Euclidian Geometry Grade 10 to 12 (CAPS) Compiled by Marlene Malan marlene.mcubed@gmail.com Prepared by Marlene Malan
CAPS DOCUMENT (Paper 2) Grade 10 Grade 11 Grade 12 (a) Revise basic results established in earlier grades. (b) Investigate line segments joining the midpoints of two sides of a triangle. (c) Properties of special quadrilaterals. (a) Investigate and prove theorems of the geometry of circles assuming results from earlier grades, together with one other result concerning tangents and radii of circles. (b) Solve circle geometry problems, providing reasons for statements when required. (c) Prove riders. (a) Revise earlier (Grade 9) work on the necessary and sufficient conditions for polygons to be similar. (b) Prove (accepting results established in earlier grades): that a line drawn parallel to one side of a triangle divides the other two sides proportionally (and the Mid-point Theorem as a special case of this theorem); that equiangular triangles are similar; that triangles with sides in proportion are similar; the Pythagorean Theorem by similar triangles; riders. REVISION FROM EARLIER GRADES SIMILARITY AAA or SSS CONGRUENCY SSS AAS SAS (included angle) RHS
PROPERTIES OF SPECIAL QUADRILATERALS PARALLELOGRAM Both pairs of opposite sides are parallel Both pairs of opposite side are equal Both pairs of opposite angles are equal Diagonals bisect each other RECTANGLE All properties of parallelogram PLUS: Both diagonals are equal in length All interior angles are equal to 90 RHOMBUS All properties of parallelogram PLUS: All sides are equal Diagonals bisect each other perpendicularly Diagonals bisect interior angles SQUARE All properties of a rhombus PLUS: All interior angles are 90 Diagonals are equal in length KITE Two pairs of adjacent sides are equal Diagonal between equal sides bisects other diagonal One pair of opposite angles are equal (unequal sides) Diagonal between equal sides bisects interior angles (is axis of symmetry) Diagonals intersect perpendicularly TRAPEZIUM One pair of opposite sides are parallel HOW TO PROVE THAT A QUADRILATERAL IS A PARALLELOGRAM Prove any ONE of the following: Prove that both pairs of opposite sides are parallel Prove that both pairs of opposite sides are equal Prove that both pairs of opposite angles are equal Prove that the diagonals bisect each other Prove that ONE pair of sides are equal and parallel
HOW TO PROVE THAT A PARALLLELOGRAM IS A RHOMBUS Prove ONE of the following: Prove that the diagonals bisect each other perpendicularly Prove that any two adjacent sides are equal in length TRIANGLES BETWEEN PARALLEL LINES The AREA of two triangles on the SAME (OR EQUAL) BASE between two parallel lines, are EQUAL. Area of = Area of MIDPOINT THEOREM The line segment joining the midpoints of two sides of a triangle, is parallel to the third side of the triangle and half the length of that side. ( Midpt Theorem ) If AD = DB and AE = EC, then DE ǁ BC and DE = BC CONVERSE OF MIDPOINT THEOREM If a line is drawn from the midpoint of one side of a triangle parallel to another side, that line will bisect the third side and will be half the length of the side it is parallel to. ( line through midpoint to 2nd side ) If AD = DB and DE ǁ BC, then AE = EC and DE = BC.
GRADE 11 GEOMETRY Note: THEOREMS OF WHICH PROOFS ARE EXAMINABLE ARE INDICATED WITH Theorem 1 Converse of Theorem 1 If AC = CB in circle O, then OC AB. If OC chord AB, then AC = BC. (line from centre to midpt of chord) (line from centre to chord) Theorem 2 The angle at the centre of a circle subtended by an arc/a chord is double the angle at the circumference subtended by the same arc/chord. AO B=2 AC B ( at centre = 2 at circumference ) Theorem 3 Converse of Theorem 3 The angle on the circumference subtended by If =90, then AB is the diameter the diameter, is a right angle. of the circle. The angle in a semi-circle is 90. ( s in semi circle OR (chord subtends 90 OR diameter subtends right angle) converse s in semi circle)
Theorem 4 Converse of Theorem 4 The angles on the circumference of a If a line segment subtends equal angles circle subtended by the same arc or at two other points, then these four points chord, are equal. lie on the circumference of a circle. ( s in the same seg) (line subtends equal s OR converse s in the same seg) Corollary of Theorem 4 Equal chords subtend equal Equal chords subtend equal angles Equal chords of equal circles angles at the circumference at the centre of the circle. subtend equal angles at the of the circle. circumference. (equal chords; equal s) (equal chords; equal s) (equal circles; equal chords; equal s) Theorem 5 Converse of Theorem 5 The opposite angles of a cyclic quadrilateral are supplementary. =180 180 (opp s of cyclic quad ) If the opposite angles of a quadrilateral are supplementary, then it is a cyclic quadrilateral. ( opp s quad sup OR converse opp s of cyclic quad )
Theorem 6 Converse of Theorem 6 The exterior angle of a cyclic quadrilateral If the exterior angle of a quadrilateral is equal is equal to the opposite interior angle. to the opposite interior angle, then it is a cyclic quadrilateral. (ext of cyclic quad ) (ext = int opp OR converse ext of cyclic quad) Theorem 7 Converse of Theorem 7 The tangent to a circle is perpendicular to the If a line is drawn perpendicularly to the radius radius at the point of tangency. through the point where the radius meets the circle, then this line is a tangent to the circle. ( tan radius OR ( line radius OR converse tan radius OR tan diameter ) converse tan diameter ) Theorem 8 If two tangents are drawn from the same point outside a circle, then they are equal in length. (tans from common pt OR Tans from same pt )
Theorem 9 (Tan chord theorem) Converse of Theorem 9 The angle between the tangent to a circle and a chord drawn from the point of tangency, is equal to the angle in the opposite circle segment. If a line is drawn through the endpoint of a chord to form an angle which is equal to the angle in the opposite segment, then this line is a tangent. ( tan chord theorem ) ( converse tan chord theorem OR between line and chord ) Acute angle Obtuse angle THREE WAYS TO PROVE THAT A QUADRILATERAL IS A CYCLIC QUADRILATERAL Prove that : one pair of opposite angles are supplementary the exterior angle is equal to the opposite interior angle two angles subtended by a line segment at two other vertices of the quadrilateral, are equal.
GRADE 12 GEOMETRY The Concept of Proportionality (Revision) A 6 cm B 4 cm C D 9 cm E 6 cm F AB : BC = 6 : 4 = 3 : 2 and DE : EF = 9 : 6 = 3 : 2 Although, AB : BC = DE : EF it does NOT mean that AB = DE, AC = DF or BC = EF. Theorem 1 Converse of Theorem 1 A line drawn parallel to one side of a triangle If a line divides two sides of a triangle proporthat intersects the other two sides, will divide tionally, then the line is parallel to the third the other two sides proportionally. side of the triangle. ( line one side of Δ ( line divides two sides of Δ in prop ) OR prop theorem; name lines ) If DE ǁ BC then = or AD : DB = AE : EC If = then DE ǁ BC. Theorem 2 (Midpoint Theorem) Converse of Theorem 2 (Special case of Theorem 1) The line segment joining the midpoints of two If a line is drawn from the midpoint of one sides of a triangle, is parallel to the third side side of a triangle parallel to another side, that of the triangle and half the length of that side. line will bisect the third side and will be half the length of the side it is parallel to. ( midpt theorem ) ( line through midpt to 2 nd side ) If AD = DB and AE = EC, then DE ǁ BC and DE = BC If AD = DB and DE ǁ BC, then AE = EC and DE = BC.
Theorem 3 Converse of Theorem 3 The corresponding sides of two equiangular triangles are proportional and consequently the triangles are similar. If the sides of two triangles are proportional, then the triangles are equiangular and consequently the triangles are similar. ( Δs OR equiangular Δs ) ( Sides of Δ in prop ) If then If then Theorem 4 The perpendicular drawn from the vertex of the right angle of a right-angled triangle, divides the triangle in two triangles which are similar to each other and similar to the original triangle. Corollaries of Theorem 4... Theorem 5 (The Theorem of Pythagoras) From the corollaries it can be proven that:
TIPS TO SOLVING GEOMETRY RIDERS READ-READ-READ the information next to the diagram thoroughly TRANSFER all given information to the DIAGRAM Look for KEYWORDS, e.g. TANGENT: What do the theorems say about tangents? CYCLIC QUADRILATERAL: What are the properties of a cyclic quad? NEVER ASSUME something! - Don t assume that a certain line is the DIAMETER of a circle unless it is clearly state or unless you can prove it - Don t assume that a point is the CENTRE of a circle unless it is clearly stated ( circle M means the circle with midpoint M ) Set yourself SECONDARY GOALS, e.g. - To prove that = (primary goal), first prove that = (secondary goal) and vice versa - To prove that line AC is a tangent (primary goal), first prove that the line is perpendicular to radius OB (secondary goal) AC is tangent - To prove that BC is the diameter of the circle (primary goal), first prove that = 90 (secondary goal) BC is the diameter of the circle For questions like: Prove that. Start with ONE PART. Move to the OTHER PART step-by-step stating reasons. Remember it has to be clear and logical to the reader! E.g. = ; = ; = ; =
GRADE 11 GEOMETRY SAMPLE QUESTIONS Question 1 AB and CD are two chords of the circle with centre O., AF = FB, OE = 4 cm, OF = 3 cm and AB = 8 cm. Calculate the length of CD. [8] Question 2 Question 3 O is the centre of the circle. STU is a tangent at T. BC = CT 105 and =40 Calculate, giving reasons, the size of: 2.1 (2) 2.2 (2) 2.3 (3) 2.4 (6) [13] 3.1 Write down with reasons four other angles which are equal to. (8) 3.2 Prove that ABC EDC. (4) 3.3 Prove that =. (2) [14] Question 4 O is the centre of the circle. BC = CD Express the following in terms of : 4.1 (2) 4.2 (3) 4.3 (4) [9]
Question 5 LOM is the diameter of circle LMT. The centre of the circle is O. TN is a tangent at T. Prove that: 5.1 MNPT is a cyclic quadrilateral. (3) 5.2 NP = NT (6) [9] Question 6 PA and PC are tangents to the circle at C and A. AD ǁ PC and PD intersects the circle at B. Prove that: 6.1 bisects (6) 6.2 (6) 6.3 (4) [16] Question 7 TA is a tangent to the circle. M is the centre of chord PT.. O is the centre of the circle. Prove that: 7.1 MTAR is a cyclic quadrilateral. (3) 7.2 PR = RT (4) 7.3 TR bisects PTA (4) 7.4 (4) [15]
GRADE 12 GEOMETRY SAMPLE QUESTIONS Example Given: : 2:3 and. Instruction: Determine the ratio of :. Solution: In : = But it was given that = = = = = In : = = :=15:8 Question 1 =22, 33, 15. Calculate the value of. [4] Question 2,= : 4:3 Determine the ratio :. [8] Question 3, : 1:2. 3.1 Write down the values of : and :. (2) 3.2 Determine : (1) 3.3 Prove that. (6) [9]
Question 4 Given: Prove that. [4] Question 5 is inscribed in a circle.,= PR is the diameter of the circle. Prove that: 5.1 (2) 5.2 O is the centre of the circle (2) 5.3 BORT is a trapezium. (2) [6] Question 6 Given: :=5:4 : 5:2 S is the midpoint of AQ 6.1 Prove that 2 (8) 6.2 If, determine : (6) [14] Question 7 Rectangle DEFK is drawn inside right-angled ABC. Prove that: 7.1.=. (4) 7.2 :=: (4) 7.3 :=: (1) 7.4 = (3) [12]
Question 8 ABOC is a kite with = =90 8.1 Why is? (2) 8.2 Complete: 8.2.1 =... 8.2.2 =... 8.2.3 =... (3) 8.3 Prove that = (3) 8.4 Prove that =. (2) 8.5 If = =, prove that = 2. (2) [12]
MIXED EXERCISES 1. In the diagram, TBD is a tangent to circles BAPC and BNKM at B. AKC is a chord of the larger circle and is also a tangent to the smaller circle at K. Chords MN and BK intersect at F. PA is produced to D. BMC, BNA and BFKP are straight lines. Prove that: a) MN ǁ CA b) is isosceles c) = d) DA is a tangent to the circle passing through points A, B and K. 2. In the diagram below, chord BA and tangent TC of circle ABC are produced to meet at R. BC is produced to P with RC=RP. AP is not a tangent. Prove that: a) ACPR is a cyclic quadrilateral. b) c) =. d).=. e) Hence prove that =. 3. In the diagram alongside, circles ACBN and AMBD Intersect at A and B. CB is a tangent to the larger circle at B. M is the centre of the smaller circle. CAD and BND are straight lines. Let = a) Determine the size of in terms of. b) Prove that: i) CB ǁ AN ii) AB is a tangent to circle ADN.
4. In the diagram below, O is the centre of circle ABCD. DC is extended to meet circle BODE at point E. OE cuts BC at F. Let =. a) Determine in terms of. b) Prove that: i) BE=EC ii) BE is NOT a tangent to circle ABCD. 5. In the diagram alongside, medians AM and CN of intersect at O. BO is produced to meet AC at P. MP and CN intersect in D. ORǁMP with R on AC. a) Calculate, giving reasons, the numerical value of. b) Use :=2:3, to calculate the numerical value of. 6. In the diagram, AD is the diameter of circle ABCD. AD is extended to meet tangent NCP in P. Straight line NB is extended to Q and intersect AC in M with Q on straight line ADP. AC NQ at M. a) Prove that NQ ǁ CD. b) Prove that ANCQ is a cyclic quadrilateral. c) i) Prove that. ii) Hence, complete: = d) Prove that =. e) If it is further given that PC=MC, prove that 1. =.
SOLUTIONS TO MIXED EXERCISE 1. a) = tan chord = = corr s = b) = alt s = tan chord is isosceles c ) = alt s = = s in same segment s in same segment = alt s= line to one side of But line to one side of d) = s in same segment = equal chords subt equal s = is a tangent to the circle through A, B and K 2. a) = s opp equal sides = ext of = tan chord = = both = ACPR is a cyclic quadrilateral (ext of quad) b) In and : c) = = = = s in same segment proven in 2 a ext of cyclic quad 3 rd of. from 2 b but = =. d) In and : = tan chord is common = 3 rd angle
e).=. = = from 2. b) RC=RP =. From 2.d) =.. =. =. 3. a) = = s opp equal sides =180 2 =2 sum s of b. i) at centre =2x circ 90 180 (90 2 sum s of 90 90 ext of cyclic quad corr s b. ii) = =2 tan chord AB is a tangent alt s betw line&chord 4. a) s in same segment s opp = sides 180 2 sum s of =90 at centre =2x at circumference b. i) 90 ext of cyclic quad 180 (90 sum s of =90 In and : = =90 BF = FC FE is common BE = EC s on str line s s b. ii) =90 sum s of = BE is not a tangent
5. a) P is midpoint of AC medians concur AB PM midpt theorem In : = = line one side of = = b) In : = = = = = BP is a median line one side of 6. a) =90 in semi =90 AM NM corr s= b) = lines, corr s = tan chord = ANCQ is a cyclic quad s subt by same line segm c) i) In and : = is common tan chord = 3 rd c) ii) =. d) In and : = s in same segm = s in same segm = tan chord = s in same segm = 3 rd. e 1 =.. Pyth.