Physics for Scientists and Engineers I

Similar documents
Average & instantaneous velocity and acceleration Motion with constant acceleration

(b) 10 yr. (b) 13 m. 1.6 m s, m s m s (c) 13.1 s. 32. (a) 20.0 s (b) No, the minimum distance to stop = 1.00 km. 1.

1. Consider a PSA initially at rest in the beginning of the left-hand end of a long ISS corridor. Assume xo = 0 on the left end of the ISS corridor.

Physics for Scientists and Engineers I

Motion. Part 2: Constant Acceleration. Acceleration. October Lab Physics. Ms. Levine 1. Acceleration. Acceleration. Units for Acceleration.

Chapter 2. Motion along a straight line. 9/9/2015 Physics 218

Motion in a Straight Line

PHYSICS 1210 Exam 1 University of Wyoming 14 February points

Lecture 3: 1-D Kinematics. This Week s Announcements: Class Webpage: visit regularly

Phys 110. Answers to even numbered problems on Midterm Map

Physics Worksheet Lesson 4: Linear Motion Section: Name:

Physics 100: Lecture 1

Physics 101 Lecture 4 Motion in 2D and 3D

CHAPTER 2 KINEMATICS IN ONE DIMENSION ANSWERS TO FOCUS ON CONCEPTS QUESTIONS

A 1.3 m 2.5 m 2.8 m. x = m m = 8400 m. y = 4900 m 3200 m = 1700 m

Name: Per: L o s A l t o s H i g h S c h o o l. Physics Unit 1 Workbook. 1D Kinematics. Mr. Randall Room 705

Physic 231 Lecture 4. Mi it ftd l t. Main points of today s lecture: Example: addition of velocities Trajectories of objects in 2 = =

What distance must an airliner travel down a runway before reaching

Introduction to LoggerPro

Chapter 2 PROBLEM SOLUTIONS

Chapter Direct Method of Interpolation

Physics 2A HW #3 Solutions

3 Motion with constant acceleration: Linear and projectile motion

ENGR 1990 Engineering Mathematics The Integral of a Function as a Function

2D Motion WS. A horizontally launched projectile s initial vertical velocity is zero. Solve the following problems with this information.

A Kalman filtering simulation

PHY2048 Exam 1 Formula Sheet Vectors. Motion. v ave (3 dim) ( (1 dim) dt. ( (3 dim) Equations of Motion (Constant Acceleration)

September 20 Homework Solutions

Phys 221 Fall Chapter 2. Motion in One Dimension. 2014, 2005 A. Dzyubenko Brooks/Cole

An object moving with speed v around a point at distance r, has an angular velocity. m/s m

2/5/2012 9:01 AM. Chapter 11. Kinematics of Particles. Dr. Mohammad Abuhaiba, P.E.

Version 001 test-1 swinney (57010) 1. is constant at m/s.

0 for t < 0 1 for t > 0

Chapter 3: Motion in One Dimension

MATH 124 AND 125 FINAL EXAM REVIEW PACKET (Revised spring 2008)

f t f a f x dx By Lin McMullin f x dx= f b f a. 2

ME 141. Engineering Mechanics

Physics Notes - Ch. 2 Motion in One Dimension

CHAPTER 2: Describing Motion: Kinematics in One Dimension

e t dt e t dt = lim e t dt T (1 e T ) = 1

Ch.4 Motion in 2D. Ch.4 Motion in 2D

Science Advertisement Intergovernmental Panel on Climate Change: The Physical Science Basis 2/3/2007 Physics 253

Unit 1 Test Review Physics Basics, Movement, and Vectors Chapters 1-3

Motion in One Dimension 2

Forms of Energy. Mass = Energy. Page 1. SPH4U: Introduction to Work. Work & Energy. Particle Physics:

4.8 Improper Integrals

Solutions to Problems from Chapter 2

Brock University Physics 1P21/1P91 Fall 2013 Dr. D Agostino. Solutions for Tutorial 3: Chapter 2, Motion in One Dimension

Chapter 12: Velocity, acceleration, and forces

One-Dimensional Kinematics

Ground Rules. PC1221 Fundamentals of Physics I. Kinematics. Position. Lectures 3 and 4 Motion in One Dimension. A/Prof Tay Seng Chuan

Decimal moved after first digit = 4.6 x Decimal moves five places left SCIENTIFIC > POSITIONAL. a) g) 5.31 x b) 0.

Lecture 2-1 Kinematics in One Dimension Displacement, Velocity and Acceleration Everything in the world is moving. Nothing stays still.

NEWTON S SECOND LAW OF MOTION

Chapter 10. Simple Harmonic Motion and Elasticity. Goals for Chapter 10

Physics for Scientists and Engineers. Chapter 2 Kinematics in One Dimension

Motion on a Curve and Curvature

t s (half of the total time in the air) d?

Physics 201, Lecture 5

Motion. Acceleration. Part 2: Constant Acceleration. October Lab Phyiscs. Ms. Levine 1. Acceleration. Acceleration. Units for Acceleration.

Magnetostatics Bar Magnet. Magnetostatics Oersted s Experiment

Suggested Practice Problems (set #2) for the Physics Placement Test

Equations of motion for constant acceleration

UNIT # 01 (PART II) JEE-Physics KINEMATICS EXERCISE I. 2h g. 8. t 1 = (4 1)i ˆ (2 2) ˆj (3 3)kˆ 1. ˆv = 2 2h g. t 2 = 2 3h g

Properties of Logarithms. Solving Exponential and Logarithmic Equations. Properties of Logarithms. Properties of Logarithms. ( x)

The solution is often represented as a vector: 2xI + 4X2 + 2X3 + 4X4 + 2X5 = 4 2xI + 4X2 + 3X3 + 3X4 + 3X5 = 4. 3xI + 6X2 + 6X3 + 3X4 + 6X5 = 6.

Kinematics Vocabulary. Kinematics and One Dimensional Motion. Position. Coordinate System in One Dimension. Kinema means movement 8.

1. Kinematics I: Position and Velocity

Q2.4 Average velocity equals instantaneous velocity when the speed is constant and motion is in a straight line.

KINEMATICS IN ONE DIMENSION

1. Kinematics of Particles

Topic 1: Linear motion and forces

5.1-The Initial-Value Problems For Ordinary Differential Equations

Physics 201 Lecture 2

3.6 Derivatives as Rates of Change

Physics 180A Fall 2008 Test points. Provide the best answer to the following questions and problems. Watch your sig figs.

RESPONSE UNDER A GENERAL PERIODIC FORCE. When the external force F(t) is periodic with periodτ = 2π

15. Vector Valued Functions

Physics 218 Exam 1. with Solutions Fall 2010, Sections Part 1 (15) Part 2 (20) Part 3 (20) Part 4 (20) Bonus (5)

Welcome Back to Physics 215!

Location is relative. Coordinate Systems. Which of the following can be described with vectors??


INSTANTANEOUS VELOCITY

( ) ( ) ( ) ( ) ( ) ( y )

Contraction Mapping Principle Approach to Differential Equations

1. VELOCITY AND ACCELERATION

when t = 2 s. Sketch the path for the first 2 seconds of motion and show the velocity and acceleration vectors for t = 2 s.(2/63)

FM Applications of Integration 1.Centroid of Area

1.0 Electrical Systems

4.5 Constant Acceleration

Two Coupled Oscillators / Normal Modes

Traveling Waves. Chapter Introduction

INTEGRALS. Exercise 1. Let f : [a, b] R be bounded, and let P and Q be partitions of [a, b]. Prove that if P Q then U(P ) U(Q) and L(P ) L(Q).

Physics 101: Lecture 03 Kinematics Today s lecture will cover Textbook Sections (and some Ch. 4)

Chapter 3 Kinematics in Two Dimensions

Collision Detection and Bouncing

PHYSICS 211 MIDTERM I 21 April 2004

HW #1 Solutions. Lewis Structures: Using the above rules, determine the molecular structure for Cl2CO. Hint: C is at the center.

Think of the Relationship Between Time and Space Again

Transcription:

Physics for Scieniss nd Engineers I PHY 48, Secion 4 Dr. Beriz Roldán Cueny Uniersiy of Cenrl Florid, Physics Deprmen, Orlndo, FL

Chper - Inroducion I. Generl II. Inernionl Sysem of Unis III. Conersion of unis IV. Dimensionl Anlysis V. Problem Soling Sregies

I. Objecies of Physics - Find he limied number of fundmenl lws h goern nurl phenomen. - Use hese lws o deelop heories h cn predic he resuls of fuure eperimens. -Epress he lws in he lnguge of mhemics. - Physics is diided ino si mjor res:. Clssicl Mechnics (PHY48). Reliiy 3. Thermodynmics 4. Elecromgneism (PHY49) 5. Opics (PHY49) 6. Qunum Mechnics

II. Inernionl Sysem of Unis POWER PREFIX ABBREVIATION QUANTITY Lengh UNIT NAME meer UNIT SYMBOL m 5 9 pe er gig P T G Time second s 6 meg M Mss kilogrm kg 3 kilo k Speed m/s heco h Accelerion m/s dek d Force Newon N - deci D Pressure Pscl P N/m - ceni c Energy Power Joule W J Nm W J/s -3-6 -9 milli micro nno m µ n Temperure Kelin K - pico p -5 femo f

III. Conersion of unis Chin-link conersion mehod: The originl d re muliplied successiely by conersion fcors wrien s uniy. Unis cn be reed like lgebric quniies h cn cncel ech oher ou. Emple: 36 fee/h m/s fee h m 36.7 m/ s h 36s 3.8 fee IV. Dimensionl Anlysis Dimension of quniy: indices he ype of quniy i is; lengh [L], mss [M], ime [T] Dimensionl consisency: boh sides of he equion mus he he sme dimensions. Emple: / [ ] [ L] Noe: There re no dimensions for he consn (/) [ L] [ ] [ ] [ L] T T T [ ] [ T ] [ L] [ L] [ L] L

Significn figure one h is relibly known. Zeros my or my no be significn: E: - Those used o posiion he deciml poin re no significn. - To remoe mbiguiy, use scienific noion..56 m/s hs 3 significn figures, deciml plces..56 m/s hs 3 significn figures nd 6 deciml plces.. m hs 3 significn figures. 5 m is mbiguous.5 3 ( figures),.5 3 (3 fig.) Order of mgniude he power of h pplies.

V. Problem soling cics Eplin he problem wih your own words. Mke good picure describing he problem. Wrie down he gien d wih heir unis. Coner ll d ino S.I. sysem. Idenify he unknowns. Find he connecions beween he unknowns nd he d. Wrie he physicl equions h cn be pplied o he problem. Sole hose equions. Alwys include unis for eery quniy. Crry he unis hrough he enire clculion. Check if he lues obined re resonble order of mgniude nd unis.

MECHANICS Kinemics Chper - Moion long srigh line I. Posiion nd displcemen II. Velociy III. Accelerion IV. Moion in one dimension wih consn ccelerion V. Free fll Pricle: poin-like objec h hs mss bu infiniesiml size.

I. Posiion nd displcemen Posiion: Defined in erms of frme of reference: or y is in D. - The objec s posiion is is locion wih respec o he frme of reference. Posiion-Time grph: shows he moion of he pricle (cr). The smooh cure is guess s o wh hppened beween he d poins.

I. Posiion nd displcemen Displcemen: Chnge from posiion o - (.) during ime inerl. - Vecor quniy: Mgniude (bsolue lue) nd direcion (sign). - Coordine (posiion) Displcemen Coordine sysem > Only he iniil nd finl coordines influence he displcemen mny differen moions beween nd gie he sme displcemen.

Disnce: lengh of ph followed by pricle. - Sclr quniy Displcemen Disnce Emple: round rip house-work-house disnce reled km displcemen Reiew: - Vecor quniies need boh mgniude (size or numericl lue) nd direcion o compleely describe hem. - We will use nd signs o indice ecor direcions. - Sclr quniies re compleely described by mgniude only.

II. Velociy Aerge elociy: Rio of he displcemen h occurs during priculr ime inerl o h inerl. g (.) Moion long -is -Vecor quniy indices no jus how fs n objec is moing bu lso in which direcion i is moing. -SI Unis: m/s - Dimensions: Lengh/Time [L]/[T] - The slope of srigh line connecing poins on n -ersus- plo is equl o he erge elociy during h ime inerl.

Aerge speed: Tol disnce coered in ime inerl. S g Tol disnce (.3) S g mgniude V g S g lwys > Sclr quniy Sme unis s elociy Emple: A person dries 4 mi 3mi/h nd 4 mi nd 5 mi/h Is he erge speed >,<, 4 mi/h? <4 mi/h 4 mi/(3 mi/h).3 h ; 4 mi/(5 mi/h).8 h o.3 h S g 8 mi/.3h 37.5mi/h

Insnneous elociy: How fs pricle is moing gien insn. lim d d (.4) - Vecor quniy - The limi of he erge elociy s he ime inerl becomes infiniesimlly shor, or s he ime inerl pproches zero. - The insnneous elociy indices wh is hppening eery poin of ime. - Cn be posiie, negie, or zero. () - The insnneous elociy is he slope of he line ngen o he s. cure (green line).

Insnneous elociy: Posiion Slope of he pricle s posiion-ime cure gien insn of ime. V is ngen o () when Time When he elociy is consn, he erge elociy oer ny ime inerl is equl o he insnneous elociy ny ime. Insnneous speed: Mgniude of he insnneous elociy. Emple: cr speedomeer. - Sclr quniy Aerge elociy (or erge ccelerion) lwys refers o n specific ime inerl. Insnneous elociy (ccelerion) refers o n specific insn of ime.

III. Accelerion Aerge ccelerion: Rio of chnge in elociy o he ime inerl in which he chnge occurs. g (.5) - Vecor quniy - Dimensions [L]/[T], Unis: m/s - The erge ccelerion in - plo is he slope of srigh line connecing poins corresponding o wo differen imes. V

Insnneous ccelerion: Limi of he erge ccelerion s pproches zero. - Vecor quniy d d lim d d (.6) - The insnneous ccelerion is he slope of he ngen line (- plo) priculr ime. (green line in B) - Aerge ccelerion: blue line. - When n objec s elociy nd ccelerion re in he sme direcion (sme sign), he objec is speeding up. - When n objec s elociy nd ccelerion re in he opposie direcion, he objec is slowing down.

- Posiie ccelerion does no necessrily imply speeding up, nd negie ccelerion slowing down. Emple (): -5m/s ; m/s in 5s pricle slows down, g 5m/s - An objec cn he simulneously nd Emple (): ()A ()A ()A ; A s, () bu ()A Emple (3): - The cr is moing wih consn posiie elociy (red rrows minining sme size) Accelerion equls zero. Emple (4): ccelerion elociy - Velociy nd ccelerion re in he sme direcion, is uniform (blue rrows of sme lengh) Velociy is incresing (red rrows re geing longer).

Emple (5): - ccelerion elociy - Accelerion nd elociy re in opposie direcions. - Accelerion is uniform (blue rrows sme lengh). - Velociy is decresing (red rrows re geing shorer).

g - Equions for moion wih consn ccelerion: (.3) ) ( (. ) (.7) (. ) ) ( (. ) (.7) (.) ) ( ) ( ) ( (. ) (.7) (. ) (.9) (.8) (.9) (.7) (.8) (.7) g g g g missing IV. Moion in one dimension wih consn ccelerion - Aerge ccelerion nd insnneous ccelerion re equl. g

PROBLEMS - Chper P. A red cr nd green cr moe owrd ech oher in djcen lnes nd prllel o The -is. A ime, he red cr is nd he green cr m. If he red cr hs consn elociy of km/h, he crs pss ech oher 44.5 m, nd if i hs consn elociy of 4 km/h, hey pss ech oher 76.6m. Wh re () he iniil elociy, nd (b) he ccelerion of he green cr? r 4km/h r km/h O X r 76.6m 3 km h m 4.m / s h 36s km X r 44.5 m d m X g m r g r g r g () () r r 44.5m 8s r 5.55m / s 76.6m 6.9s r.m / s r r g g.5 g.5 g g g 76.6 44.5 g g (6.9s).5 (6.9s) (8s).5 (8s) g g The cr moes o he lef (-) in my reference sysem <, < g. m/s g 3.55 m/sc

P: A he insn he rffic ligh urns green, n uomobile srs wih consn ccelerion of. m/s. A he sme insn, ruck, reling wih consn speed of 9.5 m/s, oerkes nd psses he uomobile. () How fr beyond he rffic signl will he uomobile oerke he ruck? (b) How fs will he uomobile be reling h insn? c. m/s, c m/s s Cr (m) Truck s 9.5 m/s d? (m) T d 9.5 () Truck d c T C c d.5 (.m / s). () Cr ( ) 9.5. 8.63 s d (9.5m / s)(8.63s) 8m ( b) d (.m / s) (8m) 9m / s f c f P3: A proon moes long he -is ccording o he equion: 5, where is in meers nd is in seconds. Clcule () he erge elociy of he proon during he firs 3s of is moion. () 3 () ( 5)() 3 ( )() 3 g 8 m/s. 3 (b) Insnneous elociy of he proon 3s. d ( ) 5 (3s) 5 3 m / s d (c) Insnneous ccelerion of he proon 3s. ( ) m / s (3s) d d

(d) Grph ersus nd indice how he nswer o () (erge elociy) cn be obined from he plo. (e) Indice he nswer o (b) (insnneous elociy) on he grph. (f) Plo ersus nd indice on i he nswer o (c). 5 5 P4. An elecron moing long he -is hs posiion gien by: 6 ep(-) m, where is in seconds. How fr is he elecron from he origin when i momenrily sops? () when ()?? d d 6e 6e 6e ( ) ( ) ; ( e > ) s ( ) 6/ e 5. 9m

P5. When high speed pssenger rin reling 6 km/h rounds bend, he engineer is shocked o see h locomoie hs improperly enered ino he rck from siding nd is disnce D 676 m hed. The locomoie is moing 9 km/h. The engineer of he high speed rin immediely pplies he brkes. () Wh mus be he mgniude of he resuln decelerion if collision is o be oided? (b) Assume h he engineer is when he firs spos he locomoie. Skech () cures represening he locomoie nd high speed rin for he siuion in which collision is jus oided nd is no quie oided. s Trin Locomoie d L (m) > s D Dd L (m) T 6km/h 44.7 m/s T D moemen wih <ce L 9 km/h 8.5 m/s is consn d d L L d 8.5 L () Locomoie L 8.5 D d 676 44.7 () T T L T Trin

P5. Tf Tf T T (3) (4) d T L T T ( D d 38.3m 44.7m/ s ( 44.7m / s)(8.5m / s) 36m ( eq. ) d d L ) T (44.7m / s) (676m d ) L (4) L L / s (3) from () 47.4s 8.5 () (3) T d L 36m / s 38.3m.947m / s Locomoie Collision cn be oided L T 676 8.5 44.7.5 T - Collision cn be oided: Trin Slope of () s. locomoie 47.4 s (he poin were boh Lines mee) insnneous locom > Slope of () s. rin Collision cn no be oided - Collision cnno be oided: Slope of () s. locomoie 47.4 s < Slope of () s. rin

- The moion equions cn lso be obined by indefinie inegrion: d d d d C; ( )() C C d d d d d ( ) d () () C' d C' d d C'; V. Free fll Moion direcion long y-is ( y > upwrds) Free fll ccelerion: (ner Erh s surfce) -g -9.8 m/s (in ce ccelerion mo. eqs.) Due o griy downwrd on y, direced owrd Erh s cener

Approimions: - Loclly, Erh s surfce essenilly fl free fll hs sme direcion slighly differen poins. - All objecs he sme plce he sme free fll (neglecing ir influence). VI. Grphicl inegrion in moion nlysis From () ersus grph inegrion re beween ccelerion cure nd ime is, from o () d Similrly, from () ersus grph inegrion re under cure from o () d

P6: A rocke is lunched ericlly from he ground wih n iniil elociy of 8m/s. I scends wih consn ccelerion of 4 m/s o n liude of km. Is moors hen fil, nd he rocke coninues upwrd s free fll pricle nd hen flls bck down. () Wh is he ol ime elpsed from keoff unil he rocke srikes he ground? (b) Wh is he mimum liude reched? (c) Wh is he elociy jus before hiing ground? ) Ascen 4m/s y y y m y km -g 4m/s, 3, 4 -g y y.5 (4m / s 4 8 53.48s ) (53.48s) 8m / s 94m / s ) Ascen -9.8 m/s m s g 94 / 9. 96s 9.8m / s Tol ime scen 53.48 s9.96 s 83.44 s 8m/s 3 3) Descen -9.8 m/s 4.5 94 4.9 4. s y 4 4 4 4 4 ol 4 53.48 s 9.96 s 4. s37.6 s h m y y - 4 m -4.9 (94 m/s)(9.96s)-(4.9m/s )(9.96s) 44 m h m 4.4 km 3( ) g g 53.35m / s 3 4 4