AQA Chemistry GCSE. Topic 3: Quantitative Chemistry. Flashcards.

Similar documents
IGCSE (9-1) Edexcel - Chemistry

Revision Checklist :4.3 Quantitative Chemistry

Quantitative Chemistry. AQA Chemistry topic 3

GraspIT AQA GCSE Quantitative changes

2. Relative molecular mass, M r - The relative molecular mass of a molecule is the average mass of the one molecule when compared with

4.3.1 Chemical measurements, conservation of mass and the quantitative interpretation of chemical equations

Revision Checklist :4.3 Quantitative Chemistry

4.3 Quantitative chemistry

FACTFILE: GCSE CHEMISTRY: UNIT 2.6

Quantitative Chemistry

Part 7- Quantitative Chemistry Application Questions Triple Science

Stoichiometry Part 1

Chapter 5 Chemical Calculations

PRACTICE EXAMINATION QUESTIONS FOR 1.2 AMOUNT OF SUBSTANCE

A-LEVEL TRANSITION COURSE SUMMER 2018 PART 2: USING CHEMICAL EQUATIONS

WJEC England GCSE Chemistry. Topic 3: Chemical formulae, equations and amount of substance. Notes. (Content in bold is for Higher Tier only)

CHEM111 UNIT 1 MOLES, FORMULAE AND EQUATIONS QUESTIONS

CHEM111 UNIT 1 MOLES, FORMULAE AND EQUATIONS QUESTIONS

The Mole. Relative Atomic Mass Ar

A student wanted to make 11.0 g of copper chloride

Norgessaltpeter can be made by the reaction of calcium carbonate with dilute nitric acid as shown by the following equation.

Quantitative analysis Notes

Lower Sixth Chemistry. Sample Entrance Examination

Chemistry. Bridging the Gap Summer Homework. Name..

Chapter 3 Test Bank. d. The decomposition of magnesium oxide produces 2.4 g of magnesium metal and 3.2 g of oxygen gas.

1 Atoms, molecules and stoichiometry try

2.9 The Mole and Chemical Equations:

Personalised Learning Checklists AQA Chemistry Paper 1

Mole Calculations. Specification points. Year 10 Moles I Quantitative Chemistry

Formulae of simple compounds

TOPIC 4: THE MOLE CONCEPTS

1.21. Formulae, equations and amounts of substance

1.24 Calculations and Chemical Reactions

2 Amount of substance Exam-style questions. AQA Chemistry

IGCSE Double Award Extended Coordinated Science

Unit of Pressure (P):Pa Unit of Volume (V): m 3 Unit of Temp (T): K n= moles R = Converting temperature. C K add 273

Unit of Pressure (P):Pa Unit of Volume (V): m 3 Unit of Temp (T): K n= moles R = Converting temperature. C K add 273

Questions Q1. Which of the following contains the greatest number of hydrogen atoms? 2 moles of water, H 2 O. B 1.5 moles of ammonia, NH 3

3. Which postulate of Dalton s atomic theory is the result of the law of conservation of mass?

Chapter 1 IB Chemistry Warm Ups Stoichiometry. Mrs. Hilliard

4.4. Revision Checklist: Chemical Changes

Questions Booklet. UNIT 1: Principles & Applications of Science I CHEMISTRY SECTION. Level 3 Applied Science. Name:.. Teacher:..

NATIONAL 5 CHEMISTRY

1.21. Formulae, equations and amounts of substance

Set 1 Structure of the atoms & Chemical Equation Perfect Score F Matter is anything that. and has.

ST. FRANCIS SECONDARY SCHOOL HALF YEARLY EXAMINATION SPECIMEN PAPER FORM 4 CHEMISTRY TIME: 2 HOURS. Name: Total Mark from 90:

Moles, calcula/ons in gaseous and solu/on and acids and bases

Figure 1. Oxygen. (g) +... (g)... SO 3. The pressure of the reacting gases was increased.

mohd faisol mansor/chemistry form 4/chapter 7 CHAPTER 7 ACIDS AND BASES HCl (g) H 2 O H + (aq) + Cl - (aq) NaOH(s) H 2 O Na + (aq) + OH - (aq)

Name: DEADLINE: 1 st lesson back, September term

Stoichiometry Limiting Reactants Percent Yield

Conservation of Mass

OCR A GCSE Chemistry. Topic 3: Chemical reactions. Introducing chemical reactions. Notes.

Page 2. Q1.A student investigated the reactions of copper carbonate and copper oxide with dilute hydrochloric acid.

Unit 7: Stoichiometry Homework Packet (85 points)

2.1.3 Amount of substance

The Masses of chemicals

Nine tips for scaffolding multi-step calculations

Stoichiometry Dry Lab

Lesson (1) Mole and chemical equation

MOLE CONCEPT AND STOICHIOMETRY

Stoichiometry study of the relationships in a

NCERT Solutions for Atoms and Molecules

5. Formulae, equations and amounts of substance

5. Formulae, equations and amounts of substance

Which of the following answers is correct and has the correct number of significant figures?


Atoms, Elements, Atoms, Elements, Compounds and Mixtures. Compounds and Mixtures. Atoms and the Periodic Table. Atoms and the.

Topic 1 Review. Ms. Kiely Coral Gables Senior High IB Chemistry SL

5. Formulae, equations and amounts of substance

C4 Quick Revision Questions

Chapter 3 Stoichiometry

Q1. (a) The formula for the chemical compound magnesium sulphate is MgSO (2)

IB Topics 1 & 11 Multiple Choice Practice

Quantity Relationships in Chemical Reactions

(a) Complete Figure 9 by placing one tick in each row to show whether the salt is soluble or insoluble. salt soluble insoluble.

(g) + 3H 2. (g) 2NH 3. (g) (a) Explain what is meant by a dynamic equilibrium. (2)

Stoichiometry Dry Lab

OCR unit 5 revision booklet

RCOOH + R / OH. = 100) is obtained from 1.0 g of RCOOR / (M r. D 75% (Total 1 mark)

Answers for UNIT ONE NAT 5 Flash Cards

AMOUNT OF SUBSTANCE 18-Jun-2015 Chemsheets AS

End of chapter exercises

Chapter 3: Stoichiometry

Chemical measurements QuestionIT

Year 10 Chemistry Exam June 2011 Multiple Choice. Section A Mulltiple Choice

Stoichiometric relationships 1

Class IX Chapter 3 Atoms and Molecules Science

YEAR 11 CHEMISTRY SEMESTER 1 TITLE: CHEMICAL QUANITITES AND CALCULATIONS (3)

Chemistry 11. Unit 7 - Stoichiometry

The topics in this unit are:

Stoichiometry. A. The Meaning of Coefficients in a Reaction Equation 1. Consider the following reaction: 200 H O H 2 O or

SIC CONCEPTS TS OF CHEMISTRY. Unit. I. Multiple Choice Questions (Type-I)

REVIEW of Grade 11 Chemistry

1. How many significant digits are there in each of the following measurements? (½ mark each) a) ha b) s. c) d) 0.

Stoichiometry CHAPTER 12

Naming salts. Metal Acid Salt. Sodium hydroxide reacts with Hydrochloric acid to make Sodium chloride

Chapter 3 Calculations with Chemical Formulas and Equations

C2.6 Quantitative Chemistry Foundation

1.1 Introduction to the Particulate Nature of Matter and Chemical Change MATTER. Homogeneous (SOLUTIONS)

Transcription:

AQA Chemistry GCSE Topic 3: Quantitative Chemistry Flashcards

What is the law of conservation of mass?

What is the law of conservation of mass? The law of conservation of mass states that no atoms are lost or made during a chemical reaction so the mass of the products equals the mass of the reactants.

Write a balanced equation of magnesium reacting with hydrochloric acid.

Write a balanced equation of magnesium reacting with hydrochloric acid. Mg (s) + 2 HCl (aq) MgCl 2(aq) + H 2(g)

Define relative atomic mass and relative formula mass.

Define relative atomic mass and relative formula mass. RAM - average mass of atoms in an element taking into account masses and abundance of its isotopes, relative to 12 C. RFM - sum of RAM s of all atoms in the formula.

What is the relative formula mass of: A) CaF 2 B) B) C 6 H 12 O 6

What is the relative formula mass of: CaF 2 - (A r values: Ca = 40, F = 19) 40 + 19 + 19 = 78 --- C 2 H 12 O 6 - (A r values: C = 12, H = 1, O = 16) (12 x 6) + (1 x 12) + (16 x 6) = 180

The following reaction occurs in a test tube under a Bunsen Burner: 4 MgO(s) + CH 4 (g) 4 Mg(s) + 2 H 2 O(g) + CO 2 (g) The carbon dioxide and water escape from the test tube. Use the equation to explain why.

Use equation to explain why carbon dioxide and water escape from the test tube. They are both gases

The experiment was repeated three times. Calculate the mean mass of magnesium produced and suggest how you could increase the precision of the results. Mass of magnesium oxide used in g Experiment 1 2 3 4.0 4.0 4.0 Mass of magnesium produced in g 3.3 3.5 3.2

Calculate the mean of magnesium produced and suggest how you could increase the precision of the results (3.3 + 3.5 + 3.2) / 3 = 3.3 Measure to more decimal places or use a more sensitive balance / apparatus

What is Avogadro's constant? Higher tier only

What is Avogadro s constant? The number of atoms, molecules or ions in a mole of a given substance. The value of the constant is 6.02 x 10 23. Higher tier only

What is the formula that links mass, molecular mass and moles together Higher tier only

What is the formula that links mass, molecular mass and moles together Mass = Mr x Moles Higher tier only

What is the mass of: 20 moles of calcium carbonate, CaCO 3 Higher tier only

What is the mass of 20 moles of calcium carbonate, CaCO 3 Mass = Mr x Moles Mr = 100 100 x 20 = 200 g Higher tier only

Calculate the amount of carbon dioxide in moles in 0.32 g of carbon dioxide. Relative atomic masses (A ): carbon = r 12, oxygen = 16 Higher tier only

Calculate the amount of carbon dioxide in moles in 0.32 g of carbon dioxide. Relative atomic masses (A r ): carbon = 12, oxygen = 16 Moles = Mass / Mr 0.32 / 44 = 0.007 Higher tier only

Nitrogen and hydrogen form ammonia shown by the following equation: N 2(g) + 3 H 2(g) 2 NH 3(g) Calculate the mass of nitrogen needed to form 6.8 tonnes of ammonia. Relative atomic masses (A r ): H = 1; N = 14 Higher tier only

Calculate the mass of nitrogen needed to form 6.8 tonnes of ammonia Step 1 - Work out the number of number of moles of ammonia (Mr of ammonia = 17) 6800000 / 17 = 400000 moles of ammonia Step 2 - Use the balanced equation and number of moles of ammonia to work out the number of moles of nitrogen The ratio of nitrogen to ammonia is 1:2 Therefore the number of moles of nitrogen is 400000/2 = 200000 Step 3 - Work out the mass of nitrogen (Mr of N 2 is 28) 200000 x 28 = 5600000 g = 5.6 tonnes. Higher tier only

State what we mean by a limiting reactant in a chemical reaction Higher tier only

State what we mean by a limiting reactant in a chemical reaction In a chemical reaction involving two reactants, it is common to use an excess of one of the reactants to ensure that all of the other reactant is used. The reactant that is completely used up is called the limiting reactant because it limits the amount of products. Higher tier only

Hydrogen peroxide decomposes in water to form water and oxygen. How many grams of oxygen gas will be given off from 40.8 g of hydrogen peroxide? Higher tier only

How much oxygen will be given off from 40.8 g of hydrogen peroxide? Step 1: Write the balanced equation 2 H 2 O 2(l) 2 H 2 O + O 2(g) Mr of H 2 O 2 = 34 Step 2: Number of moles in 40.8 g : 40.8/34 = 1.2 moles Ratio in the balanced equation of H 2 O 2 : O 2 = 2:1 Step 3 :Therefore number of moles of O 2 = 0.6 moles Step 4: Mass of oxygen = 0.6 x 32 (Mr of O 2 ) = 19.2 Higher tier only

Write down the two formulae that link concentration, mass and volume together.

Write down the two formulae that link concentration, mole/mass and volume together. Concentration (g per dm 3 ) = Mass (g)/volume (dm 3 ) Concentration (mol per dm 3 ) = nr of moles/volume (dm 3 )

31.0 cm 3 of potassium hydroxide solution neutralised 25.0 cm 3 of 2.0 moldm 3 nitric acid. HNO 3 + KOH KNO 3 + H 2 O Calculate the concentration of the potassium hydroxide solution in moldm 3 Higher tier only

Calculate the concentration of the potassium hydroxide solution in moldm 3 Step 1: Calculate the moles of HNO 3 used = Concentration x volume 2 x 0.025 dm 3 (25/1000 to convert the units) = 0.05 moles Step 2 : Calculate the moles of KOH Ratio is 1:1 therefore number of moles of KOH = 0.05 Step 3 : Calculate the concentration of KOH Volume = Moles/concentration; 0.05 / 0.031 = 1.61 Higher tier only

What is the molar volume of a gas at room temperature and pressure?

What is the molar volume of a gas at room temperature and pressure? 1 mole of a gas at room temperature and pressure occupies 24 dm 3

What is titration?

What is titration? A technique for finding the concentration of a solution by reacting a known volume of this solution with a solution of known concentration.

How do you conduct a titration?

How do you conduct a titration? a) Rinse the pipette with a solution of unknown concentration. Use the pipette to measure out the known volume of this solution. b) Add an indicator (a substance that changes colour at the end of titration) c) Rinse the burette with a solution of known concentration. Discard the liquid. Use a burette to gradually add the solution of a known concentration. d) When indicator changes colour (at the end point), the volume added is recorded e) It is important to get concordant volume results - they have to lie close to each other f) Suitable calculations are performed to find the concentration.

Why is it not always possible to obtain the theoretical amount of product in a chemical reaction?

Why is it not always possible to obtain the theoretical amount of product in a chemical reaction? The reaction may not go to completion because it is reversible. Some of the product may be lost when it is separated from the reaction mixture. Some of the reactants may react in ways different to the expected reaction (side reactions may occur).

How is the percentage yield of a product in a chemical reaction?

How is the percentage yield of a product in a chemical reaction? % Yield = Actual mass of a product x 100% Maximum theoretical mass of product

Calculate the percentage yield from the following data

Calculate the percentage yield from the following data:

What is the % yield of NH 3 if 40.5 g NH 3 is produced from 20.0 mol H 2 and excess N 2? Higher tier only

What is the % yield of NH 3 if 40.5 g NH 3 is produced from 20.0 mol H 2 and excess N 2? Step 1 - Write the balanced equation N 2 + 3 H 2 2 NH 3 Step 2 - Calculate the theoretical amount of NH 3. Moles NH 3 (ratio of H 2 to NH 3 is 3:2); of 20/1.5 = 13.3 moles 13.3 X 17 (Mr of NH 3 ) = 227 Step 3 - Calculate percentage yield of NH 3 40.5/227 x 100 = 17.8% Higher tier only

What is atom economy?

What is atom economy? A measure of the amount of starting materials that end up as useful products. It is a ratio of the relative formula mass of desired product to the sum of relative formula masses of reactants.

Look at the equations for the two reactions that produce CuCl 2 Reaction I: CuCO 3(s) + 2 HCl (aq) CuCl 2(aq) + H 2 O (l) + CO 2(g) Reaction II: CuO (s) + 2 HCl (aq) CuCl 2(aq) + H 2 O (l) Reactive formula masses: CuO = 79.5; HCl = 36.5; CuCl 2 = 134.5; H 2 O = 18 Which reaction has a better atom economy?

Which reaction has a better atom economy? Reaction II (look at the reactants): Total formula mass of reactants = 152.5 Formula mass of CuCl 2 = 134.5 (134.5/152.5) x 100% = 88.2%