Notes Chapter 2: Measurements and Calculations. It is used to easily and simply write very large numbers, and very small numbers.

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Scientific Notation Notes Chapter 2: Measurements and Calculations It is used to easily and simply write very large numbers, and very small numbers. It begins with a number greater than zero & less than 10. In other words, one digit before the decimal point. This number is multiplied by an appropriate power of 10 Powers of 10 positive exponents 10 0 = 1 10 5 = 100,000 10 1 = 10 10 6 = 1,000,000 10 2 = 100 10 7 = 10,000,000 10 3 = 1,000 10 8 = 100,000,000 10 4 = 10,000 10 9 = 1,000,000,000 Scientific notation of numbers greater than 1 136 = 1.36 x 10 2 15,000 = 1.5 x 10 4 10,200 = 1.02 x 10 4 105,000,000 = 1.05 x 10 8 Chemistry-1 Notes Chapter 2 Page 1

Powers of 10 negative exponents 10 0 = 1 10-1 = 0.1 = 1 / 10 10-4 = 0.0001 10-5 = 0.00001 = 1 / 10,000 = 1 / 100,000 10-2 = 0.01 = 1 / 100 10-6 = 0.000001 = 1 / 1,000,000 10-3 = 0.001 = 1 / 1,000 10-7 = 0.0000001 = 1 / 10,000,000 Scientific notation of numbers less than 1 0.136 = 1.36 x 10-1 0.0560 = 5.6 x 10-2 0.0000352 = 3.52 x 10-5 0.00000105 = 1.05 x 10-6 To Review: Positive exponents tells you how many decimal places you must move the decimal point to the right to get to the real number. They indicate numbers that are greater than 1. 6.21 x 10 3 says you must move the decimal point 3 places to the right to get to the real number. 6.21 x 10 3 = 6,210. Chemistry-1 Notes Chapter 2 Page 2

Negative exponents tells you how many decimal places you must move the decimal point to the left to get to the real number. They indicate numbers that are less than 1. 6.21 x 10 3 says you must move the decimal point 3 places to the left to get to the real number. 6.21 x 10 3 = 0.00621 Self-Check: Write the following using scientific notation. a) 93,000,000 9.3 x 10 7 b) 0.000,000,000,105 1.05 x 10-10 c) one million 1.0 x 10 6 Cover Answers for Self Test d) one millionth 1.0 x 10-6 Chemistry-1 Notes Chapter 2 Page 3

International System of Measurements a.k.a. Metric System a.k.a. SI Metric Unit British Unit Length Meter (m) foot (ft.) Volume (space) Liter (L) quart (qt.) Mass (not weight) Gram (g) pound (lb.) Prefixes (multiples of the basic unit) Example kilo 1,000 x unit 1 kilogram = 1,000 grams hecto 100 x unit 1 hectogram = 100 grams deca 10 x unit 1 decagram = 10 grams --- Basic Unit --- --- 1 gram --- deci 0.1 x unit ( 1 / 10 ) 1 decigram = 0.1 gram centi 0.01 x unit ( 1 / 100 ) milli 0.001 x unit ( 1 / 1,000 ) 1 centigram = 0.01 gram 1 milligram = 0.001 gram kilo meter hectometer decameter decimeter centimeter milli meter km hm dam METER dm cm mm kg hg dag GRAM dg cg mg kl hl dal LITER dl cl ml Chemistry-1 Notes Chapter 2 Page 4

International System of Measurements a.k.a. Metric System a.k.a. SI kilometer hectometer decameter deci meter centi meter millimeter km hm dam METER dm cm mm kg hg dag GRAM dg cg mg kl hl dal LITER dl cl ml mega kilo hecto deca M k h da 1,000,000 1,000 100 10 10 6 10 3 10 2 10 1 Basic Unit gram (g) liter (L) liter (L) meter (m) deci centi milli micro d c m µ 0.1 0.01 0.001 0.000001 1 / 10 1 / 100 1 / 1,000 1 / 1,000,000 10 1 10 2 10 3 10 6 Chemistry-1 Notes Chapter 2 Page 5

Measuring Volume Method # 1: by Linear Measurement 10 cm 10 cm Volume = length x width x height 10 cm = L x W x H = 10 cm x 10 cm x 10 cm = (10 x 10 x 10) (cm x cm x cm) = 1,000 cm 3 We multiplied the numbers AND the Units. 1,000 cm 3 = 1 L 1 cm 1 cm 1 cm 3 = 1 ml Chemistry-1 Notes Chapter 2 Page 6

Method # 2: by Water Displacement We read a graduated cylinder at the bottom of the meniscus. The units are milliliters. Remember: 1 ml = 1 cm 3 to determine the volume of the object: volume of object & water volume of water = volume of object Volume of Object 38 ml 79 ml 79.0 ml 38.0 ml 41.0 ml object Chemistry-1 Notes Chapter 2 Page 7

Measuring Liquid Volume What volume is indicated on each of the graduated cylinders below? Don t forget to write the units. 60 30 4 50 20 3 1) 2) 3) 25 80 6 20 75 5 15 70 4 10 65 3 4) 5) 6) 40 4 30 3 50 20 2 10 1 40 7) 8) 9) Chemistry-1 Notes Chapter 2 Page 8

Measuring Liquid Volume What volume is indicated on each of the graduated cylinders below? Don t forget to write the units. 60 30 4 50 20 56.0 ml 4.35 ml 23.5 ml 1) 2) 3) 3 25 80 6 20 75 5 15 70 4 10 65 3 16.5 ml 76.0 ml 5.3 ml 4) 5) 6) 40 4 30 3 50 20 2 10 1 40 32 ml 3.5 ml 47.0 ml 7) 8) 9) Chemistry-1 Notes Chapter 2 Page 9

Measuriing Mass Actually,, mass and weight are different.. Mass is the amount of matter in an object while weight is the pull of gravity on an object.. If you weigh 120 lbs on Earth,, you d weigh 20 lbs on the Moon,, but you d still have the same mass.. Weight = 120 lbs Mass = 120 lbs Mass is measured with a balance.. This electronic balance is accurate to 0..01 g.. The mass of the geode is 32..47 g Not 32..5 g Not 32..50 g Not 32..470 g Weight = 20 lbs Mass = 120 lbs.. 32.47 g Chemistry-1 Notes Chapter 2 Page 10

This is called an Analytical Balance.. It is accurate to 0..0001 g.. The mass of the Volumetric Flask & the liquid inside is 89.2863 g Not 89..29 g Not 89..3 g Not 89 g What Is Density? It s the mass of each cubic centimeter of an object. It s the mass of the object compared to its size. It s how compact the matter is in the object. We use it to compare masses like price per pound. Chemistry-1 Notes Chapter 2 Page 11

Measuring Density mass of the object Density = volume of the object = grams ml or cm 3 The Unit of Density is always: g /cm 3 The Density of Pure Liquid Water is: 1.0 g /cm 3 72.42 g What is the density of the object whose volume was measured by water displacement to be 41.0 ml? You must also measure the mass of that object. Density = Mass Volume Density = 72.42 g 41.0 ml Density = 1.76634146 Floating D < 1.0 g /cm 3 Water D = 1.0 g /cm 3 D > 1.0 g /cm 3 Sinking Density = 1.77 g/cm 3 HW: Questions & Problems 2.8: # 86, 92, 97, 99 Chemistry-1 Notes Chapter 2 Page 12

Significant Figures or How Accurate Do You Have To Be? Isn t 22 cm 3 the same as 22.0 cm 3? NO!! 22.0 cm 3 is 10 times more accurate than 22 cm 3 22 cm 3 includes all measures from 21.5 cm 3 to 22.4 cm 3 a spread of 0.9 cm 3. 22.0 cm 3 includes all measures from 21.95 cm 3 to 22.04 cm 3 a spread of 0.9 cm 3. When making measurements, you are as accurate as your measuring instrument. If the smallest units in a 10 ml graduate is the tenths, or 0.1 ml, Then, your measurements are to 0.1 ml; Examples: 24.0 ml; 24.7 ml not 24 ml If your electronic balance can measure to the hundredths of a gram, Then your measurements are to 0.01 g Examples: 24.00 g; 24.76 g not 24 g Chemistry-1 Notes Chapter 2 Page 13

The significant digits of a number tells how exact that number is. 1 g is less exact than 1.0 g which is less exact than 1.00 g. Do you round off when you do computations? YES! Your answer cannot be any more accurate than your least accurate measurement 3 sig figs 4 sig figs 5 sig figs Volume = 4.03 cm x 2.413 cm x 6.3721 cm = 61.964785519 cm 3 = 61.9 cm 3 Answer has 3 sig figs 6.3721 cm 4.03 cm 2.413 cm Chemistry-1 Notes Chapter 2 Page 14

Spink s Handy Rules for Handling Numbers in Chemistry 1. Don t round until you get to your final answer. 2. All non - zero numbers are significant. Examples: 1, 2, 3, 4, 5, 6, 7, 8, and 9 3. Zeros are significant ONLY when a) they are between significant figures Examples: 802 & 4.06 each have 3 sig. figs. or b) they are ending zeros in a number with a decimal point. Examples: 400. & 6.00 each have 3 sig. figs. c) 470.00 has five sig. figs. The last zero is an ending zero in a number with a decimal point, so the first zero is between 2 sig. figs. Examples of numbers with zeros that are NOT significant. a) 4,300 has two sig. figs. The number does not have a decimal point. b) 0.00621 has three sig. figs. The zeros are not ending zeros. Chemistry-1 Notes Chapter 2 Page 15

When we say zeros are not significant, we are NOT saying they are not important. They are place holders which are important. There is a big difference between $3,200 and $3,200,000 even though each number has two sig. figs. When we say zeros are not significant, we are saying they don t make the measurement more accurate. 6,200 cm and 62,000,000 cm are both accurate to two significant figures. The zeros in the 2 nd number makes it larger, not more accurate. 620.0 cm is less accurate than 620.000 cm. The 2 nd measurement was made with a more precise ruler. 4. When you add or subtract measured numbers, the answer must have the same number of digits after the decimal point as the measurement with the smallest number of digits after the decimal point. 2 decimal places 6.32 3 decimal places 4.721 4 decimal places 6.2053 17.2463 = 17.25 2 decimal places Chemistry-1 Notes Chapter 2 Page 16

5. When you multiply or divide measured numbers, the answer must have the same number of significant figures as the measurement with the smallest number of significant figures. 3 sig. figs. 6.32 x 4 sig. figs. 4.721 29.83672 = 29.8 3 sig. figs. 4 sig. figs. 7.246 3 sig. figs. 16.8 = 0.431309 = 0.431 3 sig. figs. 6. When you are rounding off your answer to... say 3 sig. figs for example, you look at the fourth sig. fig. If it is 5 or greater, the 3 rd sig. fig. goes up one. If it is 4 or lower, the 3 rd sig. fig. stays the same. this is 4 or less this is 5 or greater 47.6372 = 47.6 47.6732 = 47.7 so this stays a 6 so this becomes a 7 Chemistry-1 Notes Chapter 2 Page 17

7. When you are rounding off your answer to 3 sig. figs, the numbers after the decimal point are dropped, but the numbers before the decimal become zeros. 62.3785406 = 62.4 62,587,865 = 62,600,000 8. Counting numbers and conversion factors* are not considered when determining the number of sig. figs. you must round your answer to. They are considered to be exact. You only look at the measurements given in the problem. * Conversion factors are equivalencies written as fractions so you can convert from one unit of measurement to another. Chemistry-1 Notes Chapter 2 Page 18

Dimensional Analysis a.k.a. Factor Label Method a.k.a. Unit Cancellation We use this method to solve many problems by using the relationship of one unit to another. For example, 12 inches = 1 foot. Since these two numbers represent the same value, the fractions are equal to 1. 1 ft. = 1 12 in. 12 in. and = 1 1 ft. When you multiply another number by the number one, you do not change its value. However, you may change its unit. Example 1: Convert 2.00 miles to inches. 2.00 miles X 1 X 5,280 ft. 1 mile X 12 in. 1 ft. Answer using significant digits: = 126,720 in. 2.00 mi. = 127,000 in. Chemistry-1 Notes Chapter 2 Page 19

4.00 days X 1 Example 2a: How many seconds are in 4.00 days? X 24 hrs. 60 min. 60 sec. X X 1 day 1 hr. 1 min. Answer using significant digits: 4 days = 346,000 sec. = 345,600 sec. Still don t see how the Unit Cancellation method can help you solve conversion problems? 1. You don t have to memorize whether to multiply by 24 hrs. / day, or to divide by it. 2. You write the conversion factor so that the unit you are changing from is cancelled out. Example 2b: How many minutes are in 4.00 days? 4.00 days 1 Start with the given information X 24 hrs. 1 day Change days to hours by having the days cancel out. X 60 min. 1 hr. Change hours to minutes by having the hours cancel out. Round your answer to 3 sig. figs. because 4.00 days has 3 sig. figs. = 346,000 sec. Chemistry-1 Notes Chapter 2 Page 20

Preparing for Test Chapter 2 You should be able to do the problems we practiced in class and the ones assigned to you for homework. change regular numbers into scientific notation change scientific notation into regular numbers know the units of mass, volume, length, and density know that 1 cm 3 = 1 ml know that 1,000 cm 3 = 1,000 ml = 1 L do conversion problems w/ different metric prefixes as well as metric & English prefixes (metric / English conversion factors are given to you in the problem know the rules for counting significant digits know the rules for rounding numbers when calculating numbers using significant digits. know how to do calculations in density problem know the density of pure water and how to determine whether an object will float or sink in water. Chemistry-1 Preparing for Test Chapter 2 Page 1 of 1