Mathematics. Mock Paper. With. Blue Print of Original Paper. on Latest Pattern. Solution Visits:

Similar documents
Paper: 02 Class-X-Math: Summative Assessment - I

CBSE CLASS-10 MARCH 2018

Paper: 03 Class-X-Math: Summative Assessment - I

MT EDUCARE LTD. SUMMATIVE ASSESSMENT Roll No. Code No. 31/1

MT EDUCARE LTD. SUMMATIVE ASSESSMENT Roll No. Code No. 31/1

CBSE QUESTION PAPER CLASS-X MATHS

CBSE QUESTION PAPER CLASS-X MATHS

ANSWER KEY & SOLUTIONS

Time: 3 Hrs. M.M. 90

Important Instructions for the School Principal. (Not to be printed with the question paper)

Sample Question Paper Mathematics First Term (SA - I) Class X. Time: 3 to 3 ½ hours

[Class-X] MATHEMATICS SESSION:

Important Instructions for the School Principal. (Not to be printed with the question paper) Note:

CBSE Board Class X Mathematics

Important Instructions for the School Principal. (Not to be printed with the question paper)

2. In an AP. if the common difference (d) = -4, and the seventh term (a7) is 4, then find the first term.

Class-IX CBSE Latest Pattern Sample Paper {Mathematics}

CBSE MATHEMATICS (SET-2)_2019

CBSE CLASS-10 MARCH 2018

Time Allowed : 3 hours Maximum Marks : 90. jsuniltutorial

MODEL TEST PAPER 9 FIRST TERM (SA-I) MATHEMATICS (With Answers)

Important Instructions for the School Principal. (Not to be printed with the question paper)

KENDRIYA VIDYALAYA GILL NAGAR CHENNAI -96 SUMMATIVE ASSESSMENT TERM I MODEL QUESTION PAPER TIME: 3 HOURS MAXIMUM MARKS: 90

1 / 23

Visit For All NCERT Solutions, CSBE Sample papers, Question, papers, Notes For Class 6 to 12

SAMPLE QUESTION PAPER Class-X ( ) Mathematics. Time allowed: 3 Hours Max. Marks: 80

MODEL QUESTION FOR SA1 (FOR LATE BLOOMERS)

9 th CBSE Mega Test - II

1 / 23

CBSE Sample Question Paper 1 ( )

DESIGN OF THE QUESTION PAPER Mathematics Class X NCERT. Time : 3 Hours Maximum Marks : 80

Blue print Chapters 1mark 2marks 3marks 4marks total

SUMMATIVE ASSESSMENT I (2011) Lakdfyr ijh{kk&i. MATHEMATICS / xf.kr Class X / & X. Time allowed : 3 hours Maximum Marks : 80 fu/kkzfjr le; % 3?k.

SUMMATIVE ASSESSMENT I, 2012 / MATHEMATICS. X / Class X

ANSWER KEY MATHS P-SA- 1st (FULL SA-1 SYLLABUS) Std. X

Class X Mathematics Sample Question Paper Time allowed: 3 Hours Max. Marks: 80. Section-A

SAMPLE QUESTION PAPER MATHEMATICS

1 / 23

KENDRIYA VIDYALAYA GACHIBOWLI, GPRA CAMPUS, HYD 32

Kendriya Vidyalaya Sangathan Class -X Subject- Mathematics Time - M.M - 80

CBSE Class X Mathematics Board Paper 2019 All India Set 3 Time: 3 hours Total Marks: 80

CLASS X FORMULAE MATHS

KENDRIYA VIDYALAYA SANGATHAN, ERNAKULAM REGION

DESIGN OF THE QUESTION PAPER Mathematics Class X

DAV Public School, Jharsuguda

KENDRIYA VIDYALAYA GACHIBOWLI, GPRA CAMPUS, HYD 32

SOLUTIONS 10th Mathematics Solution Sample paper -01

SAMPLE QUESTION PAPER Class-X ( ) Mathematics. Time allowed: 3 Hours Max. Marks: 80

KENDRIYA VIDYALAYA SANGATHAN, HYDERABAD REGION

KENDRIYA VIDYALAYA GACHIBOWLI, GPRA CAMPUS, HYD 32. SECTION A Questions 1 to 6 carry 1 mark each.

SOLUTIONS SECTION A SECTION B

CONGRUENCE OF TRIANGLES

Class-10 - Mathematics - Solution

KENDRIYA VIDYALAYA GACHIBOWLI, GPRA CAMPUS, HYD 32

KENDRIYA VIDYALAYA GACHIBOWLI, GPRA CAMPUS, HYD 32

I, SUMMATIVE ASSESSMENT I, / MATHEMATICS X / Class X

KENDRIYA VIDYALAYA GACHIBOWLI, GPRA CAMPUS, HYD-32. SECTION A Questions 1 to 6 carry 1 mark each.

KENDRIYA VIDYALAYA SANGATHAN, HYDERABAD REGION

'R'nze Allowed : 3 to 3% Hours] LMaximum Marks : 80

SAMPLE QUESTION PAPER 11 Class-X ( ) Mathematics

MODEL QUESTION PAPERS WITH ANSWERS SET 1

Algebraic Expressions

Question 1 ( 1.0 marks) places of decimals? Solution: Now, on dividing by 2, we obtain =

Marking Scheme. Mathematics Class X ( ) Section A

PRE BOARD EXAMINATION CODE : E SESSION CLASS : X MAXIMUM MARKS: 80 SECTION A

SOLUTIONS SECTION A [1] = 27(27 15)(27 25)(27 14) = 27(12)(2)(13) = cm. = s(s a)(s b)(s c)

MOCK CBSE BOARD EXAM MATHEMATICS. CLASS X (Paper 2) (AS PER THE GUIDELINES OF CBSE)

[Maxin~um Marks : 80 General Instructions :

C.B.S.E Class X

KENDRIYA VIDYALAYA SANGATHAN, HYDERABAD REGION

KENDRIYA VIDYALAYA SANGATHAN, HYDERABAD REGION

( )( ) PR PQ = QR. Mathematics Class X TOPPER SAMPLE PAPER-1 SOLUTIONS. HCF x LCM = Product of the 2 numbers 126 x LCM = 252 x 378

KENDRIYA VIDYALAYA SANGATHAN, HYDERABAD REGION

MATHEMATICS ( CANDIDATES WITH PRACTICALS/INTERNAL ASSESSMENT ) ( CANDIDATES WITHOUT PRACTICALS/INTERNAL ASSESSMENT )

Higher Order Thinking Skill questions

ANSWERS. CLASS: VIII TERM - 1 SUBJECT: Mathematics. Exercise: 1(A) Exercise: 1(B)

MATHEMATICS FORMULAE AND CONCEPTS. for CLASS X CHAPTER WISE IMPORTANT FORMULAS & CONCEPTS, Prepared by

MATHEMATICS. Time allowed : 3 hours Maximum Marks : 100 QUESTION PAPER CODE 30/1/1 SECTION - A

DESIGN OF THE QUESTION PAPER

Q4. In ABC, AC = AB and B = 50. Find the value of C. SECTION B. Q5. Find two rational numbers between 1 2 and.

KENDRIYA VIDYALAYA GACHIBOWLI, GPRA CAMPUS, HYD-32. SECTION A Questions 1 to 6 carry 1 mark each.

SURA's Guides for 3rd to 12th Std for all Subjects in TM & EM Available. MARCH Public Exam Question Paper with Answers MATHEMATICS

Answers. Chapter 9 A92. Angles Theorem (Thm. 5.6) then XZY. Base Angles Theorem (Thm. 5.6) 5, 2. then WV WZ;

KENDRIYA VIDYALAYA GACHIBOWLI, GPRA CAMPUS, HYD 32

Pre RMO Exam Paper Solution:

(This type of questions may be asked in the examination )

KENDRIYA VIDYALAYA SANGATHAN, HYDERABAD REGION

Lesson-3 TRIGONOMETRIC RATIOS AND IDENTITIES

WINTER 16 EXAMINATION

CBSE Class IX Mathematics Term 1. Time: 3 hours Total Marks: 90. Section A

Some Basic Logic. Henry Liu, 25 October 2010

Triangles. Example: In the given figure, S and T are points on PQ and PR respectively of PQR such that ST QR. Determine the length of PR.

Mathematics Class X Board Paper 2011

KENDRIYA VIDYALAYA SANGATHAN, HYDERABAD REGION

SUMMATIVE ASSESSMENT I, IX / Class IX

CBSE 10th Mathematics 2013 Unsolved Paper Summative Assessment - I

CBSE 2011 CCE QUESTION PAPER. FIRST TERM (SA-I) MATHEMATICS CODE NO A1 (With Solutions) CLASS X

Pre-Regional Mathematical Olympiad Solution 2017

4. The G.C.D of 15x 4 y 3 z 5,12x 2 y 7 z 2... a) 15x 4 y 7 z 5 b)3x 2 y 3 z 2 c)12x 2 y 3 z 2 d)3x 4 y 7 z 5

Transcription:

10 th CBSE{SA I} Mathematics Mock Paper With Blue Print of Original Paper on Latest Pattern Solution Visits: www.pioneermathematics.com/latest_updates www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 1

10 th CBSE First Term {SA- I} Blue Print Topic/Unit MCQs SA(1) SA(II) LA Total Number System () 1() (6) 5(10) Algebra () (4) (6) (8) 8(0) Geometry 1(1) (4) (6) 1(4) 6(15) Trigonometry 4(4) 1() (6) (8) 9(0) Statistics 1(1) (4) (6) 1(4) 6(15) Total 10(10) 8(16) 10(30) 6(4) 34(80) www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771

General instructions: Time: 3hrs. M: M: 90 (i) All questions are compulsory. (ii) The question paper consists of 34 questions divided into sections A, B, C and D. Section-A comprises of 8 questions of 1 mark each, section-b comprises of 6 questions of two marks each, section-c comprises of 10 questions of three marks each and section-d comprises of 10 questions of four marks each. (iii) Question numbers 1 to 8 in section-a are multiple choice questions where you are required to select one option out of the given four. (iv) There is no overall choice. However, internal choice has been provided in 1 question of two marks, 3 questions of three marks each and two questions of four marks each. You have to attempt only one of the alternatives in all such questions. (v) Use of calculator is not permitted. www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 3

Section-A Questions number 1 to 8 carry one marks each 1. The pair of equation x and x 4 has : (a) infinitely many solutions (b) no solution (c) two solutions (d) one solution (b). If sides of two similar triangles are in ratio 4 : 9, then area of these triangles are in the ratio (a) : 3 (b) 4 : 9 (c) 81 : 16 (d) 16 : 81 (d) Ratio of Areas 4 9 16 81 3. The x-coordinate of the point of intersection of more than and less then ogive is : (a) mode (b) mean (c) median (d) Variance (c) 4. If LCM (54, 336) 304, then HCF (54, 336) is: (a) 54 (b) 6 (c) 336 (d) 36 (b) L.C.M H.C.F Product of two numbers 54 336 304 H.C.F H.C.F 6 www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 4

5. Value of 5 tan A 5sec A is : (a) 1 (b) 0 (c) 5 (d) 5 (c) 5 tan A 5 (1 + tan A) 5 (tan A 1 tan A) 5 6. If sina 3, then A equal to : (a) 90 o (b) 60 o (c) 45 o (d) 30 o (d) sin A 3 SinA Sin60 0 A 30 0 7. If sec A q p, then value of 1 p cos A is: (a) 1 p (b) 1 q (c) 1 pq (d) p q (b) 1 1 p 1 cos A p p q q 8. If a positive integer n is divided by, then the remainder can be : (a) 1 or (b) 1,, or 3 (c) 0 or 1 (d) (c) www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 5

Section-B Questions number 9 to 14 carry two marks each 9. In the given figures, find measure of X. In PQR and zyx PQ 4. 1 ZY 8.4 PR 3 3 1 ZX 6 3 QR 7 1 YX 14 PQ PR QR ZY ZX YX PQR ZYX (By SSS similarity criteria) PRQ ZXY..(1) (By CPST) In PQR PQR + PRQ + RPQ 180 0 (Angle sum property of ) 60 0 + 70 0 + PRQ 180 0 0 PRQ 50..() From (1) & () 0 ZXY X 50 10. Is 7 11 13+13 a composite number? Justify your answer. 7 11 13 + 13 www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 6

13(7 11 1 + 1) 13(77 + 1) 13(78) 13 13 3 As, the no.7 11 13 + 13 is having more than prime factors, The given no. is a composite no. 11. Solve: 3 5 0 and 19 x y x y 3 0 x y 5 19 x y Put 1 a & 1 x y b..(1)..() in (1) & () 3a b 0..(3) a + 5b 19..(4) Multiply (3) & (4) by 5 & respectively, (3a b 0) 5 15a 10b 0..(5) & (a + 5b 19) 4a + 10b 38 (6) Adding (5) & (6) 15a 10b 0 4a 10b 38 19a 38 a Put a in () 3() b 0 6 b 0 www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 7

b 6 b 3 1 1 x a 1 1 & y b 3 1. The following distribution give the daily income of 50 workers of a factory: Daily income in Rs. 100 10 10 140 140 160 160 180 180 00 Number of workers 1 14 8 6 10 Write the above distribution as more than type cumulative frequency distribution. Daily income (in More than type fi Cf Rs) distribution 100 10 10 140 140 160 160 180 180 00 More than 100 More than 10 More than 140 More than 160 More than 180 1 14 8 6 10 50 38 4 16 10 Total 50 13. If 1 and are zeroes of polynomial 4x x + (k 4). Find k. If f(x) 4x x + (k 4) where, x, 1 According to relationship between zeroes & coefficients of a polynomial, 1 c a www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 8

1 k 4 4 4 k 4 k 8 Value of k 8. 14. If tan A cot (A 18 o ), where A is an acute angle, find the value of A. 0 tan A cot A 18 0 cot 90 A cot (A 18) 90 A A 18 90 + 18 3A 3A 108 A 36 0 Or If is an acute angle and sin cos, find the value of 3 tan + sin 1. sin cos (1) (Given) 3 tan sin 1 sin 3 sin sin cos cos [ sin cos 1] sin 3 sin sin cos sin cos from(1) cos 3 3 sin sin sin cos Value of 3tan sin 1 3 www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 9

Section-C Questions number 15 to 4 carry three marks each 15. A survey regarding the height (in cm) of 50 girls of class X of a school was conducted and the following data was obtained: Height(in cm) 10 130 130 140 140 150 150 160 160 170 Total Number of girls 8 1 0 8 50 Find the mode of the data. Model class 150 160 f1 0 f0 1 f 8 h 10 l 150 f1 f0 Mode l f f f 1 0 h 0 1 150 10 40 1 8 8 150 10 0 150 + 4 154 cm 16. Prove that : To prove : L. H. S. cot A cos A coseca 1 cot A cos A coseca 1. cot A cos A cosec A 1 cot A cos A cosec A 1 cot A cos A cot A cos A www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 10

cos A cos A sin A cos A cos A sin A cos A cos A sin A cos A sin A sin A cos A sin A cos A sin A cos A cos A sin A cos A cos A 1 sin A cos A 1 sin A 1 1 cosec A 1 1 cosec A cosec A 1 cosec A cosec A 1 cosec A cosec A 1 cosec A 1 Hence proved. R. H. S. 17. In the given figure, o ACB 90 and CD AB. Prove that BC AC BD AD www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 11

Sol: ADC ~ ACB AC AD CD AB AC BC AC AD.AB.(1) CDB ~ ACB CD BC BD CA AB BC BC AB.BD Equation ()/(1) we get.() BC AC BC AC AB.BD AD.AB BD AD In the given figure, if AD BC, prove that AB +CD BD +AC. Or www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 1

Given : In ABC, AD BC To Prove : AB + CD BD + AC Proof : In ADC, AD CD (Given) AC CD + AD (By Pythagoras theorem) AD AC CD..(1) In ADB, AD BD (Given) AB AD + BD (By Pythagoras theorem) AD AB BD..() From (1) & () AC CD AB BD AC + BD AB + CD AB + CD BD + AC Hence, proved. www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 13

18. In the given figure, the line segment XY is parallel to AC of a ABC and it divides the triangle into two parts of equal area. Find AX AB. Let Area of BXY k Area of BAC k In XBY and ABC XBY ABC (Common angle) BXY BAC (Corresponding angles) BXY ~ BAC by AA similarity criteria Area of BXY BX Area of BAC AB K k BX AB BX 1 AB www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 14

AB AX 1 AB AB AX AB AX 1 AB 1 AX AB AX AB 19. Prove that: sin cos 3 3 sin cos tan To prove : 3 sin sin 3 cos cos tan Proof : 3 sin sin 3 cos cos sin 1 sin cos cos cos tan tan tan 1 sin 1 sin 1 1 sin sin 1 1 sin 1 sin tan R. H. S. Hence, proved. 0. Find the mean of the following data: www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 15

Class- interval 100 10 10 140 140 160 160 180 180 00 Frequency 1 14 8 6 10 Or Find the missing frequency for the given data if mean of distribution is 5. Wages (in Rs.) 10 0 0 30 30 40 40 50 50 60 60 70 70 80 No. of workers 5 3 4 f 6 13 Class interval Frequency (fi) xi fixi 100-10 10-140 140-160 160-180 180-00 1 14 8 6 10 110 130 150 170 190 130 180 100 100 1900 fi 50 fixi 760 Mean 760 50 145. xf f i i i www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 16

Or Wages in Rs. No. of workers xi di xi 45 fidi 10-0 0-30 30-40 40-50 50-60 60-70 70-80 5 3 4 f 6 13 15 5 35 45 55 65 75 30 0 10 0 10 0 30 150 60 40 0 0 10 390 fi 33 f fidi 80 fd i i Mean A + f 5 45 + 7 80 33 f 80 33 f 31 + 7f 80 7f 80 31 f 7 i 1. Prove that 5 is an irrational number. Let us assume the 5 is a rational number. Then, according to Euclid s division lemma, use can find two co-prime integers, such them, 5 5 a b a 5 b b a b www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 17

As, a & b are integers, this implies, (b a)/b is a rational no. 5 is also a rational number. But it contradicts the fact the 5 is irrational. This contradiction has arisen due to our incorrect assumption that number. 5 is a rational 5is an irrational number.. If one zeros of polynomial p(x) 3x 8x + k + 1 is seven times of the other, then find the zeroes and the value of k. p(x) 3x 8x + (k + 1) x, 7 b 7 a 8 x 1 3 x 7 And, 8 8 3 3 7 3 7 1 3 1 7 k 1 3 3 3 c k 1 a 3..(1)..() (From (1) & ()) 7 6k + 3 6k 4 k 3 Value of k 3 www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 18

3. A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours, it can go 40 km upstream and 55 km downstream. Find the speed of the stream and that of the boat in still water. Speed of stream y km/hr Speed of boat x km/hr 5 D T Case I 30 44 x y x y Case II 40 55 x y x y 10 13 Let 1 1 a, b x y x y 1 1 a, b 5 11 on solving x 8 km/hr y 3 km/hr Or Solve by cross multiplication method: ax + by a b; bx ay a + b ax by a b bx ay a b www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 19

x y ab b a ab ab b a ab 1 a b x y 1 a b a b a b I II III Equating I & III x 1 a b a b x 1 Equating II & III y 1 a b a b y 1 Values of x 1 & y 1 sin A cos(90 A)cos A cos A sin(90 A)sin A 4. Evaluate: sina cosa. sec(90 A) cosec(90 A) sin A cos A sin A sin A cos A cosec A cos A cos A sin A sec A sin A cos A - sin 3 A cos A cos 3 A sin A sin A cos A sin A cos A (sin A + cos A) sin A cos A sin A cos A 0 0 www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 0

Section-D Questions number 5to 34 carry Four marks each 5. Draw more than ogive and less than ogive for the following distribution and hence obtain the median. Class-interval 5 10 10 15 15 0 0 5 5 30 30 35 35 40 Frequency 1 4 3 4 3 Sol: Less then type of distribution Class interval Less than type f.i c.f distribution 5 10 Less than 10 10 15 Less than15 1 14 15 0 Less than0 16 0 5 Less than 5 4 0 5 30 Less than30 3 3 30 35 Less than35 4 7 35 40 Less than40 3 30 We will plot the points (10, ); (15, 14); (0, 16); (5, 0); (30, 3) (35, 7); (40, 30) More than type of distribution Class interval More than type f.i c.f distribution 5 10 More than 5 30 10 15 More than10 1 8 15 0 More than15 16 0 5 More than 0 4 14 5 30 More than5 3 10 30 35 More than30 4 7 www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 1

35 40 Less than35 3 3 Total 30 We will plot the points (5, 30), (10, 8), (15, 16), (0, 14), (5, 10), (30, 7), (35, 3) sin sin (90 ) 3cot 30 sin 54 sec 36 6. Evaluate: o o o o 3 sec 61 cot 9 cosec 65 tan 5 o o o. Or 1 cos A sin A 1 sin A Prove that : sin A cos A 1 cos A Sol: sin cos 3 3 sin 54 3 sec 61 tan 61 cos 36 sec 5 tan 5 1 31 cos 36 1 9 sin 90 36 www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771

1 9 cos 36 3 cos 36 1 9 3 7 6 5 6 To prove : 1 cos A sin A 1 sin A sin A cos A 1 cos A Or L.H.S. 1 sin A cos A 1 sin A cos A sin A cos A sin A cos A 1 1 sin A cos A sin A cos A 1 1 sin sin A cos A sin A cos A sin Acos A 1 sin A sin A sin A 1 1 sin Acos A sin A sin A 1 sin Acos A sin A 1 R.H.S. cos A Hence proved 7. If tan A + sin A m and tan A sin A n, Show that m n 4 mn. Sol: Given : sin A tan A m & tan A sin A n To prove : m n 4 mn Proof: www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 3

m n L.H.S. sin A tan A tan A sin A sin A tan A sin A tan A tan A sin A sin A tan A 4sinA tana R.H.S. 4 mn 4 tan A sin A tan A sin A 4 tan A sin A sin A 4 sin A cos A 4 sin A sin Acos A cos A 4 sin A 1 cos A cos A 4 sin A sin A cos A 4 sin A tan A 4sin A tan A L.H.S. Hence proved 8. If the median of the distribution given below is 3.5. find x and y. Class interval 0 10 10 0 0 30 30 40 40 50 50 60 60 70 Total Frequency x 5 9 1 y 3 40 www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 4

Sol: Class interval f.i c.f 0 10 x x 10 0 5 x+5 0 30 9 x+14 30 40 1 x+6 40 50 y x+ y+6 50 60 3 x+ y+9 60 70 x+ y+31 40 x+ y + 31 40 x + y 9 Median 3.5 30 + x 3, x + y 9 3 + y 9 y 6 0 x 14 1 10 9. In the given figure, AB PQ CD, AB x units, CD y units and PQ z units, prove that, 1 1 1 x y z www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 5

Or In an equilateral triangle ABC, D is a point on BC, such that BD 1 BC. Prove that 9 AD 7 3 AB. ABD ~ PQD x z l m m xm z (l + m) x m zl + zm xm zm zl m (x z) zl www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 6

m z..(1) l x z BPQ ~ BCP z l y l m z(l + m) yl zl + mz yl mz yl zl mz l(y z) m y z l z..() From (1) & () z y z x z z y z x z z xy yz xz + z xy yz +zx xy yz zx xyz xyz xyz 1 1 1 x y www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 7

Or Sol: Given : Equilateral ABC, BD 1 BC 3 To prove : 9AD 7AB Construction: Draw AM BC. Proof: BD 1 BC (1)(Given) 3 BM 1 BC () [Altitude of an equilateral is also its median] DM BM BD DM BC BC 3 [From (1) and ()] DM 3BC BC BC 6 6.(5) In ADM,AM DM AD AM + DM (By Pythagoras theorem) AM AD DM..(3) Similarly, in ABM, www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 8

AM AB BM (4) From (3) and (4) AD DM AB BM AD AB DM BM AD AB BC BC 6 (from () and (5) AD AB BC BC 36 4 BC 9BC 36 8BC 36 AD AB BC 9 AD BC 9 9AB 9AD AB +9AB 9AD 7AB Hence proved 30. Prove that in a right angle triangle, the square of the hypotenuse is equal to the sum of the squares of other two sides. Sol: www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 9

Given : 0 ABC, BAC 90 ; AD BC To prove : BC AB +AC Proof: According to a theorem, if a is drawn from the right of a to its hypotenuse, then the two s formed are similar to each other & to the whole. BAD ACD BCA (1) BAD BCA From (1) AB BD BC AB AB BC. BD (by CPST)..() ACD BCA (from (1)) AC CD BC AC AC BC. CD Adding (1) & () AC +AB BC.BD +BC.CD BC(BD + CD) BC BC BC AC +AB BC.() Hence proved 31. Use Euclid's division lemma to show that the cube of any positive integer is of the form 9m, 9m +1 or 9m + 8. Sol: Let a be any +ve integer and b 3, the according to Euclid s division lemma, a can be www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 30

written as, a 3q +r, whose, 0 r<3. a is of the form 3q, 3q+ 1&3q +. Case I: a 3q cubing both sides a 3 (3q) 3 7 q 3 9(3q 3 ) 9m, where m 9q 3 a 3 is of the of 9m. Case II: a 3q + 1 cubing both sides a 3 (3q +1) 3 7 q 3 + 1 + 7 q +9q 9(3q 3 + 3 q +q) +1 9m +1, where m 3q 3 +3q +q a 3 is of the form 9m +1. Case III: a 3q + cubing both sides a 3 (3q+) 3 7q 3 +8 +54q + 36q 9(3q 3 +6q +4q) + 8 9m +8, where m 3q 3 + 6q +4q a 3 is of the form 9m +8 3. Draw the graph of x + y 6 and x y + 0. Shade the region bounded by these lines with x axis. Find the area of the shaded region. Sol: x + y 6 x y www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 31

Area of 1 b h 1 4 4 8 cm 33. Find other zeroes of the polynomial p(x) x 4 1x 3 + 49x 10x 0, if two of its zeroes are 5 ± 5. Sol: P(x) x 4 1 3 + 49x 10x 0 x 5 5 x 5 5 0 ( x 5) 5 0.(1) x 5 5 x 5 + 5 0 (x 5) + 5 0.() Multiplying (1) & () www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 3

(x 5) 5 0 x + 5 10x 5 0 f(x) x 10x +0 0 x x 1 4 3 x 10x 0 x 1x 49x 10x 0 4 3 x 0x 40x 3 x 9x 10x 3 x 10x 0x x 10x 0 x 10x 0 0 g(x) x x 1 0 x x + x + 1 0 x ( x 1) + 1(x 1) (x + 1) ( x 1) 0 x 1,1& 5 5, 5 5 34. Let days taken by 1 women x Let days taken by 1 man y 5 1 x y 4 (1) Ans. & 3 6 1 x y 3 Put 1 x a & 1 y () b in (1) & () www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 33

a +5b 1 4 (3) 3a + 6b 1 3 a b 1/9 a + 4b /9..(4) Subtracting (3) from (4) we get a + 5b ¼ a + 4b /9 Put b 1/36 in (3) a + 5 1 1 36 4 7a + 5 36 9 4 7a 4 a 4 1 7 18 x 1 a 18 days y 1 b 36 days All The Best For Solution Visits: www.pioneermathematics.com/latest_updates www.pioneermathematics.com S.C.O. - 36, Sector 40 D, Chd. Phone: 98155771, 461771 34