. Compute the following limits.

Similar documents
Section 2.1 The Definition of the Derivative. We are interested in finding the slope of the tangent line at a specific point.

Main Points: 1. Limit of Difference Quotients. Prep 2.7: Derivatives and Rates of Change. Names of collaborators:

MAT 145. Type of Calculator Used TI-89 Titanium 100 points Score 100 possible points

REVIEW LAB ANSWER KEY

1 Lecture 13: The derivative as a function.

Introduction to Derivatives

Exam 1 Review Solutions

Continuity and Differentiability Worksheet

Key Concepts. Important Techniques. 1. Average rate of change slope of a secant line. You will need two points ( a, the formula: to find value

DEFINITION OF A DERIVATIVE

2.11 That s So Derivative

1. State whether the function is an exponential growth or exponential decay, and describe its end behaviour using limits.

Tangent Lines-1. Tangent Lines

The Derivative as a Function

Section 15.6 Directional Derivatives and the Gradient Vector

Bob Brown Math 251 Calculus 1 Chapter 3, Section 1 Completed 1 CCBC Dundalk

MVT and Rolle s Theorem

f a h f a h h lim lim

Differentiation Rules and Formulas

(a) At what number x = a does f have a removable discontinuity? What value f(a) should be assigned to f at x = a in order to make f continuous at a?

MATH CALCULUS I 2.1: Derivatives and Rates of Change

The Derivative The rate of change

Calculus I Practice Exam 1A

Higher Derivatives. Differentiable Functions

Derivatives. By: OpenStaxCollege

MAT 1339-S14 Class 2

Function Composition and Chain Rules

Lab 6 Derivatives and Mutant Bacteria

2.1 THE DEFINITION OF DERIVATIVE

Calculus I Homework: The Derivative as a Function Page 1

Name: Answer Key No calculators. Show your work! 1. (21 points) All answers should either be,, a (finite) real number, or DNE ( does not exist ).

1. Consider the trigonometric function f(t) whose graph is shown below. Write down a possible formula for f(t).

MATH 150 TOPIC 3 FUNCTIONS: COMPOSITION AND DIFFERENCE QUOTIENTS

Section 3: The Derivative Definition of the Derivative

Polynomial Functions. Linear Functions. Precalculus: Linear and Quadratic Functions

Lesson 4 - Limits & Instantaneous Rates of Change

Continuity. Example 1

Lesson 6: The Derivative

lim 1 lim 4 Precalculus Notes: Unit 10 Concepts of Calculus

Time (hours) Morphine sulfate (mg)

Click here to see an animation of the derivative

= h. Geometrically this quantity represents the slope of the secant line connecting the points

Combining functions: algebraic methods

Section 2.7 Derivatives and Rates of Change Part II Section 2.8 The Derivative as a Function. at the point a, to be. = at time t = a is

1 The concept of limits (p.217 p.229, p.242 p.249, p.255 p.256) 1.1 Limits Consider the function determined by the formula 3. x since at this point

How to Find the Derivative of a Function: Calculus 1

LIMITS AND DERIVATIVES CONDITIONS FOR THE EXISTENCE OF A LIMIT

Some Review Problems for First Midterm Mathematics 1300, Calculus 1

NUMERICAL DIFFERENTIATION. James T. Smith San Francisco State University. In calculus classes, you compute derivatives algebraically: for example,

THE IDEA OF DIFFERENTIABILITY FOR FUNCTIONS OF SEVERAL VARIABLES Math 225

Test 2 Review. 1. Find the determinant of the matrix below using (a) cofactor expansion and (b) row reduction. A = 3 2 =

We name Functions f (x) or g(x) etc.

MTH-112 Quiz 1 Name: # :

Derivatives and Rates of Change

1 Limits and Continuity

Math 124. Section 2.6: Limits at infinity & Horizontal Asymptotes. 1 x. lim

. h I B. Average velocity can be interpreted as the slope of a tangent line. I C. The difference quotient program finds the exact value of f ( a)

5.1 We will begin this section with the definition of a rational expression. We

The derivative of a function f is a new function defined by. f f (x + h) f (x)

Notes: DERIVATIVES. Velocity and Other Rates of Change

2.2 Derivative. 1. Definition of Derivative at a Point: The derivative of the function f x at x a is defined as

3.4 Worksheet: Proof of the Chain Rule NAME

SECTION 1.10: DIFFERENCE QUOTIENTS LEARNING OBJECTIVES

2.3 Algebraic approach to limits

Practice Problem Solutions: Exam 1

Math 34A Practice Final Solutions Fall 2007

The derivative function

y = 3 2 x 3. The slope of this line is 3 and its y-intercept is (0, 3). For every two units to the right, the line rises three units vertically.

Section 3.1: Derivatives of Polynomials and Exponential Functions

Section 2: The Derivative Definition of the Derivative

Average Rate of Change

2.3 More Differentiation Patterns

1 2 x Solution. The function f x is only defined when x 0, so we will assume that x 0 for the remainder of the solution. f x. f x h f x.

UNIVERSITY OF MANITOBA DEPARTMENT OF MATHEMATICS MATH 1510 Applied Calculus I FIRST TERM EXAMINATION - Version A October 12, :30 am

2.8 The Derivative as a Function

Differential Calculus: Differentiation (First Principles, Rules) and Sketching Graphs (Grade 12) *

Function Composition and Chain Rules

5. (a) Find the slope of the tangent line to the parabola y = x + 2x

MA119-A Applied Calculus for Business Fall Homework 4 Solutions Due 9/29/ :30AM

A.P. CALCULUS (AB) Outline Chapter 3 (Derivatives)

Math 1210 Midterm 1 January 31st, 2014

1. Questions (a) through (e) refer to the graph of the function f given below. (A) 0 (B) 1 (C) 2 (D) 4 (E) does not exist

10 Derivatives ( )

Mathematics 5 Worksheet 11 Geometry, Tangency, and the Derivative

Differential Calculus (The basics) Prepared by Mr. C. Hull

JANE PROFESSOR WW Prob Lib1 Summer 2000

4. The slope of the line 2x 7y = 8 is (a) 2/7 (b) 7/2 (c) 2 (d) 2/7 (e) None of these.

Precalculus Test 2 Practice Questions Page 1. Note: You can expect other types of questions on the test than the ones presented here!

Exam 1 Solutions. x(x 2) (x + 1)(x 2) = x

Mathematics 123.3: Solutions to Lab Assignment #5

Chapter 1 Functions and Graphs. Section 1.5 = = = 4. Check Point Exercises The slope of the line y = 3x+ 1 is 3.

3.1 Extreme Values of a Function

Finding and Using Derivative The shortcuts

1. Which one of the following expressions is not equal to all the others? 1 C. 1 D. 25x. 2. Simplify this expression as much as possible.

158 Calculus and Structures

Derivatives of Exponentials

Chapter 2. Limits and Continuity 16( ) 16( 9) = = 001. Section 2.1 Rates of Change and Limits (pp ) Quick Review 2.1

Solutions to the Multivariable Calculus and Linear Algebra problems on the Comprehensive Examination of January 31, 2014

1 1. Rationalize the denominator and fully simplify the radical expression 3 3. Solution: = 1 = 3 3 = 2

3.4 Algebraic Limits. Ex 1) lim. Ex 2)

Transcription:

Today: Tangent Lines and te Derivative at a Point Warmup:. Let f(x) =x. Compute te following limits. f( + ) f() (a) lim f( +) f( ) (b) lim. Let g(x) = x. Compute te following limits. g(3 + ) g(3) (a) lim g( 5+) g( 5) (b) lim Answers: (a), (b) 8; (a) 9,(b) 5

Recall: Average velocity 5 Te average velocity from t = t to t = t is cange in distance avg velocity = cange in time = slope of secant line 4 3 0. 0.4 0.6 0.8 Plot position f versus time t: y = f(t) f(a) f(a+) a a+ Pick two points on te curve (a, f(a)) and (b, f(b)). Rewrite b = a +. Slope of te line connecting tem: f(a + ) avg velocity = m = f(a) Te smaller is, te more useful m is! di erence quotient

Te di erence quotient (average velocity) of te curve y = f(x) at x = a is f(a + ) avg velocity = f(a). Te slope (instantaneous velocity) of te curve y = f(x) at te point (a, f(a)), calledtederivative of f(x) at x = a, iste number f 0 f(a + ) f(a) (a) =lim (provided te limit exists). Te tangent line ` to te curve at (a, f(a)) is te line troug (a, f(a)) wit tis slope: ` : y f(a) =m(x a), were m = f 0 (a). (Recall point-slope form: y y 0 = m(x x 0 ).)

Te slope (instantaneous velocity) of te curve y = f(x) at te point (a, f(a)), calledtederivative of f(x) at x = a, iste number f 0 f(a + ) f(a) (a) =lim (provided te limit exists). Recall te warmup:. Let f(x) =x. Compute te following limits. (a) lim!0 f( + ) f() (b) lim!0 f( +) f( ) = slope at x = = 4 slope at x = 7 6 5 4 3 blue line: y = (x ) red line: y 4= 4(x + ) -5-4 -3 - - 3 4 - Te slope (instantaneous velocity) of te curve y = f(x) at te point (a, f(a)), calledtederivative of f(x) at x = a, iste number f 0 f(a + ) f(a) (a) =lim (provided te limit exists). Recall te warmup:. Let g(x) = x. Compute te following limits. (a) lim!0 g(3 + ) g(3) (b) lim!0 g( 5+) g( 5) = /9 slope at x =3 = /5 slope at x = 5-9 -8-7 -6-5 -4-3 - - 3 4 - blue line: y 3 = 9 (x 3) red line: y + 5 = (x + 5) 5 -

You try: For eac of te following examples... (a) Compute f 0 (a) using te formula f 0 f(a + ) f(a) (a) =lim. (b) Compute te equation for te tangent line to (a, f(a)) using point-slope form. (c) Sketc y = f(x) near x = a and te line you computed in part (b) on te same set of axes to ceck tat your answers make sense.. f(x) =x 3 at a =0, a =,anda =.. f(x) = p x at a =and a =4. 3. f(x) =sin(x) at a =0, a = /4 and a = /. [For 3, recall sin( + lim!0 sin( )/ =.] )=sin( ) cos( ) + cos( )sin( ) and - - - - -3 3 4 5 6 7-4 -5-6 -7-4 -3 - - 3 4 - -8-9

Wen can we take derivatives? Not all functions ave derivatives at all places. Before calculating f 0 (a), firstask... () Is f(x) defined at x = a? For example, even if it looks like you could draw a tangent line, if tere s a ole, f 0 (a) does not exist a NO DERIVATIVE! (It s tempting to say f 0 (a) exists ere in part because f(x) as a continuous extension at a.) Wen can we take derivatives? Not all functions ave derivatives at all places. Before calculating f 0 (a), firstask... () Is f(x) continuous at x = a? For example, even if it looks like you could draw a tangent line, if tere s a jump, f 0 (a) does not exist! a NO DERIVATIVE! (Try drawing just one line tat is tangent to tat isolated point. It s tempting to say f 0 (a) exists ere in part because f(x) as a removable discontinuity at a.)

Wen can we take derivatives? Not all functions ave derivatives at all places. Before calculating f 0 (a), firstask... () Is f(x) continuous at x = a? Again, even if te slope looks te same from te left and from te rigt, if tere s a discontinuity, f 0 (a) does not exist! a NO DERIVATIVE! Wen can we take derivatives? Not all functions ave derivatives at all places. Before calculating f 0 (a), firstask... (3) Is tere a corner at x = a? Next we ll explore ow to find tese algebraically, but if tere s asarpcorneratx = a, ten f 0 (a) does not exist! a NO DERIVATIVE! (Try drawing just one line tat is tangent to tat corner)

Wat s wrong wit corners? You try: Let f(x) = ( x x<, x + x. (a) Verify tat f(x) is continuous at x =. (Compute lim x! f(x), lim x! + f(x), andf(), and compare.) (b) Sketc a grap of f(x). (c) Estimate (ok to use a calculator), and ten calculate te rigt sided derivative. (d) Estimate (ok to use a calculator), and ten calculate te left sided derivative. (e) Compare your answers to (c) and (d), and explain wy f( + ) f() lim does not exist. Explain wy f 0 () does not exist. Estimate te rigt-sided derivative: f() = f( + ) f( + ) f() / /0 f(+) f() Compute te rigt-sided derivative: f( + ) f() lim =!0 + Estimate te left-sided derivative: f() = f( + ) f( + ) f() / /0 Compute te rigt-sided derivative: f( + ) f() lim = f(+) f()