Unit 5 Simple Circuits

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NOTE: This slide is for the purpose of including LP information that you may not necessarily show your scholars (if you include the information below in a different part of your PPT, there is no need to put it here. If you do not show it anywhere though, include it here in the notes section. Differentiation: TEKS See in slides SPED Vocabulary flash cards Outlines/Notes MJ, CS Highlighting Marking Texts Diagrams, maps, graphs Peer tutoring Extended time MJ, CS, AP, RC Shortened assignments LEP/ESL Grouping Journal Notebooks Internet Project Portfolios Manipulative Highlighting Marking Texts Diagrams, maps, graphs ELPS: 1C. Use visual strategies to organize information to solve problems. 504 Vocabulary flash cards Outlines Highlighting Marking Texts Diagrams, maps, graphs Peer tutoring Extended time - CA Shortened assignments (Other) GT Grouping Journal Notebooks Peer Tutoring Process Writing Discovery Learning Internet Project Portfolios Manipulative Other Statement of Inquiry: See in slides Learner Profile: Thinker Scholars will use strategies such as drawing models to solve problems. Unit 5 Simple Circuits

Do Now: 1. Walk in silently. 2. Grab a calculator and any papers for today. 3. Put your HW on your desk ready to grade. 4. Two charged parallel plates are 2.0 cm apart. The magnitude of the electric field between the plates is 1400 N/C. What is the electric potential difference between the plates? Due Next Class: U5.HW2 New Vocab (total 36) Current, I Resistance, R

By the end of the day today, IWBAT show how power, current, potential difference, and resistance are mathematically related. Why it matters in LIFE: Part of being a functional human being is being able to understand what s happening in the world around you! Why it matters in THIS CLASS: Our Goal = 80% Mastering today s lesson (focused participation, asking questions, etc) is the first brick that will help us reach our goal for this unit, and eventually for the year

TEKS: 5(C) describe and calculate how the magnitude of the electrical force between two objects depends on their charges and the distance between them By the end of today, IWBAT draw simple circuit diagrams and indicate the direction of conventional current flow. show how power, current, potential difference, and resistance are mathematically related. Topic: Simple Circuits

ELECTRICITY THE FLOW OF CHARGE

CLOSED CIRCUIT A complete and unbroken conducting path between the source of the current and the return of the current

OPEN CIRCUIT A circuit with a switch turned to the off position, or a circuit with any break in it (electricity cannot travel through an open circuit)

CIRCUIT SCHEMATIC SYMBOLS Current Resistance Voltage wire

CURRENT FLOW

ELECTRICITY FLOWS LIKE WATER

CURRENT, (Units of amps (A)) Current wire The flow of charge through a circuit. Ammeters measure current.

AMMETERS MEASURE CURRENT Would you get a reading? A Yes! The circuit is closed, so current is flowing. A No! The circuit is open, so current is not flowing. Reads = zero.

RESISTANCE, R (Units of ohms (Ω)) Resistance A material s ability to resist (restrict) the flow of electricity.

VOLTAGE, V (Units of volts (V)) Voltage (Electric Potential Difference) The electrical pressure that causes charges to move created by a difference and separation of charge. Voltmeters measure voltage.

VOCAB CARDS LIGHTNING ROUND!

VOLTAGE, CURRENT, RESISTANCE V = I R V = Voltage (volts, V) = Current (amps, A) R = Resistance (ohms, Ω)

ELECTRICAL POWER, P (Units watts (W)) P = V I P = Electrical Power (watts, W) V = Voltage (volts, V) = Current (amps, A)

TABLE OF VARIABLES & UNITS Variable Symbol Units (Word) Units (Symbol) Current I amps A Resistance R ohms Ω Voltage V volts V Power P watts W

EXAMPLE #1 A 12 V battery causes a 3 amp current through a light bulb. a) What is the resistance of the light bulb? b) How much power does it draw?

EXAMPLE #1 A 12 V battery causes a 3 amp current through a light bulb. a) What is the resistance of the light bulb? b) How much power does it draw? G: V = 12 V I = 3 A U: R =? E: I = V/R R = V/I S: R = 12/3 R = 4 ohms G: V = 12 V I = 3 A U: P =? E: P = VI S: P = 12*3 P = 36 watts

Do GP #1 with your table partner!

EXAMPLE #2 A light bulb in a circuit with a 12 V battery uses 24 watts. What is the resistance of the light bulb?

EXAMPLE #2 A light bulb in a circuit with a 12 V battery uses 24 watts. What is the resistance of the light bulb? G: V = 12 V P = 24 W U: R =? I =? E: I = V/R R = V/I P = VI I = P/V S: I = 24W / 12 V = 2 amps R = 12 V / 2 A = 6 ohms R = 6 ohms

Do GP #2 with your table partner!

EXAMPLE #3 In a circuit, what happens to the current if the voltage is tripled and the resistance remains the same?

EXAMPLE #3 In a circuit, what happens to the current if the voltage is tripled and the resistance remains the same? G: V = tripled = x 3 R = constant U: I =? E: I = V/R S: I = x 3/1 I = x 3 The current in the circuit is tripled! Aka the new current is 3 times as big as the old current; 3I

Do GP #3 & 4 with your table partner!

INDEPENDENT PRACTICE! Procedure for IP time: 1) Silent work time 2) Try and solve without notes first! Hierarchy of who to ask 1) Your brain 2) Your notes 3) Ms. Kelly (after you #embracethestruggle)

EXIT TICKET 1. In a circuit, what happens to power if resistance is doubled and voltage remains the same? 2. A light bulb in a circuit with a 36 V battery uses 72 watts. What is the resistance of the light bulb?

EXIT TICKET 1. The power is cut in half 2. R = 18 ohms G: V = constant R = doubled = * 2 U: P =? E: I = V/R I = constant/2 = * ½ P = VI P = constant* ½ = * ½ The power is cut in half! The new power is ½ of the original power. G: V = 36 V P = 72 W U: R =? I =? E: I = V/R R = V/I P = VI I = P/V S: I = 72W / 36 V = 2 amps R = 36 V / 2 A = 18 ohms R = 18 ohms

ON THE BACK OF YOUR E.T. 1. What was one strength of yours from today? 2. What was one weakness of yours from today? 3. What was one strength of mine from today? 4. What was one strength of mine from today?