Measurements in Chemistry

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Measurements in Chemistry Measurements are part of our daily lives. We measure our weight, driving distances and gallons of gasoline. A health professional might measure blood pressure, temperature and pulse rate or calculate drug dosage. A measurement contains a number and a unit. The unit specifies the physical property and the size of the measurement, while the number indicates how many units are present. A number without a unit is usually meaningless. Measurements made with instruments such as rulers, balances and graduated cylinders that are recorded with numbers and units are quantitative observations that are made in science. Observations that are descriptions made using the five senses are called qualitative observations. Section : International System of Units In the United States most measurements are made with the English system of units which usually contain fractions. The metric system is a decimal-based system of Physical Name of Symbol of units of measurement which is used most often worldwide. Quantity Base Unit base unit Around 960, the international scientific organization adopted a modification of the metric system call the International System of Units or SI. Table outlines five Length Mass Time meter kilogram seconds m kg s of the seven base units for the SI system. Not included in the Temperature Kelvin K Amount of mole mol table are the units for electric current (ampere) and luminous substance intensity (candela) because we will not be using them in this Table : SI base units and their symbols course. The units of every measurement in the SI system, no matter how simple or complex should be derived from one or more of the seven base units. For example, the preferred unit for volume is the cubic meter (m 3 ) because Physical Quantity Name of Base Unit Symbol of base unit Volume Liter L Temperature Degrees Celsius o C Concentration Molarity M Pressure Atmosphere atm Table 2: Non-SI units in common use volume has units of length cubed and the SI unit for length is the meter. However, volume is often expressed in scientific works in the unit of liters or milliliters. Because of this, a number of units that are not strictly acceptable under the SI conventions are still used. Some common non-si units in chemistry summarized in Table 2. Identify the physical quantity measured based on the the measurement and units provided. Measurement Physical Quantity Measurement Physical Quantity.33 m.5 atm 298 K 2.0 M 3.4 L 22.8 kg **NOTE: NYS Reference Table D includes selected physical quantities and their associated units.

Section2: Scientific Notation Scientific notation is a common method used to conveniently represent very small or very large numbers. There are two parts to any number expressed in scientific notation, a coefficient and a power of 0. The number 375 is written in scientific notation as 3.75 x 0 2. The coefficient is 3.75 and 0 2 shows the power of 0 (the superscript 2 is called an exponent). A number less than one would contain a negative exponent. For example: the number 0.0075 is written as 7.5 x 0-3 (note the negative exponent.) The coefficient must always be a number greater than or equal to but less than 0. Scientific Notation and Calculators Numbers in scientific notation can be entered into most calculators using the EE or EXP key. As an example try 9.7 x0 3.. Enter the coefficient (9.7) into the calculator. 2. Push the EE (or EXP) key. DO NOT use the times (x) button. 3. Enter the exponent (3). Number to enter Method Display Reads 9.7 x 0 3 9.7 EE 3 9.7E3 or 9700 NOTE: A positive exponent indicates that the first factor is multiplied by a power of 0 Ex. 2 x 0 2 = 2 x 00 = 200 4.5 x 0 4 = 4.5 x 0000 = 45000 A negative exponent indicates that the first factor is divided by a power of 0 Ex. 3 x 0 - = 3 x 0. = 3/0 =.3 5.6 x 0-3 = 5.6 x 0.00 = 5.6/000 =.0056 Calculating with Numbers in Scientific Notation When numbers expressed in scientific notation are added or subtracted, the base and the exponent must be the same. Sample Problem : Add 2.52 x 0 4 and 2.43 x 0 3 First change 2.43 x 0 3 to 0.243 x 0 4 **The exponents must be the same. Then add 2.52 and 0.243 The answer is 2.763 x0 4 Sample Problem 2: Subtract 5.2 x 0-4 and 2.7 x 0-3 First change 5.2 x 0-4 to 0.52 x 0-3 **The exponents must be the same. Then subtract 0.52 from 2.7. The answer is 2.8 x 0-3 Sample Problem 3: Add 3. x 0-2 and 2.7 x 0-2 Since the exponents are the same - Add 3. and 2.7 The answer is 5.8 x 0-2 *Note: Once calculated, be sure that the final answer is in proper scientific notation. The mathematical operation typically results in proper scientific notation if numbers are expressed to the larger exponent.

When numbers expressed in scientific notation are multiplied or divided, the bases are the same but the exponents can be different. When multiplying, exponents will be added; when dividing, exponents will be subtracted. Sample Problem 4 Multiply 4 x 0 2 and 5 x 0 3 Multiply the coefficients Add the exponents (4x0 2 )(5x0 3 ) = 20 x 0 (3+2) = 20 x 0 5 Answer (in Scientific Notation) = 2.0 x 0 6 Sample Problem 5 Divide 7.5 x 0 6 by 2.5 x 0 2 Divide the coefficients Subtract the exponents (7.5x0 6 )(2.5x0 2 ) = 3.0 x 0 (6+2) = 3.0 x 0 4 *Make sure the answer is in scientific notation. EXPRESS EACH OF THE FOLLOWING NUMBERS IN PROPER SCIENTIFIC NOTATION:. 0.000033 = 2. 50,000. = 3. 230,000 = 4. 465 = 5. 236,000,000,000 = 6. 0.000000000000236 = EXPRESS EACH OF THE FOLLOWING IN STANDARD FORM. 9. 3.7 x 0 5 = 0. 3.2 x 0-4 =. 6 x 0 5 = 2..99 x 0-3 = PERFORM EACH OF THE FOLLOWING OPERATIONS USING THE RULES FOR CALCULATING WITH SCIENTIFIC NOTATION. YOUR ANSWERS SHOULD BE EXPRESSED IN SCIENTIFIC NOTATION AND ROUNDED TO THE PROPER SIGNIFICANT FIGURES. CHECK YOUR WORK USING THE SCIENTIFIC NOTATION FUNCTION ON YOUR CALCULATOR. 3. (9.6 x 0 - )(5.2 x 0 2 ) 6. 6.7 x 0 2.3 x 0 3 4. (2.56 x 0 4 )+( 4.6 x 0 3 ) 7. 7.9 x 0-8 - 4.9 x 0-8 5. (.76 x 0 3 ) (5.8 x 0 2 ) 8. 8. x 0 4 9.0 x 0-3

Section 3: Metric Prefixes The metric system is a decimal-based system of units of measurement used by most scientists worldwide. Selected metric prefixes and the associated factor are listed on NYS Chemistry Reference Table C. In the metric system, a prefix can be attached to a unit to increase or decrease its size by factors (powers) of 0. Prefix Symbol Factor Value kilo- k 0 3 000 deci- d 0-0. = 0 centi- c 0-2 0.0 = milli- m 0-3 0.00 = 00 000 micro - µ 0-6 0.00000 = nano - n 0-9 0.00000000 = 000000 pico - p 0-2 0.00000000000 = 000000000 000000000000 Base unit (ex. m, g, L) have a factor of 0 o Notes: milli means one-thousandth; so a milliliter (symbol: ml) is one thousandth of a liter. That means it takes 000 ml to make L. kilo means one thousand; so a kilogram (symbol: kg) means 000 grams [ kg = 000g]. Give the metric prefix that corresponds to each of the following. a. c. 000 000000000 b. 0-6 d. 0.0 2. Compare the values given using <, >, or =. a. 60 m 60 cm b. 200 ml 200 L c. 5 g 5 µg d. 8.6 mm 8.6 km Section 4: Converting Between Units Many problems in chemistry require converting a quantity from one unit to another. To perform this conversion, you must use a conversion factor or a series of conversion factors that relate two units. This method is called dimensional analysis. Any equality can be written in the form of a fraction called a conversion factor. A conversion factor is easily distinguished from all other numbers because it is always a fraction that contains different units in the numerator and denominator. In the United States we may need to convert inches to feet. Since we know the equality is 2 inches = foot, two different conversion factors can be written as seen below. Note the difference units in the numerator and denominator, a requirement for all conversion factors. Conversion factors: Numerator Denominator foot 2 inches OR 2 inches foot

Write the two conversion factors possible for each of the following equalities. a. g = 000 mg b. dozen = 2 eggs c. 60 minutes = hour Section 5: Problem Solving with Dimensional Analysis Dimensional Analysis is a general method for solving numerical problems in chemistry. In this method we follow the rule that when multiplying or dividing numbers, we must also multiply or divide units. Solving problems with dimensional analysis is a three-step process.. Write down the given measurement; number with units 2. Multiply the measurement by one or more conversion factors. The unit in each denominator of the conversation factor must cancel (or match) the preceding unit in each numerator. 3. Perform the calculation and report the answer to proper number of significant figures based on numbers given in the question (data record), not conversion factors used. Sample Problem 6 [SINGLE STEP CONVERSION] Convert 0.455 km to meters To convert kilometers to meters, we must use the following equality km = 000 m The corresponding conversion factors would be: km or 000 m 000 m km NOTE: The final answer is rounded to the significant figures represented in measured value given in the problem. The conversion factor was not used when determining the number of significant figures for the final answer. Select the conversion factor to cancel kilometers, leaving units of meters. 000 m 0.455 km x = 455 m km Sample Problem 7 [MULTIPLE STEP CONVERSION] Convert 2.5 weeks to minutes To convert weeks to minutes, we must use the following equalities week = 7 d d = 24 h h= 60 min The corresponding conversion factors would be: week 7 d or 7 d week d 24 h or 24 h d h 60 min or 60 min h Select the conversion factors that cancel units. 7 d 2.5 weeks x x 24 h 60 min x = 25200 min Rounded to sig figs = 25000 min week d h

Complete each of the following conversions using dimensional analysis. All work must be shown in order to receive credit. ) 300 mg to g 4) 365 g to kg 2) 4 L to ml 5) 56 cm to m 3) 2 cm to mm 6) 7.6 km to mm Compare the following values using the symbols <,>, or =. NOTE: You may have to convert in order to solve. 7) 75 cm 7.5 m 9) 2.4 m 240 cm ) 6 s 60 ms 8) 9 g 900 mg 0) 754 ml 7.54 dl 2) 25 µg 0.25 mg Make the following conversions. Express your answer in proper scientific notation. 3) 5 x 0 3 mm to m 4).57 x 0 3 mg to dg 5) 25 days to seconds