Math 243 Chapter 7 Supplement The Sampling Distribution of a Proportion

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Math 243 Chapter 7 Supplement The Sampling Distribution of a Proportion The number of tattoos was quantitative data so we found a sampling distribution for the mean of each sample. Now we are going to make a sampling distribution for categorical (yes/no) data. We need to see what random samples of proportions look like before we can make inferences. Let s take an anonymous poll of our class. If we take samples of 3 students, what will the histogram look like? What if we take samples of 5 students? Statistical question: Whole Class Proportion Random Sample Sample Proportion, pp Population proportion, p = Histogram of Sample Proportions with n=3 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 Proportion in the sample who Histogram of Sample Proportions with n=5 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 Proportion in the sample who Cara Lee Page 1

Let s use a simulator app to see what proportions of larger samples look like. http://www.lock5stat.com/statkey/sampling_1_cat/sampling_1_cat.html Assume the population proportion is p=0.15. Let s look at n=5, 10, 50, 100, 500, 1000. n=5 n=10 n=50 Cara Lee Page 2

The population proportion is p=0.15 n=100 n=500 n=1000 If we take large enough samples, regardless of the original percentage, the percentage of a sample has a distribution. As the sample size gets, the standard deviation gets. Cara Lee Page 3

To get a proportion, we are taking a Binomial model and changing it from the number who answered yes to the fraction or percentage who answered yes. For example, www.gallup.com has a daily presidential approval rating. If 51 out of 100 are satisfied with the performance of the current president, that is 0.51 or 51%. We can adjust the Binomial formulas by dividing by the total sampled, which is nn. Binomial (counts), XX μμ = nnnn σσ 2 = nnnnnn σσ = nnnnnn Proportion (percentage), pp = XX nn μμ = pp σσ 2 = pppp nn σσ = pppp nn The Sampling Distribution Model for a Proportion pp is the sample proportion or the proportion who answered yes in the sample. If the four conditions below are satisfied, the sampling distribution for pp is modeled by a Normal distribution with the following parameters: μμ pp = pp σσ pp = pppp nn pp ~ NN pp, pppp nn The Normal model is an appropriate approximation for sample proportions if the following conditions hold: Independence: The individuals or items must be independent of each other Randomization: The samples need to be randomly chosen, or it s not safe to assume independence 10% Condition: Once you ve sampled more than 10% of a population, the remaining individuals or items are not considered independent of each other Success/Failure Condition: nnnn 10 and nnnn 10. The sample size must be large enough to make the distribution symmetric and close to a Normal distribution. Cara Lee Page 4

Example 1. Let s say that in the US population, 35% of employees feel engaged at work. (Remember that we are pretending to know the population parameter so we can see how samples behave). You decide to take a random sample of 100 workers and ask whether they feel engaged at work. a. Discuss each of the conditions required to use a sampling distribution for the proportion of employees who feel engaged at work. b. Define the sampling distribution model and its parameters. c. Sketch and label the model. d. What is the probability that in the sample of 100 you would get 38% or more who say they feel engaged at work? e. What is the probability that in the sample of 100 you would get fewer than 25% who say they feel engaged at work? Cara Lee Page 5

Example 2. Let s say that 20% of plain m&m s are green. In a random sample of 500 plain m&m s you find that 123 are green. a. Discuss each of the conditions required to use a sampling distribution for the proportion of green m&m s. b. Define the sampling distribution model and its parameters. c. Sketch and label the model. d. What is the probability of getting the result you found? e. Is this an unusual result? How many standard deviations away from the mean is the result? Explain. Cara Lee Page 6

Practice 1. Information on a packet of seeds claims that the germination rate is 92%. There are approximately 160 seeds in each packet. a. Discuss each of the conditions required to use a sampling distribution for the proportion of seeds that will germinate. b. Define the sampling distribution model and its parameters. c. Sketch and label the model. d. What is the probability that more than 95% of the seeds will germinate? e. Would it be unusual for only 140 or fewer of the 160 seeds to germinate? Explain. Cara Lee Page 7

Practice 2. A survey of eating habits showed that approximately 4% of people in Portland, Oregon are vegans and do not eat any animal products. A restaurant in Portland expects 300 people on opening night and the chef is planning the menu and the quantities of food needed. a. Discuss each of the conditions required to use a sampling distribution for the proportion of vegan meals needed for opening night. b. Define the sampling distribution model and its parameters. c. Sketch and label the model. d. If there are ingredients for 14 vegan meals, what is the probability that there will not be enough vegan meals? In other words, what is the probability that 15 or more customers will order a vegan meal? e. How many vegan meals should be available so that there is only a 2% chance of running out of vegan meals? How many so there is only a 1% chance? Cara Lee Page 8