PHYSICS 149: Lecture 9

Similar documents
PHYSICS 220 Lecture 02 Motion, Forces, and Newton s Laws Textbook Sections

Physics 101: Lecture 03 Kinematics Today s lecture will cover Textbook Sections (and some Ch. 4)

KINEMATICS IN ONE DIMENSION

IB Physics Kinematics Worksheet

x(m) t(sec ) Homework #2. Ph 231 Introductory Physics, Sp-03 Page 1 of 4

Kinematics Vocabulary. Kinematics and One Dimensional Motion. Position. Coordinate System in One Dimension. Kinema means movement 8.

Displacement ( x) x x x

Ground Rules. PC1221 Fundamentals of Physics I. Kinematics. Position. Lectures 3 and 4 Motion in One Dimension. A/Prof Tay Seng Chuan

2.1: What is physics? Ch02: Motion along a straight line. 2.2: Motion. 2.3: Position, Displacement, Distance

Of all of the intellectual hurdles which the human mind has confronted and has overcome in the last fifteen hundred years, the one which seems to me

Speed and Velocity. Overview. Velocity & Speed. Speed & Velocity. Instantaneous Velocity. Instantaneous and Average

WEEK-3 Recitation PHYS 131. of the projectile s velocity remains constant throughout the motion, since the acceleration a x

x i v x t a dx dt t x

Lecture 2-1 Kinematics in One Dimension Displacement, Velocity and Acceleration Everything in the world is moving. Nothing stays still.

Today: Graphing. Note: I hope this joke will be funnier (or at least make you roll your eyes and say ugh ) after class. v (miles per hour ) Time

Physics 20 Lesson 5 Graphical Analysis Acceleration

Physics 3A: Basic Physics I Shoup Sample Midterm. Useful Equations. x f. x i v x. a x. x i. v xi v xf. 2a x f x i. y f. a r.

Physics 221 Fall 2008 Homework #2 Solutions Ch. 2 Due Tues, Sept 9, 2008

Giambattista, Ch 3 Problems: 9, 15, 21, 27, 35, 37, 42, 43, 47, 55, 63, 76

4.5 Constant Acceleration

1. VELOCITY AND ACCELERATION

Welcome Back to Physics 215!

2. What is the displacement of the bug between t = 0.00 s and t = 20.0 s? A) cm B) 39.9 cm C) cm D) 16.1 cm E) +16.

Suggested Practice Problems (set #2) for the Physics Placement Test

Physics 180A Fall 2008 Test points. Provide the best answer to the following questions and problems. Watch your sig figs.

0 time. 2 Which graph represents the motion of a car that is travelling along a straight road with a uniformly increasing speed?

3.6 Derivatives as Rates of Change

Q2.1 This is the x t graph of the motion of a particle. Of the four points P, Q, R, and S, the velocity v x is greatest (most positive) at

Phys 221 Fall Chapter 2. Motion in One Dimension. 2014, 2005 A. Dzyubenko Brooks/Cole

Unit 1 Test Review Physics Basics, Movement, and Vectors Chapters 1-3

Physics 101 Fall 2006: Exam #1- PROBLEM #1

02. MOTION. Questions and Answers

SPH3U1 Lesson 03 Kinematics

Best test practice: Take the past test on the class website

Physics Notes - Ch. 2 Motion in One Dimension

t A. 3. Which vector has the largest component in the y-direction, as defined by the axes to the right?

Solution: b All the terms must have the dimension of acceleration. We see that, indeed, each term has the units of acceleration

Chapter 12: Velocity, acceleration, and forces

Linear Motion I Physics

Motion along a Straight Line

Conceptual Physics Review (Chapters 2 & 3)

Kinematics in One Dimension

University Physics with Modern Physics 14th Edition Young TEST BANK

MEI Mechanics 1 General motion. Section 1: Using calculus

and v y . The changes occur, respectively, because of the acceleration components a x and a y

AP Calculus BC Chapter 10 Part 1 AP Exam Problems

AP CALCULUS AB 2003 SCORING GUIDELINES (Form B)

1. The graph below shows the variation with time t of the acceleration a of an object from t = 0 to t = T. a

Practicing Problem Solving and Graphing

One-Dimensional Kinematics

Today: Falling. v, a

Parametrics and Vectors (BC Only)

Physics 131- Fundamentals of Physics for Biologists I

Chapter 2. Motion in One-Dimension I

Physics for Scientists and Engineers. Chapter 2 Kinematics in One Dimension

2001 November 15 Exam III Physics 191

RELATIVE MOTION. Contents. Theory 01. Exercise Exercise Exercise Exercise Answer Key 13.

Name: Teacher: DO NOT OPEN THE EXAMINATION PAPER UNTIL YOU ARE TOLD BY THE SUPERVISOR TO BEGIN PHYSICS FINAL EXAMINATION June 2010.

SPH3U: Projectiles. Recorder: Manager: Speaker:

Physics 218 Exam 1. with Solutions Fall 2010, Sections Part 1 (15) Part 2 (20) Part 3 (20) Part 4 (20) Bonus (5)

Applications of the Basic Equations Chapter 3. Paul A. Ullrich

Position, Velocity, and Acceleration

!!"#"$%&#'()!"#&'(*%)+,&',-)./0)1-*23)

Testing What You Know Now

15. Vector Valued Functions

SOLUTIONS TO CONCEPTS CHAPTER 3

~v = x. ^x + ^y + ^x + ~a = vx. v = v 0 + at. ~v P=A = ~v P=B + ~v B=A. f k = k. W tot =KE. P av =W=t. W grav = mgy 1, mgy 2 = mgh =,U grav

Chapter 3 Kinematics in Two Dimensions

MOMENTUM CONSERVATION LAW

Equations of motion for constant acceleration

Review Equations. Announcements 9/8/09. Table Tennis

Lecture 4 Kinetics of a particle Part 3: Impulse and Momentum

2002 November 14 Exam III Physics 191

1. Kinematics I: Position and Velocity

s in boxe wers ans Put

Physics for Scientists and Engineers I

Physics 5A Review 1. Eric Reichwein Department of Physics University of California, Santa Cruz. October 31, 2012

4.6 One Dimensional Kinematics and Integration

Kinematics Motion in 1 Dimension and Graphs

AP CALCULUS AB/CALCULUS BC 2016 SCORING GUIDELINES. Question 1. 1 : estimate = = 120 liters/hr

9702/1/O/N/02. are set up a vertical distance h apart. M 1 M 2. , it is found that the ball takes time t 1. to reach M 2 ) 2

Farr High School NATIONAL 5 PHYSICS. Unit 3 Dynamics and Space. Exam Questions

Mechanics Acceleration The Kinematics Equations

Two Coupled Oscillators / Normal Modes

NEWTON S SECOND LAW OF MOTION

Main Ideas in Class Today

In this chapter the model of free motion under gravity is extended to objects projected at an angle. When you have completed it, you should

Physics for Scientists & Engineers 2

Guest Lecturer Friday! Symbolic reasoning. Symbolic reasoning. Practice Problem day A. 2 B. 3 C. 4 D. 8 E. 16 Q25. Will Armentrout.

Lab #2: Kinematics in 1-Dimension

Dynamics. Option topic: Dynamics

a 10.0 (m/s 2 ) 5.0 Name: Date: 1. The graph below describes the motion of a fly that starts out going right V(m/s)


- Graphing: Position Velocity. Acceleration

The Lorentz Transformation

PHYS 100: Lecture 2. Motion at Constant Acceleration. Relative Motion: Reference Frames. x x = v t + a t. x = vdt. v = adt. x Tortoise.

Summary:Linear Motion

Motion in One Dimension

v x + v 0 x v y + a y + v 0 y + 2a y + v y Today: Projectile motion Soccer problem Firefighter example

Transcription:

PHYSICS 149: Lecure 9 Chaper 3 3.2 Velociy and Acceleraion 3.3 Newon s Second Law of Moion 3.4 Applying Newon s Second Law 3.5 Relaive Velociy Lecure 9 Purdue Universiy, Physics 149 1

Velociy (m/s) The average velociy is he change in posiion (vecor) divided by he change in ime. x() v Δr x x = = f Δ f 0 0 Insananeous velociy is he limi of average velociy as ges small. I is he slope of he x() plo. v = lim Δ 0 Δ r Δ x() Lecure 9 Purdue Universiy, Physics 149 2 Δ Δx

ILQ 1 A go-kar ravels around a circular rack a a consan speed. Which of hese is a rue saemen? (a) The go-kar has a consan velociy. (b) The go-kar has zero acceleraion. A) Boh (a) and (b) are rue B) Neiher (a) nor (b) is rue C) (a) D) (b) Lecure 9 Purdue Universiy, Physics 149 3

ILQ 2 If he average velociy of a car during a rip along a sraigh road is posiive, is i possible for he insananeous velociy a some ime during he rip o be negaive? A - Yes correc B - No The car migh have reversed If he car is raveling in a for a lile while along he rip sraigh pah he velociy creaing a negaive will always be posiive. insananeous velociy a he The car needs o ravel in poin. If he overall he opposie direcion o displacemen of he car is ge a negaive velociy. posiive for ha paricular ime inerval, han he average velociy is posiive as well. Lecure 9 Purdue Universiy, Physics 149 4

How o deermine x from v() The oal displacemen x during and ime is he area under he graph v() Assume 1D, and v consan: v v x Δx = v = v 1x av, x Δ Δx Δ x= v Δ 1x 1 2 Lecure 9 Purdue Universiy, Physics 149 5

Acceleraion (m/s 2 ) The average acceleraion is he change in velociy divided by he change in ime. a Δv = Δ v() Δv Δ Insananeous acceleraion is limi of average acceleraion as ges small. I is he slope of he v() ()plo. a = lim Δ 0 Δ v Δ v() Lecure 9 Purdue Universiy, Physics 149 6

Average Acceleraion Average acceleraion is he change in velociy during he ime inerval during which he velociy changed. = "change"in velociy elapsed ime The x- and y-componens of he average velociy are: Typical unis for he magniude of acceleraion are m/s 2, km/s 2, and so on. Lecure 9 Purdue Universiy, Physics 149 7

Insananeous Acceleraion Insananeous acceleraion is he average acceleraion we measure when he ime inerval is infiniesimally shor. The x- and y-componens of he insananeous velociy are: Lecure 9 Purdue Universiy, Physics 149 8

Direcion of Acceleraion If speed is increasing, v and a are in same direcion. If speed is decreasing, v and a are in opposie direcion. Lecure 9 Purdue Universiy, Physics 149 9

ILQ: Acceleraion If he velociy of some objec is no zero, can is acceleraion ever be zero? A) Yes B) No If he velociy is consan, he acceleraion is zero (slope of v() is 0). ) v() v() Lecure 9 Purdue Universiy, Physics 149 10

ILQ: Acceleraion Is i possible for an objec o have a posiive velociy a he same ime as i has a negaive acceleraion? A) Yes B) No Yes, when hey have differen signs, he objec is slowing down. v() v() Δv Δ Lecure 9 Purdue Universiy, Physics 149 11

Posiion vs Time Plos Gives locaion a any ime Displacemen is change in posiion Slope gives velociy x (m) 3 Posiion a =3, x(3) = 1 Displacemen beween =5 and =1. Δx = -1.0 m 4 1.0 m - 2.0 m = -1.0 m -3 Average velociy beween =5 and =1. v = -0.25 m/s -1 m / 4 s = -0.25 m/s Lecure 9 Purdue Universiy, Physics 149 12

Velociy vs Time Plos Gives velociy a any ime Area gives displacemen Slope gives acceleraion v (m/s) 3 1.5 6 Velociy a =2, v(2) = 3 m/s 4 Displacemen beween =0 and =3: 3: x = 75m 7.5-3 =0 o =1: ½ (3m/s) (1 s) = 1.5 m =1 o =3: (3m/s) (2 s) = 6 m Average velociy beween =0 and =3? v= 7.5 m / 3s = 2.5 m/s Change in v beween =5 and =3. v = -2 m/s 3 m/s = -5 m/s Average acceleraion beween =5 and =3: a = -5 m/s / (2 s) = -2.5 m/s 2 Lecure 9 Purdue Universiy, Physics 149 13

Acceleraion vs Time Plos Gives acceleraion a any ime Area gives change in velociy a (m/s 2 ) Acceleraion a =4, a(4) = -2 m/s 2 Change in v beween =4 and =1. v = +4 m/s 2 4 =1-3: v = (3m/s 2 )(2s) = 6 m/s -3 =3-4: v = (-2m/s 2 )(1s) = -2 m/s 3 6 Lecure 9 Purdue Universiy, Physics 149 14

ILQ: Conceps A skydiver is falling sraigh down, along he negaive y direcion. During he iniial par of he fall, her speed increases from 16 o 28 m/s in 1.5 s. Which of he following is correc? A) v>0, a>0 v a B) v>0, a<0 C) v<0, a>0 D) v<0, a<0 correc During a laer par of he fall, afer he parachue has opened, her speed decreases from 48 o 26 m/s in 11 s. Which of he following is correc? A) v>0, a>0 B) v>0, a<0 C) v<0, a>0 D) v<0, a<0 C) v<0 a>0 correc Lecure 9 Purdue Universiy, Physics 149 15 v a y

Dropped Ball A ball is dropped from a heigh of wo meers above he ground. Draw v y vs 3 v v v A 3 B 3 C y x -2 4 3 v D -2 4 3 v E -2 4 4 4-2 -2 Lecure 9 Purdue Universiy, Physics 149 16

Dropped Ball A ball is dropped from a heigh of wo meers above he ground. x v Draw v vs Draw x vs Draw a vs a Lecure 9 Purdue Universiy, Physics 149 17

Tossed Ball A ball is ossed from he ground up a heigh of wo meers above he ground and falls back down. y Draw v vs v v 3 3 3 A B C v x -2 4 3 v D -2 4 3 v E -2 4 4 4-2 -2 Lecure 9 Purdue Universiy, Physics 149 18

Tossed Ball A ball is ossed from he ground up a heigh of wo meers above he ground and falls back down. x v Draw v vs Draw x vs Draw a vs a Lecure 9 Purdue Universiy, Physics 149 19

ILQ Which car has a wesward acceleraion? A) a car raveling wesward a consan speed B) a car raveling easward and speeding up C) a car raveling wesward and slowing down D) a car raveling easward and slowing down E) a car saring from res and moving oward he eas Lecure 9 Purdue Universiy, Physics 149 20

Newon s Second Law of Moion If here is a ne force acing on an objec, i experiences an acceleraion in he direcion of he ne force, and he magniude of he acceleraion is he ne force s magniude divided by he mass of he objec. In componen form, Unis for force: 1 N = 1 kg m/s 2 Lecure 9 Purdue Universiy, Physics 149 21

ILQ A single force is acing on an objec. Which ype of moion is no physically allowed? A) he objec speeds up B) he objec is a res C) he objec slows down D) he objec's moion changes direcion Lecure 9 Purdue Universiy, Physics 149 22

ILQ If an objec is aced on by wo finie consan forces, is i possible for he objec o move a consan velociy? A) No, i will accelerae B) Yes, he forces mus be perpendicular p C) No, i will follow a curved pah D) Yes, he forces mus be equal and opposie E) Yes, he forces mus be in he same direcion Lecure 9 Purdue Universiy, Physics 149 23

ILQ A force F acing on a mass m 1 resuls in an acceleraion a 1.The same force acing on a differen mass m 2 resuls in an acceleraion a 2 =2a 1. Wha is he mass m 2? m 1 m 2 F a 1 F a 2 = 2a 1 A) 2m 1 B) m 1 C) 1/2 m 1 F=ma F= m 1 a 1 = m 2 a 2 = m 2 (2a 1 ) Therefore, m 2 = m 1 /2 Or in words wice he acceleraion means half he mass Lecure 9 Purdue Universiy, Physics 149 24

Mass Mass is a measure of an objec s ineria he amoun of resisance o changes in velociy. Mass is an inrinsic propery of an objec, so mass does no change wherever he objec is (unlike weigh). The unis of mass are g, kg, and so on Objecs wih a larger amoun of ineria (large mass) are harder o change he sae of moion of compared o objecs wih a small amoun of ineria (small mass) For he same ne force, a m (= ΣF/m ) > a M (= ΣF/M ) because m < M m M Lecure 9 Purdue Universiy, Physics 149 25

Newon s Second Law F = ma A racor T is pulling a railer M wih a consan acceleraion. If he forward acceleraion is 1.5 m/s 2. Calculae he force on he railer M (m=400kg) due o he racor T (m=500kg). x direcion F = x ma x T = ma x 2 ( 400 kg)( 1.5 m/s ) T = T = 600 Newons N T y x W Lecure 9 Purdue Universiy, Physics 149 26

Example A racor T (m=500kg) is pulling a railer M (m=400kg). I sars from res and pulls wih consan force such ha afer 1 seconds is velociy is 1m/s. Calculae he horizonal force y on he racor due o he ground. x-direcion: Tracor ΣF = ma F w T = m racora F w = T+ m racor a x-direcion: Trailer ΣF = ma T = m railer a N T T N W W Combine: F w = m railer a + m racor a F w = (m railer+ m racor ) a F w x Lecure 9 Purdue Universiy, Physics 149 27

Example A racor T (m=500kg) is pulling a railer M (m=400kg). I sars from res and pulls wih consan force such ha afer 1 seconds is velociy is 1m/s. Calculae he horizonal force y on he racor due o he ground. Combine: F w = m railera + m racora F w = (m railer+ m racor ) a N W T T N W F w x a=δv/δ=(1m/s)/(1s)=1 m/s 2 Consan force = consan a F w =(900kg) 1 m/s 2 =900N Lecure 9 Purdue Universiy, Physics 149 28

ILQ A wrench has a mass of 0.75 kg here on earh. I is shipped up o be used on he Inernaional Space Saion. An asronau on he Space Saion will measure is mass o be: A) 0 kg B) 7.5 N C) 1.7 lbs D) 0.75 kg How abou is weigh? Lecure 9 Purdue Universiy, Physics 149 29

Relaive Velociy We ofen assume ha our reference frame is aached o he Earh. Wha happen when he reference frame is moving a a consan velociy wih respec o he Earh? The moion can be explained by including he relaive velociy of he reference frame in he descripion of he moion. The ground speed of an airplane is he vecor sum of he airspeed and he wind velociy. Using he air as he inermediae reference frame, ground speed is: v = v + v PG PA AG Example airplanes Lecure 9 Purdue Universiy, Physics 149 30

Relaive Velociy Wha is he relaion beween he velociy of an objec as deermined in one reference frame and he velociy of he same objec as deermined in anoher reference frame ha is moving wih respec o he firs reference frame? v AC = v AB + v BC where v AC is he velociy of A relaive o C, v AB is he velociy of A relaive o B, and v BC is he velociy of B relaive o C. Lecure 9 Purdue Universiy, Physics 149 31

Example where v WT is he velociy of Wanda relaive o Tim, v TG is he velociy of Tim relaive o Greg, and v WG is he velociy of Wanda relaive o Greg. Lecure 9 Purdue Universiy, Physics 149 32

ILQ As a rain ravels wih a velociy v TG = 15.5 m/s o righ, Wanda walks oward he fron of he rain wih a velociy v WT =12m/so 1.2 righ. Wha is her velociy relaive o he ground? A) 0 m/s B) 16.7 m/s, o righ C) 14.3 m/s, o righ D) impossible o ell Lecure 9 Purdue Universiy, Physics 149 33

ILQ: Relaive Velociy You are on a rain raveling 40 mph Norh. If you walk 5 mph sideways across he car (W), wha is your speed relaive o he ground? A) < 40 mph B) 40 mph C) >40 mph 40 5 2 2 v = 40 + 5 = 40.3mph Lecure 9 Purdue Universiy, Physics 149 34

ILQ: Time o Cross he River Three swimmers can swim equally fas relaive o he waer. They have a race o see who can swim across a river in he leas ime. Relaive o he waer, Beh (B) swims perpendicular o he flow, Ann (A) swims upsream, and Carly (C) swims downsream. Which swimmer wins he race? A B C Beh uses all of her force in he 'y' A) Ann direcion, he direcion of he oher bank. B) Beh Time o ge across = widh of river / C) Carly y-componen of velociy Lecure 9 Purdue Universiy, Physics 149 35