Pre-Calculus Exponential/Logarithm Quiz A Name Date Period Part : Non-Calculator. Determine which graph below is the graph of the function. E). Identif the operation that will transform the graph of ( ) x f x into the graph of gx ( ) x. g(x) is obtained b shifting f(x) units upward (positive). g(x) is obtained b shifting f(x) units downward (negative). g(x) is obtained b shifting f(x) units to the left (negative). g(x) is obtained b shifting f(x) units to the right (positive). E) g(x) cannot be obtained b an of these tranforms. Page
. Identif the operation that will transform the graph of f ( x) x into the graph of g( x) x. g(x) is obtained b reflecting f(x) in the x-axis then shifting upward units. g(x) is obtained b reflecting f(x) in the -axis then shifting upward units. g(x) is obtained b reflecting f(x) in the x-axis then shifting downward units. g(x) is obtained b reflecting f(x) in the -axis then shifting downward units. E) g(x) cannot be obtained b an of these tranforms.. Rewrite the arithmic equation 6 in exponential form. 6 /6 6 6 E) 6. Rewrite the exponential equation in arithmic form. E) 6. Rewrite the arithm 9 in terms of the natural arithm. ln 9 ln ln ln 9 ln ln 9 ln 9 e E) ln9. Rewrite the arithm in terms of the common arithm. 0 E). Solve the following equation for x. x 6 E) Page
9. Solve the following equation for x. x E) 0. Solve x for x. E) no solution. Solve the equation ln x ln( e ) for x. e e e E) The equation has no solution.. Solve the equation ( x) (00) for x. 0 99 0 E) The equation has no solution.. Simplif the expression 9 0 E) The expression cannot be simplified.. Evaluate the function f( x ) 6 6. 6 0 6 6 / E) undefined Page
. Find the exact value of. E) 6. Expand the expression as a sum, difference, and/or constant multiple of arithms. E). Condense the expression x to the arithm of a single term. ( x ) x x x E) x +. Condense the expression [ x ] [ ] to the arithm of a single term. x x x x E) x Page
Part Calculator 9. What is the value of the function 0.x f ( x) 0e at x =.? Round to decimal places. 6. 6.00 6.0. E) 90.9 0. Let Q represent a mass of radioactive radium ( 6 Ra) (in grams), whose half-life is 99 ears. The quantit of radium present after t ears is t /99 Q Determine the quantit present after 00 ears. Round to the nearest hundredth of a gram. 0.00 g 0. g 0. g.9 g E).00 g. Identif the value of the function f ( x) 0 x at x. Round to decimal places..6..6. E) 6.0. Evaluate the arithm 0. Round to decimal places.. 0.6. 0.0 E).. Approximate the solution of x e to decimal places.. 0.06 0.6 0.6 E) 0.0. Solve for x: x (0 ). Round to decimal places..66 0.66.6.6 E) no solution. Approximate the solution to lnx.. Round to decimal places..96.90.09 0.6 E) 6.99 6. An initial investment of $9000 grows at an annual interest rate of % compounded continuousl. How long will it take to double the investment?.6 ears.6 ears.0 ears.0 ears E) ear Page
. An initial investment of $000 doubles in value in. ears. Assuming continuous compounding, what was the interest rate? Round to the nearest tenth of a percent..%.%.% 9.% E) 00%. The population of a culture of bacteria is described b the equation 0.0 t A( t) 00 e, where t is the time in hours. What was the population at t = hours? After how man hours will the population reach 0,000? Round to the nearest tenth of an hour. approximate population 6 when t after. hours, At ( ) 0,000 approximate population. when t after.9 hours, At ( ) 0,000 approximate population when t after 9. hours, At ( ) 0, 000 approximate population when t after. hours, At ( ) 0,000 E) approximate population 69 when t after 9. hours, At ( ) 0,000 9. A television rating compan tracks the viewing habits of a select sample of American TV viewers and extrapolates the results to estimate the total viewership of an particular show. The estimate of the number of viewers of a particular new show over a period of months was modeled as N( t) 0e kt, where t represents the number of weeks since the opening episode, and k is a constant. If there were 0,000 viewers for the first episode and. million viewers weeks later for the eighth episode, identif an appropriate value for k. Round to the nearest thousandth. 0. 0.0.9.06 E). Page 6