An English translation of portions of seven letters between Euler and Goldbach on Euler s complex exponential paradox and special values of cosine

Similar documents
Polynomials and Rational Functions (2.1) The shape of the graph of a polynomial function is related to the degree of the polynomial

Table of Contents. Number and Operation. Geometry. Measurement. Lesson 1 Goldbach s Conjecture Lesson 2 Micro Mites... 11

UNIVERSITY OF NORTH CAROLINA CHARLOTTE 1995 HIGH SCHOOL MATHEMATICS CONTEST March 13, 1995 (C) 10 3 (D) = 1011 (10 1) 9

Homework. Basic properties of real numbers. Adding, subtracting, multiplying and dividing real numbers. Solve one step inequalities with integers.

Course Outcome Summary

Pre-Calculus MATH 119 Fall Section 1.1. Section objectives. Section 1.3. Section objectives. Section A.10. Section objectives

Euler s Rediscovery of e

Algebra 2 Standards. Essential Standards:

I can translate between a number line graph, an inequality, and interval notation.

xvi xxiii xxvi Construction of the Real Line 2 Is Every Real Number Rational? 3 Problems Algebra of the Real Numbers 7

Review for Cumulative Test 2

Since x + we get x² + 2x = 4, or simplifying it, x² = 4. Therefore, x² + = 4 2 = 2. Ans. (C)

Section 11.1: Sequences

Basic properties of real numbers. Solving equations and inequalities. Homework. Solve and write linear equations.

April 28, 2017 Geometry 11.1 Circumference and Arc Length

Euler s Identity: why and how does e πi = 1?

Reference Material /Formulas for Pre-Calculus CP/ H Summer Packet

MATH: A2. ADE Summer Item Writing Institute. Performance-Based Assessment. x f(x) g(x)

CURRICULUM MAP. Course/Subject: Honors Math I Grade: 10 Teacher: Davis. Month: September (19 instructional days)

A Library of Functions

An Appreciation of Euler's Formula

1 Abstract. 3.New symbol definitions. (1) Concept of rims

Phasor mathematics. Resources and methods for learning about these subjects (list a few here, in preparation for your research):

Chapter 1: Fundamentals of Algebra Lecture notes Math 1010

Region 16 Board of Education. Precalculus Curriculum

Mathematics skills framework

Chapter 0 Preliminaries

Paradoxical Euler: Integrating by Differentiating. Andrew Fabian Hieu D. Nguyen. Department of Mathematics Rowan University, Glassboro, NJ 08028

wondered what would happen if they extended their table. Do you agree or disagree with each conjecture below? Explain.

5.3 Other Algebraic Functions

3.9 My Irrational and Imaginary Friends A Solidify Understanding Task

Math Exam Jam Concise. Contents. 1 Algebra Review 2. 2 Functions and Graphs 2. 3 Exponents and Radicals 3. 4 Quadratic Functions and Equations 4

Euler s Multiple Solutions to a Diophantine Problem

Basic Fraction and Integer Operations (No calculators please!)

Prepared by Sa diyya Hendrickson. Package Summary

Independent Study Project: Chapter 4 Exponential and Logarithmic Functions

Name: Class: Math 7B Date:

Further Applications of Advanced Mathematics (FP3) THURSDAY 14 JUNE 2007

Finding the sum of a finite Geometric Series. The sum of the first 5 powers of 2 The sum of the first 5 powers of 3

Catholic Central High School

AP Calculus Summer Packet

Topics from Algebra and Pre-Calculus. (Key contains solved problems)

Polynomial Functions

Sept HS.F.IF.C.07c (polynomial) HS.A.APR.B.03 (polynomial) Sept HS.A.REI.A.02 (rational) HS.F.IF.B.04 (rational)

ACCUPLACER Sample Questions for Students

AP Calculus (BC) Chapter 9 Test No Calculator Section Name: Date: Period:

6.4. The Quadratic Formula. LEARN ABOUT the Math. Selecting a strategy to solve a quadratic equation. 2x 2 + 4x - 10 = 0

arxiv: v1 [math.ho] 30 Nov 2007

The Number System (NS) 8.NS.1 Standards for Mathematical Practice (MP): Connections

Integrated CME Project Mathematics I-III 2013

Copyright 2018 UC Regents and ALEKS Corporation. ALEKS is a registered trademark of ALEKS Corporation. 2/10

Honors Precalculus Semester 1 Review

Academic Outcomes Mathematics

Infinity and Infinite Series

Pre-Calculus Chapter 0. Solving Equations and Inequalities 0.1 Solving Equations with Absolute Value 0.2 Solving Quadratic Equations

2008 Euclid Contest. Solutions. Canadian Mathematics Competition. Tuesday, April 15, c 2008 Centre for Education in Mathematics and Computing

Pre-calculus 12 Curriculum Outcomes Framework (110 hours)

Math 527 Lecture Notes Topics in Calculus and Analysis Northern Illinois University Spring, Prof. Richard Blecksmith

Coach Stones Expanded Standard Pre-Calculus Algorithm Packet Page 1 Section: P.1 Algebraic Expressions, Mathematical Models and Real Numbers

Chapter 12: Ruler and compass constructions

Index. Excerpt from "Art of Problem Solving Volume 1: the Basics" 2014 AoPS Inc. / 267. Copyrighted Material

Problems with an # after the number are the only ones that a calculator is required for in the solving process.

MATH 0960 ELEMENTARY ALGEBRA FOR COLLEGE STUDENTS (8 TH EDITION) BY ANGEL & RUNDE Course Outline

Summer Review for Students Entering AP Calculus AB

Math Review for AP Calculus

Chapter 8: More on Limits

Remember, you may not use a calculator when you take the assessment test.

Accelerated Integrated Geometry Instructional Resource Calendar

WA State Common Core Standards - Mathematics

Reading Mathematical Expressions & Arithmetic Operations Expression Reads Note

AP Calculus Summer Homework MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

Numerical Methods. Exponential and Logarithmic functions. Jaesung Lee

Algebraic. techniques1

Mini Lecture 1.1 Introduction to Algebra: Variables and Mathematical Models

b = 2, c = 3, we get x = 0.3 for the positive root. Ans. (D) x 2-2x - 8 < 0, or (x - 4)(x + 2) < 0, Therefore -2 < x < 4 Ans. (C)

Chapter 06: Analytic Trigonometry

NYS Algebra Regents Curriculum Map

MILLIS PUBLIC SCHOOLS

An integer p is prime if p > 1 and p has exactly two positive divisors, 1 and p.

MATH Calculus I - Prerequisite Review

Bishop Kelley High School Summer Math Program Course: Honors Pre-Calculus

On the remarkable Properties of the Coefficients which occur in the Expansion of the binomial raised to an arbitrary power *

PHASE 9 Ali PERFECT ALI-PI.

Part I: Multiple Choice Questions

How to use this Algebra II - Semester 2 Study Packet

CHAPTER 0: Preliminary Topics

Math 4C Fall 2008 Final Exam Study Guide Format 12 questions, some multi-part. Questions will be similar to sample problems in this study guide,

SUMMER MATH PACKET. Geometry A COURSE 227

Review Notes for IB Standard Level Math

11.10a Taylor and Maclaurin Series

UNIT 4 NOTES: PROPERTIES & EXPRESSIONS

ALGEBRA II CURRICULUM MAP

Math Requirements for applicants by Innopolis University

On Various Ways of Approximating the Quadrature of a Circle by Numbers. 1 Author Leonh. Euler

What students need to know for CALCULUS (Regular, AB and BC) Students expecting to take Calculus should demonstrate the ability to:

FOUNDATION MATHEMATICS

REVIEW Chapter 1 The Real Number System

The exponent of a number shows you how many times the number is being multiplied by itself.

Contents. 2 Lesson. Common Core State Standards. Lesson 1 Irrational Numbers Lesson 2 Square Roots and Cube Roots... 14

Transcription:

An English translation of portions of seven letters between Euler and Goldbach on Euler s complex exponential paradox and special values of cosine Elizabeth Volz August 0, 008 The following is an English translation of portions of seven correspondences between Leonard Euler and Christian Goldbach dated between December, 1741 and June 174. These letters discuss many mathematical topics; however, this translation focuses on portions which deal with a paradox discovered by Euler involving complex exponentials and special values taken on by the corresponding cosine function. These results are important since they represent some of Euler s earliest applications of his formula ix e = cos x+ isin x, which he first published in 1748 in his pre-calculus textbook, Introductio in analysin infinitorum [E101] 1. These letters show that Euler certainly knew of this formula much earlier. Acknowledgement: The author wishes to thank Reinert Schmidt for his help in the translation of these letters. I. Euler to Goldbach: Berlin Dec 9, 1741 ([1], p. 91) I have lately also found a remarkable paradox. Namely that the value of the expression + + is approximately equal to 10/13 and that this fraction differs only in parts per million from the truth. The true value of this expression however is the cosine of the arc.6931471805599 or the arc of 39 degrees 4 min. 51 sec. 5 tenths of sec. and 9 hundredths of sec. in a circle of radius one. I have also made several important discoveries over the integration of such formulas as Pdx all where P and Q are rational functions of x. At a different time the honor will be Q had to write this in a more noble and detailed way. Euler mentions that he has discovered the curiosity that the complex expression + + = 0.76939... can be approximated by10 /13 = 0.76931... to five decimal places. 1 Available at The Euler Archive: www.math.dartmouth.edu/~euler/ 1

II. Goldbach to Euler: St. Petersburg Feb 13, 174 ([1], p. 45) + + With the observation as it was communicated to me that is approximately equal to 10/13 I have noticed that if you wanted to make it so that p + = 0 then p would have to be smaller than 3 and larger than. I confess that these limits are large but I do not have the curiosity to determine them any closer. Goldbach explores what value the exponent p must be in order to make the equation p 0 + = true, but only mentions that it must be between and 3.

III. Euler to Goldbach: Berlin March 6, 174 ([1], p. 96) Now that I have the curiosity to investigate when p + = 0, it has given me the opportunity to remark that this can happen in infinitely many ways. First observed that p π is between and 3, namely.661801. The true value is p = where l 1 1 1 π = 3.1415965 and l= 1 + 3 4+ etc. =.6931471803. All following values are derived out of this in that you multiply these with 3,5,7,9 etc. Euler solves for p in the equation p + = 0 and finds its exact value to be π p =. He then mentions the cyclic nature of the others solutions, namely ln (n + 1) π p =, where n = 1, 3, 5, 7,9,.... Observe that Euler writes l to denote ln. ln 3

IV. Goldbach to Euler: St. Petersburg April 1, 174 ([1], p. 100) At the opportunity where you wrote p + = 0 I have observed that when the n variable n is placed and np + = that as often as n is an even number they on the contrary equal -, as often as n is an odd number there is an integer q so that (4 n+ q) p (4 n+ q) p qp qp + = +. It is in my opinion also remarkable that when you determine p through p + = 3 also then this will become x+ 1 x+ 1 x x xp xp (1+ 5) ( 1+ 5) (1+ 5) ( 1+ 5) + = as long as x is an x+ 1 x integer. Goldbach introduces an additional variable in the exponent to explore solutions to n np n + = and notes that when n is an even integer np + =. For n (4 n+ q) p (4 n+ q) p qp qp odd he claims there exists an integer q so that + = +, which turns out to not be entirely true as Euler points out in his next letter to Goldbach (May 8, 174). Goldbach then claims that if p + = 3, then x+ 1 x+ 1 x x xp xp (1+ 5) ( 1+ 5) (1+ 5) ( 1+ 5) + =. x+ 1 x 1 This can be shown as follows: Let y p 1 =. Then y + = 3. It follows from the y p 1 3± 5 quadratic formula that y = = = 3 ± 5 and so xp xp 3+ 5 x 3 5 x + = ( ) + ( ). x+ 1 x+ 1 x x (1+ 5) ( 1+ 5) (1+ 5) ( 1+ 5) = x+ 1 x Observe that this expression in turn equals ( Fn+ 1+ Fn 1), where { F n } is the Fibonacci sequence. It is unclear whether Goldbach or Euler noticed this connection. 4

V. Euler to Goldbach: Berlin May 8, 174 ([1], p. 101) p p Generalizing a + a = b so that xp xp 1 b+ bb 4 b bb 4 x a + a = ( ) + ( ) And when p + = 3 so will xp xp 1 3+ 5 x 3 5 x 5+ 1 x 5 x + = ( ) + ( ) = ( ) + ( ) p p Otherwise I observe that with my general theorem a + a = cos( apln) in most (4 n+ q) p (4 n+ q) p qp qp part agree only that + is not equal to + when neither ( n+ q) pln nor np ln is equal to mπ denoted 1: π There is an error in the translation involving the exponent in the second formula, which should be x instead of x : 1 1 3 5 3 5 5 1 5 1 xp xp + + ( ) x ( ) x ( ) x + = + = + ( ) x p p In this letter Euler considers the generalization a + a = and mentions that he only agrees with Goldbach claim (stated in his previous letter) to the extent that (4 n+ q) p (4 n+ q) p qp qp + + when neither ( n+ q) pln nor np lnare equal to mπ. This is because if ( n+ q) pln = npln = mπ, then (4 n+ q) pln = mπ and qp ln = 0. It follows that cos[(4 n+ q) pln ] = cos[ qpln ]. Thus, + = + (4 n + q ) p (4 n + q ) p qp qp 5

VI. Goldbach to Euler: Moscow June 7, 174 ([1], p. 103) xp xp As much as I can remember the formula + where p + = 0 has application as a serpentine curve whose abscissa y (introduced) and which the axis is intersected as often as the formula equals 0 so that when the formula equals then the maximum application below or above comes out. It follows that countless other must be equal to each other. None the less, an error crept in to my original expression which can easily be corrected in that it should be that when q is a number such that p 0 + = then (8n 4 q) p (8n 4 q) p qp qp + = +. xp xp Goldbach mentions that the expression + has application as a serpentine curve. He then admits an error in his original expression and provides a new one. This is true because if we choose q= 8n 4 m, where m is any integer, then π π (8n 4 q) = q + mπ (8n 4 q) p ln = qp ln + mπ cos[(8n 4 q) p ln ] = cos[ qp ln ] + = + (8n 4 q) p (8n 4 q) p qp qp 6

VII. Euler to Goldbach: Berlin June 30, 174 ([1], p. 109) p p In general + = cos( Apln). When p + = 0 also there must be p ln in such a circular arc the cosine of which equals 0. All the arcs have the formula (n + 1) π (n + 1) π (n + 1) π and consequently will p =. If p = or p + = 0 so l l 1 1 ( 1) will cos lncos n x xp xp + π + = Axp = A. When therefore it should be that qp qp rp rp ( 1) ( 1) + = +, so must cos n + q π cos n + A A r π = but the cosine from two different arcs are equal to each other when either the sum or the difference of the arcs are equal to a multiple of the entire perimeter π. Therefore it will be ( n+ 1) qπ ( n+ 1) rπ 4m ± = mπ and from that it follows that q± r = so that it n + 1 will become ( 4m q) p ( 4m q) p n+ 1 n+ 1 qp qp + = +. Note: Euler appears to further his generalization by using the symmetry of the cosine function to find a relation between the quantities q and r when qp qp rp rp + = +. 7

References [1] Leonhard Euler und Christian Goldbach: briefwechsel 179-1764. Berlin: Akademie- Verlag, 1965. [] The Euler Archive: http://www.math.dartmouth.edu/~euler/ Department of Mathematics Rowan University Glassboro, NJ 0808 8