Stratification of 3 3 Matrices

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Stratification of 3 3 Matrices Meesue Yoo & Clay Shonkwiler March 2, 2006 1 Warmup with 2 2 Matrices { Best matrices of rank 2} = O(2) S 3 ( 2) { Best matrices of rank 1} S 3 (1) 1.1 Viewing O(2) S 3 ( 2) {( cos θ sin θ O(2) = sin θ cos θ )} {( cos θ sin θ sin θ cos θ Both of two components are intersections of 2-plane with S 3 ( 2), hence great circles which are orthogonal, and linked with on another in S 3 ( 2). S 3 ( 2) = Nbhd of SO(2) Nbhd of O (2)(= SO(2) O(2)), where each tubular nbhd is a solid torus and their common boundary is a Clifford torus in S 3 ( 2), consisting of matrices of rank 1. The Clifford torus is a minimal surface in S 3. )} Gauss Theorem for T 2 S 3 : K(X, Y ) K(X, Y ) = 0 1 = 1 < B(X, X), B(Y, Y ) > B(X, Y ) 2 =< N, N >= 1. 1.2 Symmetries of the stratification of 2 2 matrices The orthogonal group O(2) acts on the space of 2 2 matrices by either left or right multiplication left and right multiplications are isometry, orientation preserving, and preserves the various strata of M(2) and their cores. The combined map A E 1 AE 1 2 gives an isometric action of O(2) O(2) on M(2). 1

1.3 Alexander duality If C is a closed subset of S n, then Alexander duality says The free part of H k (C; Z) is isomorphic to the free part of H n k 1 (S n C; Z), where we use reduced homology. The torsion part of H k (C; Z) is isomorphic to the torsion part of H n k 2 (S n C; Z). H 1 (O(2); Z) = Z + Z. S 3 ( 2) O(2) deformation retracts to the Clifford torus T 2. H 1 (T 2 ; Z) = Z + Z. H 2 (T 2 ; Z) = Z, and the reduced 0-dim l homology of S 3 T 2 is also = Z, reminding us that it is disconnected. 2 Stratification of 3 3 Matrices M(3) = set of all 3 3 matrices = R 9 Euclidean inner product < A, B >= trab t = a ij b ij {Best matrices of rank 3} = O(3) S 8 ( 3) {Best matrices of rank 2} S 8 ( 2) {Best matrices of rank 1} S 8 (1). 2.1 Symmetries of the stratification of 3 3 matrices The map A E 1 AE 1 2 gives an isometric action of O(3) O(3) on M(3). It is clearly transitive on O(3) S 8 ( 3). 2.2 Viewing O(3) S 8 ( 3) SO(3) S 8 ( 3) is isometric to the RP 3 which is double covered by S 3 (2 2). The closed geodesics on SO(3) are small circles of radius 2 on S 8 ( 3). 2

2.3 Tubular neighborhood of O(3) in S 8 ( 3) Left (or right) action of SO(3) on S 8 ( 3) acts simply transitively on each of SO(3) and O (3). The tubular nbhds of SO(3) and of O (3) in S 8 ( 3) are product bundles, with fibre a 5-cell. The largest possible tubular nbhds of SO(3) and O (3) in S 8 ( 3) are the two components of GL(3, R) S 8 ( 3). The fibres will be open 5-cells lying on the great 5-spheres which meet O(3) orthogonally. But these 5-cells will not be round as is the case of 2 2 matrices. Instead, they will be elongated in some directions, and foreshortened in others. 2.4 Shape of the 5-cell fibres Consider the great 5-sphere in S 8 ( 3) orthogonal to SO(3) at the identity. Note that its tangent space at the identity consists of symmetric 3 3 matrices with trace 0. We want to see how far one can go out from the identity along this 5-sphere before coming to a singular matrix. The isotropy subgroup of the identity in the symmetry group SO(3) SO(3) consists of SO(3) acting by conjugation, so, under this action, any traceless symmetric matrix can be written in the normal form diag(λ 1, λ 2, λ 3 ) where λ 1 λ 2 λ 3 and λ 1 + λ 2 + λ 3. Scaling so that λ 2 1 + λ2 2 + λ2 3 = 3, the great circle through the identity in the direction of this matrix is given by diag(cos t + λ 1 sin t, cos t + λ 2 sin t, cos t + λ 3 sin t), so this great circle first hits a singular matrix when t = cot 1 λ 3, which, depending on the λ i, varies from 0.196π to 0.304π. Each such value corresponds to an orbit of the conjugation action of SO(3) on a 4-sphere in the space of symmetric traceless 3 3 matrices. Orbit structure: note that each orbit contains a traceless matrix diag(λ 1, λ 2, λ 3 ) with λ 1 λ 2 λ 3. When the λ i are distinct, the subgroup of SO(3) fixing this matrix is isomorphic to Z/2 Z/2, so the orbit is diffeomorphic to SO(3)/Z/2 Z/2. The middle orbit occurs when λ 2 = 0 3

and is minimal in the corresponding 4-sphere. There are two singular orbits diffeomorphic to a round RP 2 which occur when λ 1 = λ 2 and λ 2 = λ 3 ; these are also minimal in the corresponding 4-sphere. 2.5 O(3) is a minimal submanifold of S 8 ( 3) Straightforward covariant derivative computations demonstrate that O(3) S 8 ( 3) has vanishing mean curvature at the identity in SO(3); since the isometry group O(3) O(3) acts transitively, this suffices to show that O(3) is a minimal submanifold of S 8 ( 3). 2.6 3 3 matrices of rank 2 The set of rank 2 matrices is an 8-dimensional space separating M(3) into the two open components of GL(3, R), so {rank 2} meets S 8 (any radius) in a closed 7-dimensional set separating that 8-sphere into two open components. {rank 2} S 8 is singular along its subset {rank = 1} S 8. On the other hand, {rank = 2} is an 8-dimensional submanifold of M(3) and so {rank = 2} S 8 is a 7-dimensional submanifold of S 8. This is easy to see, since it is the pre-image of 0 under the determinant map, which has critical points only on rank 1 matrices. 2.7 {Best of rank 2} The best 3 3 matrices of rank 2 consist of orthogonal projections of R 3 to a 2-plane, followed by an orthogonal transformation to another 2-plane. Dimension-counting, we see that {Best of rank 2} is a 5-dimensional manifold, which is acted on transitively by the identity component SO(3) SO(3) of the symmetry group of our stratification. Considering P =. The isotropy subgroup in SO(3) consists of 1 0 0 0 1 0 0 0 0 cos t sin t 0 sin t cos t 0 0 0 1 and cos t sin t 0 sin t cos t 0 0 0 1 acting simultaneously from the left and the right. 4

Hence, {Best of rank 2} is homeomorphic to SO(3) SO(3) modulo this diagonal SO(2) subgroup. 2.8 {Best of rank 2} is a minimal submanifold of S 8 ( 2) To see that M 5 = {Best of rank 2} is a minimal submanifold of S 8 ( 2), a straightforward computation shows that the isotropy subgroup of P M 5 fixes no nonzero normal vector. This implies that the mean curvature vector at P must be zero (since it is fixed by the isotropy subgroup) and so, by symmetry, this is true at every point of M 5. 2.9 3 3 matrices of rank 1 The best 3 3 matrices of rank 1 consist of orthogonal projections of R 3 to a line, followed by an orthogonal transformation of this line to another line. In fact, the best of rank 1 are precisely the intersection {All of rank 1} S 8 (1). The identity component SO(3) SO(3) of symmetries acts transitively on the best of rank 1, with isotropy subgroup SO(2) SO(2). 2.10 A way to describe the best 3 3 matrices of rank 1 If X = (x 1, x 2, x 3 ), Y = (y 1, y 2, y 3 ), then (y i x j ) takes X to Y and kills X, so this is one of the best matrices of rank 1. All the best of rank 1 appear in this way twice, since taking X to Y is the same as taking X to Y. Hence, M 4 = {Best of rank 1} is homeomorphic to (S 2 S 2 )/{(X, Y ) ( X, Y )}, which is orientable. It s easy to see that S 2 S 2 {Best of rank 1} S 8 (1) is a local isometry. 2.11 The singularity at M 4 A geodesic through P = 1 0 0 0 0 0 0 0 0 orthogonal there to M 4 = {best of rank 1} = {rank 1} S 8 (1) has the form γ(t) = cos t 0 0 0 a sin t b sin t 0 c sin t d sin t. 5

( a b If c d ) has rank 1, then γ(t) has rank 2 for small t > 0. from our study of 2 2 matrices, we know the matrices of rank 1 form a cone over the Clifford torus, so the tubular neighborhood of {Best of rank 1} in {Best of rank 2 } S 8 (1) is a bundle over M 4 whose normal fiber is a cone over the Clifford torus. 2.12 {Best of rank 1} is a minimal submanifold of S 8 (1) This follows from a similar argument to that given above in the case of {Best of rank 2}: since the subgoup of the isometry group of our stratification that fixes a point of {Best of rank 1} fixes none of its normal vectors in S 8 (1) except 0, the mean curvature vector must be zero and so, by symmetry, the mean curvature is zero on all of {Best of rank 1}. 2.13 Topology of {Best of rank 1} Since M 4 = {Best of rank 1} is orientable and double covered by S 2 S 2 Thus, π 1 (M 4 ) Z/2, and so H 1 (M 4 ) Z/2. Using Poincaré duality, we see that H 0 Z, H 1 Z/2, H 2 free part + Z/2, H 3 0, H 4 Z. 2.14 Theorem of Wu-Yi Hsiang Theorem 2.1. (Wu-Yi Hsiang, 1966) Let G be a compact connected group of isometries of a Riemannian manifold M. Then any orbit of G, whose volume is extremal among nearby orbits of the same type, is a minimal submanifold of M. This theorem can be used to give alternate proofs of the minimality of many of the above submanifolds. 6