C.3 First-Order Linear Differential Equations

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A34 APPENDIX C Differential Equations C.3 First-Order Linear Differential Equations Solve first-order linear differential equations. Use first-order linear differential equations to model and solve real-life problems. First-Order Linear Differential Equations Definition of a First-Order Linear Differential Equation A first-order linear differential equation is an equation of the form where P and Q are functions of x. An equation that is written in this form is said to be in standard form. STUDY TIP The term first-order refers to the fact that the highest-order derivative of y in the equation is the first derivative. To solve a linear differential equation, write it in standard form to identify the functions Px and Qx. Then integrate Px and form the expression ux e Px dx Integrating factor which is called an integrating factor. The general solution of the equation is y uxqxux dx. EXAMPLE Find the general solution of y y e x. Solving a Linear Differential Equation Solution For this equation, Px and Qx ex. So, the integrating factor is ux e dx Integrating factor e x. This implies that the general solution is y e xex e x dx e x 2 e2x C 2 ex Ce x. In Example, the differential equation was given in standard form. For equations that are not written in standard form, you should first convert to standard form so that you can identify the functions Px and Qx.

APPENDIX C Differential Equations A35 EXAMPLE 2 Find the general solution of xy 2y x 2. Solving a Linear Differential Equation Assume x > 0. Solution Begin by writing the equation in standard form. y 2 x y x Standard form, In this form, you can see that Px 2x and Qx x. So, Px dx 2 x dx 2 ln x ln x 2 which implies that the integrating factor is y Solve for in the differential equation in Example 2. Use this equation for to determine the slopes of y at the points, 0 and e 2, 2e. Now graph the particular solution y x 2 ln x and estimate the slopes at x and x e 2. What happens to the slope of y as x approaches zero? y TECHNOLOGY ux e Px dx e ln x2 x 2. This implies that the general solution is y ux Qxux dx 2 x x x 2 dx 2 x x dx x 2 ln x C. Integrating factor Form of general solution Substitute. Simplify. From Example 2, you can see that it can be difficult to solve a linear differential equation. Fortunately, the task is greatly simplified by symbolic integration utilities. Use a symbolic integration utility to find the particular solution of the differential equation in Example 2, given the initial condition y when x. Guidelines for Solving a Linear Differential Equation. Write the equation in standard form. 2. Find the integrating factor ux e Px dx. 3. Evaluate the integral below to find the general solution. y uxqxux dx

A36 APPENDIX C Differential Equations Application EXAMPLE 3 Finding a Balance You are setting up a continuous annuity trust fund. For 20 years, money is continuously transferred from your checking account to the trust fund at the rate of $000 per year (about $2.74 per day). The account earns 8% interest, compounded continuously. What is the balance in the account after 20 years? Solution Let A represent the balance after t years. The balance increases in two ways: with interest and with additional deposits. The rate at which the balance is changing can be modeled by In standard form, this linear differential equation is 0.08A 000. Interest 0.08A 000 Standard form which implies that Pt 0.08 and Qt 000. The general solution is A 2,500 Ce 0.08t. Because A 0 when t 0, you can determine that C 2,500. So, the revenue after 20 years is A 2,500 2,500e 0.0820 2,500 6,92.9 $49,42.9. Deposits TAKE ANOTHER LOOK Why an Integrating Factor Works When both sides of the first-order linear differential equation are multiplied by the integrating factor e Px dx, you obtain ye Px dx Pxe Px dx y Qxe Px dx. Show that the left side is the derivative of ye Px dx, which implies that the general solution is given by ye Px dx Qxe Px dx dx.

APPENDIX C Differential Equations A37 WARM-UP C.3 The following warm-up exercises involve skills that were covered in earlier sections. You will use these skills in the exercise set for this section. In Exercises 4, simplify the expression.. e x e 2x e x 2. 3. 4. e ln x 3 In Exercises 5 0, find the indefinite integral. e xex e 2x 2 ln xx e 5. 6. 7. 8. 9. e x 2 e 2x dx e 2x xe x dx 2x 5 dx x x 2 2x 3 dx 4x 3 2 dx 0. x x 2 2 dx EXERCISES C.3 In Exercises 6, write the linear differential equation in standard form.. x 3 2x 2 y 3y 0 2. 3. 4. 5. y x y 6. x x 2 y y In Exercises 7 8, solve the differential equation. 7. 3y 6 8. 5y 5 dx dx 9. y ex 0. 3y e3x dx dx. 2y 2. 3x dx y 3x 4 x dx x 3. 4. 5. x y y x 2 6. xy y x 2 7. x 3 y 2y e x 2 8. y 52x y 0 xy xy y xe x y x 3 y y 5xy x In Exercises 9 22, solve for y in two ways. y y 4 9. 20. 2. 22. y 2xy 2x y 5y e 5x xy y x 2 ln x y 0y 5 y 4xy x In Exercises 23 26, match the differential equation with its solution. Differential Equation Solution 23. (a) y Ce x2 24. (b) y 2 Cex2 25. (c) y x 2 C 26. (d) y Ce 2x y 2x 0 y 2y 0 y 2xy 0 y 2xy x In Exercises 27 34, find the particular solution that satisfies the initial condition. Differential Equation Initial Condition 27. 28. 29. y 4 when x y 2 when x 2 30. 3. y 6 when x 0 32. 33. 34. x 2 y 4xy 0 y 5 when x y 0 when x y y 6e x y 2y e 2x y 3 when x 0 xy y 0 y y x y 4 when x 0 y 3x 2 y 3x 2 y 2x y 0 y 2 when x xy 2y x 2

A38 APPENDIX C Differential Equations 35. Sales The rate of change (in thousands of units) in sales S is modeled by where t is the time in years. Solve this differential equation and use the result to complete the table. 36. Sales The rate of change in sales S is modeled by where t is the time in years and S 0 when t 0. Solve this differential equation for S as a function of t. Elasticity of Demand In Exercises 37 and 38, find the demand function p f x. Recall from Section 3.5 that the price elasticity of demand was defined as 37. ds 0.200 S 0.2t t 0 2 3 4 5 6 7 8 9 0 S 0 ds k L S k 2 t 400 3x, 500 38. 3x, p 2 when x 00 Supply and Demand In Exercises 39 and 40, use the demand and supply functions to find the price p as a function of time t. Begin by setting Dt equal to St and solving the resulting differential equation. Find the general solution, and then use the initial condition to find the particular solution. 39. Dt 480 5pt 2pt St 300 8pt pt p0 $75.00 Demand function Supply function Initial condition 40. Dt 4000 5pt 4pt St 2800 7pt 2pt p0 $000.00 Demand function Supply function Initial condition 4. Investment A brokerage firm opens a new real estate investment plan for which the earnings are equivalent to continuous compounding at the rate of r. The firm estimates that deposits from investors will create a net cash flow of Pt dollars, where t is the time in years. The rate of change in the total investment A is modeled by ra Pt. p 340 when x 20 pxdpdx. (a) Solve the differential equation and find the total investment A as a function of t. Assume that A 0 when t 0. (b) Find the total investment A after 0 years given that P $500,000 and r 9%. 42. Investment Let At be the amount in a fund earning interest at the annual rate of r, compounded continuously. If a continuous cash flow of P dollars per year is withdrawn from the fund, then the rate of decrease of A is given by the differential equation ra P where A A 0 when t 0. (a) Solve this equation for A as a function of t. (b) Use the result of part (a) to find A when A 0 $2,000,000, r 7%, P $250,000, and t 5 years. (c) Find A 0 if a retired person wants a continuous cash flow of $40,000 per year for 20 years. Assume that the person s investment will earn 8%, compounded continuously. 43. Velocity A booster rocket carrying an observation satellite is launched into space. The rocket and satellite have mass m and are subject to air resistance proportional to the velocity v at any time t. A differential equation that models the velocity of the rocket and satellite is m dv mg kv where g is the acceleration due to gravity. Solve the differential equation for v as a function of t. 44. Health An infectious disease spreads through a large population according to the model y 4 where y is the percent of the population exposed to the disease, and t is the time in years. (a) Solve this differential equation, assuming y0 0. (b) Find the number of years it takes for half of the population to have been exposed to the disease. (c) Find the percentage of the population that has been exposed to the disease after 4 years. 45. Research Project Use your school s library, the Internet, or some other reference source to find an article in a scientific or business journal that uses a differential equation to model a real-life situation. Write a short paper describing the situation. If possible, describe the solution of the differential equation.