H 4 H 8 N 2. Example 1 A compound is found to have an accurate relative formula mass of It is thought to be either CH 3.

Similar documents
6.3.2 Spectroscopy. N Goalby chemrevise.org 1 NO 2 CH 3. CH 3 C a. NMR spectroscopy. Different types of NMR

6.3.2 Spectroscopy. N Goalby chemrevise.org 1 NO 2 H 3 CH3 C. NMR spectroscopy. Different types of NMR

3.15 NMR spectroscopy Different types of NMR There are two main types of NMR 1. C 13 NMR 2. H (proton) NMR

Analytical Techniques Chromatography

22.Analytical Techniques Chromatography

1 This question is about mean bond enthalpies and their use in the calculation of enthalpy changes.

Chapter 4rth LIQUIDS AND SOLIDS MCQs

Generalization of 2-Corner Frequency Source Models Used in SMSIM

CALCULATING REACTING QUANTITIES

1 This diagram represents the energy change that occurs when a d electron in a transition metal ion is excited by visible light.

Trigonometry Revision Sheet Q5 of Paper 2

Logarithms LOGARITHMS.

Activities. 4.1 Pythagoras' Theorem 4.2 Spirals 4.3 Clinometers 4.4 Radar 4.5 Posting Parcels 4.6 Interlocking Pipes 4.7 Sine Rule Notes and Solutions

Review Topic 14: Relationships between two numerical variables

1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Numbers and indices. 1.1 Fractions. GCSE C Example 1. Handy hint. Key point

4-cyanopentanoic acid dithiobenzoate (CPADB) was synthesized as reported by Y.

Project 6: Minigoals Towards Simplifying and Rewriting Expressions

Thermodynamics. Question 1. Question 2. Question 3 3/10/2010. Practice Questions PV TR PV T R

CS311 Computational Structures Regular Languages and Regular Grammars. Lecture 6

Nondeterministic Automata vs Deterministic Automata

Lesson 2: The Pythagorean Theorem and Similar Triangles. A Brief Review of the Pythagorean Theorem.

AP Calculus BC Chapter 8: Integration Techniques, L Hopital s Rule and Improper Integrals

8 THREE PHASE A.C. CIRCUITS

PAIR OF LINEAR EQUATIONS IN TWO VARIABLES

Instructions. An 8.5 x 11 Cheat Sheet may also be used as an aid for this test. MUST be original handwriting.

Chem Homework 11 due Monday, Apr. 28, 2014, 2 PM

Part 4. Integration (with Proofs)

Spacetime and the Quantum World Questions Fall 2010

Factorising FACTORISING.

Maintaining Mathematical Proficiency

Section 6: Area, Volume, and Average Value

A Study on the Properties of Rational Triangles

First compression (0-6.3 GPa) First decompression ( GPa) Second compression ( GPa) Second decompression (35.

I1 = I2 I1 = I2 + I3 I1 + I2 = I3 + I4 I 3

THE PYTHAGOREAN THEOREM

Section 1.3 Triangles

Non Right Angled Triangles

Comparing the Pre-image and Image of a Dilation

MAT 403 NOTES 4. f + f =

Dorf, R.C., Wan, Z. T- Equivalent Networks The Electrical Engineering Handbook Ed. Richard C. Dorf Boca Raton: CRC Press LLC, 2000

Discrete Structures Lecture 11

Something found at a salad bar

SECTION A STUDENT MATERIAL. Part 1. What and Why.?

Finite State Automata and Determinisation

Iowa Training Systems Trial Snus Hill Winery Madrid, IA

where the box contains a finite number of gates from the given collection. Examples of gates that are commonly used are the following: a b

1.3 SCALARS AND VECTORS

Lecture Notes No. 10

Lecture 6: Coding theory

1 Which of the following summarises the change in wave characteristics on going from infra-red to ultraviolet in the electromagnetic spectrum?

PYTHAGORAS THEOREM WHAT S IN CHAPTER 1? IN THIS CHAPTER YOU WILL:

Appendix C Partial discharges. 1. Relationship Between Measured and Actual Discharge Quantities

12.4 Similarity in Right Triangles

Eigenvectors and Eigenvalues

Solving Radical Equations

Linear Inequalities. Work Sheet 1

NON-DETERMINISTIC FSA

22: Union Find. CS 473u - Algorithms - Spring April 14, We want to maintain a collection of sets, under the operations of:

Linear Algebra Introduction

Math 32B Discussion Session Week 8 Notes February 28 and March 2, f(b) f(a) = f (t)dt (1)

18.06 Problem Set 4 Due Wednesday, Oct. 11, 2006 at 4:00 p.m. in 2-106

Review of Gaussian Quadrature method

Continuous Random Variables Class 5, Jeremy Orloff and Jonathan Bloom

This chapter will show you. What you should already know. 1 Write down the value of each of the following. a 5 2

Acid-Base Equilibria

6.5 Improper integrals

6. Photoionization of acridine through singlet and triplet channels

Surds and Indices. Surds and Indices. Curriculum Ready ACMNA: 233,

CHAPTER 20: Second Law of Thermodynamics

Logic Synthesis and Verification

TOPPER SAMPLE PAPER - 5 CLASS XI MATHEMATICS. Questions. Time Allowed : 3 Hrs Maximum Marks: 100

CEM143 MWF 8:00 8:50 am. October 5, 2018

CEM143 MWF 8:00 8:50 am. October 5, 2018

( ) Same as above but m = f x = f x - symmetric to y-axis. find where f ( x) Relative: Find where f ( x) x a + lim exists ( lim f exists.

The Properties of Stars

SOLUTIONS TO ASSIGNMENT NO The given nonrecursive signal processing structure is shown as

Table of Content. c 1 / 5

AP CALCULUS Test #6: Unit #6 Basic Integration and Applications

Chapter E - Problems

Calculus Cheat Sheet. Integrals Definitions. where F( x ) is an anti-derivative of f ( x ). Fundamental Theorem of Calculus. dx = f x dx g x dx

Green s Theorem. (2x e y ) da. (2x e y ) dx dy. x 2 xe y. (1 e y ) dy. y=1. = y e y. y=0. = 2 e

CS 573 Automata Theory and Formal Languages

SUMMER KNOWHOW STUDY AND LEARNING CENTRE

1B40 Practical Skills

Electromagnetism Notes, NYU Spring 2018

The practical version

CHENG Chun Chor Litwin The Hong Kong Institute of Education

Chapter Gauss Quadrature Rule of Integration

Chapter 8 Roots and Radicals

u( t) + K 2 ( ) = 1 t > 0 Analyzing Damped Oscillations Problem (Meador, example 2-18, pp 44-48): Determine the equation of the following graph.

Section 4.4. Green s Theorem

AP Calculus AB Unit 4 Assessment

Section 4: Integration ECO4112F 2011

MA123, Chapter 10: Formulas for integrals: integrals, antiderivatives, and the Fundamental Theorem of Calculus (pp.

Riemann Sums and Riemann Integrals

Introduction to Olympiad Inequalities

5. Every rational number have either terminating or repeating (recurring) decimal representation.

SECOND HARMONIC GENERATION OF Bi 4 Ti 3 O 12 FILMS

Core 2 Logarithms and exponentials. Section 1: Introduction to logarithms

Transcription:

. Spetrosopy Mss spetrosopy igh resolution mss spetrometry n e used to determine the moleulr formul of ompound from the urte mss of the moleulr ion For exmple, the following moleulr formuls ll hve rough M r of 60, ut more preise M r n give the moleulr formul. e.g. M r = 60.0 moleulr formul = 4 M r M r = 60.0575 moleulr formul = 8 = 60.05 moleulr formul = 4 N igh resolution mss spetrosopy n mesure the mss to 5 d.p. This n help differentite etween ompounds tht pper to hve similr Mr (to the nerest whole numer) Aurte msses of toms: =.0078 =.0000 = 5.9949 N = 4.00 Exmple A ompound is found to hve n urte reltive formul mss of 46.047. It is thought to e either or N N. lulte the M r of eh ompound to 4 deiml ples to work out whih one it is. = (.0000 x ) + (5.9949 x ) + (.0078 x6) = 46.047 N N. = (.0000 x ) + (4.00 x ) + (.0078 x6) = 46.050 Frgmenttion When orgni moleules re pssed through mss spetrometer, it detets oth the whole moleule nd frgments of the moleule. Moleulr ion formed: M [M] +. + e The moleule loses n eletron nd eomes oth n ion nd free rdil Severl peks in the mss spetrum our due to frgmenttion. The Moleulr ion frgments due to ovlent onds reking: [M] +. X + + Y. Reltively stle ions suh s rotions R + suh s + nd ylium ions [R-=] + re ommon. The more stle the ion, the greter the pek intensity. The pek with the highest mss/hrge rtio will e normlly due to the originl moleule tht hsn t frgmented (lled the moleulr ion). As the hrge of the ion is + the mss/ hrge rtio is equl to Mr. This proess produes n ion nd free rdil. The ion is responsile for the pek The yl group present in ronyls, esters id derivtives is R ommon stle ion + Mss spetrum for utne 9 4 4 0 = 58 Eqution for formtion moleulr ion 4 0 [ 4 0 ] +. + e m/z 58 Equtions for formtion of frgment ions from moleulr ions [ 4 0 ] +. [ ] + +. m/z 4 [ 4 0 ] +. [ ] + +. m/z 9 Mss spetrum for utnone The high pek t 4 due to stility of yl group 4 [ ] + Eqution for formtion moleulr ion [ ] +. + e m/z 7 Equtions for formtion of frgment ions from moleulr ions [ ] +. [ ] + +. m/z 57 9 [ ] + [ ] + 57 [ ] +. 7 [ ] +. [ ] + +. m/z 4 [ ] +. [ ] + +. m/z 9 N Goly hemrevise.org

Infrred spetrosopy ertin groups in moleule sor infr-red rdition t hrteristi frequenies omplited spetr n e otined thn provide informtion out the types of onds present in moleule ABVE 500 m - Funtionl group identifition BELW 500 m - Fingerprinting omplited nd ontins mny signls piking out funtionl group signls diffiult. This prt of the spetrum is unique for every ompound, nd so n e used s "fingerprint". e.g. = 680 750 m - - (id) 500-000 m - Use n IR sorption tle provided in exm to dedue presene or sene of prtiulr onds or funtionl groups A omputer will ompre the IR spetr ginst dtse of known pure ompounds to identify the ompound use spetr to identify prtiulr funtionl groups nd to identify impurities, limited to dt presented in wvenumer form Spetr for utnl 000 500 = Asorption or trough in etween 680-750 m - rnge indites presene of = ond Alwys quote the wve numer rnge from the dt sheet - sorptions tend to e rod Asorption or trough in etween 500-000 m - rnge indites presene of - ond in n id Spetr for ethnoi id = rogue sorptions n lso our nd re inditors of impurities N Goly hemrevise.org

NMR spetrosopy Different types of NMR There re two min types of NMR. NMR. (proton) NMR There is only round % in orgni moleules ut modern NMR mhines re sensitive enough to give full spetr for The spetr is simpler spetrum thn the NMR Equivlent ron toms. In NMR spetrum, there is one signl (pek) for eh set of equivlent toms. d peks 4 peks, dinitroenzene, dinitroenzene,4 dinitroenzene N peks N 4 peks peks d 4 peks peks l d peks d e N 5 peks Equivlent ydrogen toms. In n NMR spetrum, there is one signl for eh set of equivlent toms. Ethnol hs groups of different hydrogen toms sets of equivlent s: rtio ::9 sets of equivlent s: rtio :: In ddition the intensity (integrtion vlue) of eh signl is proportionl to the numer of equivlent toms it represents. Br d d d 4sets of equivlent s: rtio 6::: signl sets of equivlent s: rtio :: 4 sets of equivlent s: rtio ::: d N Goly hemrevise.org

Solvents Smples re dissolved in solvents without ny toms, e.g. l 4, Dl. This mens tht in the NMR the solvent will not give ny peks The sme solvent is used in NMR nd in this se there will e one pek due to the solvent tht will pper on the spetrum. owever, it is known where this pek is so it n e ignored. In the exm it is likely this pek will not our on the spetr. lirtion nd shift A smll mount of TMS (tetrmethylsilne) is dded to the smple to lirte the spetrum TMS is used euse: its signl is wy from ll the others it only gives one signl it is non-toxi it is inert it hs low oiling point nd so n e removed from smple esily Si tetrmethylsilne The sme lirtion ompound is used for oth nd NMR The spetr re reorded on sle known s the hemil shift (δ), whih is how muh the field hs shifted wy from the field for TMS.. The δ is mesure in prts per million (ppm) is reltive sle of how fr the frequeny of the proton signl hs shifted wy from tht for TMS. 0 9 8 7 6 5 4 δ hemil shift (ppm) 0 NMR shift The δ depends on wht other toms/groups re ner the more eletronegtive groups gives greter shift. δ ppm N Goly hemrevise.org δ ppm 4

NMR shift 50-90 5-40 60-85 0-40 Spin-Spin oupling in Nmr In high resolution NMR eh signl in the spetrum n e split into further lines due to inequivlent s on neighouring toms. ppm Nulei in identil hemil environments do not show oupling mongst themselves! Splitting of pek = numer of inequivlent s on neighouring toms + signl singlet doulet triplet qurtet pperne Split numer of peks numer of neighouring inequivlent toms 4 0 reltive size : :: ::: The pek due to group will e triplet s it is next to ( ron with s) The pek due to group will e qurtet s it is next to ( ron with s) The pek due to group will e singlet s it is next to ron with no s) The pek due to group will e triplet s it is next to ron with s Shift 0.7-. Integrtion tre The pek due to group will e singlet s it is next to ron with 0 s Shift.-.6 Integrtion tre The pek due to group will e qurtet s it is next to ron with s Shift.7-4. Integrtion tre ppm N Goly hemrevise.org 5

hromtogrphy hromtogrphy is n nlytil tehnique tht seprtes omponents in mixture etween moile phse nd sttionry phse. Seprtion y olumn hromtogrphy depends on the lne etween soluility in the moving phse nd retention in the sttionry phse. A solid sttionry phse seprtes y dsorption, A liquid sttionry phse seprtes y reltive soluility The moile phse my e liquid or gs. The sttionry phse my e solid (s in thinlyer hromtogrphy, TL) or either liquid or solid on solid support (s in gs hromtogrphy, G) If the sttionry phse ws polr nd the moving phse ws non- polr e.g. exne. Then nonpolr ompounds would pss through the olumn more quikly thn polr ompounds s they would hve greter soluility in the non-polr moving phse. (Think out intermoleulr fores) PL stnds for high performne liquid hromtogrphy. PL: sttionry phse is solid sili PL: moile phse liquid In gs-liquid hromtogrphy G the moile phse is inert gs suh s nitrogen, helium, rgon. The Sttionry phse is liquid on n inert solid. Gs-Liquid hromtogrphy Gs-liquid hromtogrphy n e used to seprte mixtures of voltile liquids. The time tken for prtiulr ompound to trvel from the injetion of the smple to where it leves the olumn to the detetor is known s its retention time. This n e used to identify sustne. Flow ontrol In gs-liquid hromtogrphy, the moile phse is gs suh s helium nd the sttionry phse is high oiling point liquid sored onto solid. Smple in oven Some ompounds hve similr retention times so will not e distinguished. disply Bsi gs-liquid hromtogrphy will tell us how mny omponents there re in the mixture y the numer of peks. It will lso tell us the undne of eh sustne. The re under eh pek will e proportionl to the undne of tht omponent. rrier gs olumn detetor Wste outlet It is lso possile for gs-liquid hromtogrphy mhine to e onneted to mss spetrometer, IR or NMR mhine, enling ll the omponents in mixture to e identified. G-MS is used in nlysis, in forensis, environmentl nlysis, irport seurity nd spe proes. Most ommonly mss spetrometer is omined with G to generte mss spetr whih n e nlysed or ompred with spetrl dtse y omputer for positive identifition of eh omponent in the mixture. N Goly hemrevise.org 6

Bringing it ll together. Work out empiril formul Elementl nlysis 66.6%.8%.9%. Using moleulr ion pek m/z vlue from mss spetrum lulte Moleulr formul moleulr ion pek m/z vlue= 44 66.6/.8/.9/6 =5.555 =.8 =.86875 =4 =8 = Mr empiril formul 4 8 = 7 If Mr moleulr formul 44 then ompound is 8 6. Use IR spetr to identify min onds/funtionl group 8 6 ould e n ester, roxyli id or omintion of lohol nd ronyl. Look for IR spetr for = nd - onds There is = ut no - sorptions, so must e n ester. - = 4. Use NMR spetr to give detils of ron hin 4 peks only 4 different environments. singlet of re 9 At δ =0.9 Mens groups 9 Pek t δ 4 shows Are suggests Qurtet mens next to Pek t δ. shows = Are suggests Singlet mens djent to with no hydrogens Pek t δ. shows R- Are mens Triplet mens next to 5 4 δ ppm Put ll together to give finl struture N Goly hemrevise.org 7