Asymptotics of Young Diagrams and Hook Numbers

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Asymptotics of Young Diagrams and Hook Numbers Amitai Regev Department of Theoretical Mathematics The Weizmann Institute of Science Rehovot 76100, Israel and Department of Mathematics The Pennsylvania State University University Park, PA 16802, U.S.A. Anatoly Vershik St. Petersburg branch of the Mathematics Institute of the Russian Academy of Science Fontanka 27 St. Petersburg, 191011 Russia and The Institute for Advanced Studies of the Hebrew University Givat Ram Jerusalem, Israel Submitted: August 22, 1997; Accepted: September 21, 1997 Abstract: Asymptotic calculations are applied to study the degrees of certain sequences of characters of symmetric groups. Starting with a given partition µ, we deduce several skew diagrams which are related to µ. To each such skew diagram there corresponds the product of its hook numbers. By asymptotic methods we obtain some unexpected arithmetic properties between these products. The authors do not know finite, nonasymptotic proofs of these results. The problem appeared in the study of the hook formula for various kinds of Young diagrams. The proofs are based on properties of shifted Schur functions, due to Okounkov and Olshanski. The theory of these functions arose from the asymptotic theory of Vershik and Kerov of the representations of the symmetric groups. Work partially supported by N.S.F. Grant No.DMS-94-01197. Partially supported by Grant INTAS 94-3420 and Russian Fund 96-01-00676

the electronic journal of combinatorics 4 no.1 (1997), #R22 2 1. Introduction and the main results Asymptotic calculations are applied to study the degrees of certain sequences of characters of symmetric groups S n, n. We obtain some unexpected arithmetic properties of the set of the hook numbers for some special families of (fixed) skew-young diagrams (Theorem1.2). The problem appeared in the study of the hook formula for various kinds of Young diagrams. The proof of 1.2 is based on the properties of shifted Schur functions[ok.ol]which appeared in the asymptotic theory of the representation theory of the symmetric groups in[ver.ker]. The authors do not know a finite proof of the theorem. Given a partition µ, we describe in [1.1]a construction of certain skew diagrams which are derived from µ: these are SQ(µ), SR(µ), SR(µ ), R and D µ below. Next, one fills these skew diagrams with their corresponding hook numbers [Mac]Theorem[1.2]which is the main result here, gives some divisibility properties of the products of these hook numbers. We remark again that even though the statement of theorem[1.2]nothing to do with asymptotics, its proof does use asymptotic methods. It should be interesting to find an asymptotic free proof of Theorem[1.2] We start with 1.1: A Construction: Given a partition ( diagram) µ, let Dµ denote the double reflection of µ. For example, if µ (4,2,1) then x x x x D µ x x and Dµ x x x x. x x x x Recall that µ 1 l(µ) is the number of nonzero parts of µ. Complete D µ to the µ 1 rectangle R(µ), then draw D µ on top and on the left of R. Finally, erase the first Dµ. Denote the resulting skew diagram by SQ(µ). For example, with µ (4,2,1) we get 2

SQ(4, 2, 1) A 1 x x x x the electronic journal of combinatorics 4 no.1 (1997), #R22 3 A 2 x x x x x x x x x x x x x x x A We subdivide SQ(µ) into the three areas A, A 1 and A 2 : A R Dµ,A 1 is the Dµ on the left of R and A 2 is the Dµ on top of R. Denote SR(µ) A 1 A, the shifted rectangle. Clearly, A A 1 A A 2 R, A 1 A 2 µ, so SQ(µ) R + µ. Now, fill SQ(µ),SR(µ), Rand µ with their hook numbers. For example, when µ (4,2,1) SQ(4, 2, 1) : 3 4 2 6 5 3 1 6 4 3 1 5 4 2 1 4 3 2 1 SR(4, 2, 1) : 6 4 3 1 5 4 2 1 4 3 2 1 R(4, 2, 1) : 6 5 4 3 5 4 3 2 4 3 2 1 3

the electronic journal of combinatorics 4 no.1 (1997), #R22 4 and (4, 2, 1) : 6 4 2 1 3 1 1 Thus, for example, x (4,2,1) 13 2 3 4 6 144. Note that the hook numbers in SR(µ) are the same as those in the area A 1 A of SQ(µ). As usual, µ 1 l(µ) is the number of nonzero parts of µ. Recall that s µ (x 1,x 2, ) is the corresponding Schur function, and s µ (1,,1) is the number µ 1 of (semi-standard, i.e. rows weakly and column strictly increasing) tableaux of shape µ, filled with elements from {1, 2,,µ 1 }[Mac]Similarly for s µ (1,,1). 1.2 Theorem: Let µ be a partition. With the above construction of SQ(µ)A A 1 A 2 and R, wehave (1) ( x R ) / x A 1 A s µ (1,,1). µ 1 In particular, x A 1 A divides x R. [Note that A A 1 SQ(µ), and for x A 1 A, is the corresponding hook number in x SQ(µ)]. (1 ) Similarly, ( x R ) / x A 2 A s µ (1,,1). (2) x SQ(µ) ( x R ) x µ. 4

the electronic journal of combinatorics 4 no.1 (1997), #R22 5 We conjecture that a statement much stronger than[1.2.2]holds, namely: the two multisets { x SQ(µ)} and { x R} { x µ}are equal. Theorem[1.2.1]is an obvious consequence of the following asymptotic theorem. 1.3. Theorem: Let µ (,,µ k ), be a partition. Let n kl, l, and denote λ λ(l) (l k ). Then (a) lim l d λ/µ d λ ( ) 1 µ s µ (1,,1 k ) k and (b) lim l d λ/µ d λ ( ) 1 µ k / x R(,µ 1 ) x A 1 A. Theorem[1.2.1 ]follows from[1.2.1]by conjugation. Theorem[1.2.2]is a consequence of the following asymptotic theorem 1.4. Theorem: Let µ be a fixed partition. Let l, µ 1 m,nlm and λ λ(l, m) (lm ). Then (a) lim l,m d λ/µ d λ 1 x µ. (b) lim l,m d λ/µ d λ ( x R ) / x SQ(µ). In this note we apply the following main tools: a) The theory of symmetric functions[mac,]. In particular, we apply the hook formula d λ λ! x λ 5

the electronic journal of combinatorics 4 no.1 (1997), #R22 6 and I.3, Example 4, page 45 in[mac,]. b) The Okounkov-Olshanski[Ok.Ol]theory of shifted symmetric functions. In particular, we apply formula (0.14) of[ok.ol]let µ k, λ n, k n, µ λ, then d λ/µ d λ s µ(λ) n(n 1) (n k+1). Here s µ(x) is the shifted Schur function [Ok.Ol]; that one of its key properties is s µ(x) s µ (x)+ lower terms, where s µ (x) is the ordinary Schur function. We remark that the paper[ok.ol]was influenced by the work of Vershik and Kerov on the asymptotic theory of the representations of the symmetric groups. See for example[ver.ker], in which the characters of the infinite symmetric group are found from limits involving ordinary Schur functions. See also the introduction of[ok.ol] 1.2.1 ). 2. Here we prove theorem [1.3]which, as noted before, implies [1.2.1](and 2.1. The proof of theorem[1.3]. d λ(l)/µ d λ(l) s µ(λ 1 (l),,λ k (l)) n(n 1) (n µ +1), where n λ kl. Since l,n(n 1) (n µ +1) (kl) µ. Also, s µ(λ) s µ (λ)+(lower terms in n), hence s µ(λ) s µ (λ) s µ (l,,l). k Recall that for two sequences a n, b n of real numbers, a n lim n a n bn 1. b n means that 6

the electronic journal of combinatorics 4 no.1 (1997), #R22 7 Since s µ (x) is homogeneous of degree µ, s µ (λ) l µ s µ (1,,1). k The proof now follows easily. 2.2. The proof of theorem[1.3.b] Since λ is a rectangle, hence d λ/µ d η, where η is the double reflection of λ/µ. Denote by µ D µ the double reflection of µ. Thus l η D µ i 1 To calculate d λ and d η by the hook formula, fill λ λ(l) and η with their respective hook numbers. In both, examine the i th row from the bottom - with their respective hook numbers. Divide η into B 1 and B 2 as follows: Notice that B 1 SR(µ) of 1.1. Note also that the hook numbers in B 1 are those in SR(µ), and they are independent of l. Examine the hook numbers in B 2. In the i th row (from bottom), these are + i, + i +1,,l+i 1 µ i, consecutive integers. We also divide λ(l) into two rectangles: Again, the hook numbers in R 1 are independent of l, and those in the i th row (from bottom) of R 2 are + i, + i +1,,l+i 1, again consecutive integers. 7

the electronic journal of combinatorics 4 no.1 (1997), #R22 8 l B 2 B 1 Dµ l λ(l) R 2 R 1 By the hook formula, the left hand side of 1.3.b is [ ] d λ(l)/µ d / [ η (n µ )! d λ(l) d λ(l) x η where n kl. Since l, (n µ )! n! (n µ )! n! [ x λ(l) ] x η ( ) 1 µ n ( ) 1 µ. kl n! x λ(l) ] Now x λ(l) x η [ ] [ ] x R 1 x R 2 α β. x B 1 x B 2 8

the electronic journal of combinatorics 4 no.1 (1997), #R22 9 Note that the right hand side of 1.3.b is ( k 1 ) µ α. We calculate β: µ 1 [( + i)( + i +1) (l+i 1)], x R 2 i1 µ 1 [( + i)( + i +1) (l+i 1 µ i )], x B 2 i1 thus µ 1 β [(l + i µ i )(l + i µ i +1) (l+i 1)] l µ, (since l ). i1 Hence, lim l d λ(l)/µ d λ(l) ( ) 1 µ α k and the proof is complete. 3. Here we prove theorem 1.4 which, as noted before, implies theorem 1.2.2. 3.1. The proof of 1.4.a: Let λ λ(l, m) (l m ), l,m. We show first that s µ(λ) s µ (λ), as follows: By [Ok.Ol.(0.9)], e r(λ) i i 1 < <i r m (l+r 1)(l + r 2) l (l + r 1)(l + r 2) l ( m ) lr m r r r!. Similarly, e r (λ) lr m r r!. Let be given as in [Ok.Ol. 13]. By [Ok.Ol.(13.8)] it easily follows that for any u and r, u e r(λ) e r(λ) e r (λ). 9

the electronic journal of combinatorics 4 no.1 (1997), #R22 10 Applying the Jacobi Trudi formulas for s µ (λ) ([Mac,]I, (3.5), page 41] and for s µ(λ)[ok.ol(13.10)]that s µ(λ) s µ (λ). Now in[2.1,], here d λ(l,m)/µ d λ(l,m) s µ(λ 1 (l, m),,λ m+k (l, m)) n(n 1) (n µ +1) where n lm. Here Thus d λ(l,m)/µ d λ(l,m) s µ(λ(l, m)) s µ (λ(l, m)) l µ s µ (1,,1). m ( ) 1 µ s µ (1,,1 n ) m ( ) 1 µ m x µ m+c(x) ([[Mac,], pg. 45, Ex 4]) where c(x) is the content of x µ. Since m, m+ c(x) m for all x µ, and the proof follows., 3.2. The proof of [1.4b ] Choose l, m large so that µ λ(l, m). Let η be the double reflection of λ(l, m)/µ, sod λ(l,m)/µ d η, then calculate d η by the hook formula. To analyze the hook numbers in η, we subdivide η into the areas A 1,η,,A 4,η as shown below: i.e., Dµ is drawn at the bottom-right of the l m rectangle. We then follow [1.1]and construct A 4,η SQ(µ). Now A 1,η is the (l ) (m µ 1 ) rectangle, and this determines A 2,η and A 3,η. We also split the l m rectangle λ λ(l, m) accordingly: Since λ(l, m) lm and η lm µ, ( ) d η 1 µ x λ(l,m) h λ(l,m) (x) d λ(l,m) lm x η h. η(x) 10

the electronic journal of combinatorics 4 no.1 (1997), #R22 11 l η : m A 1,η A 3,η A 4,η A 2,η } µ 1 D µ A 1,λ(l,m) A 3,λ(l,m) A 2,λ(l,m) } µ 1 A 4,λ(l,m) Now, h λ(l,m) (x) h η (x) for x A 1,η A 1,λ(l,m).Asin2.3 x A 2,λ(l,m) h λ(l,m) (x) x A 2,η h η (x) l µ. Similarly (or, by conjugation), x A 3,λ h λ(l,m) (x) x A 3,η h η (x) m µ. 11

the electronic journal of combinatorics 4 no.1 (1997), #R22 12 After cancellations we have d η d λ and the proof is complete. x A 4,λ h λ(l,m) (x) x A 4,η h η (x) x R(,µ 1 ) x SQ(µ) References [Ok.Ol] Okounkov A. and Olshanski G., Shifted Schur functions, preprint. [Mac] Macdonald I.G., Symmetric functions and Hall polynomials, Oxford University Press, 2nd edition 1995. [Ver.Ker] Vershik A.M. and Kerov, S.V., Asymptotic Theory of characters of the symmetric group, Funct. Anal. Appl. 15 (1981) 246-255. email addresses: regev@wisdom.weizmann.ac.il, vershik@pdmi.ras.ru 12