Optimal Polynomial Admissible Meshes on the Closure of C 1,1 Bounded Domains

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Optimal Polynomial Admissible Meshes on the Closure of C 1,1 Bounded Domains Constructive Theory of Functions Sozopol, June 9-15, 2013 F. Piazzon, joint work with M. Vianello Department of Mathematics. Doctoral School in Mathematical Sciences, Applied Mathematics Area

Outline 1 Introducing Polynomial Admissible Meshes Defining (Weakly) Admissible Meshes, Optimal Admissible Meshes. Main properties and motivations. Building Admissible Meshes, the state of the art. 2 A new result for C 1,1 bounded domains Main Result. Tools: Bernstein Inequality and regularity property of oriented distance function Sketch of the proof. CTF - 2013-2 of 39

First definitions (1) In 2008 J.P. Calvi and N.Levenberg proposed these well promising definitions. Admissible Meshes, AM Let K R d (or C d ) be a compact polynomial determining set. The sequence {A n } N of finite subsets of K is said to be an Admissible Mesh for K if there exist C, s > 0 such that Card A n = O(n s ) p K C p An p P n (K). Weakly Admissible Meshes, WAM If instead C = C n = O(n q ), then we say that A n is a Weakly Admissible Mesh. CTF - 2013-3 of 39

First definitions (2) By the definitions both AMs and WAMs are determining for P n (K), thus we have ( ) n + d Card A n dim P n (K) = = O(n d ) n For this reason A. Kroó introduced Optimal Admissible Mesh The AM A n w.r.t. K R d is said to be optimal if Card A n = O(n d ). CTF - 2013-4 of 39

Motivations DLS Approximation on a WAM - Calvi Levenberg (2008) Let K R d be compact and polynomial determining, A n a WAM on it and f C 0 (K), then one has f Λ An f K ( )) (1 + C n f K (1 + Card(A n )) d n (f, K) Where Λ An is the discrete least squares (DLS) operator performed sampling f on A n and d n (f, K) is the error of best polynomial approximation to f on K. Mild regularity of f and K = convergence of DLS operator. CTF - 2013-5 of 39

Properties (1) WAMs work nicely under some fundamental operations. Stability under affine mapping, union and tensor product. Weak stability under polynomial mapping. Supersets of WAM are WAMs. Good interpolation sets are WAMs. CTF - 2013-6 of 39

Properties (2) Discrete Extremal Sets - Bos, De Marchi, Sommariva and Vianello Starting from a WAM one can extract by standard Numerical Linear Algebra such that AFP Approximate Fekete Points ALS Approximate Leja Sequences Unisolvent sets. Slowly increasing Lebesgue constants. Same asymptotic (in measure theoretic sense). CTF - 2013-7 of 39

Problems Two questions naturally arise.. Question 1 How to build AMs or even WAMs for a given K? Question 2 How to build Optimal AMs for a given K? CTF - 2013-8 of 39

Solving (Q1) One should choose/combine different results requiring K to have particular shape and/or smoothness Elich-Zeller: Double degree Chebyshev points for the interval are AM of constant 2. shape: Use symmetries of K, polar coordinates, tensors, quadratic maps.. Calvi-Levenberg used Multivariate Markov Inequality. Kroó: Star shaped bounded domains with smooth Minkowski functional + Bernstein Inequality. Piazzon-Vianello Mapping and Perturbing WAMs and AMs. W. Plesniak improve for sub-analytic sets. Kroó result on Analytic Graph domains. Bloom Bos Calvi and Levenberg existence for L-regular sets. CTF - 2013-9 of 39

Building AM by Markov Inequality Markov Inequality (MI) The set K is preserving a Markov Inequality of constant M K and exponent r if p K M K n r p K. p P n (R d ) MI holds under mild assumptions on K, typically r = 2. Idea: take any equally spaced grid having step size O(n r ). Calvi Levenberg (2008) If K R d preserves a Markov Inequality of exponent r, then it has a AM with O(n rd ) points. CTF - 2013-10 of 39

Building AM by Bernstein Inequality and Star Shape Using the classical Bernstein Inequality on segments and star-shaped property it has been proved Kroó (2011) Let K R d be compact and star-shaped with C 1+α smooth Minkowski functional. Then K has an AM with O(n 2d+α 1 α+1 ) points. CTF - 2013-11 of 39

Mapping and Perturbing Perturbation Result Piazzon Vianello Let K C d be a polynomially convex and Markov compact set. If that there exists a sequence of compact sets {K j } N such that there exists A n,j (W)AM for K j having constant C n,j and d H (K, K j ) ɛ j where lim sup j ɛ j C n,j = 0 n. Then K has a (W)AM. Mapping Result Piazzon Vianello (W)AMs are weakly stable under smooth mapping: for any holomorphic map ϕ : Q K there exists j ϕ (n) = O(log n) such that B n := ϕ(a n jϕ (n)) is a WAM for K. CTF - 2013-12 of 39

Nearly Optimal AM AM having Card A n = O((n log n) d ) as the ones above are termed nearly optimal. W. Plesniak showed that Piazzon-Vianello results in particular apply to any compact sub-analytic set that hence has a nearly optimal AM. A. Kroó proved that analytic graph domains have a nearly optimal AM Bloom,Bos,Calvi and Levenberg showed (non constructively) that any L-regular compact set has. CTF - 2013-13 of 39

Solving (Q2) Question 2 How to build Optimal AMs for a given K? Polytopes, Balls have Optimal AMs by 1dim techniques, symmetry or thanks to the particular shape and finite unions. The Kroó result applies to star-shaped C 2 smooth sets. The Kroó result has been refined: if d = 2, then C 2 smoothness can be replaced by uniform interior ball condition. What about sets with a more general shape? CTF - 2013-14 of 39

Main Result Idea: Smoothness may completely replace Particular Shape. Piazzon 2013 Let Ω be a bounded C 1,1 domain in R d, then there exists an optimal admissible mesh for K := Ω. CTF - 2013-15 of 39

Tools I Bernstein Inequality Let p P n (R), then for any a < b R we have dp dx (x) n p [a,b]. (x a)(b x) (BI) and thus dp dx ( a+b 2 ) 2n (b a) p [a,b]. Markov Tangential Inequality Let p P n (R d ), then for any x 0 R d, r > 0 and v S d 1 T x B(x 0, r) we have dp dv (x) n r p B(x 0,r]. (MTI) CTF - 2013-16 of 39

Tools II C 1,1 domains Ω R d domain whose boundary is locally the graph of a C 1,1 function of controlled norm. If Ω is bounded, then all the parameters involved in this definition can be chosen uniformly. 10 5 0 5 10 10 0 10 20 30 CTF - 2013-17 of 39

Tools III Geometric Characterization Bounded C 1,1 domains are characterized by the uniform double sided ball condition. 10 5 0 5 10 10 0 10 20 30 CTF - 2013-18 of 39

Tools IV Oriented Distance Function b Ω (x) := inf x y inf x z y Ω z Ω 10 5 0 5 10 10 0 10 20 CTF 30-2013 - 19 of 39

Tools V Regularity Properties of b Ω ( ) If Ω is a bounded C 1,1 domain, then there exists δ such that for any 0 < δ < δ we have The metric projection on the boundary x π Ω (x) is single valued on U δ where U δ is a δ-tubular neighborhood of Ω. b Ω C 1,1 (U δ ). b Ω (x) = x π Ω(x) b Ω (x) 0 in U δ. b Ω (x) defines the outer normal unit vector field w.r.t. Ω. Differentiability across the boundary. We can take δ as the radius of the ball. Level sets of b Ω are C 1,1 manifolds. CTF - 2013-20 of 39

Sketch of the Proof 1 Bound normal derivatives of polynomials by a modified Bernstein Inequality along segments of metric projection. Thanks to boundary regularity. Find a norming set for Ω : by union of m n = O(n) hypersurfaces which are level sets of b Ω and K δ := {x Ω : b Ω (x) δ} { } p K 2 max p Kδ, p mn. p P n (R d ) i=0 Γi CTF - 2013-21 of 39

construction 10 5 0 5 10 10 0 10 20 30 CTF - 2013-22 of 39

Sketch of the Proof 2 Bound any directional derivative of polynomials by a modified Bernstein Inequality holding in K δ. Find a weak norming set for K δ : w.r.t. Ω by a grid mesh Z n, of stepsize O(n 1 ) i.e. p Kδ p Zn + 1 λ p Ω λ > 2. p Pn (R d ) Card Z n = O(n d ) CTF - 2013-23 of 39

Sketch of the Proof 3 Bound tangential derivatives of polynomials on Γ i s by the combination of Regularity of Γ i s Ball property. Markov Tangential Inequality Find weak norming sets for m i=0 n Γ i w.r.t. Ω by the union of geodesic meshes Y i n Γ i having geodesic fill distance O(n 1 ) p mn i=0 Γi p Y i n + 1 λ p Ω λ > 2. p Pn (R d ) Card m n i=0 Γi = m n O(n d 1 ) = O(n d ). CTF - 2013-24 of 39

Sketch of the Proof 4 Finally we set A n := Z n ( m n i=0 Γi) and the inequalities above read as p Ω 2 p An + 2 λ p Ω p Pn (R d ) p Ω 2λ λ 2 p A n p P n (R d ) Card(A n ) = O(n d ). CTF - 2013-25 of 39

further investigations... We conclude by recalling the open problem Conjecture Bloom Bos Calvi and Levenberg If K C d is compact and L-regular then there exists c := c(k) such that any array of degree c(k)n Fekete points forms an Admissible mesh for K, that hence is Optimal. CTF - 2013-26 of 39

References J.P. Calvi and N. Levenberg. Uniform approximation by discrete least squares polynomials. JAT, 152:82 100, 2008. A. Kroó. On optimal polinomial meshes. JAT, 163:1107 1124, 2011. L.Bos, S. De Marchi, A.Sommariva, and M.Vianello. Weakly admissible meshes and discrete extremal sets. Numer. Math. Theory Methods Appl., 4(1):1 12, 2011. F. Piazzon. Optimal polynomial admissible meshes on compact subsets of R d with mild boundary regularity. preprint submitted to JAT, arxiv:1302.4718, 2013. F. Piazzon and M. Vianello. Analytic transformation of admissible meshes. East J. on Approx, 16:389 398, 2010(4). F. Piazzon and M. Vianello. Computing optimal polynomial meshes on planar starlike domains. draft,http://www.math.unipd.it/ marcov/pdf/star.pdf, 2012. F. Piazzon and M. Vianello. Small perturbations of admissible meshes. Appl. Anal., pubblished online 18 jan., 2012. CTF - 2013-27 of 39

Thank You! CTF - 2013-28 of 39

more details... CTF - 2013-29 of 39

Proof (1) Step 1 we build a norming set. We pick δ < r and work out a modification of (BI) of the form D S p(x) nϕδ (b Ω (x)) p Ω Where S is a segment of metric projection, ϕ δ arises as follows.. CTF - 2013-30 of 39

Proof (2) ϕ δ (ξ) := 1, ξ(δ ξ) if ξ < δ 1 ξ, otherwise. (1) 10 5 0 5 10 10 0 10 20 30 CTF - 2013-31 of 39

Proof (3) Then we define a function by integration along segments of metric projection x F n,δ (x) := n bω (x) 0 ϕ δ (ξ)dξ 4 3 2 1 10 20 30 40 50 CTF - 2013-32 of 39

Proof(4) and consider equally spaced level sets where Therefore we have Γ i n,δ := F n,δ (ai ) i = 0, 1,... m n = O(n), a i = 0,..., max F n,δ Ω 1/2 a i+1 a i. p Ω p i Γ i n,δ + 1/2 p Ω 2 p i Γ i n,δ. CTF - 2013-33 of 39

Proof (5) For some technical reasons we switch m n i=0 Γi n,δ = m n i=0 Γi n,δ m n i= m n +1 Γi n,δ where the second set is a subset of K δ := {x Ω : b Ω (x) δ} and then we can replace it by K δ itself. p Ω 2 max{ p mn, p Γ i Kδ }. i n,δ CTF - 2013-34 of 39

Proof (6) Step 2: finding a norming mesh Z n for K δ. we use (BI) jointly with B(x, δ) Ω x K δ to get p(x) n δ p Ω. Thus we can build a suitable Z n by a grid of step size δ 4n = O(n 1 ) and hence cardinality obtaining Card Z n = O(n d ) p Kδ p Zn + 1 4 p Ω CTF - 2013-35 of 39

Proof (7) Step 3: finding a norming mesh Y n for m n i=0 Γi n,δ Any Γ i n,δ is a C 1,1 manifold. we can pick a tangent ball of radius δ/2 lying in Ω. 2 0 2 4 6 thus.. 22 24 26 28 30 CTF - 2013-36 of 39

Proof (8) We can bound any tangential derivative by MTI applied to the ball to get dp dv (x) n δ/2 p Ω v Sd 1 T x Γ i n,δ Therefore if we pick a mesh Yn i on each Γi n,δ having controlled geodesic fill distance h i = O(n 1 ) we get p mn p Γ i i Y i + 1 i n,δ n 4 p Ω. CTF - 2013-37 of 39

Proof (9) The regularity of Γ i n,δ s ensures that we can produce suitable Y i n,δ using O(n d 1 ) points, since we have m n = O(n) level set Γ i n,δ we have Card Y n,δ := Card i Y i n,δ = O(nd ) CTF - 2013-38 of 39

Proof (10) Step 4: joining all the inequalities. Finally putting all together we get p Ω ( 2 p Yn,δ Z n + 1 4 p Ω and thus p Ω ( ) 4 p Yn,δ Z n where (2) Card(Y n,δ Z n ) = O(n d ) (3) ) That is optimal. CTF - 2013-39 of 39

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