Q. Four sprig coec wih ss s show i figure. Fid frequecy of S.H.. TEST- TOPIC : SH d WVES 4 7 (D) These wo coeced i series. So = = Now ll re i prllel so eq = 4 so freq. = 4 4 7 Q. sll ss execue S.H.. bou poi O wih pliude & ie period T. Is T displcee fer ie fro e posiio 8 is- (D) 8 [D] eq. of S.H.. x = si T so = 8 x = Q.3 uifor rod of legh.0 is suspeded hrough ed & oscille wih sll pliude. The ie period is -.60 s.80 s.00 s (D).40 s [D] T = I0 h gh where I 0 = / h = So T =.40 s Q.4 Four siple hroic ibrios x = 8 si, x = 6si ( + /), x 3 = 4 si ( + ) d x 4 = si ( + 3/) re superiposed o ech oher. The resulig pliude d is phse differece wih x re respeciely - [D] 0, 0, () 4 (D) 4,, 4 Q.5 O sooh iclied ple body of ss is [] ched bewee wo sprigs. The oher eds of he sprigs re fixed o fir suppors. If ech sprig hs force cos, he period of oscillio of he body is (ssuig he sprig s ssless) - si (D) si WWW.PHYSICSNOWLEDGE.CO Pge of 8
Q.6 The ccelerio-displcee (-x) grph of pricle execuig siple oio is show i figure. The frequecy of oscillio is gie by - (c/s ) 0.5 s 5s [] = 0 x = 0 = 0 0 x (c) 0s (D) 0s = 0 Q.7 pricle execues SH of pliude 5 c d period 3s. The elociy of he pricle disce 4 c fro he e posiio - 8 c/s c/s 4 c/s (D) 6 c/s [D] V = = 3 3 x = x T 5 6 = 6 c/s Q.8 If he legh of pedulu is de 9 ies d ss of he bob is de 4 ies, he he lue of ie period becoes - 3 T 3/ T 4 T (D) T [] Tie period does o deped o ss T. (i), T 9.(ii) or T = 3 T. Q.9 The legh of siple pedulu execuig SH is icresed by %. The percege icrese i he ie period of he pedulu is - 0% % % (D) 4 % [] T T = T = T 00 0 T 00 % = 00 % = 0% T 0 Q.0 uifor sprig of orl legh hs force cos. I is cu io wo pieces of leghs, d such h = where is ieger. The he lue of (force cos of sprig of legh ) is - ( ) ( ) = = ( + ) = ( ) ( ) (D) ( ) or = ( ) or = Q. syse show i figure, cosiss of ssless pulley, sprig of force cos d bloc of ss. If bloc is jus slighly displced ericlly dow fro is equilibriu posiio d relesed, he he period of ericl oscillios is T = T = 4 Displcee i box = x displcee i box = x F = x F = F F = 4 x T = 4 T = (D) T = 4 3 Q. Four sprigs & ss is coeced s show i figure. If ss is displced horizolly he wh is he frequecy of S.H..? F F x F WWW.PHYSICSNOWLEDGE.CO Pge of 8
4 7 Coeced i series so eq so ow Now ll i prllel so eq = + + = 4 & so frequecy f = 4 (D) 4 7 Q. 3 Vriio of pliude of ibrios s fucio of ie show s grph is- 0 ( ) or = Q.4 pricle of ss is ched o hree ideicl sprigs, B d C ech of force cos s show i figure. If he pricle of ss is pushed slighly gis he sprig d relesed, he he ie period of oscillio is - T = B O ( cos C ) (D) = ( cos 45) = 3 Q.5 siple pedulu wih is bob (ss ) chrged wih +q oscilles i uifor elecric field E, s show i he figure he period of oscillio shll be +q 0 0 (D) 0 g / g qe / g qe / E (uifor) / / [C]. q (D) ge / / [C] WWW.PHYSICSNOWLEDGE.CO Pge 3 of 8
Q.6 Which of he followig digrs correcly rele displcee, elociy d ccelerio wih ie for pricle execuig SH - PE I II () y (b) y T/ PE III IV y (c) (d) y [] Q.7 Boh he equios y = si d. y = si + cos represe S.H.. The rio of he pliudes of he wo oios is- 0.5 (D) [D] Q.8 siple pedulu hs ie period T whe o he erh s surfce, d T whe e o heigh R boe he erh s surfce, where R is he rdius of he erh. The lue of T / T is - [IIT-00] 4 (D) [D] I d III II d IV II d III (D) I d IV Q. Tie period of siple pedulu is T. Whe poi of suspesio of he pedulu is oig upwrd followig he equio y = (where = /s, y is he displcee of poi of suspesio) is ie period becoes T, he - [IIT-005] T 5 = T 6 x T 6 = T 5 T T = (D) 4 = T T 5 Q. I he syse show if he iexesible srig coecig d is cu, he ccelerios of ss d re - [IIT-006] Q.9 pricle execues siple hroic oio bewee x = d x = +. The ie e for i o go fro 0 o / is T d o go fro / o is T.The - [IIT-00] T < T T > T T = T (D) T = T [] Q.0 For pricle execuig SH he displcee x is gie by x = cos. Ideify he grph which represes he riio of poeil eergy (PE) s fucio of ie d displcee x - [IIT-003] g, g srig g, g g, g (D) g, g Q.3 source of frequecy 'f ' is siory d obserer srs oig owrds i = 0 wih WWW.PHYSICSNOWLEDGE.CO Pge 4 of 8
cos sll ccelerio. The he riio of obsered frequecy f ' resisered by he obserer wih ie is bes represeed s - f ' f ' The seprio bewee he source d liseer will be icresig (D) The seprio bewee source d he liseer is decresig [D] [] f 0 f ' 0 f s (D) f ' ( )f Q.4 perso P is 600 wy fro he sio whe ri is pprochig sio wih 7 /h, i blows whisle of frequecy 800 Hz whe 800 wy fro he sio. Fid he frequecy herd by he perso. Speed of soud = 340 s - 800 Hz 89.5 Hz s 800 pp = = cos s s cos s S 600 P 839.5 Hz (D) 843.5 Hz 340 340 6 800 = 839.5 Q.5 If he ppre frequecy of soud herd by he obserer is ore h he cul frequecy he- The liseer will be oig wy fro source The source will be oig wy fro liseer Q.6 ppre frequecy of ri is herd by obserer i ri B s 3/4 of he rue frequecy. Fid he lue of elociy of ri B i /sec. ig ri o be siory. If he soud elociy is 33 /sec. - 0 08 75 (D) 83 [D] Q.7 police cr oig /s, chses oorcyclis. The police souds his hor 76 Hz, while boh of he oe owrds siory sire of frequecy 65 Hz. Clcule he speed of he oorcycle, if i is gie h he does o obseres y bes. 33 /s /s [IIT - 003] zero (D) /s Q.8 oor cycle srs fro res d cceleres log srigh ph /s. he srig poi of he oor cycle here is siory elecric sire. How fr hs he oor cycle goe whe he drier hers he frequecy of he sire 94% of is lue whe he oor cycle ws res? (Speed of soud = 330 s ) [IEEE-009] 49 98 47 (D) 96 Whe source i siory d obserer is oig wy fro he source. ' = V 0 V V 330 V0 0.94 = 330 V 0 = 9.8 /s V 0 = 0 + s WWW.PHYSICSNOWLEDGE.CO Pge 5 of 8
0 V S = 9.89.8 = = 98. Q.9 The equio of we disurbce is gie s : y = 0.0 cos 50 cos (0x), where x d 5 [C] w = 50, y re i eres d i secods. Choose he wrog see - iode occurs x = 0.3 The welegh is 0. The speed of he cosiue wes is 4 /s (D) Node occurs x = 0.5 = 0 = w = 5 /sec Q.30 The rio of iesiies bewee wo cohere soud source is 4 :. The differece of loudess i decibels (db) bewee xiu d iiu iesiies, whe hey ierfere i spce is - 0 log 0 log 3 0 log 3 (D) 0 log I I 4 = = = So 3 I = So x 9 I = L = 0 log x Ii Ii = 0 log 3 Q.3 Two wes re represeed by y = si d y = cos 6 Wh will be heir resul pliude? = 0 log 9 3 (D) [C] Q.3 The speed of rserse ibrios i sreched srig is 700 c/s. If he srig is log, he frequecy wih which i resoes i fudel ode is - 7 Hz 4 Hz L = 4 7 Hz (D) 7 Hz = L & = = 4 7 Hz Q.33 Whe wo wes of los equl frequecies d re produced siuleously, he he ie ierl bewee successie xi is - (D) x T x T = x Q.34 For he siory we y = 4si 5 [] cos (96), he disce bewee ode d he ex iode is : 7.5 5.5 (D) 30 [] Q.35 ibrig uig for of frequecy is plced er he ope ed of log cylidricl ube. Er The ube hs side opeig d is lso fied wih oble reflecig piso. s he piso is oed hrough 8.75 c, he iesiy of soud chges fro xiu o iiu. If he speed of soud is 350 ere per secod, he is 500 Hz 000 Hz 000 Hz (D) 4000 Hz Q.36 uig for of ow frequecy 56 Hz es 5 bes per secod wih he ibrig srig of pio. The be frequecy decreses o bes per secod whe he esio i he pio srig is WWW.PHYSICSNOWLEDGE.CO Pge 6 of 8
slighly icresed. The frequecy of he pio srig before icresig he esio ws 56 Hz [IEEE-003] 56 5 Hz 56 + 5 Hz (D) 56 + Hz Q.37 srig is sreched bewee fixed pois sepred by 75.0 c. I is obsered o he reso frequecies of 40 Hz d 35 Hz. There re o oher reso frequecies bewee hese wo. The, he lowes reso frequecy for his srig is [IEEE 006] 050 Hz 0.5 Hz 05 Hz (D).05 Hz [C] Q.38 we rellig log he x- xis is described by he equio y(x,) = 0.005 cos (x ). If he welegh d he ie period of he we re 0.08 d.0 s, respeciely, he d i pproprie uis re [IEEE 008] = = 0.08 0.04, =.0. 0, = =.50 =.0 (D) = 5.00 = [D] Q.39 Two ideicl srigh wires re sreched so s o produce 6 bes per secod whe ibrig siuleously. O chgig he esio slighly i oe of he, he be frequecy reis uchged. Deoig by T, T he higher d he lower iiil esios i he srigs, he i could be sid h while ig he boe chges i esio - T ws decresed T ws icresed [IIT 99] T ws icresed (D) Nohig c be sid Q.40 The displcee y of pricle execuig periodic oio is gie by y = cos ( ) si (000 ) This expressio y be cosidered o be resul of he superposiio of idepede hroic oios wo hree [IIT 99] four (D) fie Q.4 The exesio i srig, obeyig Hooe s lw is x. The speed of soud i he srig is. If he exesio i he srig is icresed o.5 x, he speed of soud will be-. 0.6 [IIT 996].50 (D) 0.75 [] Q.4 rellig we i sreched srig is described by he equio y = si(x ). The xiu pricle elociy is [IIT 997] / d/d (D) x/ [] Q.43 rserse siusoidl we of pliude, welegh d frequecy f is rellig o sreched srig. The xiu speed of y poi o he srig is /0, where is he speed of propgio of he we. If = 0 3 d = 0 s, he is gie by- [IIT 998] = 0 = 0 3 = 0 3 /() (D) = 0 4 [] Q.44 Sdig wes c be produced- [IIT 999] o srig clped boh he eds WWW.PHYSICSNOWLEDGE.CO Pge 7 of 8
o srig clped oe ed d free he oher whe icide we ges refleced fro wll (D) ll of hese [D] Q.45 I we oio y = si (x - ), y c represe- [IIT 999] elecric field geic field displcee (D) ll of hese [D] WWW.PHYSICSNOWLEDGE.CO Pge 8 of 8