Geometry Midterm Review 18-19

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Class: Date: Geometry Midterm Review 18-19 Multiple Choice Identify the choice that best completes the statement or answers the question. 1. Find the length of BC. a. BC = 7 c. BC = 7 b. BC = 9 d. BC = 8 2. Find the best sketch, drawing, or construction of a segment congruent to JK. a. c. b. d. 3. K is the midpoint of JL. JK = 6x and KL = 3x + 3. Find J K, KL, and J L. a. J K = 1, KL = 1, J L = 2 c. J K = 12, KL = 12, J L = 6 b. J K = 6, KL = 6, J L = 12 d. J K = 18, KL = 18, J L = 36 1

4. The tip of a pendulum at rest sits at point B. During an experiment, a physics student sets the pendulum in motion. The tip of the pendulum swings back and forth along part of a circular path from point A to point C. During each swing the tip passes through point B. Name all the angles in the diagram. a. AOB, BOC c. AOB, BOA, COB, BOC b. AOB, COB, AOC d. OAB, OBC, OCB 5. Tell whether 1 and 3 are only adjacent, adjacent and form a linear pair, or not adjacent. a. not adjacent b. only adjacent c. adjacent and form a linear pair 2

6. A billiard ball bounces off the sides of a rectangular billiards table in such a way that 1 3, 4 6, and 3 and 4 are complementary. If m 1 = 26.5, find m 3, m 4, and m 5. a. m 3 = 26.5 ; m 4 = 63.5 ; m 5 = 63.5 b. m 3 = 26.5 ; m 4 = 63.5 ; m 5 = 53 c. m 3 = 63.5 ; m 4 = 26.5 ; m 5 = 53 d. m 3 = 26.5 ; m 4 = 153.5 ; m 5 = 26.5 7. Find the perimeter and area of the figure. a. perimeter = 6x 2 + 14; area = 3x + 24 b. perimeter = 7x + 14; area = 3x + 24 c. perimeter = 7x + 14; area = 6x + 48 d. perimeter = 7x + 14; area = 6x 2 + 14 8. M is the midpoint of AN, A has coordinates ( 6, 6), and M has coordinates (1, 2). Find the coordinates of N. a. (8, 10) c. ( 2 1 2, 2) b. ( 5, 4) d. (8 1 2, 91 2 ) 9. Use the Distance Formula and the Pythagorean Theorem to find the distance, to the nearest tenth, from T(4, 2) to U( 2, 3). a. 1.0 units c. 0.0 units b. 3.4 units d. 7.8 units 10. Complete the conjecture. The sum of two odd numbers is. a. even c. sometimes odd, sometimes even b. odd d. even most of the time 11. Show that the conjecture is false by finding a counterexample. If a > b, then a b > 0. a. a = 11, b = 3 c. a = 3, b = 11 b. a = 11, b = 3 d. a = 11, b = 3 3

12. How many true conditional statements may be written using the following statements? n is a rational number. n is an integer. n is a whole number. a. 2 conditional statements c. 4 conditional statements b. 3 conditional statements d. 5 conditional statements 13. What is the truth value of the biconditional formed from the conditional, If B is the midpoint of A and C, then AB = BC. Explain. a. The conditional is true. The converse, If AB = BC then B is the midpoint of AC is false. Since the conditional is true but the converse is false, the biconditional is false. b. The conditional is true. The converse, If AB = BC then B is the midpoint of AC is true. Since the conditional is true and the converse is true, the biconditional is true. c. The conditional is false. The converse, If AB = BC then B is the midpoint of AC is false. Since the conditional is false and the converse is false, the biconditional is true. d. The conditional is false. The converse, If AB = BC then B is the midpoint of AC is true. Since the conditional is false and the converse is true, the biconditional is false. 14. A gardener has 26 feet of fencing for a garden. To find the width of the rectangular garden, the gardener uses the formula P = 2l + 2w, where P is the perimeter, l is the length, and w is the width of the rectangle. The gardener wants to fence a garden that is 8 feet long. How wide is the garden? Solve the equation for w, and justify each step. P = 2l + 2w Given equation 26 = 2(8) + 2w [1] 26 = 16 + 2w Simplify. 16 = 16 10 = 2w Subtraction Property of Equality Simplify. 10 2 = 2w 2 [2] 5 = w Simplify. w = 5 Symmetric Property of Equality a. [1] Substitution Property of Equality [2] Division Property of Equality The garden is 5 ft wide. b. [1] Simplify [2] Division Property of Equality The garden is 5 ft wide. c. [1] Substitution Property of Equality [2] Subtraction Property of Equality The garden is 5 ft wide. d. [1] Subtraction Property of Equality [2] Simplify The garden is 5 ft wide. 4

15. Two angles with measures (2x 2 + 3x 5) and (x 2 + 11x 7) are supplementary. Find the value of x and the measure of each angle. a. x = 5; 60 ; 30 c. x = 5; 60 ; 120 b. x = 6; 85 ; 95 d. x = 4; 40 ; 90 16. Use p and q to find the truth value of the compound statement p q. p : Blue is a color. q : The sum of the measures of the angles of a triangle is 160. a. Since p is true, the conjunction is true. b. Since q is true, the conjunction is true. c. Since p and q are true, the conjunction is true. d. Since q is false, the conjunction is false. 5

17. Draw two lines and a transversal such that 1 and 2 are alternate interior angles, 2 and 3 are corresponding angles, and 3 and 4 are alternate exterior angles. What type of angle pair is 1 and 4? a. b. 1 and 4 are supplementary angles. c. 1 and 4 are corresponding angles. d. 1 and 4 are vertical angles. 1 and 4 are alternate exterior angles. 6

18. Find m ABC. a. m ABC = 40 c. m ABC = 35 b. m ABC = 45 d. m ABC = 50 19. Use the Converse of the Corresponding Angles Postulate and 1 2 to show that l Ä m. a. 1 2 is given. From the diagram, 1 and 2 are corresponding angles. So by the Converse of the Corresponding Angles Postulate, l Ä m. b. 1 2 is given. From the diagram, 1 and 2 are alternate interior angles. So by the Converse of the Alternate Interior Angles Postulate, l Ä m. c. By the Converse of the Corresponding Angles Postulate, 1 2. From the diagram, l Ä m. d. 1 2 is given. From the diagram, 1 and 2 are corresponding angles. So by the Corresponding Angles Postulate, l Ä m. 20. Write the equation of the line with slope 2 through the point (4, 7) in point-slope form. a. y = 2x 1 c. y 4 = 2(x 7) b. y = 2x + 7 d. y 7 = 2(x 4) 7

21. Both stores see the same number of people. How many customers must both stores have before the total amount of money they have is equal? Jala s Yogurt Shop Ela s Salad Store Starting Money $20 $30 Money per Customer $6 $4 a. 5 customers c. 20 cents b. $50 d. 20 customers 22. Find m K. a. m K = 63 c. m K = 79 b. m K = 55 d. m K = 39 23. Given: ABC MNO Identify all pairs of congruent corresponding parts. a. A M, B N, C O, AB MN, BC NO, AC MO b. A M, B O, C N, AB MN, BC NO, AC MO c. A M, B N, C O, AB MO, BC NO, AC MN d. A O, B N, C M, AB NO, BC MN, AC MO 8

24. Show ABD CDB for a = 3. Complete the proof. AB = a + 7 = [1] = 10 CD = 4a 2 = [2] = 12 2 = 10 AD = 6a 2 = 6(3) 2 = 18 2 = [3] CB = [4] AB CD. AD CB. BD BD by the Reflexive Property of Congruence. So ABD CDB by [5]. a. [1] a + 7 [2] 4a 2 [3] 16 [4] 16 [5] SAS b. [1] 3 + 7 [2] 4(3) 2 [3] 26 [4] 26 [5] SSS c. [1] 3 + 7 [2] 4(3) 2 [3] 16 [4] 16 [5] SAS d. [1] 3 + 7 [2] 4(3) 2 [3] 16 [4] 16 [5] SSS 25. Determine if you can use the HL Congruence Theorem to prove ACD DBA. If not, tell what else you need to know. a. Yes. b. No. You do not know that C and B are right angles. c. No. You do not know that AC BD. d. No. You do not know that AB Ä CD. 9

26. Which of the following is not a positioning of a right triangle with leg lengths of 4 units and 5 units? a. c. b. d. 27. Find the measure of each numbered angle. a. m 1 = 54, m 2 = 117, m 3 = 63 b. m 1 = 117, m 2 = 63, m 3 = 63 c. m 1 = 54, m 2 = 63, m 3 = 63 d. m 1 = 54, m 2 = 63, m 3 = 117 28. Find the orthocenter of ABC with vertices A(1, 3), B(2, 7), and C( 2, 3). Ê a. 2, 17 ˆ Ê 5 Ë Á c. 2, 16 ˆ 5 Ë Á Ê b. 2, 13 ˆ Ê 5 Ë Á d. 2, 11 ˆ 5 Ë Á 10

29. Find the value of x. Express your answer in simplest radical form. a. x = 3 5 c. x = 3 3 b. x = 9 5 d. x = 5 3 30. The size of a TV screen is given by the length of its diagonal. The screen aspect ratio is the ratio of its width to its height. The screen aspect ratio of a standard TV screen is 4:3. What are the width and height of a 27" TV screen? a. width: 21.6 in., height: 16.2 in. c. width: 21.6 in., height: 5.4 in. b. width: 16.2 in., height: 21.6 in. d. width: 5.4 in., height: 21.6 in. 31. Find the missing side length. Tell if the side lengths form a Pythagorean triple. Explain. a. The missing side length is 15. The side lengths form a Pythagorean triple because they are nonzero whole numbers that satisfy the equation a 2 + b 2 = c 2. b. The missing side length is 32.02. The side lengths do not form a Pythagorean triple because one of them is not a nonzero whole number. c. The missing side length is 5. The side lengths form a Pythagorean triple because they are nonzero whole numbers that satisfy the equation a 2 + b 2 = c 2. d. The missing side length is 32.02. The side lengths form a Pythagorean triple because they satisfy the equation a 2 + b 2 = c 2. 11

32. Tell if the measures 6, 14, and 13 can be side lengths of a triangle. If so, classify the triangle as acute, right, or obtuse. a. Yes; acute triangle c. Yes; right triangle b. Yes; obtuse triangle d. No. 33. Find all the values of k so that ( 3, 4), ( 8, 5), and ( 5, k) are the vertices of a right triangle. a. k = 6, 1, 9, 20 c. k = 5, 1, 9, 19 b. k = 5, 2, 7, 19 d. k = 6, 2, 7, 20 34. An architect designs the front view of a house with a gable roof that has a 45-45 -90 triangle shape. The overhangs are 0.5 meter each from the exterior walls, and the width of the house is 16 meters. What should the side length l of the triangle be? Round your answer to the nearest meter. a. 12 m c. 24 m b. 11 m d. 23 m 12

Geometry Midterm Review 18-19 Answer Section MULTIPLE CHOICE 1. ANS: C REF: 19313ea6-4683-11df-9c7d-001185f0d2ea OBJ: 1-2.1 Finding the Length of a Segment TOP: 1-2 Measuring and Constructing Segments 2. ANS: B REF: 193379f2-4683-11df-9c7d-001185f0d2ea OBJ: 1-2.2 Copying a Segment TOP: 1-2 Measuring and Constructing Segments 3. ANS: B REF: 19383eaa-4683-11df-9c7d-001185f0d2ea OBJ: 1-2.5 Using Midpoints to Find Lengths TOP: 1-2 Measuring and Constructing Segments 4. ANS: B REF: 193aa106-4683-11df-9c7d-001185f0d2ea OBJ: 1-3.1 Naming Angles TOP: 1-3 Measuring and Constructing Angles 5. ANS: A REF: 1941c81a-4683-11df-9c7d-001185f0d2ea OBJ: 1-4.1 Identifying Angle Pairs TOP: 1-4 Pairs of Angles 6. ANS: B REF: 1949163e-4683-11df-9c7d-001185f0d2ea OBJ: 1-4.4 Problem-Solving Application TOP: 1-4 Pairs of Angles 7. ANS: B REF: 194b789a-4683-11df-9c7d-001185f0d2ea OBJ: 1-5.1 Finding Perimeter and Area TOP: 1-5 Using Formulas in Geometry 8. ANS: A REF: 1954dafa-4683-11df-9c7d-001185f0d2ea OBJ: 1-6.2 Finding the Coordinates of an Endpoint TOP: 1-6 Midpoint and Distance in the Coordinate Plane 9. ANS: D REF: 19573d56-4683-11df-9c7d-001185f0d2ea OBJ: 1-6.4 Finding Distances in the Coordinate Plane TOP: 1-6 Midpoint and Distance in the Coordinate Plane 10. ANS: A REF: 19c02526-4683-11df-9c7d-001185f0d2ea OBJ: 2-1.2 Making a Conjecture TOP: 2-1 Using Inductive Reasoning to Make Conjectures 11. ANS: A REF: 19c2ae92-4683-11df-9c7d-001185f0d2ea OBJ: 2-1.4 Finding a Counterexample TOP: 2-1 Using Inductive Reasoning to Make Conjectures 12. ANS: B REF: 19cc3802-4683-11df-9c7d-001185f0d2ea TOP: 2-2 Conditional Statements 13. ANS: A REF: 19dcc176-4683-11df-9c7d-001185f0d2ea TOP: 2-4 Biconditional Statements and Definitions 14. ANS: A REF: 19df23d2-4683-11df-9c7d-001185f0d2ea OBJ: 2-5.2 Problem-Solving Application TOP: 2-5 Algebraic Proof 15. ANS: B REF: 19e8ad42-4683-11df-9c7d-001185f0d2ea TOP: 2-6 Geometric Proof 16. ANS: D REF: 19f236b2-4683-11df-9c7d-001185f0d2ea OBJ: 2-7-Ext.1 Analyzing Truth Values of Conjunctions and Disjunctions TOP: 2-7-Ext. Introduction to Symbolic Logic 17. ANS: B REF: 1a220cf2-4683-11df-9c7d-001185f0d2ea TOP: 3-1 Lines and Angles 1

18. ANS: C REF: 1a24483e-4683-11df-9c7d-001185f0d2ea OBJ: 3-2.1 Using the Corresponding Angles Postulate TOP: 3-2 Angles Formed by Parallel Lines and Transversals 19. ANS: A REF: 1a2b6f52-4683-11df-9c7d-001185f0d2ea OBJ: 3-3.1 Using the converse of the Corresponding Angles Postulate TOP: 3-3 Proving Lines Parallel 20. ANS: D REF: 1a3e8232-4683-11df-9c7d-001185f0d2ea OBJ: 3-6.1 Writing Equations of Lines TOP: 3-6 Lines in the Coordinate Plane 21. ANS: A REF: 1a4346ea-4683-11df-9c7d-001185f0d2ea OBJ: 3-6.4 Problem-Solving Application TOP: 3-6 Lines in the Coordinate Plane 22. ANS: A REF: 1a6bcf06-4683-11df-9c7d-001185f0d2ea OBJ: 4-3.3 Applying the Exterior Angle Theorem TOP: 4-3 Angle Relationships in Triangles 23. ANS: A REF: 1a7093be-4683-11df-9c7d-001185f0d2ea OBJ: 4-4.1 Naming Congruent Corresponding Parts TOP: 4-4 Congruent Triangles 24. ANS: D REF: 1a7c7f8a-4683-11df-9c7d-001185f0d2ea OBJ: 4-5.3 Verifying Triangle Congruence TOP: 4-5 Triangle Congruence: SSS and SAS 25. ANS: A REF: 1a8608fa-4683-11df-9c7d-001185f0d2ea OBJ: 4-6.4 Applying HL Congruence TOP: 4-6 Triangle Congruence: ASA, AAS, and HL 26. ANS: B REF: 1a8fb97a-4683-11df-9c7d-001185f0d2ea OBJ: 4-8.1 Positioning a Figure in the Coordinate Plane TOP: 4-8 Introduction to Coordinate Proof 27. ANS: C REF: 1a9de092-4683-11df-9c7d-001185f0d2ea TOP: 4-9 Isosceles and Equilateral Triangles 28. ANS: A REF: 1ade6756-4683-11df-9c7d-001185f0d2ea OBJ: 5-3.3 Finding the Orthocenter TOP: 5-3 Medians and Altitudes of Triangles 29. ANS: A REF: 1af8a14a-4683-11df-9c7d-001185f0d2ea OBJ: 5-7.1 Using the Pythagorean Theorem TOP: 5-7 The Pythagorean Theorem 30. ANS: A REF: 1afadc96-4683-11df-9c7d-001185f0d2ea OBJ: 5-7.2 Application TOP: 5-7 The Pythagorean Theorem 31. ANS: A REF: 1afd3ef2-4683-11df-9c7d-001185f0d2ea OBJ: 5-7.3 Identifying Pythagorean Triples TOP: 5-7 The Pythagorean Theorem 32. ANS: A REF: 1afd6602-4683-11df-9c7d-001185f0d2ea OBJ: 5-7.4 Classifying Triangles TOP: 5-7 The Pythagorean Theorem 33. ANS: D REF: 1affa14e-4683-11df-9c7d-001185f0d2ea TOP: 5-7 The Pythagorean Theorem 34. ANS: A REF: 1b022aba-4683-11df-9c7d-001185f0d2ea OBJ: 5-8.2 Application TOP: 5-8 Applying Special Right Triangles 2

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