4 + () = ( ) () ( )! (2)! (!.2! ) 2 (2)! ( ) 2 2 2 (!) Page 4

Eample 4: Fid the MacLauris series (MacLauris Epasio) or the uctio () = e. Solutio: We use a shortcut here sice we kow that e! we ca id e = =!! 4 5 6 7...! 5 6 7 4 =... 2 6 24 Eample 5: Fid the MacLauris series (MacLauris Epasio) or the uctio () = si Solutio: We use a shortcut here sice we kow that si (2 )! 2 we ca id si (2 )! 2 (2 )! 2 = 2 + 4 5! 6 7! + Practice :. Fid the MacLauri power series or the ollowig uctios. (a) () = si (b) () = l( + ) (c) () = cos 4 2. Fid the Taylors series at or () = si at a = π 2. Fid the Taylors series at or () = l at a = e 4. Fid MacLauri series or the ollowig uctios usig a shortcut method. (a) () = 4 e (b) si( 2 ) (c) si(4) Page 5

C. Fidig the Radius o Covergece o a MacLauri or Taylors Series. To id the radius o covergece o a MacLauris or Taylors series we will use the ratio test as i previous eamples. Eample : What is the radius o covergece or the MacLauris series () = si( 2 ). Solutio: First we eed to id the MacLauris epasio or (). We ca use the shortcut method as we already kow that y = si (2 )! 2 so the MacLauris epasio or si 2 ( (2 )! (2 )! Net we use the ratio test. lim a + a = lim Sice the lim a + a coversio is R = 42 2 ) 2 ( ) + 4+6 (2+)! ( ) 4+2 (2+)! ( )+4+6 = lim (2+)! ( ) 4 (2+2)(2+) = lim = (2+)! ( ) 4+2 = < the series will coverge or all values o ad its radius o Page 6

Deiitio: The th - degree Taylor Polyomial o at a is a polyomial o degree deied as the irst (+) terms o its Taylors Series (icludig those terms which are zero) T() = k ( ) k ( a) k! ' T() = ( a) '' ( a) 2 ( a) ()... ( a)! ( ) Deiitio: The remaider series R() is deied as the power series ormed by usig the terms that are let rom the Taylors series so it will start at the (+) th power o ad is deied as. R () = k ( ) k ( a) k! ( 2) ( ) 2 = ( a) ( a)... ( a)... ( )! ( 2)! ( )! Aother way to look at this is that R()= () T(). These deiitios lead us to the result that () = T() + R() or all values o with a < R, or some value R provided that lim R () = or ay give value o iside the radius o covergece. It ca also be show that I (+) () M or all values o with a d the R () M( a)+ or all values o with a d (+)! This essetially meas that the remaider i a Tailors series is bouded by some multiple o the (+) th term. Eample 2. Use the MacLauris series or si usig T5() to estimate si(.2) ad give the error boud o this. Solutio: The Taylors series or th degree is T() = ' ( a) '' ( a) 2 ( a) ()... ( a)! ( ) The MacLauris series or () = si or th degree uses a = ad is deied as T5() = T5() = '() 5 5! () () () 5! '' () (4) (4) 2 4 5 ( ) Page 7

We ow eed to id a umber M that has the property (+) () M (6) () M cos M cos or all values o with a d or all values o with.2 d or all values o with.2 d or all values o with.2 d We ow use the remaider theorem which states that we use d =.2 as a choice or d. Sice we oly wish to id oe speciic value o the uctio we could make d very small (almost zero). R () M+ or all values o with a d (+)! R 5 () 6 or all values o with.2.2 6! R 5 () (.2)6 or all values o with.2.2 6! R 5 (). 5 or all values o with.2.2 Net we calculate T5(.2) = 5 (.2) (.2).2 =.972274 5! So we ca coclude that si(.2) =.9 72 2 ±. 5 Usig a calculator we i act get si(.2) =.9 722 7 ow thats accurate!!!!! Note: We used =.2 as that is the largest value o i the iterval.2.2 ad so is the largest possible error. Page 8