Chapter: Haloalkanes and Haloarenes

Similar documents
HALOALKANES AND HALOARENES

a. (CH 3 ) 2 CHCH(Cl)CH 3 b. CH 3 CH 2 CH(CH 3 )CH(C 2 H 5 )Cl c. CH 3 CH 2 C(CH 3 ) 2 CH 2 I d. (CH 3 ) 3 CCH 2 CH(Br)C 6 H 5.

Halo Alkanes and Halo Arenes

Chapter 10- Halo Alkanes and Halo arenes LEVEL-1 QUESTIONS

UNIT.10 HALOALKANES AND HALOARENES

DAV CENTENARY PUBLIC SCHOOL, PASCHIM ENCLAVE, NEW DELHI-87

REASONING QUESTIONS FROM ORGANIC CHEMISTRY (CH. 1 & 2)


UNIT-10 HALOALKANES AND HALOARENES

Q1. Pentanenitrile can be made by reaction of 1-bromobutane with potassium cyanide.

HSSLiVE.IN HALOALKANES AND HALOARENES

CBSE Class-12 Chemistry Quick Revision Notes Chapter-10: Haloalkanes and Haloarenes

3.2.8 Haloalkanes. Elimination. 148 minutes. 145 marks. Page 1 of 22

Organic Halogen Compounds


3.2.8 Haloalkanes. Nucleophilic Substitution. 267 minutes. 264 marks. Page 1 of 36

Alkyl halides. Substitutive nomenclature. Nomenclature of Alkyl halides. Primary, Secondary and Tertiary Alkyl halides 3/12/2012

REACTIONS OF HALOALKANES - SUBSTITUTION AND ELIMINATION

MUNISH KAKAR s INSTITUTE OF CHEMISTRY

Aryl Halides. Structure

Indian School Muscat. Chemistry IIT - JEE

A4 Alcohols form H-bonds with water due to the presence of OH group. However, hydrocarbons cannot form H-bonds with water.

AJNISH GUPTA & BHARTI GUPTA

Preparation of Alkyl Halides, R-X. Reaction of alkanes with Cl 2 & Br 2 (F 2 is too reactive, I 2 is unreactive): R + X X 2.

The C-X bond gets longerand weakergoing down the periodic table.

Name: Unit 3 Packet: Activation Energy, Free Radical Chain Reactions, Alkane Preparations, S N 2, E 2

Classes of Halides. Chapter 6 Alkyl Halides: Nucleophilic Substitution and Elimination. Polarity and Reactivity. Classes of Alkyl Halides

C 3 H 6 ClBr represent a saturated alkyl halide. The following structural isomers are possible for the given compound. Among the above 5 structural is

I. Multiple Choice Questions (Type-I)

10. Alkyl Halides. What Is an Alkyl Halide. An organic compound containing at least one carbonhalogen

DAV CENTENARY PUBLIC SCHOOL, PASCHIM ENCLAVE, NEW DELHI - 87

75. A This is a Markovnikov addition reaction. In these reactions, the pielectrons in the alkene act as a nucleophile. The strongest electrophile will

CHE 275 NUCLEOPHILIC SUBSTITUTUION CHAP 8 ASSIGN. 1. Which best depicts the partial charges on methyl bromide and sodium methoxide?

When 2-bromopentane reacts with ethanolic KOH, two structurally isomeric alkenes are formed.

Chapter 8. Substitution reactions of Alkyl Halides

1. CONCEPTS IN ORGANIC CHEMISTRY 2. SYNTHETIC ORGANIC CHEMISTRY 3. ISOMERISM II 4. HYDROCARBONS II 5. HALOALKANES. Vikasana - CET 2012

CHAPTER 7. Further Reactions of Haloalkanes: Unimolecular Substitution and Pathways of Elimination

CHE1502. Tutorial letter 201/1/2016. General Chemistry 1B. Semester 1. Department of Chemistry CHE1502/201/1/2016

Chapter 6: Organic Halogen Compounds; Substitution and Elimination Reactions

Organic Chemistry. Unit 10

1. CONCEPTS IN ORGANIC CHEMISTRY 2. SYNTHETIC ORGANIC CHEMISTRY 3. ISOMERISM II 4. HYDROCARBONS II 5. HALOALKANES. Vikasana - CET 2012

Organic Chemistry, 7 L. G. Wade, Jr. Chapter , Prentice Hall

DAMIETTA UNIVERSITY. Energy Diagram of One-Step Exothermic Reaction

Basic Organic Chemistry Course code : CHEM (Pre-requisites : CHEM 11122)

Homework problems Chapters 6 and Give the curved-arrow formalism for the following reaction: CH 3 OH + H 2 C CH +

Chemistry 2321 Last name, First name (please print) April 22, 2008 McMurry, Chapters 10 and 11 Row # Seat #

MCAT Organic Chemistry Problem Drill 10: Aldehydes and Ketones

Chapter 17. Reactions of Aromatic Compounds

AMINES. 3. Secondary When two hydrogen atoms are replaced by two alkyl or aryl groups.

ALCOHOLS AND PHENOLS

Haloalkanes. Isomers: Draw and name the possible isomers for C 5 H 11 Br

Class XI Chapter 13 Hydrocarbons Chemistry

Essential Organic Chemistry. Chapter 9

Organic Chemistry. M. R. Naimi-Jamal. Faculty of Chemistry Iran University of Science & Technology

ζ ε δ γ β α α β γ δ ε ζ

Class XII Chapter 11 Alcohols Phenols and Ethers Chemistry. Question 11.1: Write IUPAC names of the following compounds: (i) (ii) (iii) (iv) (v) (vi)

Alkyl Halides. Alkyl halides are a class of compounds where a halogen atom or atoms are bound to an sp 3 orbital of an alkyl group.

Reactions of Haloalkanes

Nucleophilic Substitution Synthesis of 1-Iodobutane.

Lesmahagow High School CfE Advanced Higher Chemistry

Test Date: (Sunday) Test Time: 1:00 pm to 2:00 pm Test Venue: Lajpat Bhawan, Madhya Marg, Sector 15-B, Chandigarh

Chapter 1 Reactions of Organic Compounds. Reactions Involving Hydrocarbons

Chapter 12. Reactions of Arenes: Electrophilic Aromatic Substitution. Class Notes. A. The method by which substituted benzenes are synthesized

Mechanisms. . CCl2 F + Cl.

General A haloalkane is a compound in which one or more H atoms of an alkane are replaced by halogen atoms.

Organic Chemistry Lecture 2 - Hydrocarbons, Alcohols, Substitutions

Chapter 11, Part 1: Polar substitution reactions involving alkyl halides

Chapter 15 Reactions of Aromatic Compounds

12/27/2010. Chapter 15 Reactions of Aromatic Compounds

Organic Chemistry. REACTIONS Grade 12 Physical Science Mrs KL Faling

Lecture Topics: I. Electrophilic Aromatic Substitution (EAS)

Haloalkanes and Haloar

HALOALKANES (HALOGENOALKANES) Structure Contain the functional group C-X where X is a halogen (F, Cl, Br or I)

7. Haloalkanes (text )

HALOGENOALKANES (HALOALKANES) Structure Contain the functional group C-X where X is a halogen (F,Cl,Br or I)

CHAPTER HYDROCARBONS. Chapterwise Previous year Qs. (a) Na (b) HCl in H2O (c) KOH in C2H5OH (d) Zn in alcohol. Ans: (c)

Aromatic Compounds II

HALO ALKANES AND HALO ARENES

Paper Reference. Advanced Unit Test 6B (Synoptic) Thursday 18 June 2009 Morning Time: 1 hour 30 minutes

PAPER No. 5: REACTION MECHANISM MODULE No. 2: Types of Organic Reaction Mechanisms

11. Nucleophilic Substitution Reactions

TOPIC 13 ANSWERS & MARK SCHEMES QUESTIONSHEET 1 ALKANES

Chapter 10 Radical Reactions"

Downloaded from

dihalogenoalkane H 2, Nickel Catalyst KOH alcoholic HBr, HCl Br Cl Elimination KOH aqueous heat under reflux Nucleophilic substitution

Class XII: Chemistry Chapter 13: Amines Top concepts

ST. JOSEPH S COLLEGE OF ARTS & SCIENCE (AUTONOMOUS) ST. JOSEPH S COLLEGE ROAD, CUDDALORE CH101T ORGANIC CHEMISTRY I (SEMESTER-I)

18.8 Oxidation. Oxidation by silver ion requires an alkaline medium

Haloalkanes and Haloar


BENZENE & AROMATIC COMPOUNDS

Topic 6 Alkyl halide and carbonyl compounds Organic compounds containing a halogen

Topic 6 Alkyl halide and carbonyl compounds Organic compounds containing a halogen

Chapter 22 Amines. Nomenclature Amines are classified according to the degree of substitution at nitrogen.

William H. Brown & Christopher Foote

HALOGENOALKANES (HALOALKANES) Structure Contain the functional group C-X where X is a halogen (F, Cl, Br or I)

Chemistry 2.5 AS WORKBOOK. Working to Excellence Working to Excellence

ALKYNE, AROMATIC HYDROCARBONS OR ARENES ALKYNES. Alkynes are unsaturated hydrocarbon with at least one triple bond between two carbon atoms ( C = C)

Chemistry of Benzene: Electrophilic Aromatic Substitution

Reaction of alkanes with bromine / chlorine in UV light. This is the overall reaction, but a more complex mixture of products is actually formed

Transcription:

Characteristics of halo compounds. Chapter: Haloalkanes and Haloarenes Question 1 Write the IUPAC name of the following compound:(ch 3 ) 3 CCH 2 Br The IUPAC name of the given structure is 2, 2-Dimethylbromopropane. Question 2 Question 3 Give the common name of the following. (i) 1- Bromopropane (ii) 2-chloro propane (iii) 1-chloro-2-methylpropane (i) Common name of 1- Bromopropane is n-propylbromide (ii) Common name of 2-chloro propane is Isopropyl chloride (iii) Common name of 1-chloro-2-methylpropane Isobutyl chloride

Question 4 Classify the following as alkyl, allyl, benzyl, vinyl or aryl halides: (i) (CH 3 ) 2 CHCH(Cl)CH 3 (ii) ( CH 3 ) 3 CCH 2 CH(Br)C 6 H 5 (iii) CH 3 CH=C(Cl)CH 2 CH(CH 3 ) 2 (iv) CH 3 CH=CHC(Br)(CH 3 ) 2 (v) p-clc 6 H 4 CH 2 CH(CH 3 ) 2 (i) Alkyl halide: (CH 3 ) 2 CHCH (Cl) CH 3 (ii) Allyl halide: CH 3 CH=CHC (Br) (CH 3 ) 2 (iii) Benzyl halide: (CH3) 3 CCH 2 CH (Br) C 6 H 5 (iv) Vinyl halide: CH 3 CH=C (Cl) CH 2 CH (CH 3 ) 2 (v) Aryl halide: p-clc 6 H 4 CH 2 CH (CH 3 ) 2 Question 5 Write the isomers of the compound having formula C 4 H 9 Br. i. CH 3 CH 2 CH 2 CH 2 Br ii. CH 3 CH 2 CH (Br)CH 3 iii. CH 3 CH(CH 3 ) CH 2 Br iv. CH 3 CBr(CH 3 ) CH 3 Question 6 Define racemisation? A mixture containing two enantiomers in equal proportions is known as racemic mixture and the process of conversion of enantiomers into a racemic mixture is known as racemisation. Question 7 What are enantiomers? Give example. The stereoisomers related to each other as nonsuperimposable mirror images are called enantiomers. For example 2-chloro butane (CH 3 CH 2 C * H (Cl) CH 3 ). Here the carbon atom marked is the chiral centre and posses four different group.

Question 8 What is benzylic halide? Give the structure. The compounds in which the halogen atom is bonded to an sp 3 -hybridised carbon atom next to an aromatic ring is called benzylic halide. Question 9 What is the common name of 1, 3-Dibromobenzene? m- Dibromobenzene. Question 10 What is the general formula for alkyl halide? C n H 2n + 1 X, where X is halogen atom and n is the number of carbon atom. Question 11 Write the structures of the following organic halogen compound. 2-Chloro-3-methylpentane. CH 3 CH (Cl) CH (CH 3 ) CH 2 CH 3 Question 12 Give the IUPAC name of the compound CH 3 CH (Cl) CH (Br) CH 3. 2-bromo-3-chloro-Butane

General methods of preparation Question 1 Write the structure of the major organic product in each of the following reactions: (i) CH 3 CH 2 CH 2 OH + SOCl 2 (ii) CH 3 CH 2 CH = CH 2 + HBr (iii) CH 3 CH = C (CH 3 ) 2 + HBr (i) CH 3 CH 2 CH 2 Cl (ii) CH 3 CH 2 CH 2 CH 2 Br (iii) CH 3 CH 2 CBr(CH 3 ) 2 Question 2 Write the equations for the preparation of 1-iodobutane from (i) 1-butanol (ii) 1-chlorobutane (iii) But-1-ene. (i) CH 3 CH 2 CH 2 CH 2 OH 1-butanol (ii) CH 3 CH 2 CH 2 CH 2 Cl + NaI 1-chlorobutane CH 3 CH 2 CH 2 CH 2 I 1-iodobutane CH 3 CH 2 CH 2 CH 2 I + NaCl 1-iodobutane (iii) CH 3 CH 2 CH = CH 2 + HI But-1-ene. CH 3 CH 2 CH 2 CH 2 I 1-iodobutane Question 3 Complete the following reactions: (i)

(ii) (iii) CH 3 CH 2 Br + NaI (i) + SO 2 + HCl (ii) (iii) CH 3 CH 2 Br + NaI CH 3 CH 2 I + NaBr Question 4 p-dichlorobenzene has higher melting point and solubility than those of orthoand meta-isomers. Discuss. Due to its symmetry p-dichlorobenzene fits in crystal lattice better as compared to o- and m-isomers. As a result the melting point and solubility of p-dichlorobenzene is higher than ortho- and meta-isomers. Question 5 Explain the statement "Alkyl halides, though polar, are immiscible with water". Energy is required to overcome the attractions between the haloalkane molecules and to break the hydrogen bonds between water molecules. The energy released during the formation of new attractive force between Haloalkane and the water molecule is very less as the attractions between the haloalkane and the water molecule is not as strong as the original hydrogen bonds in water. Thus Alkyl halides, though polar, are immiscible with water.

Question 6 Why is sulphuric acid not used during the reaction of alcohols with KI? H 2 SO 4 converts KI to corresponding HI and then oxidizes it to I 2. Hence it cannot be used during the reaction of alcohols with KI. Question 7 Name the aromatic salt formed as intermediate during the Sandmeyer's Reaction. Benzene diazonium halide also known as diazonium salt is formed as intermediate during the Sandmeyer's Reaction. Question 8 Which alkyl halides show colour on exposure to light? Alkyl Bromide and Alky iodide. Question 9 Give the Swarts reaction for the synthesis of fluoromethane. Question 10 Give the order of reactivity of alcohols with a given haloacid. The order of reactivity of alcohols with a given haloacid is 3 >2 >1. Chemical properties Question 1 Answer the following: (i) Haloalkanes easily dissolve in organic solvents, why? (ii) What is known as a racemic mixture? Give an example. (iii) Of the two bromo derivatives, C 6 H 5 CH(CH 3 )Br and C 6 H 5 CH(C 6 H 5 )Br, which one is more reactive in S N 1 substitution reaction and why?

(i) Haloalkanes can easily dissolve in organic solvents of low polarity because the new forces of attraction set up between haloalkanes and the solvent molecules are of same strength as the forces of attraction being broken. (ii) A mixture of equal amounts of two enantiomers is known as racemic mixture. For example: When a 3 o halide undergoes substitution with KOH, the reaction proceeds through S N 1 mechanism forming the racemic mixture in which one of the products has the same configuration as a reactant, while the product has an inverted configuration. (iii) The S N 1 substitution reaction involves the formation of carbocation, which is not affected by the presence of bulky groups. Thus, C 6 H 5 CH(C 6 H 5 )Br will be more reactive towards S N 1 substitution reaction forming racemic mixture. Question 2 A solution of KOH hydrolyses CH 3 CHClCH 2 CH 3 and CH 2 CH 2 CH 2 CH 2 Cl.Which one of these is more easily hydrolysed? than undergoes hydrolysis more easily than. being a primary alkyl halide has less steric hindrance which is secondary alkyl halide.

Question 3 Question 4 Give reasons for the following: (i) Grignard reagent should be prepared under anhydrous conditions. (ii) Neo-pentyl bromide undergoes nucleophilic substituting reactions very slowly. (iii) p-methoxybenzyl bromide reacts faster than p-nitrobenzyl bromide with ethanol to form an ether product. (i) Grignard reagent reacts with water and gets decomposed, so it is produced in anhydrous conditions. (ii) Neo-pentyl bromide being a primary halide reacts slowly through SN 1, and being a sterically hindered halide reacts slowly even through SN 2 mechanism. (iii) Methoxy (-OCH 3 ) group being an electron releasing group stabilizes the intermediate carbocation. On the other hand nitro group (-NO 2 ) is an electron withdrawing group and hence it destabalises the intermediate carbocation. Thus p-methoxy benzyl bromide reacts faster than p-nitrobenzyl bromide because in its case the reaction proceeds via more stable intermediate carbocation. Question 5 A primary alkyl halide (A) C 4 H 9 reacts with alcoholic KOH to give a compound (B). The compound (B) reacts with HBr to give the compound C which is an isomer of A. When A reacts with sodium metal it give a compound (D) whose molecular formula is C 8 H 18. The compound D is different from the compound formed when n-butyl bromide reacts with sodium. Give the structural formula of A and write all the equations involved in the reaction.

For C 4 H 9 Br, two primary halides are possible CH 3 CH 2 CH 2 CH 2 Br (n-butyl bromide) and (CH 3 ) 2 CHCH 2 Br (iso-butyl bromide). Since A is not normal butyl bromide, it must be isobutyl bromide. Question 6 Give reasons for the following: i) Haloalkanes react with KCN to form alkyl cyanides as main product while AgCN forms isocyanide as the chief products. ii) Alcohols do not react with NaBr, but when H 2 SO 4 is added, they form alkyl bromides. i) KCN is predominantly ionic and provides cyanide ions in solution. Although both carbon and nitrogen atoms of CN can donate electron pairs but the attack takes place mainly through carbon atom and not through nitrogen atom because C-C bond is more stable than C-N bond. However AgCN is mainly covalent in nature and nitrogen is free to donate electron pair forming isocyanide as the main product. ii) Br - is a weak base. So it cannot displace the strong base OH - when H 2 SO 4 is added, it leads to protonation of alcohol, as a result of which water molecule is formed. Since water molecule is a very weak base it is easily replaced by Br -.

Question 7 What is Saytzeff rule? Illustrate with suitable example. According to Saytzeff rule in dehydrohalogenation reactions the Haloalkane can form more than one alkene due to the availability of more than one alpha hydrogen atoms. In such a case the preferred alkene is that alkene which has greater number of alkyl groups attached to the doubly bonded carbon atoms. For example: the dehydrohalogenation of 2-bromobutane yields two products 1 butene and 2 butene. Out of these 2 butene is the major product (80%) as it is more highly substituted and it is more stable Question 8 Give the nitration and sulphonation reaction of chlorobenzene.

Question 9 Which compound in each of the following pairs will react faster in S N 2 reaction with - OH? (i) CH 3 Br or CH 3 I (ii) (CH 3 ) 3 CCl or CH 3 Cl (i) CH3I will react faster than CH3Br because the order of reactivity is as follows R-I > R-Br > R-Cl > R-F (ii) CH 3 Cl will react faster than (CH 3 ) 3 CCl because the order of reactivity is as follows in SN 2 reaction. Question 10 What is the directive influence of chlorine in chlorobenzene? The -Cl group is ortho and para directing in chlorobenzene. Question 11 What is Grignard reagent? It is an organometallic compound having formula RMgX also called alkyl magnesium halide.

Question 12 Give the order of reactivity for S N 1 reaction in methyl, primary, secondary and tertiary halide. Methyl halide >Primary halide > secondary halide> Tertiary halide Question 13 What are ambident nucleophiles? Nucleophiles that possess two nucleophilic centres are called ambident nucleophiles. Example cyanide Polyhalogen compounds uestion 1 (i) State one use each of DDT and iodoform. (ii) Which compound in the following couples will react faster in S N 2 displacement and why? (a) 1-Bromopentane or 2-bromopentane (b) 1-Bromo-2-methylbutane or 2-bromo-2methylbutane. (i) Use of DDT: It is used as an insecticide. Use of iodoform: It is used as an antiseptic. (ii) (a) 1 Bromopentane will undergo faster S N 2 displacement reaction than 2- bromopentane because 1- bromopentane has less steric hindrance than 2 bromopentane. This is because 1- bromopentane is a primary alkyl halide whereas 2- bromopentane is a secondary alkyl halide. (b) 1- Bromo-2-methylbutane will undergo S N 2 reaction faster than 2- Bromo-2- methylbutane because 1- Bromo-2-methylbutane has less steric hindrance than 2- Bromo-2-methylbutane. This is because 1- Bromo-2-methylbutane is a primary alkyl halide whereas 2- Bromo-2-methylbutane is a tertiary alkyl halide.

Question 2 What is DDT and why its use is banned in United States? DDT is p, p'-dichlorodiphenyltrichloroethane and is used as insecticide. It is banned for the following reason (i) Its high toxicity towards fish. (ii) DDT is not metabolized very rapidly by animals but get deposited and stored in the fatty tissues. Question 3 Give the three uses of each of the following: (i) Dichloromethane (ii) Tetrachloromethane Dichloromethane: It can be used (i) As solvent (ii) As paint remover (iii) As aerosol propellant Tetrachloro methane: It can be used (i) As a solvent (ii) As a fire extinguisher (iii) As a degreasing agent Question 4 What is the reason that Haloarenes are less reactive than haloalkane towards nucleophilic substitution reaction? In haloalkane, the halogen is attached to sp 2 hybridised carbon atom while in case of haloarene it is attached to sp 2 hybridised carbon atom. The sp 2 hybridized carbon have greater s-character than sp 3 -hybridised carbon and thus more electronegative and can hold the electron pair of C X bond more tightly than in haloalkane. The, C Cl bond length in haloalkane is greater than in haloarene. Since it is difficult to break a shorter bond than a longer bond, therefore, Haloarenes are less reactive than haloalkanes towards nucleophilic substitution reaction. Question 5 Why chloroform is kept closed in dark colored bottles? Chloroform is oxidized slowly by air in the presence of light to an extremely poisonous gas, carbonyl chloride, also known as Phosgene

Hence it is kept closed in dark colored bottles. Question 6 Give the role of carbon tetrachloride and Freon on environmental degradation. Both the carbon tetrachloride and Freon causes depletion of ozone layer when released in air because they remain unchanged and diffuses into stratosphere. The depletion of ozone layer increases the exposure of UV rays to human being which results in skin cancer, eye disorder and immune system diseases. Question 7 Why the use of chloroform as anesthetic is decreasing? Inhaling chloroform vapors depresses the central nervous system and its chronic exposure may cause damage to the liver and kidneys due to metabolism of chloroform to phosgene gas. Hence the use of chloroform as anesthetic is decreasing. Question 8 Give two hazardous effects of methylene dichloride. i) It harms the central nervous system. (ii) On direct contact with skin causes severe burning. Question 9 What is iodoform? Give one use of it. Triodomethane is called iodoform and can be used as antiseptic due to liberation of free iodine. Question 10 What are freons? Give one example. Freons are chloro fluoro carbons used as refrigerants. Example CCl 2 F 2. Give the full name of DDT. p,p -Dichlorodiphenyltrichloroethane @@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@