Lecture No 1 Introduction to Diffusion equations The heat equat

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Lecture No 1 Introduction to Diffusion equations The heat equation Columbia University IAS summer program June, 2009

Outline of the lectures We will discuss some basic models of diffusion equations and present their basic properties. Such models include various geometric flows such as: the curve shortening flow, the Ricci flow on surfaces and the Yamabe flow. We will discuss existence, regularity, a priori estimates, asymptotic behavior and classification of solutions. Lecture 1: Introduction and the heat equation Lecture 2: Slow diffusion and free-boundaries Lecture 3: Fast diffusion and the Ricci flow on surfaces Lecture 4: Ancient solutions to the curve shortening flow and the Ricci flow on surfaces

Introduction to diffusion The simplest model of linear diffusion is the familiar heat equation: u t = u, u = u(x, t), x R n, T > 0 where u := n i=1 u x i x i = div ( u). (Diffusion of heat, chemical concentration). One of the simplest models of non-linear diffusion is the porous medium (m > 1) or fast-diffusion (m < 1) equation u t = u m, u 0, x R n, T > 0. (Diffusion of gas through a porous medium, population dynamics, gas kinetics, diffusion in plasma, geometry). Another simple model is the reaction-diffusion equation u t = u + u p, u 0, p > 0. (Population dynamics, geometry).

Other models of Diffusion Evolution p-laplacian Equation (quasi-linear) u t = div ( u p 2 u), p > 0. Motion of a curve y = u(x, t) by its curvature u xx u t = 1 + ux 2. Motion of a surface z = u(x, y, t) in R 3 by its mean curvature u t = (1 + u2 y )u xx 2u x u y u xy + (1 + u 2 x)u yy 1 + u 2 x + u 2 y Motion of a surface y = u(x, y, t) in R 3 by its Gaussian curvature (fully-nonlinear) u t = det D 2 u (1 + u 2 x + u 2 y ) 3/2.

Slow and fast-diffusion Consider the equation u t = u m. Since u m = div ( u m ) = div (m u m 1 u) the diffusion is governed by D(u) := m u m 1. m = 1: The diffusivity D(u) := 1 is constant in any direction and the equation is linear. m > 1: Since the diffusivity D(u) := m u m 1 0, as u 0 and we have slow diffusion. m < 1: Since the diffusivity D(u) := m u m 1 +, as u 0 and we have fast diffusion. m = 0: The equation takes the form u t = log u. m < 0: We have super-fast diffusion. Remark: We will see in these lectures that slow and fast diffusion have very different properties.

The Heat Equation - Derivation The heat equation u t = u describes the distribution of heat in a given region over time. The heat equation can be derived from the following principles: The amount of heat Q contained in a region Ω is proportional to the temperature T, the density ρ and the heat capacity κ s of the material, i.e. if Ω is a region of the material: Q = ρ κ s T (x, t) dx. (1) Ω The heat transfer through the boundary Ω of the region is proportional to the heat conductivity σ, to the gradient of the temperature across the region and to the area of contact, i.e. dq dt = Ω σ T n da. (2)

The Heat equation - Derivation If we differentiate (1) in time and apply the divergence Theorem in (2) we obtain: T ρ κ s Ω t dx = div (σ T ) da. Ω Since Ω can be an arbitrary part of the material under study, we obtain the heat equation T t = λ T if we assume that ρ, κ s and σ are independent of the position x. Remark: If the heat conductivity σ is taken to depend on the temperature T, then we obtain non-linear versions of the heat equation.

Parabolic scaling and the Fundamental Solution Parabolic Scaling: If u(x, t) solves the heat equation, then ũ(x, t) = u(γ x, γ 2 t), γ > 0 also solves the heat equation. Self-Similar solution: The above scaling suggests that we search for a special radially symmetric solution of the form ( ) x 2 Φ(x, t) = α(t) v. t for some functions α(t) and v(r). The above representation leads to the fundamental solution 1 Φ(x, t) = (4πt) n 2 e x 2 4t, t > 0.

Properties of the Fundamental solution A simple calculation leads to: R n Φ(x, t) dx = 1, t > 0. Also, lim t 0 Φ(x, t) = 0, for all x 0. Hence, lim Φ(, t) = δ 0. t 0 We observe the following two characteristic properties of the fundamental solution: Infinite speed of propagation: Φ(, t) > 0, for all t > 0. Smoothing effect: Φ is C smooth in x and t, for all t > 0. Remark: All solutions of the heat equation have the above two properties. Non-linear equations don t in general.

The Cauchy problem Solutions u of the Cauchy problem { u t = u in R n [0, T ) ( ) u(, 0) = g on R n are given by 1 u(x, t) = Φ(x y, t) g(y) dy = R n (4πt) n 2 R n e x y 2 4t Indeed, we have: u t x u = [(Φ t x Φ)(x y, t)] g(y) dy = 0 R n and (since lim t 0 Φ(x y, t) = δ x (y)): lim u(x, t) = lim Φ(x y, t) g(y) dy = g(x). t 0 t 0 R n g(y) dy.

Non-homogeneous problem Consider now solutions u of the non-homogeneous problem { u t u = f in R n (0, ) ( ) u(, 0) = 0 on R n. Let u(x, t; s) be the solution of the Cauchy problem { u t = u in R n (s, ) u(, s) = f (, s) on R n Duhamel s principle asserts that the solution u of ( ) is given by: Hence, u(x, t) = u(x, t) = t t 0 0 u(x, t; s) ds, x R n, t 0. R n Φ(x y, t s) f (y, s) dy ds.

The Mean-value formula The well known mean value formula for harmonic functions: u = 0 in Ω R n, asserts that 1 u(x 0 ) = u(x) dx, if B r (x 0 ) Ω. B r (x 0 ) B r (x 0 ) A similar formula holds for solutions of the heat equation u t = u in Q T = Ω (0, T ]. Considering the parabolic balls: { E(x 0, t 0 ; r) := (x, t) R n+1 t t 0, Φ(x x 0, t 0 t) 1 } r n then u(x 0, t 0 ) = 1 4r n if E(x 0, t 0 ; r) Q T. E(x 0,t 0 ;r) u(x, t) x x 0 2 dx dt (t t 0 ) 2

The Strong Maximum Principle The parabolic boundary p Q T of the cylinder Q T := Ω (0, T ] is defined as: p Q T = ( Ω (0, T ]) (Ω {0}). Strong maximum principle: If u solves the heat equation in Q T then: We have: max u = max u. Q T pq T Furthermore, if Ω is connected and there exists a point (x 0, t 0 ) Q T such that u(x 0, t 0 ) = max u Q T then u must be constant in Q T.

Uniqueness of Solutions Uniqueness on bounded domains: If g C( p Q T ), then there exists at most one solution u C 2,1 (Q T ) C( Q T ) of: { u t = u in Q T u = g on p Q T Maximum principle for the Cauchy problem: If u solves { u t = u in R n (0, T ) u(, 0) = g on R n u C 2,1 (R n (0, T ]) C(R n [0, T ]) and satisfies the growth estimate u(x, t) A e a x 2, then sup R n [0,T ] u = sup R n g. Uniqueness: Solutions to the Cauchy problem which satisfy the above growth condition are unique. Remark: The growth assumption is necessary!

Regularity Let Q r (x 0, t 0 ) denote the parabolic cylinder of size r around a point (x 0, t 0 ), namely: Q r (x 0, t 0 ) := B r (x 0 ) [t 0 r 2, t 0 ]. Derivative estimates: For each k, l = 0, 1,, there exists a constant C k,l such that max Q r 2 (x 0,t 0 ) Dk x D l tu C k,l r k+2l+n+2 u L 1 (Q r (x 0,t 0 )) for all cylinders Q r (x 0, t 0 ) Q T and all solutions to the heat equation in Q T. Conclusion: Local solutions to the heat equation are C -smooth. Proof: You use the exact representation of solutions to the heat equation in terms of the initial data and cut-off functions.

Schauder Estimate Parabolic Hölder spaces: We say that u C α (Q T ) if u(x 1, t 1 ) u(x 2, t 2 ) C ( x 1 x 2 + t 1 t 2 ) α. We say that u C 2+α (Q T ) if u, u t, D x u, Dx 2 u C α (Q T ). Schauder estimate: If u is a smooth solution of { u t u = f in Q T u = g on p Q T then u C 2+α (Q T ) C ( u C 0 (Q T ) + f C α (Q T ) + g C 2,α ( Q T )).

Harnack Inequality Assume that u is a nonnegative solution of the heat equation u t = u, t > 0. Then, u satisfies the Harnack inequality: u(x 1, t 1 ) ( t2 t 1 for all 0 < t 1 < t 2 and x 1, x 2 R n. ) n 2 u(x2, t 2 ) e x 2 x 1 2 4(t 2 t 1 ) Application: If u(0, T ) M <, then for all t < T ɛ we have u(x, t) C(M, T ) t n x 2 2 e 4ɛ i.e. nonnegative solutions of the heat equation grow at most exponentially as x.

Widder theory for the heat equation Let u be a nonnegative distributional solution of the heat equation u t = u in S T := R n (0, T ]. The initial trace µ exists; there exists a nonnegative Borel measure µ 0 on R n such that lim t 0 u(, t) = dµ 0 and satisfies the growth condition ( ) e C x 2 T dµ 0 < where C is an absolute constant. The trace µ 0 determines the solution uniquely. For each nonnegative Borel measure µ 0 on R n satisfying the ( ), there is a nonnegative continuous weak solution u the heat equation in S T with trace µ 0 and u(x, t) = C n t n/2 e x y 2 4t dµ 0 (y) for an absolute constant C n depending only on dimension n.