Non compensatory Multicriteria Methods

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Non compensatory Multicriteria Methods andrea.saltelli@jrc.ec.europa.eu 12 th JRC Annual Training on Composite Indicators & Multicriteria Decision Analysis (COIN 2014) European Commission Joint Research Centre Econometrics and Applied Statistics Unit Composite Indicators Research Group (JRC-COIN) Introduction 1

Can weights be used as importance coefficients? There is a theoretical inconsistency in the way weights are used in practice (e.g. in linear aggregation) and their real theoretical meaning. The Dean Example. Introduction 2

The linear aggregation paradox The linear aggregation paradox: weights are used as if they were importance coefficients while they are trade off coefficients Introduction 3

The linear aggregation paradox An example. A dean wants to rank teachers based on hours of teaching and number of publications. Unfortunately when adding these two variables up she sees that teachers are practically ranked by publications. Introduction 4

Dean s example: y=x 1 +x 2. Estimated R 12 = 0.0759, R 22 = 0.826, corr(x 1, x 2 ) = 0.151, V(x 1 ) = 116, V(x 2 ) = 614, V(y) = 162. X 1 : hours of teaching X 2 : number of publications Introduction 5

The linear aggregation paradox To obviate this the dean substitutes the model y=1/2(x 1 +x 2 ) with y=0.7x 1 +0.3x 2 X 1 : hours of teaching X 2 : number of publications A professor comes by, looks at the last formula, and complains that publishing is disregarded in the department Introduction 6

Introduction 7

Moral of the story - Linear aggregation only possible under special circumstances (eg standardized variables, uniform covariance matrix ) Introduction 8

Can weights be used as importance coefficients? There is a theoretical inconsistency in the way weights are used in practice (e.g. in linear aggregation) and their real theoretical meaning. For the weights to be interpreted as importance coefficients (the greatest weight is placed on the most important dimension ) non-compensatory aggregation procedures must be used to construct composite indicators. Introduction 9

MCA problem In a multi-criteria problem, there is no solution optimising all the criteria at the same time (the socalled ideal or utopia solution) and therefore compromise solutions have to be found. Introduction 10

Compensability The aggregation of several criteria implies taking a position on the fundamental issue of compensability. Compensability refers to the existence of trade-offs, i.e. the possibility of offsetting a disadvantage on some criteria by an advantage on another criterion. Introduction 11

Compensability Compensability E.g. in the construction of a composite indicator of human development a compensatory logic (using equal weighting) would imply that one is willing to accept 10% less enrolling in secondary education in exchange of a 10% increase in GDP. Introduction 12

Social choice theory methods Social choice theory methods would be ideally suited for building meaningful aggregated indicators and were already available between the end of the XIII and the XV century, but almost everybody uses linear aggregation Introduction 13

Notes to the previous page Ramon Llull (ca. 1232 ca. 1315) proposed first what would then become known as the method of Condorcet. Nicholas of Kues (1401 August 11, 1464), also referred to as Nicolaus Cusanus and Nicholas of Cusa developed what would later be known as the method of Borda. Nicolas de Condorcet, (17 September 1743 28 March 1794) developed the method eponimous. His Sketch for a Historical Picture of the Progress of the Human Spirit (1795) can be considered as an ideological foundation for evidence based policy (modernity at its best!). Jean-Charles, chevalier de Borda (May 4, 1733 February 19, 1799) developed the Borda count. Introduction 14

All examples and discussion based on: Introduction 15

See also: Step 1. Developing a theoretical framework Step 2. Selecting indicators Step 3. Multivariate analysis Step 4. Imputation of missing data Step 5. Normalisation of data Step 6. Weighting and aggregation Step 7. Robustness and sensitivity Step 8. Association with other variables Step 9. Back to the details (indicators) Step 10. Presentation and dissemination Introduction 16

Voting = Multi Criteria = Composite Indicator Social choice theory = Multi Criteria Analysis (see Social Choice and Multi Criteria Decision Making by Kenneth Arrow and Herve Raynaud, 1986). But the same theory also works for building composite indicators. Introduction 17

Voting = Multi Criteria = Composite Indicators Voters voting for candidates are equivalent to Criteria voting for options which is equivalent to.indicators voting for countries Introduction 18

A simple composite Indicator An impact matrix Indic. GDP Unemp. Rate Solid wastes Income dispar. Crime rate Country A 25,000 0.15 0.4 9.2 40 B 45,000 0.10 0.7 13.2 52 C 20,000 0.08 0.35 5.3 80 weights.166.166 0.333.166.166 We can say that indicator GDP votes for B>A>C (countries / options) Introduction 19

What information can be derived from the impact matrix? Intensity of preference (the value of the indicator/criterion) Number of indicators/criterions in favour of a given country/option Introduction 20

What information can be derived from the impact matrix? Weight attached to each indicator/criterion Relative Performance of each country/option with respect to each of the other countries/option Combinations of this ingredients generate different aggregation conventions Introduction 21

Indic. GDP Unemp. Rate Solid wastes Income dispar. Andrea Country Saltelli A 25,000 0.15 0.4 9.2 40 B 45,000 0.10 0.7 13.2 52 C 20,000 0.08 0.35 5.3 80 weights.166.166 0.333.166.166 Crime rate # of indicators 2 1 1 1 1st position c b c a 2nd position a a b b 3rd position b c a c GDP: UR: SW: ID: CR: B>A>C C>B>A C>A>B C>A>B A>B>C Introduction 22

Building a frequency matrix Different ways to organize the same information: # of indicators 2 1 1 1 Rank a b c 1st position c b c a 2nd position a a b b 3rd position b c a c 1st 1 1 3 2nd 3 2 0 3rd 1 2 2 Three countries [options/candidates] and five indicators [criteria/voters] Introduction 23

Example (Moulin): 21 criteria/voters/indicators and 4 option/candidate/countries Objective: find best country A first possibility: apply the plurality rule the country which is more often ranked in the first position is the winning one. Country a is the best (8/21). # of indicators 3 5 7 6 1st position a a b c 2nd position b c d b 3rd position c b c d 4th position d d a a BUT Country a is also the one with the strongest opposition since 13/21 indicators put it into the last position! This paradox was the starting step of Borda s and Condorcet s research at the end of the 18th century, but the plurality rule corresponds to the most common electoral system in the 21st century! Introduction 24

Plurality rule paradox Two main lessons can be learned from the plurality rule paradox: Good ranking procedures should consider the whole ranking of countries and not the first position only. It is important to consider not only what a majority of indicators prefers but also what they do not prefer at all. Borda & Condorcet solution to the plurality rule paradox next Introduction 25

Borda s approach: the Borda count Frequency matrix (Moulin, 21 criteria 4 options) Rank a b c d Points 1st 8 7 6 0 3 2nd 0 9 5 7 2 3rd 0 5 10 6 1 4th 13 0 0 8 0 Jean-Charles, chevalier de Borda Columns add up to the number of criteria/voters=21 Introduction 26

How was the frequency matrix generated? # of indicators 3 5 7 6 Rank a b c d Points 1st position a a b c 1st 8 7 6 0 3 2nd position b c d b 3rd position c b c d 4th position d d a a 2nd 0 9 5 7 2 3rd 0 5 10 6 1 4th 13 0 0 8 0 Frequency matrix (21 criteria 4 alternatives) Introduction 27

Borda s approach: how to use the frequency matrix Borda score: Borda solution: b c a d Now: country b is the best, no longer a, which was the winner when applying the plurality rule; The plurality rule paradox has been solved. a = 8 3= 24 b = 5+ 9 2+ 7 3= 44 c = 10 + 5 2 + 6 3 = 38 d = 6+ 7 2= 20 Rank a b c d Points 1st 8 7 6 0 3 2nd 0 9 5 7 2 3rd 0 5 10 6 1 4th 13 0 0 8 0 Frequency matrix (21 criteria 4 alternatives) Introduction 28

Borda s count The Borda count was developed independently several times, (e.g. by Nicolaus Cusanus beginning XV century) but is named for Jean-Charles de Borda, who devised the system in 1770. It is currently used for the election of two ethnic minority members of the National Assembly of Slovenia (source: Wikipedia En). It is used throughout the world by various organisations and competitions [e.g. in academia]. Introduction 29

Borda s count Borda was a mariner and a scientist. Worked on chronometers. Between 1777 and 1778, he participated in the American Revolutionary War. The French Academy of Sciences used Borda's method to elect its members for about two decades [till Napoleon Bonaparte became president ]. Introduction 30

Nicolas de Caritat, marquis de Condorcet (17 September 1743 28 March 1794), known as Nicolas de Condorcet, was a philosopher, mathematician, and early political scientist [ ] advocated a liberal economy, free and equal public education, [ ] equal rights for women [ ] He died a mysterious death during the French revolution. Introduction 31

Condorcet s outscoring matrix (21 criteria 4 alternatives) # of indicators 3 5 7 6 1st position a a b c 2nd position b c d b 3rd position c b c d 4th position d d a a Frequency matrix a b c d a b c d 0 8 8 8 13 0 10 21 13 11 0 14 13 0 7 0 Outscoring matrix Introduction 32

How to move from frequency to outscoring? # of indicators 3 5 7 6 1st position a a b c 2nd position b c d b 3rd position c b c d 4th position d d a a Frequency matrix a b c d a b c d 0 8 8 8 13 0 10 21 13 11 0 14 13 0 7 0 Outscoring matrix Introduction 33

Condorcet s outscoring matrix (21 criteria 4 alternatives) For each pair of countries a concordance index is computed by counting how many indicators/voters are in favour of each country (e.g. 13 voters prefer b to a ). Note the constant sum property in the outranking matrix (13+8=21 number of indicators/voters) a b c d a b c d 0 8 8 8 13 0 10 21 13 11 0 14 13 0 7 0 Outranking matrix Introduction 34

How to use Condorcet s outscoring matrix (21 criteria 4 alternatives) Pairs with concordance index > 50% of the indicators/voters are considered: majority threshold = 11 (i.e. a number of voters > 50% of voters=21) Thus bpa= 13, bpd=21(=always), cpa=13, cpb=11, cpd=14, dpa=13. c is better than a,b,d so it is the winner b is better than the remaining a,d, it is the second best d is better than a. Condorcet solution: c b d a a b c d a b c d 0 8 8 8 13 0 10 21 13 11 0 14 13 0 7 0 Count row-wise discarding entries < 11 as there are 21voters/criteria Introduction 35

Which approach should one prefer? Both Borda and Condorcet approaches solve the plurality rule paradox. However, the solutions offered are different. Borda solution: b c a d Condorcet solution: c b d a In the framework of composite indicators, can we choose between Borda and Condorcet on some theoretical and/or practical grounds? Introduction 36

Which approach should one prefer? Some difficulties Introduction 37

Example with 3 options, 60 indicators/voters [Condorcet s own example, 1785] Number of indicators 23 17 2 10 8 1st a b b c c 2nd b c a a b 3rd c a c b a Borda approach Frequency matrix Rank a b c Points 1st 23 19 18 2 2nd 12 31 17 1 3rd 25 10 25 0 Borda count: a = 58, b= 69, c = 53 Condorcet approach a b c Outranking matrix a b c 0 33 25 27 0 42 35 18 0 Concordance threshold =31 apb, bpc and cpa (cycle)??? Introduction 38

Borda wins or not? From this example we might conclude that the Borda rule is more effective since a country is always selected while the Condorcet one sometimes leads to an irreducible indecisiveness. However Borda rules have other drawbacks, too Introduction 39

Fishburn Example (1984) on Borda Rule (7 indicators 4 alternatives) Borda score: a = 13, b= 12, c = 11, d = 6 a b c d So far, so good Rank a b c d Points 1st 2 2 3 0 3 2nd 2 3 0 2 2 3rd 3 0 2 2 1 4th 0 2 2 3 0 Introduction 40

Taking away an irrelevant country/option (d) a new frequency matrix is generated Rank a b c d Points 1st 2 2 3 0 3 2nd 2 3 0 2 2 3rd 3 0 2 2 1 4th 0 2 2 3 0 a b c d Rank a b c Points 1st 2 2 3 2 2nd 2 3 0 1 3rd 3 0 2 0 a=6,b=7,c=6 Now: b (c,a) i.e. a reversal! Unfortunately, Borda rule is fully dependent on irrelevant options and preference reversals can happen with an extreme high frequency Introduction 41

Implications for football Disqualifying a poor club may result in a different team winning the championship! Introduction 42

Which approach should one prefer? Given that there is a consensus in the literature that the Condorcet theory of voting is noncompensatory while Borda s one is compensatory, when one wishes to have weights as importance coefficients then Condorcet should be used. Introduction 43

Condorcet s approach Basic problem: presence of cycles, i.e. apb, bpc and cpa The probability of obtaining a cycle increases with both N. of indicators) and N. of countries Introduction 44

Condorcet s approach Condorcet himself was aware of this problem (he built examples to explain it) and he was even close to find a consistent rule able to rank any number of alternatives when cycles are present but Introduction 45

Condorcet s approach Basic problem: presence of cycles, i.e. apb, bpc and cpa Furter attempts made by Kemeny (1959) and by Young and Levenglick (1978) led to: Condorcet-Kemeny-Young-Levenglick (C-K-Y-L) ranking procedure Introduction 46

C-K-Y-L ranking procedure Main methodological foundation: maximum likelihood concept. The maximum likelihood principle selects as a final ranking the one with the maximum pair-wise support. What does this mean and how does it work? Introduction 47

C-K-Y-L ranking procedure We go back to Condorcet s own example, 60 criteria 3 alternatives concordance threshold =31 Based on the Cordorcet: apb 33, bpc 42 and cpa 35 (cycle). Outranking matrix a b c a 0 33 25 b 27 0 42 c 35 18 0 Introduction 48

C-K-Y-L ranking procedure Outranking matrix a b c a 0 33 25 b 27 0 42 c 35 18 0 But bpa=27, cpb=18 and apc=25 were not used as below the concordance threshold. Let us use them now: Support of permutation abc = =apb+apc+bpc =33+25+42=100 Support of permutation bca= =bpc+bpa+cpa = 42+27+35=104 and so on for all 3! permutations of three elements a,b,c Introduction 49

Computing the support for all permutations a b c a b c 0 33 25 27 0 42 35 18 0 Outranking matrix a b c 100 b c a 104 c a b 86 b a c 94 c b a 80 a c b 76 In conclusion: b c a Support Introduction 50

a b c Likelihood a b c 0 33 25 27 0 42 35 18 0 a b c 100 b c a 104 c a b 86 b c a Is the solution with the b a c 94 highest support c b a 80 likelihood a c b 76 The original Condorcet problem has been solved in a satisfactory way by the C-K-Y-L. Introduction 51

C-K-Y-L ranking procedure Indic. GDP Unemp. Rate Solid wastes Income Crime rate dispar. Country A 25,000 0.15 0.4 9.2 40 B 45,000 0.10 0.7 13.2 52 C 20,000 0.08 0.35 5.3 80 weights.166.166 0.333.166.166 When is A>B? On GDP? No On unempl.? No On waste? Yes On disparity? Yes On crime? Yes AB = 0.333+0.166+0.166=0.666 BA = 0.166+0.166=0.333 AC = 0.166+0.166=0.333 CA = 0.166+0.333+0.166=0.666 BC = 0.166+0.166=0.333 CB = 0.166+0.333+0.166=0.666 Introduction 52

C-K-Y-L ranking procedure Indic. GDP Unemp. Rate Solid wastes Income dispar. Crime rate Country A 25,000 0.15 0.4 9.2 40 B 45,000 0.10 0.7 13.2 52 C 20,000 0.08 0.35 5.3 80 weights.166.166 0.333.166.166 A B C A B C 0 0.666 0.333 0.333 0 0.333 0.666 0.666 0 AB = 0.333+0.166+0.166=0.666 BA = 0.166+0.166=0.333 AC = 0.166+0.166=0.333 CA = 0.166+0.333+0.166=0.666 BC = 0.166+0.166=0.333 CB = 0.166+0.333+0.166=0.666 Introduction 53

C-K-Y-L ranking procedure Indic. GDP Unemp. Rate Solid wastes Income Crime rate dispar. Country A 25,000 0.15 0.4 9.2 40 B 45,000 0.10 0.7 13.2 52 C 20,000 0.08 0.35 5.3 80 weights.166.166 0.333.166.166 BCA = 0.333 + 0.333 + 0.666 = 1.333 A B C A B C 0 0.666 0.333 0.333 0 0.333 0.666 0.666 0 ABC = 0.666 + 0.333 + 0.333 = 1.333 CAB = 0.666 + 0.666 + 0.666 = 2 ACB = 0.333 + 0.666 + 0.666 = 1.666 CBA = 0.666 + 0.333 + 0.666 = 1.666 BAC = 0.333 + 0.333 + 0.333 = 1 Introduction 54

C-K-Y-L ranking procedure The Computational problem The only drawback of this aggregation method is the difficulty in computing it when the number of candidates grows. With only 10 countries 10! = 3,628,800 permutations (instead of 3!=6 of the example) To solve this problem one needs to use numerical algorithms (see references) Introduction 55

Related Reading Borda J.C. de (1784) Mémoire sur les élections au scrutin, in Histoire de l Académie Royale des Sciences, Paris. Condorcet, Marquis de (1785) Essai sur l application de l analyse à la probabilité des décisions rendues à la probabilité des voix, De l Imprimerie Royale, Paris. Fishburn P.C. (1973) The theory of social choice, Princeton University Press, Princeton. Fishburn P.C. (1984) Discrete mathematics in voting and group choice, SIAM Journal of Algebraic and Discrete Methods, 5, pp. 263-275. Introduction 56

Related Reading Munda G. (1995), Multicriteria evaluation in a fuzzy environment, Physica-Verlag, Contributions to Economics Series, Heidelberg. Munda G. (2004) Social multi-criteria evaluation (SMCE) : methodological foundations and operational consequences, European Journal of Operational Research, vol. 158/3, pp. 662-677. Munda G. (2005a) Multi-Criteria Decision Analysis and Sustainable Development, in J. Figueira, S. Greco and M. Ehrgott (eds.) Multiple-criteria decision analysis. State of the art surveys, Springer International Series in Operations Research and Management Science, New York, pp. 953-986. Munda G. (2005b) Measuring sustainability : a multi-criterion framework, Environment, Development and Sustainability Vol 7, No. 1, pp. 117-134. Munda G. and Nardo M. (2005) - Constructing Consistent Composite Indicators: the Issue of Weights, EUR 21834 EN, Joint Research Centre, Ispra. Munda G. and Nardo M. (2007) - Non-compensatory/Non-Linear composite indicators for ranking countries: a defensible setting, Forthcoming in Applied Economics. Munda G. (2007) - Social multi-criteria evaluation, Springer-Verlag, Heidelberg, New York, Economics Series Introduction 57

Click to edit Master text styles Second level Third level Fourth level Fifth level Introduction 58