V = 2ze 2 n. . a. i=1

Similar documents
8.592J HST.452J: Statistical Physics in Biology

2 Structure. 2.1 Coulomb interactions

Proteins polymer molecules, folded in complex structures. Konstantin Popov Department of Biochemistry and Biophysics

8.333: Statistical Mechanics I Problem Set # 5 Due: 11/22/13 Interacting particles & Quantum ensembles

Bchem 675 Lecture 9 Electrostatics-Lecture 2 Debye-Hückel: Continued Counter ion condensation

2.4 DNA structure. S(l) bl + c log l + d, with c 1.8k B. (2.72)

S(l) bl + c log l + d, with c 1.8k B. (2.71)

Electrostatic Interactions in Mixtures of Cationic and Anionic Biomolecules: Bulk Structures and Induced Surface Pattern Formation

Fundamental Principles to Tutorials. Lecture 3: Introduction to Electrostatics in Salty Solution. Giuseppe Milano

MAE 545: Lecture 4 (9/29) Statistical mechanics of proteins

3 Biopolymers Uncorrelated chains - Freely jointed chain model

PHASE TRANSITIONS IN SOFT MATTER SYSTEMS

Statistical Thermodynamics Exercise 11 HS Exercise 11

Magnetic tweezers and its application to DNA mechanics

Soft Matter and Biological Physics

DNA/RNA structure and packing

Polymer solutions and melts

Lectures 11-13: Electrostatics of Salty Solutions

March 11. Physics 272. Spring Prof. Philip von Doetinchem

Lecture 1: Introduction. Keywords: Mathematics as a language, Need of learning mathematics, Applications of mathematics in BIology

Physics of DNA. R. Podgornik. Laboratory of Physical and Structural Biology. National Institute of Child Health and Human Development

Chap. 2. Polymers Introduction. - Polymers: synthetic materials <--> natural materials

Electrostatic correlations and fluctuations for ion binding to a finite length polyelectrolyte

Lecture 5: Macromolecules, polymers and DNA

Aqueous solutions. Solubility of different compounds in water

Confinement of polymer chains and gels

1924 Biophysical Journal Volume 107 October

DNA supercoiling: plectonemes or curls?

Introduction to polymer physics Lecture 1

V(φ) CH 3 CH 2 CH 2 CH 3. High energy states. Low energy states. Views along the C2-C3 bond

GEM4 Summer School OpenCourseWare

Polyelectrolyte and polyampholyte. effects in synthetic and biological

Sec. 2.1 Filaments in the cell 21 PART I - RODS AND ROPES

The lattice model of polymer solutions

Multimedia : Fibronectin and Titin unfolding simulation movies.

Assignment 5 Biophys 4322/5322

Lecture 3 Charged interfaces

arxiv: v1 [q-bio.bm] 6 Apr 2016

Polymer Solution Thermodynamics:

Electrostatics and the assembly of an RNA virus

Hydrogels in charged solvents

Physics Graduate Group. Saturday, September 15 th 2007

`1AP Biology Study Guide Chapter 2 v Atomic structure is the basis of life s chemistry Ø Living and non- living things are composed of atoms Ø

POGIL 7 KEY Intermolecular Forces

Swelling and Collapse of Single Polymer Molecules and Gels.

DNA Condensation. Matej Marin Advisor: prof. Rudi Podgornik. 4th April 2002

Simple Simulations of DNA Condensation

Coil to Globule Transition: This follows Giant Molecules by Alexander Yu. Grosberg and Alexei R. Khokhlov (1997).

Gases: Properties and Behaviour

VIII. Rubber Elasticity [B.Erman, J.E.Mark, Structure and properties of rubberlike networks]

Atoms & Their Interactions

Soft Matter - Theoretical and Industrial Challenges Celebrating the Pioneering Work of Sir Sam Edwards

arxiv:cond-mat/ v1 [cond-mat.soft] 21 Mar 2003

The Microcanonical Approach. (a) The volume of accessible phase space for a given total energy is proportional to. dq 1 dq 2 dq N dp 1 dp 2 dp N,

Monolayers. Factors affecting the adsorption from solution. Adsorption of amphiphilic molecules on solid support

Phys 450 Spring 2011 Solution set 6. A bimolecular reaction in which A and B combine to form the product P may be written as:

ds around the door frame is: A) T m D) T m B) T m E) none of these C) T m

An experimental study of the temperature-dependent DNA elasticity using optical tweezers.

PH 222-2C Fall Gauss Law. Lectures 3-4. Chapter 23 (Halliday/Resnick/Walker, Fundamentals of Physics 8 th edition)

Liquids and Solutions Crib Sheet

(a) Write down the total Hamiltonian of this system, including the spin degree of freedom of the electron, but neglecting spin-orbit interactions.

Grand-canonical simulation of DNA condensation with two salts, effect of divalent counterion size

EXAM I COURSE TFY4310 MOLECULAR BIOPHYSICS December Suggested resolution

Atoms, electrons and Solids

Interactions of Flexible Macromolecules with Surfaces and Their Role in Viral Assembly

Origin of the Electrophoretic Force on DNA in Nanopores. Biological and Soft Systems - Cavendish Laboratory

UNIVERSITY OF MISSOURI-COLUMBIA PHYSICS DEPARTMENT. PART I Qualifying Examination. January 20, 2015, 5:00 p.m. to 8:00 p.m.

Chapter 21 Chapter 23 Gauss Law. Copyright 2014 John Wiley & Sons, Inc. All rights reserved.

Mansfield Independent School District AP Physics C: Electricity and Magnetism Year at a Glance

3/22/2016. Chapter 27 Gauss s Law. Chapter 27 Preview. Chapter 27 Preview. Chapter Goal: To understand and apply Gauss s law. Slide 27-2.

Roland R. Netz Max-Planck Institute for Colloids and Interfaces, Potsdam, Germany

Effect of Polyelectrolyte Adsorption on Intercolloidal Forces

Lecture 6. NONELECTROLYTE SOLUTONS

Physics of RecA-mediated homologous recognition

8.333: Statistical Mechanics I Re: 2007 Final Exam. Review Problems

Chapter 1. Basic Concepts. 1.1 Trajectories

Chapter 19. Gene creatures, Part 1: viruses, viroids and plasmids. Prepared by Woojoo Choi

Chapter 8. Chemical Bonding: Basic Concepts

Section B. Electromagnetism

Introduction to Polymer Physics

Definition of Matter. Subatomic particles 8/20/2012

Experimental Soft Matter (M. Durand, G. Foffi)

PHYSICS. Chapter 24 Lecture FOR SCIENTISTS AND ENGINEERS A STRATEGIC APPROACH 4/E RANDALL D. KNIGHT

Chapter (2) Gauss s Law

CONDUCTORS + CAPACITORS

I. Multiple Choice Questions (Type-I)

AP Physics C. Magnetism - Term 4

Nanomechanical Forces Generated by Surface Grafted DNA

Lecture 5: Electrostatic Interactions & Screening

(a) What are the probabilities associated with finding the different allowed values of the z-component of the spin after time T?

Measurements of interaction forces in (biological) model systems

3 Chapter. Gauss s Law

Polymers. Hevea brasiilensis

BIOCHEMISTRY GUIDED NOTES - AP BIOLOGY-

Amorphous Polymers: Polymer Conformation Laboratory 1: Module 1

Chemical bonding in solids from ab-initio Calculations

Single molecule force spectroscopy reveals a highly compliant helical

Problem Set Number 01, MIT (Winter-Spring 2018)

Atomic and molecular interactions. Scanning probe microscopy.

) is the interaction energy between a pair of chain units in the state ψ i 1

Transcription:

IITS: Statistical Physics in Biology Assignment # 3 KU Leuven 5/29/2013 Coulomb Interactions & Polymers 1. Flory Theory: The Coulomb energy of a ball of charge Q and dimension R in d spacial dimensions scales as E c Q2 R d 2. The proportionality coefficient depends on the exact shape and charge distribution; details that are not relevant to our intended scaling analysis. (a) For a charged polymer of length N, estimate the dependence of R on Q and N, by balancing the above Coulomb energy with the entropy associated with confining the polymer to a sie R. (Follow the Flory reasoning for selfavoiding polymers.) (b) For a polyelectrolyte in which Q N, find the Flory exponent ν F in the scaling relation R N ν F. Identify the upper critical dimension d u above which ν = 1/2 (the Coulomb interaction is irrelevant), and the lower critical dimension d F u below which ν F = 1 (the polymer is fully stretched). (c) Unlike in the case of selfavoiding walks, the Flory estimate is a rather poor description for charged polymers. In fact, it can be shown that the exact value of the swelling exponent for uniformly changed polymers is ν = 2/(d 2). Identify the correct upper and lower critical dimensions from this formula. Note that a uniformly charged polymer in three dimensions is fully stretched. (d) A polyampholyte is a heteropolymer with charged monomers of both signs. If the charges are randomly and independently chosen to be positive or negative, we expect Q 2 N. What is the Flory estimate of the swelling exponent in this case? 2. The Manning Transition: When ionic polymers (polyelectrolytes) such as DNA are immersed in water, the smaller charged counterions go into solution, leaving behind an oppositely charged polymer. Because of the electrostatic repulsion of the charges left behind, the polymer is stretched, and shall be modeled as a cylinder of radius a and length L, as depicted in the figure. While thermal fluctuations tend to make the ions wander about in the solvent, electrostatic attractions favor their return and condensation on the polymer. The potential due to a uniform linear charge density is logarithmic, and assuming that the counterions have valence (chrage e), their potential energy is given by V = 2e 2 n N ln i=1 ( ri ). a Here, n is the linear density and r i is the radial coordinate of the i th particle. Note that the Coulomb repulsions between the counterions have been left out. 1

R 2a + + + + h r + L (a) For a cylindrical container of radius R, show that at a temperature T, the canonical partition function Z has the form [ ] R 2(1 ζ) a 2(1 ζ) N Z = (constant), 2(1 ζ) and give the value of ζ. (b) Calculate the probability distribution function p(r) for the radial position of a counterion, and its first moment r, the average radial position of a counterion. (c) The behavior of the results calculated above in the limit of R a is very different at high and low temperatures. Identify the transition temperature, and characterie the nature of the two phases. In particular, how does r depend on R and a in each case? (d) Calculate the pressure exerted by the counterions on the wall of the container, in the limit R a, at all temperatures. (e) According to Manning, at low temperatures just enough counterions reattach to the polymer to reduce its charge density such that the value of ζ stays at 1. Along a fully ionied double stranded DNA, unit (negative) charges occur at a separation of b = 1.7Å. Use the Manning reasoning to calculate the fraction of this charge that is neutralied by salt counterions in solutions of either Na Cl or Mg Cl 2. (The Bjerrum length in water is l B = e 2 /(ǫk B T) 7Å.) 3. Packaging DNA in a phage: After an infected bacterium has duplicated the DNA and coat of an infecting phage, a new phage is assembled with the aid of protein motors. In the case of bacteriophage φ29, a 20,000 base pair dsdna has to be packaged in a capsid, which is a cylinder of radius r = 42nm and height h = 47nm. Inside the capsid the DNA is arranged like a spool, first winding in a helical shell next to the wall, and then forming successively tighter shells moving inwards. A typical separation between strands in this 2

structure is 2.3nm. Single molecule experiments have shown that the work required to pack the DNA in the capsid is approximately 10 5 k B T at room temperature (T = 300 o K). In the following, use order of magnitude estimates to determine what sets this energy scale. (a) Estimate the entropy of the DNA in solution, using a persistence length of l P 50nm. Can the loss of this entropic free energy account for the work of packaging? (b) Estimate the energy cost of bending DNA into the helical form found in the capsid. (Express the rigidity parameter κ in terms of the persistence length l P.) Is bending energy a significant fraction of the overall work of packaging? (c) Estimate the electrostatic energy of DNA in the capsid: Assume unit charges along the DNA at a spacing of b 0.17nm, which interact through a Debye Hückel potential of screening length λ 1nm, with charges on nearby strands (separations of around 2nm). Can electrostatic energies account for the work of packaging? Here are a couple of articles on the packaging of DNA in a phage: P. K. Purohit, M. M. Inamdar, P. D. Grayson, T. M. Squires, J. Kondev, and R. Phillips, Forces during Bacteriophage DNA Packaging and Ejection Biophys. J., February1, 2005; 88(2): 851 866. (http://www.biophysj.org/cgi/reprint/88/2/851); and S. Tlil, J. T. Kindt, W. M. Gelbart, and A. BenShaul, Forces and Pressures in DNA Packaging and Release from Viral Capsids Biophys. J., March1,2003; 84(3): 1616 1627. (http://www.biophysj.org/cgi/reprint/84/3/1616). 4. Charged membranes: In class, we solved the Poisson Boltmann for a flat membrane of uniform charge density σ, with a neutraliing background of counterions of charge e. (a) Extend the solution to counterions of charge e, and compute their density at a distance y from the membrane. (b) There is an overall constant of proportionality that can be fixed by examining the electric field at the charged surface. Plot the electric field as a function of y. (c) Check the overall neutrality of the system by integrating over the density of counterions. (d) Calculate the selfconsistent potential and charge density between two uniformly charged plates. (Each plate has uniform charge density σ, the neutraliing counterions have charge e, and the plates are separated by L.) (Optional) (e) Solve the Poisson Bolmann equation around a cylinder of radius a and charge density n = e/b. (Hint: By changing variables to x = ln(r/a) and ψ = βeφ 2x, you should be able to reduce the two dimensional problem to the already solved one dimensional case.) Can you make connections to the results in problem 2 on Manning condensation? 5. Bending a charged polymer: As indicated in the figure below, bending a polymer reduces the distances between its monomers. (a) For two monomers which are at a distance d mn = b m n when the polymer is straight, compute the change δd mn (R), when the polymer is bend into a circle of radius R d mn. 3

(b) Assume that unit charges at each monomer interact through the Debye potential V(d) = k B Tl B e d/λ d, where l B and λ and the Bjerrum and screening lengths, respectively. Compute the change in this pairwise energy if the distance is changed from d to d+δd. (c) Show that bending increases the energy of the charged polymer by an amount proportional to L/R 2, where L = Nb is the total length of the polymer. (d) The overall bending modulus for a charged polymer can be written as κ = κ b +κ e, where κ b is the cost of deforming the backbone, while κ e comes from the additional electrostatic energy. Compute κ e using the model explored in the previous parts. (e) Is electrostatic energy a significant component of the cost of bending a double stranded DNA? (For DNA in water, b.17nm, l B.7nm, λ 1nm, and l P 50nm. What about singlestranded DNA or RNA?) 6. Bending a charged membrane: Consider a membrane with a uniform charge density σ immersed in a solution with salt ions. Assuming that the charges interact through a Debye Hückel potential with screening length λ, estimate the electrostatic contribution to the bending rigidity κ? (Follow the steps in the previous problem for a polymer.) 7. Force/extension of linear polymers: Using optical tweeers, it is now possible to pull on the two ends of a single molecule. (Actually the tweeers pull on latex balls that are attached to the ends of the polymer; a complication that we shall ignore.) In the presence of the force F pulling on the ends of the polymer, there is an additional energy term δe = F R, 4

where R = r N r 1 is the end to end distance (between the first and N th monomers) of the chain. (a) For an ideal polymer, the number of configurations with an end to end distance of R is given by the usual Gaussian formula ( ) ) Ω N R g N = exp ( 3R2. (2πNa 2 3/2 /3) 2Na 2 By integrating the Boltmann weight over all R, calculate the (Gibbs) partition function Z(N,F,T) at a temperature T. Using this result, obtain the mean extension R F = k B T lnz/ F along the direction of the force F. (b) For other cases in which Ω N does not have a simple form (such as for selfavoiding polymers), it is still possible to obtain the linear response) of the polymer to small force. To this end, expand the Boltmann weight exp( F R/kB T to second order in F, and hence show that R F = 1 R 2 3k B T F 0 +O(F3 ), where R 2 0 is the mean end to end squared distance of the polymer in the absence of the force. (c) Dimensional analysis suggests that quite generally the extension force curve for polymers should have the form ( R F F ) R 2 = Φ 0. R2 0 k B T The left hand side is a dimensionless extension; on the right hand side a dimensionless combination involving the force appears as the argument of an unknown function Φ. At large forces F, the polymer becomes stretched such that R f N. For selfavoiding polymers R2 0 an ν with ν 0.59. Use these facts to deduce a nonlinear behavior R F F λ for the extension at large force, and give the value of the exponent λ. 8. Force/extension of Sliplinked polymer: Consider a polymer with a sliplink that can slide along it, but that cannot fall off its ends, as depicted in the figure. The sliplink constrains two monomers to be at the same location in space (e.g. monomers m and m+n at R, as in the figure). (a)assume thatthepolymer isanideal randomwalk, such thatthenumber ofconfigurations of each segment is given by a formula similar to part (a) in problem 1 above. As before, assume that the ends of the polymer are pulled apart by a force F. Integrate over the position vectors R and R, to get the partition function, and hence obtain R F = a2 3k B T (N n F )F, 5

m, m+ n 1 R R N where n F is the mean sie of the loop. Note that the force is carried by a backbone that excludes the loop. (Quite generally, the manner in which the force is transmitted through a Gaussian polymer network is quite similar to the way that current goes through a resistor network.) (b) Show that for small force, n F N, while for large F, it is reduced to ero (or a small sie determined by microscopic considerations). Is the force extension curve linear in the presence of a sliplink? 9. Overstretching DNA: In standard (B from) DNA the basepairs stack in spiral fashion at separation of 3.4Å. As indicated in the following figure [from S. B. Smith, Y. Cui, C. Bustamante, Science 271, 795 (1996), and http://alice.berkeley.edu/ steve/dnastr.html], pulling on DNA with optical tweeers causes it to greatly stretch at forces of around 65±5pN. 6

(a) One interpretation is that this represents a transition to a new structure of overstretched DNA, in which the separation of bases has increased to 5.8Å. As a very simple model of this putative state consider DNA as a one dimensional chain in which each unit can either be in the regular form of sie 3.4Å, or in the stretched form of sie 5.8Å. Assume that an energy U is required to change the regular form to the stretched form. For this part of the problem ignore the three dimensional orientations of each segment, and assume that the state of each element is independent of its neighbors. Calculate the length L(F,T) for this model when pulled by a force F at a temperature T. (b) Compare the result from part (a) to the experimental figure, and thus estimate the parameter U from the data in the above model from experiments. Is the width of the transition region in F consistent with the assumptions of the model. (c) Now consider a more realistic model in which neighboring elements tend to be in the same state. Would this lead to a sharpening or widening of the transition region in F? Suggested reading: Chapter 7 of Biological Physics by Philip Nelson. 7