BACHELOR'S DEGREE PROGRAMME (BDP) Term-End Examination June, 2013 ELECTIVE COURSE : MATHEMATICS MTE-12 : LINEAR PROGRAMMING

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No. of Printed Pages : 12 MTE-12 BACHELOR'S DEGREE PROGRAMME (BDP) Term-End Examination June, 2013 ELECTIVE COURSE : MATHEMATICS MTE-12 : LINEAR PROGRAMMING Time : 2 hours Maximum Marks : 50 Weightage : 70% Note : Question no. 1 is compulsory. Do any four questions out of question no. 2 to 7. Use of Calculator is not allowed. 1. Which of the following statements are true and which are false? Give reasons for your answer. 5x2=10 (a) In a solution to a two - dimensional LPP the objective function can assume the same value at two distinct extreme points. CO (b) x1 =1, x2 = 1, x3 =1, x4 = 2, is a basic CO solution for the linear system. CD x1 + x 2 + X 3 = 3 2x1 + x2 + x4 =- 5. (c) An LPP may have a feasible solution even if an artificial variable appears at a positive level in the optimal iteration. MTE-12 1 P.T.O.

(d) (e) There may be balanced transportation models without any feasible solution. The addition of a constant to all the elements of a pay off matrix in a two - person zero - sum game can affect only the value of the game, not the optimal mix of the strategies. 2. (a) A diet for a sick person must contain at least 6 4000 units of vitamins, 50 units of minerals and 1400 Calories. Two foods A and B are available at a cost of 4 and 3 per unit respectively. If one unit of A contains 200 units of vitamins, 1 unit of mineral and 40 calories, and one unit of food B contains 100 units of vitamins, 2 units of minerals and 40 calories, find by graphical method, what combination of foods be used to have least (b) cost? If [31 [11 1 [ 4] 'A2 [ 2 _,A3=[4], a nd B= [ 1 4 then determine whether all possible basic solutions exist for the following set of equations [A i, A2, A3] X =B. 3. (a) For the following game, write the equivalent LPPs for solving the game. [ 2 3 1 1 4 MTE-12 2

(b) A Company has four plants P1, P2, P3, P4 6 from which it supplies to three markets M1, M2, and M3, Find the initial basic feasible solution using matrix minima method of transportation. schedule Data containing transportation cost, availabilities at every plant and requirements in the market is given below. P1 P2 P3 P4 Requirement (units) Market M1 1 2 1 4 30 Availability (units) M2 3 3 2 1 50 M3 4 2 5 9 20 20 40 30 10 Also, find the optional solution of the problem. 4. (a) Write the dual of the problem, 4 Min z =2xi + 5x3 s.t x1 +x2 > 2 + x2 + 6x3 6 - X2 ± 3X3 = 4 xi, x2, x3 >0. Your answer should contain atleast one artificial variable. MTE-12 3 P.T.O.

(b) Use principal of dominance, to reduce the 6 size of the following game and hence solve the game. 1 2 8 7 5 1 6 0 12 5. (a) Solve the following assignment problem. 5 I II III IV V A 2 9 2 7 1- B 6 8 7 6 1 C 4 6 5 3 1 D 4 2 7 3 1 E 5 3 9 5 1 (b) Solve the following game using the 5 graphical method : B:s strategy Al A's strategy A2 A3 B1 B2 3 4 2 5 2 8 6. (a) Consider problem of assigning four 5 operators to four machines. The assignment costs are given between. Operators I II III IV A 10 5 13 15 Machines B 3 9 18 3 C 1. 0 7 2 2 5 11 9 7 Formulate on LP model to determine an optimum assignment. MT E-12 4

(b) Show that the set 5 S = {(x, y) 5x2 +2y2 10} is convex. 7. (a) Solve by simplex method the following 6 Linear Programming Problem : Minimize z =xi 3x2 + 2x3 Subject to 3x1 x2 + 2x3 7 +4x2 12 +3x2 +8x3 10 x1, x2, x3 > 0. (b) Show that the vectors 4 1 1-1 al = 1,a2 = 1, a 3 = 1 1 1 2 are linearly independent. MTE-12 5 P.T.O.

Idcf) 3Crai chltighl-1 (Atift) ITN IT 2013 7f21.1.-12 TE 41(4qc114-1 : fluid 71A-4.-12 : WWW W)911-I-1 TITI7 : 2 Frrr - 3.710W-d7 3.TW : 50 TO' qv: 70% VE": 1 --(71,31 k-q mgri #. 2 4 7 UW T?: r4u 575- w7f-471 TI*77. WT-4 eh') 3-7TA. t I 1. f 14-1 f rl rod A- chl-r 2,1-ff t A 3T-AT? 5x2=10 311:14 titut q`lr,-r (a) TF fg-f-411-17[ LPP Sri, 3kvzr Lhol chi 4-11-1 31-6TE-fi tf -cri4 f-4-14 1T (b) tr-ut f9-*-174 x1 + x2 + x3=3 t I 2x1,X2 + = 5 x1=1, x2 =1, x3=1, x4 =2, -) 3T1. tl (c) LsrT4 T177* -14 TNA trffittit TaT -cr -97 LPP Orm cll t I MTE-12 7 P.T.O.

(d) fair.7frr-d t (e) rqogra-d -qp4 *Tr t 91-n-d-F t -14-7t 31--4T oh).,511s4 -ER a,i Hil PTP=4.111 #15Au1-1). 2. (a).7w t4t-{ 4) TFTT 4,44 *4-1 4000 c11.a 3-t)J,Z3-51-fd -4 50 r --4111 *1400 3-11-6-R A 3 B 9h4-R1: Z4-114-Vc17d4c T l 7:ifqA 14 200 t*--1 Ur-i7 riciul *40 -k-0)-t B 7t- loo 2f-*--r uf-9-7 claui *40 t 1)-R-171 faftcir -t-tt fic-f 'w1-f---7 ql 31-r-a4 t ft-tr #-4zT 4)1 T -4 ITT *44 1--4 1Jir? 3 1 (b) -Erfq Ai = [4, A2 = 2,A3= 6 111 41 B= [ 4 4 ttfffq-i-r7t-if-a- ri, Fp-friruct --11-11cboi, -ichiq t FQI 4-ITfaa 31-m-rt (vi t TIT -01 [A1, A2, A3,] X= B. 3. (a) F14--Irrirt.qd chl tr4 t r2 31 I [-1 1 MTE-12 8

(b) 7T oh 4--4 t TI 1 t#zfq P1, P2, P3, P4 t f t 4 r a1 i T M1, M2 *1\43 3 q-)1 t fqn chr i-rflii-w 317 frr-d c 1 71Icl -f1r I 6 Ttzr ct,1 1,1 31-raTzr*---dr tift-- 7 -a-4 -k 341- r-o--trorod t 341011chd1 P1 P2 P3 P4 ().47ATT M1 1 2 1 4 30 M2 3 3 2 1 50 M3 4 2 5 9 20 37-ffaTUT 20 40 30 10 () err r.7ātt `1ft 711c1 I 4. (a) F-1-iro cr f-ffr-- 171 4 z=2x1+5x3chi --Tic-ficbtur xi +x2 >2 2x1+x2 +6x3 6 x1 x2 +3x3 =4 xi, x2, x3 >0 371 t 37-R -14 l 3-Tvra---44-a -r -frairqvqt- t1 MTE-12 9 P.T.O.

(b) Fri RA ci t -f971-1,1 qr I 6 111 ci 4;1F,3i 4:-f.9m7 I 2 8 7 5 1 6 0 12 cf-)1 5. (a) F-14--irriF{_qd 5 I II III IV V A 2 9 2 7 1 B 6 8 7 6 1 C 4 6 5 3 1 D 4 2 7 3 1 E 5 3 9 5 1 (b) fqfq ql7t r-t 4-1 Fri ruct 40 c4 41 s3i I 5 Al A 1,-; Ifwi. A '2 A3 B 44Ti Bi B2-3 4 2 5 2 8 MTE-12 10

6. (a) uit c1ml't fr- 5 TITT-FErr (-111',4 f9-zr-d-a- t I I II III IV A 10 5 13 15 B 3 9 18 3 C 10 7 2 2 D 5 11 9 7 1 LP (b) Trli -zr 5 S = {(x, y) 5x2 + 2y2 10} at-9-zg t 7. (a) 1:14-16 Ac-r trffq-9- Tri,Rzzur T fqfq 6 z =xi 3x2 +2x3 cf-d 74f-T wr1---a- 3x1 x2 + 2x35_7 2x1 + 4x2.12 4x1 + 3x2 + 8x3.5_10 xi, x2, x3, > O. MTE-12 11 P.T.O.

(b) TqlN7 Tit'z41 4 1 1 1,a2 1,a3 = 1 1 1 2 f I MTE-12 12