Nontrivial solutions for fractional q-difference boundary value problems

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Electronic Journal of Qualitative Theory of Differential Equations 21, No. 7, 1-1; http://www.math.u-szeged.hu/ejqtde/ Nontrivial solutions for fractional q-difference boundary value problems Rui A. C. Ferreira Department of Mathematics Lusophone University of Humanities and Technologies 1749-24 Lisbon, Portugal November 21, 21 Abstract In this paper, we investigate the existence of nontrivial solutions to the nonlinear q-fractional boundary value problem (D α q y)(x) = f(x,y(x)), < x < 1, y() = = y(1), by applying a fixed point theorem in cones. Keywords: Fractional q-difference equations, boundary value problem, nontrivial solution. 21 Mathematics Subject Classification: 39A13, 34B18, 34A8. 1 Introduction The q-difference calculus or quantum calculus is an old subject that was first developed by Jackson [9, 1]. It is rich in history and in applications as the reader can confirm in the paper [6]. Email: ruiacferreira@ulusofona.pt EJQTDE, 21 No. 7, p. 1

The origin of the fractional q-difference calculus can be traced back to the works by Al-Salam [3] and Agarwal [1]. More recently, perhaps due to the explosion in research within the fractional calculus setting (see the books [13, 14]), new developments in this theory of fractional q-difference calculus were made, specifically, q-analogues of the integral and differential fractional operators properties such as q-laplace transform, q-taylor s formula [4, 15], just to mention some. To the best of the author knowledge there are no results available in the literature considering the problem of existence of nontrivial solutions for fractional q-difference boundary value problems. As is well-known, the aim of finding nontrivial solutions is of main importance in various fields of science and engineering (see the book [2] and references therein). Therefore, we find it pertinent to investigate on such a demand within this q-fractional setting. This paper is organized as follows: in Section 2 we introduce some notation and provide to the reader the definitions of the q-fractional integral and differential operators together with some basic properties. Moreover, some new general results within this theory are given. In Section 3 we consider a Dirichlet type boundary value problem. Sufficient conditions for the existence of nontrivial solutions are enunciated. 2 Preliminaries on fractional q-calculus Let q (, 1) and define [a] q = 1 qa 1 q, a R. The q-analogue of the power function (a b) n with n N is n 1 (a b) = 1, (a b) n = (a bq k ), n N, a, b R. More generally, if α R, then k= (a b) (α) = a α n= a bq n a bq α+n. Note that, if b = then a (α) = a α. The q-gamma function is defined by Γ q (x) = (1 q)(x 1), x R\{, 1, 2,...}, (1 q) x 1 EJQTDE, 21 No. 7, p. 2

and satisfies Γ q (x + 1) = [x] q Γ q (x). The q-derivative of a function f is here defined by (D q f)(x) = and q-derivatives of higher order by f(x) f(qx) (1 q)x, (D qf)() = lim x (D q f)(x), (D q f)(x) = f(x) and (Dn q f)(x) = D q(d n 1 q f)(x), n N. The q-integral of a function f defined in the interval [, b] is given by (I q f)(x) = f(t)d q t = x(1 q) f(xq n )q n, x [, b]. If a [, b] and f is defined in the interval [, b], its integral from a to b is defined by b a f(t)d q t = b n= f(t)d q t a f(t)d q t. Similarly as done for derivatives, it can be defined an operator I n q, namely, (I q f)(x) = f(x) and (In q f)(x) = I q(i n 1 q f)(x), n N. The fundamental theorem of calculus applies to these operators I q and D q, i.e., (D q I q f)(x) = f(x), and if f is continuous at x =, then (I q D q f)(x) = f(x) f(). Basic properties of the two operators can be found in the book [11]. We point out here four formulas that will be used later, namely, the integration by parts formula f(t)(d q g)td q t = [f(t)g(t)] t=x t= (D q f)(t)g(qt)d q t, and ( i D q denotes the derivative with respect to variable i) [a(t s)] (α) = a α (t s) (α), (1) td q (t s) (α) = [α] q (t s) (α 1), (2) sd q (t s) (α) = [α] q (t qs) (α 1). (3) EJQTDE, 21 No. 7, p. 3

Remark 2.1. We note that if α > and a b t, then (t a) (α) (t b) (α). To see this, assume that a b t. Then, it is intended to show that t α n= Let n N. We show that t aq n tα t aqα+n n= t bq n t bqα+n. (4) (t aq n )(t bq α+n ) (t bq n )(t aq α+n ). (5) Indeed, expanding both sides of the inequality (5) we obtain t 2 tbq α+n taq n + aq n bq α+n t 2 taq α+n tbq n + bq n aq α+n q n (aq α + b) q n (bq α + a) b a q α (b a) 1 q α. Since inequality (5) implies inequality (4) we are done with the proof. The following definition was considered first in [1] Definition 2.2. Let α and f be a function defined on [, 1]. The fractional q-integral of the Riemann Liouville type is (Iqf)(x) = f(x) and (I α q f)(x) = 1 (x qt) (α 1) f(t)d q t, α >, x [, 1]. The fractional q-derivative of order α is defined by (Dq f)(x) = f(x) and (Dq α f)(x) = (Dq m Iq m α f)(x) for α >, where m is the smallest integer greater or equal than α. Let us now list some properties that are already known in the literature. Its proof can be found in [1, 15]. Lemma 2.3. Let α, β and f be a function defined on [, 1]. Then, the next formulas hold: 1. (I β q Iα q f)(x) = (Iα+β q f)(x), 2. (D α q I α q f)(x) = f(x). The next result is important in the sequel. Since we didn t find it in the literature we provide a proof here. EJQTDE, 21 No. 7, p. 4

Theorem 2.4. Let α > and p be a positive integer. Then, the following equality holds: p 1 (Iq α Dp q f)(x) = (Dp q Iα q f)(x) x α p+k Γ q (α + k p + 1) (Dk qf)(). (6) k= Proof. Let α be any positive number. We will do a proof using induction on p. Suppose that p = 1. Using formula (3) we get: td q [(x t) (α 1) f(t)] = (x qt) (α 1) td q f(t) [α 1] q (x qt) (α 2) f(t). Therefore, (I α q D q f)(x) = 1 = [α 1] q (x qt) (α 1) (D q f)(t)d q t = (D q I α q f)(x) xα 1 f(). Suppose now that (6) holds for p N. Then, (Iq α Dq p+1 f)(x) = (Iq α DqD p q f)(x) = D p q = (D p qi α q D q f)(x) (x qt) (α 2) f(t)d q t + 1 [(x t)(α 1) f(t)] t=x t= p 1 k= [(D q I αq f)(x) xα 1 f() = (D p+1 q I α q f)(x) xα 1 p Γ q (α p) f() The theorem is proved. k=1 x α p+k Γ q (α + k p + 1) (Dk+1 q f)() ] p 1 x α p+k Γ q (α + k p + 1) (Dk+1 q f)() k= p x α (p+1)+k Γ q (α + k (p + 1) + 1) (Dk qf)() p = (Dq p+1 Iq α f)(x) x α (p+1)+k Γ q (α + k (p + 1) + 1) (Dk q f)(). k= EJQTDE, 21 No. 7, p. 5

3 Fractional boundary value problem We shall consider now the question of existence of nontrivial solutions to the following problem: subject to the boundary conditions (D α q y)(x) = f(x, y(x)), < x < 1, (7) y() =, y(1) =, (8) where 1 < α 2 and f : [, 1] R R is a nonnegative continuous function (this is the q-analogue of the fractional differential problem considered in [5]). To that end we need the following theorem (see [8, 12]). Theorem 3.1. Let B be a Banach space, and let C B be a cone. Assume Ω 1, Ω 2 are open disks contained in B with Ω 1, Ω 1 Ω 2 and let T : C (Ω 2 \Ω 1 ) C be a completely continuous operator such that Ty y, y C Ω 1 and Ty y, y C Ω 2. Then T has at least one fixed point in C (Ω 2 \Ω 1 ). Let us put p = 2. In view of item 2 of Lemma 2.3 and Theorem 2.4 we see that (Dq α y)(x) = f(x, y(x)) (Iα q D2 q I2 α q y)(x) = Iq α f(x, y(x)) y(x) = c 1 x α 1 + c 2 x α 2 1 (x qt) (α 1) f(t, y(t))d q t, for some constants c 1, c 2 R. Using the boundary conditions given in (8) we take c 1 = 1 1 (1 Γ q(α) qt)(α 1) f(t, y(t))d q t and c 2 = to get y(x) = 1 = 1 [ (1 qt) (α 1) x α 1 f(t, y(t))d q t 1 x (x qt) (α 1) f(t, y(t))d q t ( [x(1 qt)] (α 1) (x qt) (α 1)) f(t, y(t))d q t ] + [x(1 qt)] (α 1) f(t, y(t))d q t. EJQTDE, 21 No. 7, p. 6

If we define a function G by G(x, t) = 1 { (x(1 t)) (α 1) (x t) (α 1), t x 1, (x(1 t)) (α 1), x t 1, then, the following result follows. Lemma 3.2. y is a solution of the boundary value problem (7)-(8) if, and only if, y satisfies the integral equation y(x) = G(x, qt)f(t, y(t))d q t. Remark 3.3. If we let α = 2 in the function G, then we get a particular case of the Green function obtained in [16], namely, { t(1 x), t x 1 G(x, t) = x(1 t), x t 1. Some properties of the function G needed in the sequel are now stated and proved. Lemma 3.4. Function G defined above satisfies the following conditions: G(x, qt) and G(x, qt) G(qt, qt) for all x, t 1. (9) Proof. We start by defining two functions g 1 (x, t) = (x(1 t)) (α 1) (x t) (α 1), t x 1 and g 2 (x, t) = (x(1 t)) (α 1), x t 1. It is clear that g 2 (x, qt). Now, in view of Remark 2.1 we get, g 1 (x, qt) = x α 1 (1 qt) (α 1) x α 1 (1 q t x )(α 1) Moreover, for t (, 1] we have that x α 1 (1 qt) (α 1) x α 1 (1 qt) (α 1) =. xd q g 1 (x, t) = x D q [(x(1 t)) (α 1) (x t) (α 1) ] = [α 1] q (1 t) (α 1) x α 2 [α 1] q (x t) (α 2) ( = [α 1] q x [(1 α 2 t) (α 1) 1 t ) ] (α 2) x [ [α 1] q x α 2 (1 t) (α 1) (1 t) (α 2)], EJQTDE, 21 No. 7, p. 7

which implies that g 1 (x, t) is decreasing with respect to x for all t (, 1]. Therefore, g 1 (x, qt) g 1 (qt, qt), < x, t 1. (1) Now note that G(, qt) = G(qt, qt) for all t [, 1]. Therefore, by (1) and the definition of g 2 (it is obviously increasing in x) we conclude that G(x, qt) G(qt, qt) for all x, t 1. This finishes the proof. Let B = C[, 1] be the Banach space endowed with norm u = sup t [,1] u(t). Define the cone C B by C = {u B : u(t) }. Remark 3.5. It follows from the nonnegativeness and continuity of G and f that the operator T : C B defined by (Tu)(x) = G(x, qt)f(t, u(t))d q t, satisfies T(C) C and is completely continuous. For our purposes, let us define two constants ( 1 M = G(qt, qt)d q t), N = ( τ2 τ 1 ) 1 G (qt, qt)d q t, where τ 1 {, q m } and τ 2 = q n with m, n N, m > n. Our existence result is now given. Theorem 3.6. Let f(t, u) be a nonnegative continuous function on [, 1] [, ). If there exists two positive constants r 2 > r 1 > such that f(t, u) Mr 2, for (t, u) [, 1] [, r 2 ], (11) f(t, u) Nr 1, for (t, u) [τ 1, τ 2 ] [, r 1 ], (12) then problem (7)-(8) has a solution y satisfying r 1 y r 2. Proof. Since the operator T : C C is completely continuous we only have to show that the operator equation y = Ty has a solution satisfying r 1 y r 2. EJQTDE, 21 No. 7, p. 8

Let Ω 1 = {y C : y < r 1 }. For y C Ω 1, we have y(t) r 1 on [, 1]. Using (9) and (12), and the definitions of τ 1 and τ 2, we obtain (see page 282 in [7]), τ2 Ty = max G (x, qt) f(t, y(t))d q t Nr 1 G (qt, qt)d q t = y. x 1 τ 1 Let Ω 2 = {y C : y < r 2 }. For y C Ω 2, we have y(t) r 2 on [, 1]. Using (9) and (11) we obtain, Ty = max x 1 G (x, qt) f(t, y(t))d q t Mr 2 G (qt, qt) d q t = y. Now an application of Theorem 3.1 concludes the proof. References [1] R. P. Agarwal, Certain fractional q-integrals and q-derivatives, Proc. Cambridge Philos. Soc. 66 (1969), 365 37. [2] R. P. Agarwal, D. O Regan and P. J. Y. Wong, Positive Solutions of Differential, Difference and Integral Equations, Kluwer Acad. Publ., Dordrecht, 1999. [3] W. A. Al-Salam, Some fractional q-integrals and q-derivatives, Proc. Edinburgh Math. Soc. (2) 15 (1966/1967), 135 14. [4] F. M. Atici and P. W. Eloe, Fractional q-calculus on a time scale, J. Nonlinear Math. Phys. 14 (27), no. 3, 333 344. [5] Z. Bai and H. Lü, Positive solutions for boundary value problem of nonlinear fractional differential equation, J. Math. Anal. Appl. 311 (25), no. 2, 495 55. [6] Ernst T, The History of q-calculus and a New Method, U. U. D. M. Report 2:16, ISSN 111-3591, Department of Mathematics, Uppsala University, 2. [7] H. Gauchman, Integral inequalities in q-calculus, Comput. Math. Appl. 47 (24), no. 2-3, 281 3. EJQTDE, 21 No. 7, p. 9

[8] D. J. Guo and V. Lakshmikantham, Nonlinear Problems in Abstract Cones, Academic Press, Boston, MA, 1988. [9] Jackson F.H.: On q-functions and a certain difference operator. Trans. Roy Soc. Edin. 46, (198), 253-281. [1] Jackson F.H.: On q-definite integrals. Quart. J. Pure and Appl. Math. 41 (191), 193-23. [11] V. Kac and P. Cheung, Quantum Calculus, Springer, New York, 22. [12] M. A. Krasnosel skiĭ, Positive Solutions of Operator Equations, Translated from the Russian by Richard E. Flaherty; edited by Leo F. Boron, P. Noordhoff Ltd. Groningen, 1964. [13] K. S. Miller and B. Ross, An Introduction to the Fractional Calculus and Fractional Differential Equations, Wiley, New York, 1993. [14] I. Podlubny, Fractional Differential Equations, Academic Press, San Diego, CA, 1999. [15] P. M. Rajković, S. D. Marinković and M. S. Stanković, Fractional integrals and derivatives in q-calculus, Appl. Anal. Discrete Math. 1 (27), no. 1, 311 323. [16] M. El-Shahed and H. A. Hassan, Positive solutions of q-difference equation, Proc. Amer. Math. Soc. 138 (21), no. 5, 1733 1738. (Received August 4, 21) EJQTDE, 21 No. 7, p. 1