Electric potential energy The concept of electric potential and potential difference Motion of charges in electric field

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In this chapter, you will learn: Electric potential energy The concept of electric potential and potential difference Motion of charges in electric field

2.1 Electric potential energy When a charged particle moves in an electric field, the field exerts a force that can do work on the particle. The force on a particle moves the charges from point a to point b, the work done by the force is given by a line integral This work can always be expressed in terms of electric potential energy. Mathematically, we can say: Note: when the charge moves, the potential energy converts to kinetic energy. Figure 2.1 a charged particle is displaced along the electric field direction. Work is done by the field. 2

Continue Suppose a positive charge of +q is placed in a uniform electric field as in figure 2.1. The charge +q has its maximum electric potential energy just near the positive plate at point 1 and after it is released, Its electric potential energy decreases as it changes into kinetic energy. Hence the electric potential energy (Ep) of a charge q in a uniform electric field is; is measured by joule (J). 3

2.2 Electric potential energy of point charges: The electric potential energy of a system of two point charges, of the same sign, is equal to the work done by the electric force to move the charge q from r to infinity. We said By substituting the value of E in the above formular, we obtain, Figure 2.2 point charges have potential energy Note: this quantity can be either positive or negative depending on the sign of q. 4

Example 1 The potential energy has increased charges increases as we separate them apart. because the potential energy of unlike 5

2.3 Electric potential Electric potential, V, is defined as: the electric potential energy per unit charge. And it is equal to the work done by an electric field in carrying a unit positive charge from infinity to point a. Mathematically, we can say: For a point charge at point a, by substituting the value of E from above equation, we obtain: thus, V is measured by volt, and Fig. 2.3 Electric potential of charge q at point a. 6

Example 2 Two charges of 5μC and -10μC are placed at the corners of an equilateral triangle of single length of 10 cm. Determine the electric potential at point a. Solution: The net electric potential at point a is the algebraic sum of electric potential due to both charges, then. 7

2.4 Potential difference (voltage): Potential difference is the work that has to be done to transfer a unit positive charge from one point (for example A) to the other (example B), denoted by ΔV and measure by volts. Mathematically, potential difference between two points is defined as the work done on a positive charge by external force dividing by the magnitude of the charge. So potential difference is: And Thus Figure 2.4 a point charge, q, is displaced by an external force F, from point a to point b. 8

9

Continue We said, By substituting the E value, we get Note: in some books the sign of (Ʋ is used instead of V ) Example 3 10

Example 4 Calceolate the work done when a charge of q1= 2μC is moved from point a to point b under the effect of charge q= 50 μc as shown below: Solution: The negative sign means the work done by the electric field is positive, so that the potential energy f the system decreased 11

Example 5 12

2.5 The relationship between potential difference and electric field: We can make a relation between E and V. This principle occurs for any two Plates bring together connected to a source (battery) Figure 2.5 the direction if the uniform electric field due to a charged parallel-plate capacitor is directed from the positive plate towards the negative plate. 13

2.6 motion of charge in a uniform electric field: when a particle of charge q and mass m is released in a uniform electric field, it experiences an electric force as shown in figure below, if the only force acting on it is the electric force we can use Newton s law in the form: Substituting the value if Fe, we obtain, is the magnitude of the acceleration of the particle. Note: we have ignored the gravitational force acting in the particle. In some cases where gravitational force is not be small compared to electric force, we should take this force into account too. Its direction is the same as the electric field direction if the charge is positive as its direction is opposite the electric field direction if the charge is negative 14

Example 6 15

Example 7 An object of charge -10μc and mass 50 mg remains in equilibrium in an uniform electric field. Find the magnitude and direction of the electric field. Solution 16