Classical and Planck picture. Planck s constant. Question. Quantum explanation for the Wein Effect.

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6.1 Quantum Physics. Particle Nature of Light Particle nature of Light Blackbody Radiation Photoelectric Effect Properties of photons Ionizing radiation Radiation damage x-rays Compton effect X-ray diffraction Photons When light exchanges energy with atoms it behaves as a particle - called the photon The energy of a photon is proportional to the frequency f of light E photon = hf Planck s Constant h=6.626x10-34 J s Thermal Radiation Blackbody radiation Spectrum of Blackbody radiation A wide spectrum of wavelengths is produced. visible infrared The total intensity increases with temperature A container at temperature T in equilibrium with electromagnetic radiation. Light is absorbed and emitted by the walls. At equilibrium the spectrum of the light only depends on the temperature. The peak wavelength decreases with temperature Wien s displacement law λ max T= 0.2898x10-2 mk The intensity goes down at low wavelengths (I->0, as λ-> 0) Demonstration of blackbody radiation A tungsten filament light bulb is approximately a black body radiator. http://www.physics.ucla.edu/demoweb/demomanual/astronom y/quantum_mechanics/blackbody_radiation.html Disagreement with classical theory of light The classical theory predicts that intensity continues to increase with decreasing wavelength. Ultraviolet Catastrophe To explain the experimental data Planck proposed the quantum hypothesis. 1

Max Planck Planck s constant Planck proposed that light could only have certain energies E=hf Then the energy of oscillators in the black body could only have certain fixed values Classical and Planck picture Suppose we have a box that contains light waves with different wavelengths. The energy is contained in energy states containing particles with different energies Classical theory predicts that the number of energy states (like standing waves) increased with decreasing wavelength. Planck proposed that in addition the short wavelength particles are more energetically expensive So at short wavelength, they would be hard to produce. This explains the peak in the black body spectrum Quantum explanation for the Wein Effect. The blackbody spectrum reflects the distribution of photon energies. The peak wavelength reflects the average energy. The average photon energy increases linearly with temperature from λ = constant since then T max T c λ = f 1 hf max λmax c Average photon energy sun earth Question The sun has a surface temperature of 5,800 K. The solar radiation has a peak wavelength of 500 nm. The earth has temperature of about 300 K. What is the maximum wavelength of the blackbody spectrum of the earth? Wein Law λ T = constant max λ T =λ earth earth sun sun max max sun sun 9 earth λmaxt 500x10 m(5800k) 6 max earth λ = = = 9.7x10 m T 300K T 10micrometers infrared region The Greenhouse Effect is based on properties of blackbody radiation sun T~6000K visible Infrared CO 2 and Global Warming Atmosphere is transparent to light from sun earth T~ 300 K Atmosphere absorbs infrared radiation and serves as a blanket. Graph showing that the observed temperature rise can easily result from the observed rise of CO 2, based on simple numerical experiment. (Smoothed temperature data in Jones et al., 1998; CO 2 forcing data from CO 2 history, and calculated expected rise in temperature assuming 2 degree Celsius rise for CO 2 doubling; sunspot abundance from J.Lean, NASA) http://earthguide.ucsd.edu/globalchange/global_warming/03.html 2

Sources of visible light e - Hg semiconductor hf hf hf incandescent lamp black body radiation of a heated metal filament fluorescent bulb emission of excited atoms light emitting diode emission by electron across an energy gap in a semiconductor Fluorescent bulbs and LEDs are more efficient sources of light than incandescent lamps. Tungsten Lamp light source blackbody spectrum Visible light A tungsten lamp is inefficient as a light source because the spectrum at temperatures lower than the melting point includes a large amount of useless infrared radiation. Light emitting diode LED Photoelectric effect. - Electrode λ - Light emitting diodes are more efficient as an illumination source because the spectrum is not based on blackbody radiation. The light can be produced at specific wavelengths in the visible region A current is observed when light of certain wavelengths hits the electrode - + I Photoelectric effect Photoelectric Effect (e V s ) e V s = KE max 0 The stopping voltage V s is a measure of the kinetic energy of the photo electrons. When the V s is high enough electrons don t reach the electrode C. Kinetic energy rises linearly with the frequency of light. 3

Einstein s explanation photon energy =hf Slope =h Photon concept E photon =hf e - 0 Energy loss φ KE max = hf - φ metal electrode KE max = E photon -φ = hf- φ φ is the work function, the energy needed to remove the electron from the electrode. A photon interacts with the electron The light energy can have only specific values. Light energy is quantized Properties of Photons Photon energies - Interactions of light with matter. Ionizing radiation Radiation damage x-rays Compton effect X-ray diffraction Photon Energy Find the energy of a photon with a wavelength of 500 nm. Use units of electron volts (1eV= 1.60x10-19 J) 8 c 34 3x10 m/ s 19 E = hf = h = 6.63x10 Js 4.0x10 J 9 = λ 500x10 m 19 4x10 J E = = 2.5eV 19 1.6x10 J/ ev An electron volt is the energy change in moving an electron across a potential of 1 volt. A few electron volts is the energy of electrons in molecules. This is why visible light is absorbed by molecules (pigment molecules). 10 Photon Energies (ev) E=hf =hc/λ -9 10-6 10-3 1 10 3 10 6 ev Photon concept source absorber E photon =hf E=hf E=hf ir uv Light energy is has specific energies i.e. is quantized in the interaction of light with matter. Photons of different wavelengths, interact with different molecular properties- either in the generation of the photon or the absorption of the photon. 4

light Typical Wavelength (m) Photon Energies Typical Photon energy (ev) Molecular interactions applications Microwave Oven radio microwaves Infrared 10 10-2 10-5 10-7 ev 10-4 ev 10-1 ev nuclear magnetic Molecular rotations Molecular vibrations NMR imaging Microwave oven cell phone Heat lamp f =10GHz hf =4x10-5 ev Visible Ultraviolet X-rays 400-700 nm 200-300 nm 1 nm 2-3 ev 4-5 ev 10 4 ev Low energy electrons (pigments) bonding electrons Electrons scattering, tightly bound electrons Vision Photosynthesis Photography Radiation damage Skin cancer X-ray imaging X-ray diffraction Heats by exciting molecular rotations and vibrations. Cell phones use the same frequency range but at much lower intensity. UV light damage to inkjet prints Infrared light absorbed by vibrations of gas molecules Visible light absorbed by electronic transitions in pigment UV radiation 4-5 ev photons cause radiation damage by altering DNA (UV-B radiation at 320-290 nm) Ozone in the atmosphere protects by absorbing UV radiation. UV light treated Uv protected Radiation damage to DNA Biological effects of uv radiation UV light Altered DNA Organisms living in shallow sea water are susceptible to increased uv radiation. 5

X-rays Generation of x-rays by electrons X-rays are produced by electrons accelerated through high voltages V~ 10 4 V Photon energies ~ 10 4 ev X-rays X-rays e - Rotating anode A Quantum Effect. The maximum photon energy is ~ equal to the kinetic energy of the electron. λ min e V hc = hfmax = λ min X-ray source X-ray spectrum produced by 35 kev electrons hitting a molybdenum target. Question Find the minimum x-ray wavelength for a 35 kev electron. E=hf e- KE photon hf=ke (neglect work functionit is small compared to x-ray energies) KE= 35x10 3 ev x (1.6x10-19 J/eV) = 5.6x10-15 J hc Emax = hfmax = = KE λmin hc 34 8 6.63x10 Js(3.0x10 m/ s) 11 λ min = = = 3.6x10 m 15 KE 5.6x10 J 0.036 nm x-ray imaging x-ray photograph of Wolfgang Roentgen s wife s hand. x-rays penetrate soft tissue (light atoms) but are absorbed by heavy metal atoms. eg.calcium, Gold 6

Compton scattering of x-rays. High energy photons knock electrons out of atoms The wavelength of a photon scattered from an electron is increased due to loss of photon energy. Incident photon Scattered electron X-ray diffraction X-rays have wavelengths close to atomic dimensions Crystalline solids have an ordered array of atoms that scatter x-rays much like a three-dimensional diffraction grating h λ = λ λ o = (1 cos θ ) mc e λ o electron ө λ Scattered photon The x-ray diffraction pattern from crystals of molecules can be used to determine the density of scattering electrons (i.e. the electron density) and thus the molecular structure. Lower energy > Longer wavelength NaCl Crystal an ordered array of atoms 0.56 n Diffraction of x-rays from a crystal. Each atom acts as a wave source. Fig. 27-11, p.883 X-ray diffraction pattern of NaCl Condition for diffraction of x-rays from planes of atoms in a crystal Bragg s Law 2dsinө = mλ m=1, 2, 3... 7

DNA structure determined by x-ray diffraction X-ray diffraction pattern from a crystalline fiber of DNA. Watson And Crick used this data to deduce the structure of the DNA molecule 8