CHEM Exam 2 - October 11, INFORMATION PAGE (Use for reference and for scratch paper)

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CHEM 5200 - Exam 2 - October 11, 2018 INFORMATION PAGE (Use for reference and for scratch paper) Constants and Conversion Factors: R = 0.082 L-atm/mol-K = 8.31 J/mol-K = 8.31 kpa-l/mol-k 1 L-atm = 101 J 1 L-bar = 100 J 1 kpa-l = 1 J 1 bar = 100 kpa 1 bar = 750 torr 1 atm = 760 torr Trouton s Rule: vaps o = 85. J/mol-K The relation between the Molar Mass (M), density (ρ) and Molar Volume (Vm) M of a material is: ρ = V m NOTE: if a question asks for the value of S (without stating it's the "surroundings"), it is asking for the value of S for the system.

CHEM 5200 - Exam 2 - October 11, 2018 Name NOTE: if a question asks for the value of S (without stating it's the "surroundings"), it is asking for the value of S for the system. (51) MULTIPLE CHOICE [3 points per question] (Circle the ONE correct answer) 1. The entropy change is +237 J/K for the reaction: 2 HgO(s) 2 Hg(l) + O2(g). The standard molar entropies of HgO(s) and O2(g) are 70 J/mol-K and 205 J/mol-K. Therefore, the standard molar entropy of Hg(l) is: (A) 86 J/mol-K (B) 0 J/mol-K (C) 51 J/mol-K (D) 102 J/K For #2: Consider the reaction, 2 SO2(g) + O2(g) 2 SO3(g). Relevant thermodynamic data is given in the table below: Compound Sm o fg o SO2(g) 248 J/mol-K -350 kj/mol O2(g) 205 SO3(g) 257-371 2. The Enthalpy change ( H o ) change for the above reaction at 25 o C is: (A) +13.7 kj (B) -46.7 kj (C) -97.7 kj (D) There is insufficient data 3. A sample of 0.5 moles of O2(g) originally at 500 kpa and 5 L is expanded reversibly and isothermally to a final pressure of 100 kpa. What is S for this process? (A) +13.4 J/K (B) -6.7 J/K (C) +4030 J/K (D) +6.7 J/K 4. The constant volume molar heat capacity of Ar(g) is 12.5 J/mol-K. What is S when 3 moles of Ar(g) is cooled at constant pressure from 500 o C to 100 o C? (A) +27.3 J/K (B) -45.5 J/K (C) -100.5 J/K (D) -27.3 J/K 5. A sample of 3 moles of O2(g) at an initial temperature of 100 o C and initial volume of 60 L is expanded reversibly and adiabatically to a final volume of 200 L. What is S for this process? (A) -30 J/K (B) +11.2 kj/k (C) 0 kj/k (D) +30 J/K

For #6 - #8: The normal boiling point of methanol [CH3OH, M=32] is 65 o C. The Enthalpy of Vaporization of methanol is 35.2 kj/mol. 80 grams of methanol gas are condensed to the liquid at 65 o C and 1 bar pressure. Calculate the following quantities for this condensation: 6. The Entropy Change, S, for this process is approximately (A) +260 J/K (B) -104 J/K (C) -260 J/K (D) None of the above 7. The work, w, for this process is approximately (A) +7.0 kj (B) +8.8 kj (C) -7.0 kj (D) None of the above 8. The Internal Energy change, U for this process is approximately (A) -95 kj (B) -81 kj (C) -88 kj (D) None of the above 9. The normal boiling point of toluene is 111 o C. The enthalpy of vaporization of toluene is 39.2 kj/mol. What is the entropy change of the surroundings when one mole of toluene vaporizes at 111 o C? (A) +102 J/mol-K (B) +35.3 J/mol-K (C) -102 J/mol-K (D) -353 J/mol-K 10. The Enthalpy of Vaporizaton of cyclooctane, C8H16, is 37.0 kj/mol. An estimate of the normal boiling point (in o C) of cyclooctane using Trouton's Rule is: (A) 128 o C (B) 435 o C (C) 294 o C (D) 162 o C 11. The change in the Gibbs Energy for a certain constant pressure process is given by: G a bt 2 = +, a = 4,000 J, b = 5. x10-2 J/K 2. The value of S for this process at 50 o C is approximately: (A) -16 J/K (B) -32 J/K (C) 0 J/K (D) +32 J/K 12. The density of liquid benzene,, C6H6(l) [M=78], is 0.85 g/ml at 50 o C. Therefore, the change in the Gibbs energy [in J] of one(1) mole of benzene when the pressure is increased isothermally from 100 kpa to 10,000 kpa at 50 o C is approximately (A) 910 J (B) 9.1x10 4 J (C) 1.2x10 4 J (D) 770 J There are Five more MC questions on the following page

13. A solid has two crystalline forms, A(s) and B(s). For the transition A(s) B(s), G o = +10. kj/mol (i.e. at 1 bar pressure). The difference in molar volumes of the two forms is Vm(B) - Vm(A) = Vm = -25. ml/mol. This transition will be spontaneous at pressures a pressure of bar. (A) above, 4x10 5 bar (C) above, 4000 bar (B) below, 4000 bar (D) Not spontaneous at any pressure For #14 - #17, consider the phase diagram on the right. 14. The Triple Point in the diagram is represented by (A) Point A (B) Point B (C) Point C (D) Point D 15. The slope of curve A-B is steeper than the slope of curve A-D because (A) vaps > subs (C) subv > vapv (B) subs > vaps (D) subv < vapv 16. The slope of curve A-C is negative because (A) fuss o > 0 (B) fuss o < 0 (C) Vm(liq) > Vm(sol) (D) Vm(sol) > Vm(liq) 17. If the pressure on this substance is increased from 1 bar to 500 bar, the boiling point will and the melting point will. (A) decrease, increase (B) increase, increase (C) increase, decrease (D) increase/ increase or decrease depends on relative solid and liquid entropies There are Three (3) Problems on following pages.

(18) 1. A Perfect Gas has a temperature dependent constant pressure molar heat b C = a, with a = 75. J/mol-K and b = 3.0x10 6 J K/mol. T capacity, pm, 2 3 moles of this gas, originally at a temperature of 100 o C and volume of 75. L is heated reversibly at constant pressure to 400 o C. (9) (a) Calculate the Entropy change, S, for this process (in J/K). Part (b) is on following page

(18) 1. CONT'D. A Perfect Gas has a temperature dependent constant pressure molar heat b C = a, with a = 75. J/mol-K and b = 3.0x10 6 J K/mol. T capacity, pm, 2 3 moles of this gas, originally at a temperature of 100 o C and volume of 75. L is heated reversibly at constant pressure to 400 o C. (9) (b) Calculate the heat (q) and work (w) for this process (in kj).

(16) 2. The normal melting point of CHCl3 is -63 o C. The Enthalpy of Fusion of CHCl2 at -63 o C is 8.80 kj/mol The constant pressure heat capacity of liquid CHCl3 is 116 J/mol-K The constant pressure heat capacity of solid CHCl3 is 96 J/mol-K Calculate the entropy change of the system, Ssys, when one (1) mole of liquid trichloromethane freezes irreversibly to the solid at -90 o C.

(15) 3. Consider a hypothetical gas that obeys the equation of state: 2 ( ) p + BV V = RT, where B is a constant If this gas undergoes an isothermal expansion from V1 to V2, develop INTEGRATED expressions for U, H and G in terms of B, R, T, V1 and V2.