March Algebra 2 Question 1 If the statement is always true for the domain, assign that part a 3. If it is sometimes true, assign it a 2. If it is never true, assign it a 1. Your answer for this question is the sum of the assigned values. A. (x 3) & = (3 x) &, x belongs to the real numbers. B. 1 + 3 + 5 + + (2n 1) = n &, n belongs to the natural numbers. C. (x 1) & = x & + 1, x belongs to the real numbers. D. &./. = 2x, x belongs to the real numbers. E. x 01 = x 23, x belongs to the real numbers. March Algebra 2 Question 1 If the statement is always true for the domain, assign that part a 3. If it is sometimes true, assign it a 2. If it is never true, assign it a 1. Your answer for this question is the sum of the assigned values. A. (x 3) & = (3 x) &, x belongs to the real numbers. B. 1 + 3 + 5 + + (2n 1) = n &, n belongs to the natural numbers. C. (x 1) & = x & + 1, x belongs to the real numbers. D. &./. = 2x, x belongs to the real numbers. E. x 01 = x 23, x belongs to the real numbers.
March Algebra 2 Question 2 Below are five separate columns. Find the least solution in each column. Add up the least solution from each column for your final answer, and leave your answer as a mixed number. Column 1 Column 2 Column 3 5 log 7 (6B 10) = 10 9E & 51E = 30 1 4 @2 1 5 F@ 10 7 = 13 14 6(A 8) = 40 8A 4( 17 3A) & 0 9 = 55 2(5T 8) & E = 8 V 5 2V 3 = 7V + 2V log GE (L & + 8L) = log GE (6 + 3L) U 0 + 6U & + 5U = 0 Column 4 Column 5 4 N & 16 = 4N& 7N + 3 N & 16 1 N + 4 K 1 625 L 0M = 25 55L & + 28L 16 = 5L & T 0 3T = 2T & + 6 7S 4 = 3 125 0P&Q = 625 March Algebra 2 Question 2 Below are five separate columns. Find the least solution in each column. Add up the least solution from each column for your final answer, and leave your answer as a mixed number. Column 1 Column 2 Column 3 5 log 7 (6B 10) = 10 9E & 51E = 30 1 4 @2 1 5 F@ 10 7 = 13 14 6(A 8) = 40 8A 4( 17 3A) & 0 9 = 55 2(5T 8) & E = 8 V 5 2V 3 = 7V + 2V log GE (L & + 8L) = log GE (6 + 3L) U 0 + 6U & + 5U = 0 Column 4 Column 5 4 N & 16 = 4N& 7N + 3 N & 16 1 N + 4 K 1 625 L 0M = 25 55L & + 28L 16 = 5L & T 0 3T = 2T & + 6 7S 4 = 3 125 0P&Q = 625
f(x) = (3x + 2) 0 g(x) = ( 2x 1) 2 h(x) = K2x 1 x L E March Algebra 2 Question 3 j(x) = ((x + 1) & + 1) & When f(x) g(x) + h(x) j(x) is in standard form, what is the sum of its coefficients? f(x) = (3x + 2) 0 g(x) = ( 2x 1) 2 h(x) = K2x 1 x L E March Algebra 2 Question 3 j(x) = ((x + 1) & + 1) & When f(x) g(x) + h(x) j(x) is in standard form, what is the sum of its coefficients?
March Algebra 2 Question 4 Below are several functions. The expression below the table is a composition of 2, as in r Ks XtZu(2)\]L. Using four different functions from the table, complete the statement below so it makes a true statement by filling in the blanks with the missing function letters. For the answer, I want you to write the expression with the blanks filled in. 3 C(x) = 2x + 5 + 3 A(x) = 4 x 2 + 2 R(x) = 1 4 x E(x) = 3(4). + 8 S(x) = 1 2 x + 2 3 (_ _ _ _)(2) = 30 March Algebra 2 Question 4 Below are several functions. The expression below the table is a composition of 2, as in r Ks XtZu(2)\]L. Using four different functions from the table, complete the statement below so it makes a true statement by filling in the blanks with the missing function letters. For the answer, I want you to write the expression with the blanks filled in. 3 C(x) = 2x + 5 + 3 A(x) = 4 x 2 + 2 R(x) = 1 4 x E(x) = 3(4). + 8 S(x) = 1 2 x + 2 3 (_ _ _ _)(2) = 30
March Algebra 2 Question 5 f(x) is an invertible function whose domain is all real numbers. Below is a table with some values for f(x). x 1 2 4 8 16 f(x) 4 1 8 2 16 A = f PG Zf(64)\ B = f PG Zf f(2)\ C = f PG (8) D = fzf(2) f(1)\ What is x, if 2. = A B C D? March Algebra 2 Question 5 f(x) is an invertible function whose domain is all real numbers. Below is a table with some values for f(x). x 1 2 4 8 16 f(x) 4 1 8 2 16 A = f PG Zf(64)\ B = f PG Zf f(2)\ C = f PG (8) D = fzf(2) f(1)\ What is x, if 2. = A B C D?
March Algebra 2 Question 6 Find A+B+C+D for the expressions below, for i = -1 A = i g, where W is the remainder when the polynomial x 0 + 2x 1 is divided by the binomial x + 3. B = i i, where X = 450! C = i l, where Y is the sum of the first 200 terms of the arithmetic sequence 3, 7, 11 D = i p, where Z is f(2,398,146), if f(n) = n & 8n + 15. March Algebra 2 Question 6 Find A+B+C+D for the expressions below, for i = -1 A = i g, where W is the remainder when the polynomial x 0 + 2x 1 is divided by the binomial x + 3. B = i i, where X = 450! C = i l, where Y is the sum of the first 200 terms of the arithmetic sequence 3, 7, 11 D = i p, where Z is f(2,398,146), if f(n) = n & 8n + 15.
March Algebra 2 Question 7 In the grid below, there are many factorable expressions. Factor them all into linear factors of the form (x + k), where k belongs to the set of complex numbers, then cross off any factors that occur more than once. Expand the ones that remain into standard polynomial form. For your answer, write the sum of the coefficients. Note: Factorizations can include imaginary numbers to reduce factorization to a linear factor. x & + 18 x 0 + 8x x 2 + 5x & + 4 x & + 3ix 2 x 2 16 x 2 + 26x & + 144 March Algebra 2 Question 7 In the grid below, there are many factorable expressions. Factor them all into linear factors of the form (x + k), where k belongs to the set of complex numbers, then cross off any factors that occur more than once. Expand the ones that remain into standard polynomial form. For your answer, write the sum of the coefficients. Note: Factorizations can include imaginary numbers to reduce factorization to a linear factor. x & + 18 x 0 + 8x x 2 + 5x & + 4 x & + 3ix 2 x 2 16 x 2 + 26x & + 144
March Algebra 2 Question 8 The ordered pair (3, 6) is a solution for the function f(x). Where would the point be transformed to for the function Af(Bx + C) + D where: A is equal to the maximum number of intersections a circle and a parabola can have in the Cartesian plane B is equal to X4 Ps /] 0 C is equal to log (10000000) D is equal to the maximum number of turning points a polynomial of degree nine could have. March Algebra 2 Question 8 The ordered pair (3, 6) is a solution for the function f(x). Where would the point be transformed to for the function Af(Bx + C) + D where: A is equal to the maximum number of intersections a circle and a parabola can have in the Cartesian plane B is equal to X4 Ps /] 0 C is equal to log (10000000) D is equal to the maximum number of turning points a polynomial of degree nine could have.
March Algebra 2 Question 9 If the equation is only even over the domain of the function, assign it a value of 2. If the equation is odd over the domain of the function only, assign it a value of 3. If it is neither even nor odd over the domain of the function, assign it a value of 5, and if it is both even and odd over the domain of the function, assign it a value of 7. When complete, add all of the numbers up and let me know what number you get! y = u x y = x 0 + x + 1 y = x x y = 10. log (x) y = x 0 + ux & y = ±w1 1 x & x = y 0 x & + 4y & = 36 y = 0 March Algebra 2 Question 9 If the equation is only even over the domain of the function, assign it a value of 2. If the equation is odd over the domain of the function only, assign it a value of 3. If it is neither even nor odd over the domain of the function, assign it a value of 5, and if it is both even and odd over the domain of the function, assign it a value of 7. When complete, add all of the numbers up and let me know what number you get! y = u x y = x 0 + x + 1 y = x x y = 10. log (x) y = x 0 + ux & y = ±w1 1 x & x = y 0 x & + 4y & = 36 y = 0
f(x) = x0 + 3x & 4x 12 x & 3x + 2 The y-intercept of this graph is located at (0, A). The removable discontinuity is located at (B, 2C). March Algebra 2 Question 10 What is the solution, written as a coordinate, to the following system of equations? Ax + By = C x Bx 3y = A f(x) = x0 + 3x & 4x 12 x & 3x + 2 The y-intercept of this graph is located at (0, A). The removable discontinuity is located at (B, 2C). March Algebra 2 Question 10 What is the solution, written as a coordinate, to the following system of equations? Ax + By = C x Bx 3y = A
March Algebra 2 Question 11 Let A be the solution set to the inequality x & 3x + 4 < 2 x 3. Let B be the x-interval over which the values of the function y = (x 2) 0 + 2(x 2) & + x are positive. What is A B, in interval notation? March Algebra 2 Question 11 Let A be the solution set to the inequality x & 3x + 4 < 2 x 3. Let B be the x-interval over which the values of the function y = (x 2) 0 + 2(x 2) & + x are positive. What is A B, in interval notation?
March Algebra 2 Question 12 Find A + B + C if: A = (F U N C T I O N)(2) B = (P A R A B O L A)(2) C = (N O N Z E R O)(2) A(x) = x + 1 B(x) = x 1 C(x) = x + 2 D(x) = x 2 E(x) = x + 1 F(x) = x 1 G(x) = x + 2 H(x) = x 2 I(x) = x + 1 J(x) = x 1 K(x) = x + 2 L(x) = x 2 M(x) = x & N(x) = x & 1 O(x) = x & + 1 P(x) = 2x + 1 Q(x) = 2x 1 R(x) = 2x + 2 S(x) = 2x 2 T(x) = x + 1 U(x) = x 1 V(x) = x + 2 W(x) = x 2 X(x) = x 0 Y(x) = 0.2x Z(x) = 2 March Algebra 2 Question 12 Find A + B + C if: A = (F U N C T I O N)(2) B = (P A R A B O L A)(2) C = (N O N Z E R O)(2) A(x) = x + 1 B(x) = x 1 C(x) = x + 2 D(x) = x 2 E(x) = x + 1 F(x) = x 1 G(x) = x + 2 H(x) = x 2 I(x) = x + 1 J(x) = x 1 K(x) = x + 2 L(x) = x 2 M(x) = x & N(x) = x & 1 O(x) = x & + 1 P(x) = 2x + 1 Q(x) = 2x 1 R(x) = 2x + 2 S(x) = 2x 2 T(x) = x + 1 U(x) = x 1 V(x) = x + 2 W(x) = x 2 X(x) = x 0 Y(x) = 0.2x Z(x) = 2
March Algebra 2 Question 13 Find A + B a = 2a PG + 1, a G = 1 G& A = a E b = b PG + 2b P& 3b P0, b G = b & = b 0 = 1 GE B = b G March Algebra 2 Question 13 Find A + B a = 2a PG + 1, a G = 1 G& A = a E b = b PG + 2b P& 3b P0, b G = b & = b 0 = 1 GE B = b G
March Algebra 2 Question 14 Consider the circle with the equation x & + y & + 8x 16y + 31 = 0. Find The product of A, B, and C if: The area of the circle is Aπ. The center of the circle is (B, C) March Algebra 2 Question 14 Consider the circle with the equation x & + y & + 8x 16y + 31 = 0. Find The product of A, B, and C if: The area of the circle is Aπ. The center of the circle is (B, C)
March Algebra 2 Question 15 What is the determinant of the matrix? 4 0 2 7 0 2 4 0 Œ 2 3 0 5 4 7 3 0 March Algebra 2 Question 15 What is the determinant of the matrix? 4 0 2 7 0 2 4 0 Œ 2 3 0 5 4 7 3 0