...Thermodynamics. Entropy: The state function for the Second Law. Entropy ds = d Q. Central Equation du = TdS PdV

Similar documents
Chemistry. Lecture 10 Maxwell Relations. NC State University

ESCI 341 Atmospheric Thermodynamics Lesson 12 The Energy Minimum Principle

Thermodynamic Variables and Relations

Chapter 3. Property Relations The essence of macroscopic thermodynamics Dependence of U, H, S, G, and F on T, P, V, etc.

Lecture Notes 2014March 13 on Thermodynamics A. First Law: based upon conservation of energy

Outline Review Example Problem 1. Thermodynamics. Review and Example Problems: Part-2. X Bai. SDSMT, Physics. Fall 2014

The Second Law of Thermodynamics (Chapter 4)

Chapter 3. Entropy, temperature, and the microcanonical partition function: how to calculate results with statistical mechanics.

Outline Review Example Problem 1 Example Problem 2. Thermodynamics. Review and Example Problems. X Bai. SDSMT, Physics. Fall 2013

Applied Thermodynamics for Marine Systems Prof. P. K. Das Department of Mechanical Engineering Indian Institute of Technology, Kharagpur

Some properties of the Helmholtz free energy

WHY SHOULD WE CARE ABOUT THERMAL PHENOMENA? they can profoundly influence dynamic behavior. MECHANICS.

1 mol ideal gas, PV=RT, show the entropy can be written as! S = C v. lnt + RlnV + cons tant

Section 3 Entropy and Classical Thermodynamics

Lecture. Polymer Thermodynamics 0331 L First and Second Law of Thermodynamics

Thermodynamics of phase transitions

Chem 75 Winter, 2017 Practice Exam 1

OCN 623: Thermodynamic Laws & Gibbs Free Energy. or how to predict chemical reactions without doing experiments

even at constant T and P, many reversible and irreversible changes of thermodynamic state may

Minimum Bias Events at ATLAS

NENG 301 Week 8 Unary Heterogeneous Systems (DeHoff, Chap. 7, Chap )

Lecture 3 Clausius Inequality

[S R (U 0 ɛ 1 ) S R (U 0 ɛ 2 ]. (0.1) k B

Thermodynamic Properties

(prev) (top) (next) (Throughout, we will assume the processes involve an ideal gas with constant n.)

Chapter 5. Simple Mixtures Fall Semester Physical Chemistry 1 (CHM2201)

Lecture 4 Clausius Inequality

8.044 Lecture Notes Chapter 5: Thermodynamcs, Part 2

Concentrating on the system

Thermodynamic equilibrium

Thermodynamics Free E and Phase D. J.D. Price

Effect of adding an ideal inert gas, M

Basic Thermodynamics Prof. S. K. Som Department of Mechanical Engineering Indian Institute of Technology, Kharagpur

Thermodynamics and Phase Transitions in Minerals

3.20 Exam 1 Fall 2003 SOLUTIONS

The Gibbs Phase Rule F = 2 + C - P

Gibb s free energy change with temperature in a single component system

CHEMICAL ENGINEERING THERMODYNAMICS. Andrew S. Rosen

Chapter 2 Carnot Principle

MME 2010 METALLURGICAL THERMODYNAMICS II. Fundamentals of Thermodynamics for Systems of Constant Composition

MS212 Thermodynamics of Materials ( 소재열역학의이해 ) Lecture Note: Chapter 7

Module 5 : Electrochemistry Lecture 21 : Review Of Thermodynamics

Chapter 4: Partial differentiation

Chapter 7. Entropy. by Asst.Prof. Dr.Woranee Paengjuntuek and Asst. Prof. Dr.Worarattana Pattaraprakorn

4) It is a state function because enthalpy(h), entropy(s) and temperature (T) are state functions.

Introduction Statistical Thermodynamics. Monday, January 6, 14

CONVECTION AND MATTER TRANSPORT PROCESSES REVIEW: CLOSED SYSTEM

Lecture 4 Clausius Inequality

4. All questions are NOT ofequal value. Marks available for each question are shown in the examination paper.

Lecture 3 Evaluation of Entropy

Distinguish between an isothermal process and an adiabatic process as applied to an ideal gas (2)

Preliminary Examination - Day 2 August 16, 2013

Last Name or Student ID

fiziks Institute for NET/JRF, GATE, IIT-JAM, JEST, TIFR and GRE in PHYSICAL SCIENCES

Name: Discussion Section:

Physics 408 Final Exam

Identify the intensive quantities from the following: (a) enthalpy (b) volume (c) refractive index (d) none of these

A Simplified Interpretation of the Basic Thermodynamic Equations

Preliminary Examination - Day 2 August 15, 2014

Challa Vijaya Kumar University of Connecticut Module 4. Physical Chemistry 1 (Thermodynamics) Module 4. Open Source Textbook. Challa Vijaya Kumar

Thermodynamics is the Science of Energy and Entropy

THERMODYNAMIC POTENTIALS

Chapter 2 Gibbs and Helmholtz Energies

Lecture Ch. 2a. Lord Kelvin (a.k.a William Thomson) James P. Joule. Other Kinds of Energy What is the difference between E and U? Exact Differentials

Chapter 12. The Laws of Thermodynamics. First Law of Thermodynamics

Clausius Clapeyron Equation

The Chemical Potential

Enthalpy and Adiabatic Changes

Classical Thermodynamics. Dr. Massimo Mella School of Chemistry Cardiff University

MATTER TRANSPORT (CONTINUED)

Entropy and the Second Law of Thermodynamics

Data Provided: A formula sheet and table of physical constants are attached to this paper.

THERMODYNAMICS. Dr. Sapna Gupta

The Euler Equation. Using the additive property of the internal energy U, we can derive a useful thermodynamic relation the Euler equation.

UNIVESITY OF SWAZILAND FACl.JLTY OF SCIENCE AND ENGINEERING DEPARTMENT OF PHYSICS

(a) How much work is done by the gas? (b) Assuming the gas behaves as an ideal gas, what is the final temperature? V γ+1 2 V γ+1 ) pdv = K 1 γ + 1

Thermodynamics! for Environmentology!

Entropy Changes & Processes

Physics 360 Review 3

UNIVERSITY OF SOUTHAMPTON

Chemistry 223: State Functions, Exact Differentials, and Maxwell Relations David Ronis McGill University

1. Second Law of Thermodynamics

Physics Nov Cooling by Expansion

Thermodynamics of solids 5. Unary systems. Kwangheon Park Kyung Hee University Department of Nuclear Engineering

Physics 408 Final Exam

CHAPTER 3 LECTURE NOTES 3.1. The Carnot Cycle Consider the following reversible cyclic process involving one mole of an ideal gas:

10, Physical Chemistry- III (Classical Thermodynamics, Non-Equilibrium Thermodynamics, Surface chemistry, Fast kinetics)

Thermodynamic condition for equilibrium between two phases a and b is G a = G b, so that during an equilibrium phase change, G ab = G a G b = 0.

Preliminary Examination - Day 2 May 16, 2014

The mathematical description of the motion of Atoms, Molecules & Other Particles. University of Rome La Sapienza - SAER - Mauro Valorani (2007)

1. (10) Calorically perfect ideal air at 300 K, 100 kpa, 1000 m/s, is brought to rest isentropically. Determine its final temperature.

Existing Resources: Supplemental/reference for students with thermodynamics background and interests:

where R = universal gas constant R = PV/nT R = atm L mol R = atm dm 3 mol 1 K 1 R = J mol 1 K 1 (SI unit)

A.1 Homogeneity of the fundamental relation

Quantities and Variables in Thermodynamics. Alexander Miles

PY2005: Thermodynamics

General Physical Chemistry I

Modeling and Analysis of Dynamic Systems

Consequences of Second Law of Thermodynamics. Entropy. Clausius Inequity

Week 5. Energy Analysis of Closed Systems. GENESYS Laboratory

Transcription:

...Thermodynamics Entropy: The state function for the Second Law Entropy ds = d Q T Central Equation du = TdS PdV Ideal gas entropy s = c v ln T /T 0 + R ln v/v 0 Boltzmann entropy S = klogw Statistical Entropy S = k B i p i ln(p i ) October 13, 2017 1 / 25

Fewer entropy with chickens Counting Things You can t count a continuum. This includes states which may never be actually realised. This is where the ideal gas entropy breaks down Boltzmann s entropy requires Quantum Mechanics. October 13, 2017 2 / 25

Equilibrium and the thermodynamic potentials Second Law : entropy increases in any isolated system. Entropy of system+surroundings must increase. A system can reduce its entropy, provided the entropy of the surroundings increases by more. October 13, 2017 3 / 25

Equilibrium and boundary conditions Main postulate of thermodynamics: systems tend to equilibrium. Equilibrium depends on boundary conditions. October 13, 2017 4 / 25

A function for every boundary condition Another statement of 2nd Law... System+surroundings maximise S Compare with mechanical equilibrium System minimises energy In thermodynamic equilibrium System minimises... Free energy October 13, 2017 5 / 25

Free energy Willard Gibbs 1839-1903: A Method of Geometrical Representation of the Thermodynamic Properties of Substances by Means of Surfaces, 1873 Equation of state plotted as a surface of energy vs T and P. Volume, entropy are slopes of this surface Heat capacity, compressibility are curvatures. October 13, 2017 6 / 25

Surface and Slopes: Not like this October 13, 2017 7 / 25

Surfaces and slope: More like something from Lovecraft H.P.Lovecraft 1928 The Call of Cthulhu PV or TS space is completely non-euclidean. Einstein 1928: [on general relativity] The fact that the metric tensor is denoted as geometrical is simply connected to the fact that this formal structure first appeared in the area of study denoted as geometry. However, this is by no means a justification for denoting as geometry every area of study in which this formal structure plays a role, October 13, 2017 8 / 25

Why Free energy Different axes: different function Unmeasurable entropy axis is awkward Equilibrium depends on the type of boundary conditions. Different Definition of Free energy for every boundary condition. Depends on the dependent variables. Maximum work available from a system when boundaries move. Free energies are all state variables. Also referred to as thermodynamic potentials. October 13, 2017 9 / 25

The thermodynamic potentials potential differential natural variables entropy S TdS = du + PdV U, V internal energy U du = TdS PdV S, V enthalpy H H = U + PV dh = TdS + VdP S, P Helmholtz free energy F F = U TS df = PdV SdT T, V the Gibbs free energy G G = H TS dg = VdP SdT T, P October 13, 2017 10 / 25

Hamiltonians, Lagrangians and all that Physicists often lazily think we can start with the Hamiltonian ( energy ). This makes a hidden assumption about boundary conditions In reality, careful thought is needed about what energy to use. e.g. Particle moving in a potential: S,V boundary, use U= PE + KE e.g. Air as sound wave passes: S,P boundary, use H e.g. Reagents dissolved in water: T, V boundary, use F e.g. Water exposed to atmosphere : T, P boundary, use G October 13, 2017 11 / 25

Maxwell Relations State functions have TWO independent variables. Must be relationships between P, V, T and S. Equation of state is one - material specific. Also general mathematical relationships: Maxwell relations. Essential for most thermodynamic derivations. October 13, 2017 12 / 25

Derivation of Maxwell s relations The four Maxwell s relations are identities involving P, V, T and S. They are most conveniently derived from U,H,F,G State functions: second derivatives do not depend on the order of differentiation. e.g. du = TdS -PdV etc. 2 U = 2 U = T = P V S S V S V V S V s S v October 13, 2017 13 / 25

Derivation of Maxwell s relations To recall the Maxwell relations from their derivation it can be seen that: 1 The independent (natural) variables of the potential from which each Maxwell relation is derived appear in the denominators of the relation. 2 Cross multiplication of numerators and denominators yields products of pairs of conjugate variables, S T and P V. 3 The sign can be deduced by recourse to the appropriate potential function. October 13, 2017 14 / 25

Potentials etc potential differential Maxwell relation internal energy U du = TdS PdV ( T ) V S = ( ) P S V enthalpy H H = U + PV Helmholtz free energy F F = U TS the Gibbs free energy G G = H TS dh = TdS + VdP df = PdV SdT dg = VdP SdT ( T ) P S = ( ) V S P ( P ) T V = ( ) S V T ( V ) T P = ( ) S P T Worth remembering! October 13, 2017 15 / 25

TdS equations To relate entropy changes to measurable quantities. ( ) P Tds = c V dt + T dv T v ( ) V Tds = c P dt T dp T P ( ) ( ) T T Tds = c P dv + c V dp V P P V such as Heat capacities, thermal expansion, compressibility and Gay-Lussac coefficient October 13, 2017 16 / 25

Gay Lussac Coefficient Gay-Lussac, or Amonton s Law greater pressure causes more hot air k GL = P T k GL = ( ) P T V = ( ) S V T = or maybe not - unspoken isothermal assumption. k GL = ( P T k GL = ) P T S = ( S V ) T Louis Joseph Gay-Lussac; 1778 1850 These k GL are properties of the material. October 13, 2017 17 / 25

ISO iso- is a prefix from the Greek isos, meaning equal. Equal in all parts/directions isotropic Equal element isotopic Equal Temperature: isothermal Equal Pressure: isobaric Equal Volume: isochoric = isovolumetric Equal Enthalpic: isenthalpic Equal Energy: isoenergetic Equal Entropy: isentropic Equal Heat: adiabatic October 13, 2017 18 / 25

Internal Energy for Isochoric Isentropic processes If no work is done (V constant) du = TdS ( ) PdV U = ds + S Equate coefficients to get: 1 T = ( ) U S V 2 P = ( U V TdS equation V ) S, Tds = c V dt + T ( ) U dv V S ( ) P dv T v U = Q (isochoric, no work) note: d q R = TdS for any REVERSIBLE change with no restriction on dv Heat capacity For reversible, isochoric heat flows: C V = d Q V dt = du V dt = ( ) U T V and C V = T ds dt V = T ( ) S T V From ( partial derivatives T ) V S = ( ) P S V, a Maxwell s relation. October 13, 2017 19 / 25

Enthalpy for Isobaric Isentropic processes H=U+PV dh = du + PdV + VdP = TdS ( + ) VdP H dh = ds + S P ( ) H dp P S Equate coefficients to get: 1 T = ( ) H S P 2 V = ( ) H P S TdS equation ( ) V Tds = c P dt T dp T P Constant P 0, only P 0 V work: H = Q (P f = P i = P 0 ), dh = TdS for isobaric process. note d q R = T ds for any REVERSIBLE changes with no restriction on dp. Heat capacity C P = d Q P dt = dh P dt = ( ) H T P and C P = T ds P dt = T ( ) S T P From ( partial derivatives T ) P S = ( ) V S P, another Maxwell s relation. October 13, 2017 20 / 25

Helmholtz for Isobaric Isothermal processes F=U-TS df = du TdS SdT = PdV SdT F F dv + dt = V T T V Equate coefficients to get: F 1 P = V T F 2 S = T V e.g. Chemicals in a closed container, Finally, second derivatives of F. P S = reactants dispersed in water. T V V T, another Maxwell s relation. October 13, 2017 21 / 25

Gibbs for Isobaric isothermal processes. dg = dh TdS SdT = VdP SdT G G = dp + dt P T T P For systems open to pressure transmitting medium, no exchanging material. Equate coefficients to get: G 1 V = P T G 2 S = T P from partial derivatives V S T P = P T, another Maxwell s relation. October 13, 2017 22 / 25

System in contact with a T 0 & P 0 reservoir, dg=0 Consider a system held at T 0, P 0, initially out of equilibrium. Heat flows, and work is done as it equilibrates. Change in surroundings S 0 = Q/T 0, V 0 = V = W /P 0 Eventually system reaches equilibrium. free diathermal wall system Q TP 2nd law S sys + S 0 0. 1st law Q = U + P 0 V Combined: U + P 0 V T 0 S 0 reservoir T 0 P 0 adiabatic wall October 13, 2017 23 / 25

System in contact with itself: dg=0 Combined Laws: U + P 0 V T 0 S 0 free diathermal wall Since P 0 = P i = P f and T 0 = T i = T f U + (P f V f P i V i ) (T f S f T i S i ) 0 U + (PV ) (TS) 0 (U + PV TS) 0 G 0 system Q TP reservoir T 0 P 0 adiabatic wall Any change moving towards equilibrium must reduce G sys Minimising G sys is equivalent to maximising S sys + S 0 : i.e. obeys 2nd law. October 13, 2017 24 / 25

Max s Maxwell Mnemonic Good Physicists Have Studied Under Very Fine Teachers Max Born (1882-1970, UoE 1936-52) P and S have negative signs. Potentials: coefficients in opposite corners, differentials adjacent. Sign goes with coefficient. e.g. df = SdT PdV Maxwell: Use corners, signs and constants from the bottom variables. e.g. ds dp T = dv dt P October 13, 2017 25 / 25