THEOREM OF OSELEDETS. We recall some basic facts and terminology relative to linear cocycles and the multiplicative ergodic theorem of Oseledets [1].

Similar documents
THE MULTIPLICATIVE ERGODIC THEOREM OF OSELEDETS

Lecture Notes Introduction to Ergodic Theory

Integration on Measure Spaces

Disintegration into conditional measures: Rokhlin s theorem

Problem: A class of dynamical systems characterized by a fast divergence of the orbits. A paradigmatic example: the Arnold cat.

THEOREMS, ETC., FOR MATH 515

Chapter 6. Integration. 1. Integrals of Nonnegative Functions. a j µ(e j ) (ca j )µ(e j ) = c X. and ψ =

The projectivity of C -algebras and the topology of their spectra

Functional Analysis I

Recall that if X is a compact metric space, C(X), the space of continuous (real-valued) functions on X, is a Banach space with the norm

CHILE LECTURES: MULTIPLICATIVE ERGODIC THEOREM, FRIENDS AND APPLICATIONS

l(y j ) = 0 for all y j (1)

Math 52H: Multilinear algebra, differential forms and Stokes theorem. Yakov Eliashberg

Part II Probability and Measure

LINKED ALTERNATING FORMS AND LINKED SYMPLECTIC GRASSMANNIANS

The following definition is fundamental.

arxiv: v2 [math.ag] 24 Jun 2015

HAMILTONIAN ACTIONS IN GENERALIZED COMPLEX GEOMETRY

I teach myself... Hilbert spaces

Exercise Solutions to Functional Analysis

TIME RESCALING OF LYAPUNOV EXPONENTS. Dedicated to Michael Rabinovich on the occasion of his 75th birthday. 1. Introduction.

SRB MEASURES FOR AXIOM A ENDOMORPHISMS

Finite-dimensional spaces. C n is the space of n-tuples x = (x 1,..., x n ) of complex numbers. It is a Hilbert space with the inner product

Math 4377/6308 Advanced Linear Algebra I Dr. Vaughn Climenhaga, PGH 651A HOMEWORK 3

YORK UNIVERSITY. Faculty of Science Department of Mathematics and Statistics MATH M Test #2 Solutions

ECE 275A Homework #3 Solutions

CHAPTER V DUAL SPACES

10. The ergodic theory of hyperbolic dynamical systems

PROBLEMS. (b) (Polarization Identity) Show that in any inner product space

Your first day at work MATH 806 (Fall 2015)

1/12/05: sec 3.1 and my article: How good is the Lebesgue measure?, Math. Intelligencer 11(2) (1989),

MATHS 730 FC Lecture Notes March 5, Introduction

Groups of Prime Power Order with Derived Subgroup of Prime Order

LECTURE 2: SYMPLECTIC VECTOR BUNDLES

On Equivariant Block Triangularization of Matrix Cocyles

6 Orthogonal groups. O 2m 1 q. q 2i 1 q 2i. 1 i 1. 1 q 2i 2. O 2m q. q m m 1. 1 q 2i 1 i 1. 1 q 2i. i 1. 2 q 1 q i 1 q i 1. m 1.

1 Math 241A-B Homework Problem List for F2015 and W2016

2 Lebesgue integration

3. (a) What is a simple function? What is an integrable function? How is f dµ defined? Define it first

Periodic approximation of exceptional Lyapunov exponents for sem

2) Let X be a compact space. Prove that the space C(X) of continuous real-valued functions is a complete metric space.

LECTURE VI: SELF-ADJOINT AND UNITARY OPERATORS MAT FALL 2006 PRINCETON UNIVERSITY

Final Exam Practice Problems Math 428, Spring 2017

These notes are incomplete they will be updated regularly.

6. Duals of L p spaces

LECTURE 3 MATH 261A. Office hours are now settled to be after class on Thursdays from 12 : 30 2 in Evans 815, or still by appointment.

Math Linear Algebra II. 1. Inner Products and Norms

Homogeneous para-kähler Einstein manifolds. Dmitri V. Alekseevsky

MATH 8253 ALGEBRAIC GEOMETRY WEEK 12

Ir O D = D = ( ) Section 2.6 Example 1. (Bottom of page 119) dim(v ) = dim(l(v, W )) = dim(v ) dim(f ) = dim(v )

Lyapunov exponents of Teichmüller flows

EXERCISES IN POISSON GEOMETRY

ISOMORPHISMS OF POISSON AND JACOBI BRACKETS

The Hitchin map, local to global

arxiv: v1 [math.ds] 6 Jun 2016

CHAPTER I THE RIESZ REPRESENTATION THEOREM

Vector bundles in Algebraic Geometry Enrique Arrondo. 1. The notion of vector bundle

ARCS IN FINITE PROJECTIVE SPACES. Basic objects and definitions

MASLOV INDEX. Contents. Drawing from [1]. 1. Outline

Preliminary/Qualifying Exam in Numerical Analysis (Math 502a) Spring 2012

LECTURE 10: THE ATIYAH-GUILLEMIN-STERNBERG CONVEXITY THEOREM

Lecture 11 Hyperbolicity.

The Hopf argument. Yves Coudene. IRMAR, Université Rennes 1, campus beaulieu, bat Rennes cedex, France

The oblique derivative problem for general elliptic systems in Lipschitz domains

Entropy production for a class of inverse SRB measures

Real Analysis Prelim Questions Day 1 August 27, 2013

Problem Set. Problem Set #1. Math 5322, Fall March 4, 2002 ANSWERS

ON RIGIDITY OF ALGEBRAIC DYNAMICAL SYSTEMS

Real Analysis Problems

BRIAN OSSERMAN. , let t be a coordinate for the line, and take θ = d. A differential form ω may be written as g(t)dt,

HYPERKÄHLER MANIFOLDS

MET Workshop: Exercises

Measurable functions are approximately nice, even if look terrible.

Math 113 Winter 2013 Prof. Church Midterm Solutions

INTRODUCTION TO LIE ALGEBRAS. LECTURE 7.

Mathematics Department Stanford University Math 61CM/DM Inner products

MATH 51H Section 4. October 16, Recall what it means for a function between metric spaces to be continuous:

Lebesgue-Radon-Nikodym Theorem

Bounded uniformly continuous functions

x 3y 2z = 6 1.2) 2x 4y 3z = 8 3x + 6y + 8z = 5 x + 3y 2z + 5t = 4 1.5) 2x + 8y z + 9t = 9 3x + 5y 12z + 17t = 7

Functional Analysis HW #3

SOME EXAMPLES OF NONUNIFORMLY HYPERBOLIC COCYCLES. L.-S. Young 1

ANALYSIS QUALIFYING EXAM FALL 2016: SOLUTIONS. = lim. F n

Review problems for MA 54, Fall 2004.

4 Hilbert spaces. The proof of the Hilbert basis theorem is not mathematics, it is theology. Camille Jordan

Supplementary Notes on Linear Algebra

HARTSHORNE EXERCISES

MATH & MATH FUNCTIONS OF A REAL VARIABLE EXERCISES FALL 2015 & SPRING Scientia Imperii Decus et Tutamen 1

Exercises in Geometry II University of Bonn, Summer semester 2015 Professor: Prof. Christian Blohmann Assistant: Saskia Voss Sheet 1

08a. Operators on Hilbert spaces. 1. Boundedness, continuity, operator norms

A Field Extension as a Vector Space

THEODORE VORONOV DIFFERENTIABLE MANIFOLDS. Fall Last updated: November 26, (Under construction.)

ABSOLUTE CONTINUITY OF FOLIATIONS

5 Birkhoff s Ergodic Theorem

Analysis Comprehensive Exam Questions Fall 2008

CLOSED RANGE POSITIVE OPERATORS ON BANACH SPACES

Math Topology II: Smooth Manifolds. Spring Homework 2 Solution Submit solutions to the following problems:

MAT 5330 Algebraic Geometry: Quiver Varieties

LYAPUNOV EXPONENTS: HOW FREQUENTLY ARE DYNAMICAL SYSTEMS HYPERBOLIC?

Cohomology of the Mumford Quotient

Transcription:

THEOREM OF OSELEDETS We recall some basic facts and terminology relative to linear cocycles and the multiplicative ergodic theorem of Oseledets []. 0.. Cocycles over maps. Let µ be a probability measure on some space M and f : M M be a measurable transformation that preserves µ. Let π : E M be a finite-dimensional vector bundle endowed with a Riemannian norm. A linear cocycle (or vector bundle morphism) over f is a map F : E E such that π F = f π and the action A(x) : E x E f(x) of F on each fiber is a linear isomorphism. It is often possible to assume that the vector bundle is trivial, meaning that E = M R d, restricting to some full µ-measure subset of M if necessary. Then A( ) takes values in the linear group GL(d, R) of invertible d d matrices. Notice that, in general, the action of the nth iterate is given by A n (x) = A(f n (x)) A(f(x)) A(x), for every n. Given any y > 0, we denote log + y = max{log y, 0}. Theorem 0.. Assume the function log + A(x) is µ-integrable. Then, for µ- almost every x M, there exists k = k(x), numbers λ (x) > > λ k (x), and a filtration E x = Fx > > Fx k > {0} = Fx k+ of the fiber, such that () k(f(x)) = k(x) and λ i (f(x)) = λ i (x) and A(x) Fx i = Ff(x) i and n + n log An (x)v = λ i (x) for all v Fx i \ Fx i+ and all i =,..., k. The Lyapunov exponents λ i and the subspaces F i depend in a measurable (but usually not continuous) fashion on the base point. The statement of the theorem, including the values of k(x), the λ i (x), and the F i (x), is not affected if one replaces by any other Riemann norm equivalent to it in the sense that there exists some µ-integrable function c( ) such that () e c(x) v v e c(x) v for all v T x M. When the measure µ is ergodic, the values of k(x) and of each of the λ i (x) are constant on a full measure subset, and so are the dimensions of the subspaces Fx. i We call dim Fx i dim Fx i+ the multiplicity of the corresponding Lyapunov exponent λ i (x). The Lyapunov spectrum of F is the set of all Lyapunov exponents, each counted with multiplicity. The Lyapunov spectrum is simple if all Lyapunov exponents have multiplicity. Date:

2 THEOREM OF OSELEDETS 0.2. The invertible case. If the transformation f is invertible then so is the cocycle F. Applying Theorem 0. also to the inverse F and combining the invariant filtrations of the two cocycles, one gets a stronger conclusion than in the general non-invertible case: Theorem 0.2. Let f : M M be invertible and both functions log + A(x) and log + A (x) be µ-integrable. Then, for µ-almost every point x M, there exists k = k(x), numbers λ (x) > > λ k (x), and a decomposition E x = Ex Ex k of the fiber, such that () A(x) Ex i = Ef(x) i and F x i = k j=i Ej x and n ± n log An (x)v = λ i (x) for all non-zero v Ex i and (3) lim n ± n log ( Ef i n (x), ) Ej f n (x) = 0 for all i, j =,..., k. Note that the multiplicity of each Lyapunov exponent λ i coincides with the dimension dim Ex i = dim Fx i dim Fx i+ of the associated Oseledets subspace Ex. i From the conclusion of the theorem one easily gets that k n ± n log det An (x) = λ i (x) dim Ex. i In most cases we deal with, the determinant is constant equal to. Then the sum of all Lyapunov exponents, counted with multiplicity, is identically zero. Remark 0.3. The natural extension of a (non-invertible) map f : M M is defined on the space ˆM of sequences (x n ) n 0 with f(x n ) = x n+ for n < 0, by i= ˆf : ˆM ˆM, (..., xn,..., x 0 ) (..., x n,..., x 0, f(x 0 )). Let P : ˆM M be the canonical projection assigning to each sequence (xn ) n 0 the term x 0. It is clear that ˆf is invertible and P ˆf = f P. Every f-invariant probability µ lifts to a unique ˆf-invariant probability ˆµ such that P ˆµ = µ. Every cocycle F : E E over f extends to a cocycle ˆF : Ê Ê over ˆf, as follows: ʈx = E P (ˆx) and Â(ˆx) = A(P (ˆx)), where Â(ˆx) denotes the action of ˆF on the fiber ʈx. Clearly, log +  dˆµ = log + A dµ and, assuming the integrals are finite, the two cocycles F and ˆF have the same Lyapunov spectrum and the same Oseledets filtration. Moreover, log +  dˆµ = log + A dµ and when the integrals are finite we may apply Theorem 0.2 to the cocycle ˆF. Remark 0.4. Any sum F i x = k j=i Ej x of Oseledets subspaces corresponding to the smallest Lyapunov exponents depends only on the forward iterates of the cocycle. Analogously, any sum of Oseledets subspaces corresponding to the largest Lyapunov exponents depends only on the backward iterates. 0.3. Symplectic cocycles. Suppose there exists some symplectic form, that is, some non-degenerate alternate 2-form ω x on each fiber E x, which is preserved by the linear cocycle F : ω f(x) (A(x)u, A(x)v) = ω x (u, v) for all x M and u, v E x. Assume the symplectic form is integrable, in the sense that there exists a µ- integrable function x c(x) such that ω x (u, v) e c(x) u v for all x M and u, v E x.

THEOREM OF OSELEDETS 3 Remark 0.5. We are going to use the following easy observation. Let µ be an invariant ergodic probability for a transformation f : M M, and let φ : M R be a µ-integrable function. Then lim n n φ(f n (x)) = 0 µ-almost everywhere. This follows from the Birkhoff ergodic theorem applied to ψ(x) = φ(f(x)) φ(x). Note that the argument remains valid under the weaker hypothesis that the function ψ be integrable. Proposition 0.6. If F preserves an integrable symplectic form then its Lyapunov spectrum is symmetric: if λ is a Lyapunov exponent at some point x then so is λ, with the same multiplicity. This statement can be justified as follows. Consider any i and j such that λ i (x) + λ j (x) 0. For all v i Ex i and v j Ex, j ω x (v i, v j ) = ω f n (x)(a n (x)v i, A n (x)v j ) e c(f n (x)) A n (x)v i A n (x)v j for all n Z. Since c(x) is integrable the first factor has no exponential growth: by Remark 0.5, lim n ± n c(f n (x)) = 0 almost everywhere. The assumption implies that A n (x)v i A n (x)v j goes to zero exponentially fast, either when n + or when n. So, the right hand of the previous inequality goes to zero either when n + or when n. Therefore, in either case, the left hand side must vanish. This proves that λ i (x) + λ j (x) 0 ω x (v i, v j ) = 0 for all v i E i x and v j E j x. Since the symplectic form is non-degenerate, it follows that for every i there exists j such that λ i (x) + λ j (x) = 0. We are left to check that the multiplicities of such symmetric exponents coincide. We may suppose λ i (x) 0, of course. Let s be the dimension of Ex. i Using a Gram-Schmidt argument, one constructs a basis v, i..., vs i of Ex i and a family of vectors v j,..., vj s in Ex j such that { (3) ω x (vp, i vq) j if p = q = 0 otherwise. Notice that ω x (v i p, v i q) = 0 = ω x (v j p, v j q) for all p and q, since λ i (x) = λ j (x) is non-zero. The relations (3) imply that the v j,..., vj s are linearly independent, and so dim E j x dim E i x. The converse inequality is proved in the same way. 0.4. Adjoint linear cocycle. Let π : E M be another vector bundle which is dual to π : E M, in the sense that there exists a nondegenerate bilinear form E x E x (u, v) u v R, for each x M. The annihilator of a subspace E E x is the subspace E E x of all v E x such that u v = 0 for all u E. We also say that E is the annihilator of E. Notice that dim E + dim E = dim E x = dim E x. The norm may be transported from E to E through the duality: (4) u = sup{ u v : v E x with v = } for u E x.

4 THEOREM OF OSELEDETS For x M, the adjoint of A(x) is the linear map A (x) : E f(x) E x defined by (5) A (x)u v = u A(x)v for every u E f(x) and v E x. The inverses A (x) : E x E f(x) define a linear cocycle F : E E over f. Proposition 0.7. The Lyapunov spectra of F and F are symmetric to one another at each point. Indeed, the definitions (4) and (5) imply A (x) = A(x) and, analogously, A (x) = A (x) for any x M. Thus, F satisfies the integrability condition in Theorem 0.2 if and only if F does. Let E x = k j= Ej x be the Oseledets decomposition of F at each point x. For each i =,..., d define (6) E i x = annihilator of E x E i x E i+ x E k x. The decomposition Ex = k j= Ej x u Ex i and any n, is invariant under F. Moreover, given any A n (x)u = max v = A n (x)u v = max v = u A n (x)v. Fix any ε > 0. Begin by considering v E i f n (x). Then A n (x)v E i x, and so u A n (x)v c u A n (x)v c u e (λi(x)+ε)n for every n sufficiently large, where c = c(ex, i Ex i ) > 0. Consequently, (7) lim n n log A n (x)u (λ i (x) + ε). Next, observe that a general unit vector v E f n (x) may be written v = k v j with v j E j f n (x). j= Using part 3 of Theorem 0.2, we see that every v j e εn if n is sufficiently large. Therefore, given any u E i x, u A n (x)v = u A n (x)v i u e (λi(x) ε)n v i u e (λi(x) 2ε)n for every unit vector v E f n (x), and so (8) lim n n log A n (x)u (λ i (x) 2ε). Since ε > 0 is arbitrary, the relations (7) and (8) show that the Lyapunov exponent is precisely λ i (x), for every i =,..., k. Thus, Ex = k j= Ej x Observe, in addition, that of F along Ex i must be the Oseledets decomposition of F at x. dim Ex i = dim Ex i for all i =,..., k. 0.5. Cocycles over flows. We call linear cocycle over a flow f t : M M, t R a flow extension F t : E E, t R such that π F t = f t π and the action A t (x) : E x E f t (x) of F t on every fiber is a linear isomorphism. Notice that A t+s (x) = A s (f t (x)) A t (x) for all t, s R. Theorem 0.8. Assume log + A t (x) is µ-integrable for all t R. Then, for µ- almost every x M, there exists k = k(x) d, numbers λ (x) > > λ k (x), and a decomposition E x = E 0 x E x E k x of the fiber, such that () A t (x) E i x = E i f t (x) and E0 x is tangent to the flow lines

t ± (3) lim t ± THEOREM OF OSELEDETS 5 t log At (x) = λ i (x) for all non-zero v Ex i t log ( Ef i t (x), ) Ej f t (x) = 0 for all i, j =,..., k. As a consequence, the relation (2) also extends to the continuous time case, as do the observations made in the previous sections for discrete time cocycles. An important special case is the derivative cocycle Df t : T M T M over a smooth flow f t : M M. We call Lyapunov exponents and Oseledets subspaces of the flow the corresponding objects for this cocycle Df t, t R. 0.6. Induced cocycle. The following construction will be useful later. Let f : M M be a transformation, not necessarily invertible, µ be an invariant probability measure, and D be some positive measure subset of M. Let ρ(x) be the first return time to D, defined for almost every x D. Given any cocycle F = (f, A) over f, there exists a corresponding cocycle G = (g, B) over the first return map g(x) = f ρ(x) (x), defined by B(x)v = A ρ(x) (x)v. Proposition 0.9. () The normalized restriction µ D of the measure µ to the domain D is invariant under the first return map g. (2) log + B ± are integrable for µ D if log + A ± are integrable for µ. (3) For µ-almost every x D, the Lyapunov exponents of G at x are obtained multiplying the Lyapunov exponents of F at x by some constant c(x). Proof. First, we treat the case when the transformation f is invertible. For each j, let D j be the subset of points x D such that ρ(x) = j. The {D j : j } are a partition of a full measure subset of D, and so are the {f j (D j ) : j }. Notice also that g D j = f j D j for all j. For any measurable set E D and any j, µ ( g (E f j (D j )) ) = µ ( f j (E f j (D j )) ) = µ ( E D j ), because µ is invariant under f. It follows that µ ( g (E) ) = µ ( g (E f j (D j )) ) = µ ( ) E D j = µ(e). j= This implies that µ D is invariant under g, as claimed in part (). Next, from the definition B(x) = A ρ(x) (x) we conclude that j log + B dµ = log + A j dµ log + A f i dµ. D D j D j j= j= j= i=0 Since µ is invariant under f and the domains f i (D j ) are pairwise disjoint for all 0 i j, it follows that j log + B dµ log + A dµ log + A dµ. D j= i=0 f i (D j) The corresponding bound for the norm of the inverse is obtained in the same way. This implies part (2) of the proposition. To prove part (3), define k c(x) = lim ρ(f j (x)). k k j=0

6 THEOREM OF OSELEDETS Notice that ρ is integrable relative to µ D : j ρ dµ = jµ(d j ) = µ(f i (D j )). D j= j= i=0 Thus, by the ergodic theorem, c(x) is well defined at µ D -almost every x. It is clear from the definition that c(x). Now, given any vector v E x \ {0} and a generic point x D, lim k k log Bk (x)v = c(x) lim n n log An (x)v (we are assuming log + A is µ-integrable and so Theorem 0. ensures that both limits exist). This proves part (3) of the proposition, when f is invertible. Finally, we extend the proposition to the non-invertible case. Let ˆf be the natural extension of f and ˆµ be the lift of µ (Remark 0.3). Denote ˆD = P (D). It is clear that the ˆf-orbit of a point ˆx ˆD returns to ˆD at some time n if and only if the f-orbit of x = P (ˆx) returns to D at time n. Thus, the first return map of ˆf to the domain ˆD is ĝ(x) = ˆf ρ(x) (ˆx), x = P (ˆx), and so it satisfies P ĝ = g P. It is also clear that the normalized restriction ˆµ D of ˆµ to the domain ˆD satisfies P ˆµ D = µ D. By the invertible case, ˆµ D is invariant under ĝ. It follows that µ D is invariant under g: µ D (g (E)) = ˆµ D (P g (E)) = ˆµ D (ĝ P (E)) = ˆµ D (P (E)) = µ D (E), for every measurable set E D. This settles part (). Now let ˆF = ( ˆf, Â) be the natural extension of the cocycle F (Remark 0.3) and Ĝ be the cocycle it induces over ĝ: Ĝ(ˆx, v) = (ĝ(ˆx), ˆB(ˆx)v), ˆB(ˆx) =  ρ(x) (ˆx). By definition, Â(ˆx) = A(x), and so ˆB(ˆx) = B(x). Consequently, log + A dµ = log +  dˆµ and log + B dµ D = log ˆB dˆµ D. By the invertible case, log + ˆB + is ˆµ D -integrable if log  is ˆµ-integrable. It follows that log + B is µ D -integrable if log + A is µ-integrable. The same argument applies to the inverses. This settles part (2) of the proposition. Part (3) also extends easily to the non-invertible case: as observed in Remark 0.3, the Lyapunov exponents of ˆF at ˆx coincide with the Lyapunov exponents of F at x. For the same reasons, the Lyapunov exponents of Ĝ at ˆx coincide with the Lyapunov exponents of G at x. By the invertible case, the exponents of Ĝ at ˆx are obtained multiplying the exponents of ˆF at ˆx by some positive factor. Consequently, the exponents of G at x are obtained multiplying the exponents of F at x by that same factor. This concludes the proof of the proposition. References [] V. I. Oseledets. A multiplicative ergodic theorem: Lyapunov characteristic numbers for dynamical systems. Trans. Moscow Math. Soc., 9:97 23, 968.