Determine the angle θ between the two position vectors.

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-100. Determine the angle θ between the two position vectors. -105. A force of 80 N is applied to the handle of the wrench. Determine the magnitudes of the components of the force acting along the axis AB of the wrench handle and perpendicular to it.

-116. The force {5i 50j 10k N acts at the end A of the pipe assembly. Determine the magnitudes of the components 1 and which act along the axis of AB and perpendicular to it.

-100 Position vector: r 1 [0 (8)]i (15 5)j (10 8)k {8i 10j 8k} ft r 1 8 10 ( 8) 8 ft 15.1 ft r [0 (8)]i (0 5)j (6 8)k {8i 5j k} ft r 8 ( 5) ( ) 93 ft 9.64 ft cos θ r1 r r r 1 (8i 10j8k ) (8i 5j k) 15.1 9.64 8(8) 10( 5) ( 8)( ) 145.6 0.060 θ 78.1 o Ans

-105 u cos 30 o sin 45 o i cos 30 o cos 45 o j sin 30 o k 0.614i 0.614j 0.5k u AB j u 80(0.614i 0.614j 0.5k) (48.990i 48.99j 40k) N AB u AB (48.990i 48.99j 40k) (j) 49.0 N Ans Negative sign indicates that AB acts in the direction opposite to that of u AB. per. e A B 80 ( 49.0) 63. N Ans Also, from prob. -104 θ 18 o AB cos θ 80 cos 18 o 49.0 N per. sin θ 80 sin 18 o 63. N

-116 5 6 4 6) (0 9) (5 0) (0 6) (0 9) (5 0) (0 k j k j i u AB 5 6 4 ) 10 50 (5 1 k j k j i u AB 5 6) ( (10) 4) 50)( ( (0) 5 19.4 N Ans N 56.79 10 50) ( 5 1 N 53.4 19.41 56.79 Ans

Ch. 3 Equilibrium of a Particle Resolve a force into components Express a force as a Cartesian vector 3.1 Conditions for the equilibrium of a Particle A particle is in equilibrium: at rest, if originally at rest. has constant velocity, if originally in motion. Static equilibrium or equilibrium, mostly at rest, if originally at rest. To maintain a state of equilibrium, it is necessary to satisfy first Law of Motion. [if resultant force acting on a particle is zero, then particle is in equilibrium]. v 0 vector sum of all the forces acting on the particle v v necessary condition of equilibrium & sufficient ma satisfied ma v 0 a v 0 constant velocity or at rest.

3. ree-body Diagram Σ includes known & unknown forces acting on the particle. (1) Draw the free body diagram of the particle sketch of the particle, which represents it as being isolated or cut force from its surroundings. * on sketch show all forces acting on the particle (action & reaction forces) () Apply equation of equilibrium Connections: 1. Springs: Linear elastic spring support change in length α force acting on it. L (L L o ) S α deformed undeformed S 1 K spring constant or stiffness KS Elongation or reduction ve is pull ve is push K 500 N/m 1 500. 100 N 500 () 100 N

. Cables & pulleys Assume 1) cable s weight is negligible ) cable s can t be stretched Cable can support only tension (pulling) force * acting in the direction of the cable * tension in a continuous cable passing over frictionless pulley has constant magnitude, to keep cable in equilibrium. T regardless of θ * cable is subjected to a constant tension T throughout its length. 3. Others supports, later

Procedure for Drawing a ree-body Diagram 1. Imagine the particle isolated, cut, free, from its surroundings. Draw / sketch its outline shape.. On the sketch, indicate all forces acting on the particle. orces active forces: tend to set particle in motion, e.g. weight, magnetic/electro static interaction reactive forces: tend to prevent motion, caused by constraints or support. o trace around the particle s boundary, noting each force acting on it. 3. Label known forces with their proper magnitudes & directions Represent unknown forces by letters - If a force has a known line of action (direction), a sense can be assumed. Then found - mag. of v is ve. ve opposite sense Equilibrium - Apply equilibrium eqn. on the free-body diagram. Σ x 0 v Σ y 0 x î ĵ kˆ y z Σ z 0

Objectives: 1. Introduce the concept of.b.d. for a particle.. Solve particle problems using the equation of equilibrium 3.3 Coplanar orce Systems v 0 x î y ĵ 0 Σ x 0 Σ y 0 scalar equilibrium eqns. algebraic sum of x & y components of all the forces acting on the particle 0. equations & unknowns (mag. & direction) Scalar Notation: sense algebraic sign arrowhead magnitude & sense can be assmed v is always ve, if (ve) result sense is opposite to that which was assumed. 10 N Σ x 0 10 0 10 N opposite sense

Procedure for Analysis: (planar forces & particle equilibrium) 1. ree body diagram: - identify the body / particle - draw.b.d. of the particle - isolation - known & unknown forces (mag. & angles) to be labeled) - assume sense for unknown forces. Equations of Equilibrium x-y axes in any direction Σ x 0 Σ y 0 Spring Ks