MOTION OF A CHARGED PARTICLE IN A UNIFORM MAGNETIC FIELD

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Transcription:

MOTION OF A CHARGED PARTICLE IN A UNIFORM MAGNETIC FIELD

When the velocity of a charged particle is perpendicular to a uniform magnetic field, the particle moves in a circular path in a plane perpendicular to B. The magnetic force FB acting on the charge is always directed toward the center of the circle.

A charged particle having a velocity vector that has a component parallel to a uniform magnetic field moves in a helical path.

Serway 29.31 The magnetic field of the Earth at a certain location is directed vertically downward and has a magnitude of 50.0 µt. A proton is moving horizontally toward the west in this field with a speed of 6.20 10 6 m/s. (a) What are the direction and magnitude of the magnetic force that the field exerts on this charge? (b) What is the radius of the circular arc followed by this proton?

Serway 29.31 The magnetic field of the Earth at a certain location is directed vertically downward and has a magnitude of 50.0 µt. A proton is moving horizontally toward the west in this field with a speed of 6.20 10 6 m/s. (a) What are the direction and magnitude of the magnetic force that the field exerts on this charge? (b) What is the radius of the circular arc followed by this proton? Answers: (a) southward, 4.96 10 17 N, (b)1.29 km

Serway 29.31 The magnetic field of the Earth at a certain location is directed vertically downward and has a magnitude of 50.0 µt. A proton is moving horizontally toward the west in this field with a speed of 6.20 10 6 m/s. (a) What are the direction and magnitude of the magnetic force that the field exerts on this charge? (b) What is the radius of the circular arc followed by this proton? Answers: (a) southward, 4.96 10 17 N, (b)1.29 km Serway 29.33 One electron collides elastically with a second electron initially at rest. After the collision, the radii of their trajectories are 1.00 cm and 2.40 cm. The trajectories are perpendicular to a uniform magnetic field of magnitude 0.044 0 T. Determine the energy (in kev) of the incident electron.

Serway 29.31 The magnetic field of the Earth at a certain location is directed vertically downward and has a magnitude of 50.0 µt. A proton is moving horizontally toward the west in this field with a speed of 6.20 10 6 m/s. (a) What are the direction and magnitude of the magnetic force that the field exerts on this charge? (b) What is the radius of the circular arc followed by this proton? Answers: (a) southward, 4.96 10 17 N, (b)1.29 km Serway 29.33 One electron collides elastically with a second electron initially at rest. After the collision, the radii of their trajectories are 1.00 cm and 2.40 cm. The trajectories are perpendicular to a uniform magnetic field of magnitude 0.044 0 T. Determine the energy (in kev) of the incident electron. Answers: 115 kev

Serway 29.16 A conductor suspended by two flexible wires as shown in the figure has a mass per unit length of 0.040 0 kg/m. What current must exist in the conductor for the tension in the supporting wires to be zero when the magnetic field is 3.60 T into the page? What is the required direction for the current?

Serway 29.16 A conductor suspended by two flexible wires as shown in the figure has a mass per unit length of 0.040 0 kg/m. What current must exist in the conductor for the tension in the supporting wires to be zero when the magnetic field is 3.60 T into the page? What is the required direction for the current? Answers: 0.109 A, to the right

Serway 29.19 A rod with a mass of 0.720 kg and a radius of 6.00 cm rests on two parallel rails that are d = 12.0 cm apart and L = 45.0 cm long. The rod carries a current of I = 48.0 A (in the direction shown) and rolls along the rails without slipping. If it starts from rest, what is the speed of the rod as it leaves the rails if a uniform magnetic field of magnitude 0.240 T is directed perpendicular to the rod and the rails?

Serway 29.19 A rod with a mass of 0.720 kg and a radius of 6.00 cm rests on two parallel rails that are d = 12.0 cm apart and L = 45.0 cm long. The rod carries a current of I = 48.0 A (in the direction shown) and rolls along the rails without slipping. If it starts from rest, what is the speed of the rod as it leaves the rails if a uniform magnetic field of magnitude 0.240 T is directed perpendicular to the rod and the rails? Answers: 1.07 m/s