Figure 4-1: Pretreatment schematic

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GAS TREATMENT The pretreatment process consists of four main stages. First, CO 2 and H 2 S removal stage which is constructed to assure that CO 2 would not exceed 50 ppm in the natural gas feed. If the composition of CO 2 exceeded that limit it would freeze in the liquefaction process pipelines. This stage is directed more to CO 2 removal since the Bolivian natural gas contains no sulfur in it. There are two available methods to remove CO 2 from the natural gas. The first method is using sulfinol, which used to be one of the famous methods for gas CO 2 removal in most industrial applications but it started to vanish and few pretreatment plants use sulfinol any more. The reason is that sulfinol does not work well with rich natural gas (rich with heavy hydrocarbons) because it tends to attract or attach to heavy hydrocarbons and then it drags the heavies to the sulfinol pump or circulation which leads to allowing the heavy hydrocarbons to vent into the air. That usually leads to a decrease in the quality and heat content of the natural gas in the feed and according to the new EPA (Environmental Protection Agency) rules heavy hydrocarbons can not be vented to the atmosphere because it would lead to an increase in the air pollution level in the surroundings significantly. So EPA regulations will be followed in Bolivia to serve ethics purposes. Another method to remove CO 2 is using DEA (Diethyl Amine) but since DEA alone can not remove CO 2 to a ppm (particle per million) level, it is activated by injecting a chemical called Piperzine which activates the DEA to MDEA (Methyl Diethyl Amine). MDEA is also used for this pretreatment stage versus sulfinol because MDEA is cheaper to install and it has less utility since it requires less rate of solvent circulation compared to sulfinol. Therefore, this pretreatment stage is named the amine wash section. The second stage is dehydration. Water is removed from the natural gas also to avoid freezing in the pipeline of the liquefaction process. The natural gas feed should be completely dry, even from the smallest traces of water molecules (<0.01Microgram/m 3 ), before entering the heavy duty cooling section of the liquefaction process. TEG (Triethylene Glycol) is the primary solvent used in gas processing industry to dehydrate gases. Dry TEG contacts the moist natural gas and absorbs the water from it in a contactor tower. The tower contains a structured packing bed to maximize the mixing between the gas and TEG and to increase the contact time between the two substances. The TEG and water mixture is then sent to a TEG recycling system where TEG is separated from water by filtering then heating. The recycled TEG is then sent back to the contactor tower. Although TEG removes H 2 O significantly from the natural gas, small amount of water traces still escape this process; so to insure that these traces do not accompany the natural gas feed, molecular sieves are used to serve this purpose. In average, two sieves are needed for every train. Despite all of this, in some processes H 2 O in a molecular level still escapes with the natural gas in the feed. A third safety step is taken in the liquefaction process where molecules of water, which accompany the natural gas in the feed, are condensed and flashed in the stage of natural gas pre-cooling. This step will be explained in detail in the liquefaction section of this report. The third stage is the Hg removal. Although the Bolivian natural gas has no Hg in it, this step is still taken as a precaution since the natural gas feed might contain molecular amount of Hg which is enough to cause corrosion in the expensive Aluminum LNG heat exchangers used in the liquefaction process. 10 ng/m 3 (nano gram per m 3 ) is enough to cause such a catastrophe. The process of Hg removal is also inexpensive since the activated bed filter that is used in the Hg filtration is inexpensive and it is replaced on an average of once every four years. So having 1

this stage in the pretreatment of the Bolivian natural gas eliminates the risk of having Hg traces in the natural gas feed that might ruin the expensive heat exchangers. The fourth and last step is the installation of a Duster in the Pretreatment process outlet to insure that the natural gas feed is free from small solid particles which might cause a clog in the pipes of the liquefaction process or damage the heat exchangers. The figure below shows the overall process flow. Figure 4-1: Pretreatment schematic 2

Gas Dehydration The purpose here is to remove water. We first start determining what is the maximum content of water in a gas. Consider the following exercise Exercise 4-1: Consider a gas with the following composition: 1 - CO2 0.0136 2 - HYSULFID 0.0170 3 - METHANE 0.8801 4 - ETHANE 0.0640 5 - PROPANE 0.0171 6 - IBUTANE 1.8074E-03 7 - BUTANE 2.3965E-03 8 - IPENTANE 6.8899E-04 9 - PENTANE 7.0896E-04 10 - HEXANE 5.3921E-04 11 - HEPTANE 6.0911E-04 12 - H2O 1.4512E-03 Set up a stream in Pro II and determine the dew point. 3

In addition, find the dew pressure. Conversely, give a certain temperature; determine how much water will condense. One method to remove water is to simply reduce the temperature and later use a flash drum to separate the water. Exercise 4-2: Take the gas of exercise 4-1, pass it through a cooler and later through a flash to separate water. S2 1 S1 E1 F1 S3 Determine the composition of the liquid obtained. Tri/Tetra-Ethylene Glycol (TEG) Systems: These units are designed to put a liquid that has the ability to dissolve water in contact with gas. These un its are called absorbers and they are depicted in the next figure: The column has gas entering from below and passing through trays that contain the liquid absorbent. These trays are either sieve trays (Just a tray with holes in it)m or more complex valve or bubble cup arrangements. The picture below has bubble cups. The liquid, in turn, flows down from one tray to the next in downcomers. Water free TEG is put in contact with gas that has already been dehydrated. Thus, the TEG keeps increasing water concentration as it moves downwards. Similarly, the gas is reducing its water content as it flows upwards, transmitting it to the TEG. 4

Figure 4-2: TEG Contactor The water-rich TEG needs to be regenerated. Thus, it is first depressurized and later heated up. This basically removes water from the liquid phase already. It is later sent to a TEG recovery column. This column has a reboiler and allows water to be removed. Thus by heating the mixture in the bottom of the column to close to the boiling point of TEG, one should be able to remove it. 5

2 TEG- 35 C 3 11 6 1 7 1 2 Heater GAS- T=55 C, P=1000 Psig 5 1 3 2 2 4 4 3 12 6 Depresurization to 60 psig TEG recovery column 6

Figure 4-3: TEG Contactor-Reconcentrator system Figure 4-4: TEG Water Temperature composition diagram. We will attempt to simulate this system. However, we need to learn how to set up distillation and absorption columns in Pro II. Degrees of Freedom in distillation Degrees of Freedom in Distillation To perform a simulation of a distillation column, a set of specifications needs to be provided. To do this, one needs to understand the concept of degree of freedom. This is defined as Degree of Freedom= Number of unknowns Number of equations (4-1) Consider a column with N T trays and N C components, total condenser and total reboiler (Figure 4-1). In the case of crude, one can consider the components to be the pseudo-components that are usually generated. 7

1 S2 2 3 4 S1 5 6 7 8 9 T1 10 S3 Figure 2-1: Single one-feed two product column with reboiler and condenser VARIABLES 1) For each tray (excluding condenser and reboiler): T j, L j, V j, x j,i, y j,i Variables= 3 N T + 2 N T N C L= Liquid rates V= Vapor rates x= liquid compositions y=vapor compositions T= Tray temperatures 2) For the condenser (temperature, flows, compositions and duty) T C, L 0, D, x C,i, Q C Variables= N C +4 D= Product Rate Q C = Condenser heat duty 3) For the reboiler (temperature, flows, compositions and duty) T R, V NT+1, B, x Ri, Q R Variables= N C +4 B= Product Rate Q R = Condenser heat duty Total number of Variables: N T (3+2N C )+8+2N C 8

EQUATIONS: 1) Steady state mass balances for all components in all trays L j-1 x j-1,i - [L j x j,i + V j y j,i ] + V j+1 y j+1,i + F j z i =0 i=1,..,n C j=1,..., N T Equations: N C N T z= feed composition F j = Feed rate to tray j (here we consider only one). 2) Steady state mass balances for all components the condenser y 1,i =x Ci i=1,..,n C Equations: N C V 1 -(L 0 + D )=0 Equations: 1 3) Steady state mass balances for all components the Reboiler y NT+1,i =x Ri i=1,..,n C Equations: N C L NT -( V NT+1 + B )=0 Equations: 1 4) Equilibrium Relations y j,i =K j,i, (x j, T j, P j )x j,i i=1,..,n C j=1,..., N T Equations: N T N C P j = pressures (assumed given) 5) Summation equations N C i= 1 x j,i = 1 j=1,..., N T N C i= 1 x C,i = 1 (Condenser) N C i= 1 y j,i = 1 j=1,..., N T 9

N C i= 1 6) Enthalpy balance in each tray y NT+1,i = 1 (Reboiler) L j-1 h j-1 - [L j h j +V j H j ] + V j+1 H j+1 + F j H F,j =0 j=1,..., N T h: liquid enthalpy H: Vapor enthalpy H F : Enthalpy of feed All enthalpies are functions of composition and temperature. 7) Enthalpy balance in condenser and reboiler V 1 H 1 -(L 0 + D ) h 0 = Q C Equations: 1 (L NT B) h NT - V NT+1 H NT+1 = Q R Equations: 1 Total number of equations: N T (3+2N C )+2N C +6 Degree of Freedom: Unknowns- Equations = 2 Consider now the case of a column with a total condenser and steam injection, like the one in Figure 4-2. 1 2 S2 3 4 S1 5 6 7 8 9 S4 10 T1 S3 Figure 2-2: Single one-feed two product column with reboiler and condenser Since there is no reboiler, there is N C +4 variables less (T R, V N+1, x Ri, B and Q R ). Therefore, Total number of equations: N T (3+2N C )+N C +4 10

The number of equations is reduced by N C +3 (N C +1 material balances, one summation of compositions, one energy balance. Thus, Total number of equations: N T (3+2N C )+ N C +3 Degree of Freedom: Unknowns- Equations = 1 EXERCISE 4-3: Determine the degrees of freedom of a column with a partial condenser and a total reboiler. EXERCISE 4-4: Determine the degrees of freedom of an absorber (no condenser or reboiler) shown in Figure 4-3 S2 S4 1 2 3 4 5 6 7 8 9 S1 10 T1 S3 Figure 2-3: Absorber Specifying a Distillation Column Simulation When a particular system has a degree of freedom different from zero, multiple solutions are expected. To reduce the degree of freedom, one needs to fix the value of some unknown variables or add more equations to the system. For example, in the case of the column with reboiler and condenser, two specifications are needed. These are obtained either through fixing some values of variables or by adding some equations. For example, one can fix two flowrates (products are usually chosen), two compositions (also usually products), etc. One can also add equations. For example, the most common is to fix the reflux ratio R. The corresponding equation one is adding is R=L 0 /D. One can also add some recovery ratio. For example, one can say that one wants in the overhead to recover 99% of component one (or any other) in the feed. The corresponding equation is: D x C,1 =0.99 F z 1. 11

EXAMPLE 4-1: Set up the distillation of a benzene/toluene separation unit. The instructor will show all the set up steps, one by one. We start by building a column and connecting the streams 1 2 3 BENZ-TOL-MIX 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 BENZENE COLUMN 20 TOLUENE We continue by defining the inlet stream 12

We enter a composition of 40% benzene and a flowrate of a 1000 lb-mol/hr. Open the column and choose the number of trays Click on Feeds and Products and enter feed tray as well and estimates on products Click on condenser and reboiler and pick a bubble point condenser and a kettle reboiler 13

Now go to the specifications (You need two) and enter a reflux ratio plus a desired composition in the top 14

Now enter the hydraulics part. Request sieve trays and sizing mode Rerun the column and generate the report by using the output menu in the top. The instructor will show how to obtain results from the screen and how to go over the output and show you where to find the column diameter. EXERCISE 4-5: Set up a column to separate a mixture of pentane and hexane. Use Peng Robinson and SRK thermodynamic methods and compare the results for the same set of specifications. You are free to choose any. This will be discussed in class. 15

Simulation of a TEG System We start setting up a column and a regenerator as in the figure above. WE recommend starting with 3 trays in each column. The gas is at 1000 psig, so it may need to be dewatered first. Consider first that you would not do that. The contactor does not have condenser or reboiler, so it does not need specifications. The regenerator has only a reboiler, so it needs one specification. We choose to specify the temperature. Finally, we need a special thermodynamic package for TEG. EXERCISE 4-6: Play around with the number of trays and the operating conditions in both contactor and regenerator until you reach conditions that are acceptable. For example, change the temperature of the incoming TEG, change the pressure of the regenerator, the flowrate of TEG. We now find a way of adding make up TEG to the system by setting up a calculator that will count how much TEG is being lost (with the gas and with the water) at the top of both columns. These are streams 2 and 11. 16

The controller, simply takes adjust the flow of TEG make up (before the pump) to be the same as the calculated loss. 17

We now substitute the heater by a heat exchanger and we add a cooler for final conditioning. The instructor will show the different values of the streams. 18

Once we get the conditions of the input close to the conditions of the output, we can connect the streams. 19

Finally, one can use a flash drum to separate the gas before sending into the regenerator and a stream calculator to simulate the recovery all the TEG as follows: 20

The stream calculator input is shown next 21

EXERCISE 4-7: Once that you connected the streams evaluate the system. Determine the loss of hydrocarbon and the loss of TEG. 22

Amine Sweetening The purpose of amine sweetening is to remove CO 2 and H 2 S form gas. As, mentioned above, to do this Monoethanol-amine (MEA) is used. We set up an absorption column with the conditions listed below (we use a special package for amines that is available in Pro II). We now also go through the same sequence of steps as in the case of TEG dehydration to make use of a regenerator and close the loop. EXERCISE 4-8: With the aid of the instructor, set up an amine regeneration column and connect the loop to verify the system performance. Note that in this case, a distillation column with a condenser is needed. 23

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